need help or buy python lattice attack

[ripemdhash]

I will buy lattice attack in python -

the requirement : must solve and give an output for transaction like:
I give pr is privatekey

Code:

pr== 725710314503069831932338849803462145797

#signature matches
# transaction no 1
nonce1= 635466181773964578301262500372890180991
r1= 108297976846971377520324989605074132103151896472147159117361705752439216206026
s1= 48292572324797056724183642652086380445245874011755990879073768086201489457713
z1= 63938712826439340853862518099459854257612295163211186721649505467015336097493
u1= 97699575293985539888638018601080422250764129175068566251439915640281734988097 u2= 3618502788666131106986593281521497120401173883721090761956411348172442546699

#signature matches
# transaction no 2
nonce2= 2297454118193228567824398247157239133518
r2= 74889971468329084910003803990369011079562277294326754647701006767622314748764
s2= 79212123193031641606101372044672917749900507861664167444636367741746657511814
z2= 46132298417762736469162841034177620350173999272899432251694803137249349925595
u1= 23520268126329852195412856329889731282263045248642579913662400885212386312513 u2= 41612782069660507730345822737497216884613499662792543762498730503983089287031

#signature matches
# transaction no 3
nonce3= 2637748242262487170382798584701327215215
r3= 101081837639086951808538070152378152221263991423217982948849118339761327089433
s3= 110262711150909411035033457661455696337682639129620537496094349903524705431432
z3= 50275109353313266349193282869602374118384021368645080631982138797498727418287
u1= 18997139640497188311679614727987859881744686472640995380871089009903279685953 u2= 42517407766827040507092471057877591164713793133722816452987833341026199923706

#signature matches
# transaction no 4
nonce4= 1951520611686446361719325675833956525376
r4= 3831779284607916311804971480150708958578435991895272139610832524249545031913
s4= 51467342793783521247405176259001956734913703797253287015647655058903432957667
z4= 86031185332315458368837884643178617581519377981157549023225872870046598950265
u1= 70560804378989556586238568989669193847653976519059059054692044388427095228737 u2= 9046256971665327767466483203803742801002934709302726904891028370431106366748

[ICYNOTE2023]

Let's me give an example :

p  = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141
r  = 0x0f18c2d1fe6513b90f44513e975e05cc498e7f5a565b46c65b1d448734392c6f
s1 = 0x00917766d14f2e9933eb269c83b3ad440ed8432da8beb5733f34046509e48b1d85
s2 = 0x00b29a06f2e30064542b298d711c315dca9ca99756180219699f776dd3d6a6bbc9
z1 = 0x0d9dd44880b58f3e12c66978fc4651f20442a0b47731f6bcc9af594a67dcfb7e
z2 = 0x0b5b55e26b463caf1a8884abb1787b675dcec68b4f3967f13bf4e50f5531496d

So, we will get decrypt calculated like here = 62914421751202395784887832168971429678493304086217746188800433854666065869728

https://prnt.sc/M8LNLcFc3c37

We will convert Dec to Base58 (PrivKey) = 5JsYaHVGCUzuXaQ5VkaA21VFPJFuArRWfSB77sqzWkWuTMMjXsT

https://prnt.sc/YYAKMU2aPry1

later, we get bitcoin address here : 1A8TY7dxURcsRtPBs7fP6bDVzAgpgP4962 (Uncompressed)

https://prnt.sc/wL1FnszMR3xD

[ICYNOTE2023]

Let's me give an example :

p  = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141
r  = 0x0f18c2d1fe6513b90f44513e975e05cc498e7f5a565b46c65b1d448734392c6f
s1 = 0x00917766d14f2e9933eb269c83b3ad440ed8432da8beb5733f34046509e48b1d85
s2 = 0x00b29a06f2e30064542b298d711c315dca9ca99756180219699f776dd3d6a6bbc9
z1 = 0x0d9dd44880b58f3e12c66978fc4651f20442a0b47731f6bcc9af594a67dcfb7e
z2 = 0x0b5b55e26b463caf1a8884abb1787b675dcec68b4f3967f13bf4e50f5531496d

So, we will get decrypt calculated like here = 62914421751202395784887832168971429678493304086217746188800433854666065869728

https://prnt.sc/M8LNLcFc3c37

We will convert Dec to Base58 (PrivKey) = 5JsYaHVGCUzuXaQ5VkaA21VFPJFuArRWfSB77sqzWkWuTMMjXsT

https://prnt.sc/YYAKMU2aPry1

later, we get bitcoin address here : 1A8TY7dxURcsRtPBs7fP6bDVzAgpgP4962 (Uncompressed)

https://prnt.sc/wL1FnszMR3xD

Just other example :

You should have same R value, so s1 - s2 and z1 - z2 with same PubKey (remember it)

p  = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0841274
r  = 0x00cabc3692f1f7ba75a8572dc5d270b35bcc00650534f6e5ecd6338e55355454d5
s1 = 0x00f65bfc44435a91814c142a3b8ee288a9183e6a3f012b84545d1fe334ccfac25e
s2 = 0x00b584c5e2f26eaac9510307f466d13f8d4e8f57b1323cc4151ff6ffeb6747ca9b
z1 = 0x9b076ad2fe6b2ce63acf4edf7fc82d5152d3c8bffb36b944da7a1cce038f544a
z2 = 0x5e628c458502ca2111587a510d2ba0cedb9d593f8748c11b5b8512d2c6c947d1

You will get decrypt code = 58913407951822682727715338620797546326422814407148582413227725695831142106677

Convert it = 5Joed8RJb5bAQjgqQuAH5Phx5wddXXD1VAcxQGFrqpFGpcUa1qs

and you will get address like here :
1Fn9L17mrXgTozKJiWEsFiaN9suEEUaPRX (unCompressed)
1HcETbnvkKusG3oof6V8hG7Rqb5sY78or2 (Compressed)

If you need software for this, you can PM me. Thanks

[ICYNOTE2023]

Let's me give an example :

p  = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141
r  = 0x0f18c2d1fe6513b90f44513e975e05cc498e7f5a565b46c65b1d448734392c6f
s1 = 0x00917766d14f2e9933eb269c83b3ad440ed8432da8beb5733f34046509e48b1d85
s2 = 0x00b29a06f2e30064542b298d711c315dca9ca99756180219699f776dd3d6a6bbc9
z1 = 0x0d9dd44880b58f3e12c66978fc4651f20442a0b47731f6bcc9af594a67dcfb7e
z2 = 0x0b5b55e26b463caf1a8884abb1787b675dcec68b4f3967f13bf4e50f5531496d

So, we will get decrypt calculated like here = 62914421751202395784887832168971429678493304086217746188800433854666065869728

https://prnt.sc/M8LNLcFc3c37

We will convert Dec to Base58 (PrivKey) = 5JsYaHVGCUzuXaQ5VkaA21VFPJFuArRWfSB77sqzWkWuTMMjXsT

https://prnt.sc/YYAKMU2aPry1

later, we get bitcoin address here : 1A8TY7dxURcsRtPBs7fP6bDVzAgpgP4962 (Uncompressed)

https://prnt.sc/wL1FnszMR3xD

Just information for you, if you want find Full bitcoin address. only one click with my software you can did it like this.

https://i.hizliresim.com/3rjo9rk.png