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Author Topic: HEX priv. key number off combination calculation?  (Read 93 times)
bane77 (OP)
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September 22, 2023, 02:48:08 PM
 #1

Hi

Question: what is the formula or how to calculate all possible combination of prv. key range, example: c3b7c35f28c8a6089657b848366fb2e0a48d35e36b2184ef0dff520e217cad3c - cb7baee72882261268c582ebfcfee7e1cfbd166f8de3ff2182a11228d9d98217

Or is there any website or github repositories to calculate that?

Thanks in advance!
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September 22, 2023, 03:03:06 PM
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I have never even thought about something like that. Can I ask why do you need it? And how hard did you try to Google it before posting here?
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September 22, 2023, 03:12:36 PM
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I have never even thought about something like that. Can I ask why do you need it? And how hard did you try to Google it before posting here?

I try many variants from topic question, but i get only: Converting HEX private key to bitcoin address, How to create a Bitcoin wallet address from a private key, How can I convert a bitcoin private key (hex) into a Bitcoin, bitcoin-ethereum-private-key-converter.html · GitHub,.....
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September 22, 2023, 03:13:12 PM
 #4

Hi

Question: what is the formula or how to calculate all possible combination of prv. key range, example: c3b7c35f28c8a6089657b848366fb2e0a48d35e36b2184ef0dff520e217cad3c - cb7baee72882261268c582ebfcfee7e1cfbd166f8de3ff2182a11228d9d98217

Or is there any website or github repositories to calculate that?

Thanks in advance!
I'm not an expert but still, I think as far as it relates to the private key generation the total possible values are going to be 2^256 , it's an extremely large number as 1.157920892373162e+77, can I ask a question OP why you need all possible combinations of a private key.

Also, I'm not sure about your context and can't reply efficiently but from what I understood I think you need something like, But be sure as these are just test kits they cant crack the high difficulty keys. Can you explain more to get efficient assistance why you need the key cracking?

Keygen.sh: https://keygen.sh/
GitHub repository: bitcoinjs-lib: https://github.com/bitcoinjs/bitcoinjs-lib

Even these cant help you with the generation of key... as the total number of combinations are too large..

Any other member can help you more but that is all I can do with the information OP you've provided me.

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September 22, 2023, 03:21:19 PM
Last edit: September 22, 2023, 06:52:01 PM by seoincorporation
Merited by pooya87 (4), o_e_l_e_o (4)
 #5

You can do it step by step:

c3b7c35f28c8a6089657b848366fb2e0a48d35e36b2184ef0dff520e217cad3c
cb7baee72882261268c582ebfcfee7e1cfbd166f8de3ff2182a11228d9d98217

Since both start with c, you can delete that hex number because both are in the same 'c' range:

3b7c35f28c8a6089657b848366fb2e0a48d35e36b2184ef0dff520e217cad3c
b7baee72882261268c582ebfcfee7e1cfbd166f8de3ff2182a11228d9d98217

Then change from Hex to Dec:

1681619964631834736909946030163359158422230413764693755437230999161102183740
5193970659261724958599847728180916496757916366088491570780608325158056854039

then rest them and that's all your possible combinations in that range:

3512350694629890221689901698017557338335685952323797815343377325996954670299

I hope this information helps, and if you are looking for a private key in that range i have to say it's impossible, they are too many digits to brute force.

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bane77 (OP)
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September 22, 2023, 04:50:08 PM
 #6

You can do it step by step:

c3b7c35f28c8a6089657b848366fb2e0a48d35e36b2184ef0dff520e217cad3c
cb7baee72882261268c582ebfcfee7e1cfbd166f8de3ff2182a11228d9d98217

Since both start with c, you can delete hex number:

3b7c35f28c8a6089657b848366fb2e0a48d35e36b2184ef0dff520e217cad3c
b7baee72882261268c582ebfcfee7e1cfbd166f8de3ff2182a11228d9d98217

Then change from Hex to Dec:

1681619964631834736909946030163359158422230413764693755437230999161102183740
5193970659261724958599847728180916496757916366088491570780608325158056854039

then rest them and that's all your possible combinations in that range:

3512350694629890221689901698017557338335685952323797815343377325996954670299

I hope this information helps, and if you are looking for a private key in that range i have to say it's impossible, they are too many digits to brute force.

Are you sure that form example there is 10^75 combinations, it seems like a lot  Huh , since all BTC priv. keys - 10^77?
No i dont wont to brute force it, that i know its impossible, juts curious.
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September 22, 2023, 06:33:25 PM
Last edit: September 23, 2023, 09:57:45 AM by o_e_l_e_o
Merited by seoincorporation (2)
 #7

Are you sure that form example there is 10^75 combinations, it seems like a lot  Huh , since all BTC priv. keys - 10^77?
1075 is 1% of 1077.

Bitcoin private keys fall within the following range:
Code:
0000000000000000000000000000000000000000000000000000000000000001
FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364140

The two keys you and seoincorporation have used:
Code:
C3B7C35F28C8A6089657B848366FB2E0A48D35E36B2184EF0DFF520E217CAD3C
CB7BAEE72882261268C582EBFCFEE7E1CFBD166F8DE3FF2182A11228D9D98217

C3... to CB... is around half of all keys starting with C. Keys starting with C are around 1/16th of all keys. 100/16/2 = ~3% of all keys.

So yes, the range shared above is two orders of magnitude lower than the set of all keys.
bane77 (OP)
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September 23, 2023, 08:28:52 AM
 #8

Are you sure that form example there is 10^75 combinations, it seems like a lot  Huh , since all BTC priv. keys - 10^77?
1075 is 1% of 1077.

Bitcoin private keys fall within the following range:
Code:
0000000000000000000000000000000000000000000000000000000000000001
FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364140

The two keys seoincorporation has used:
Code:
C3B7C35F28C8A6089657B848366FB2E0A48D35E36B2184EF0DFF520E217CAD3C
CB7BAEE72882261268C582EBFCFEE7E1CFBD166F8DE3FF2182A11228D9D98217

C3... to CB... is around half of all keys starting with C. Keys starting with C are around 1/16th of all keys. 100/16/2 = ~3% of all keys.

So yes, the range shared above is two orders of magnitude lower than the set of all keys.

Thanks for explanation and justification, and thanks to @seoincorporation for info!
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