Move p2pk balance

[pbies]

What would be the easiest way to move balance from a p2pk address?

If it is pay to public key then only public key would be needed only, right?

Can I build a raw transaction to move such funds? How?

[1715070321]

1715070321

[1715070321]

1715070321

[1715070321]

1715070321

[1715070321]

1715070321

[digaran]

https://bitcointalk.org/index.php?topic=5465605.0

[BitMaxz]

It seems you can only move your balance out from P2PK if you using a Bitcoin core wallet and import it and send them via Bitcoin cli(RPC) commands.

Check this link below

- https://bitcoin.stackexchange.com/questions/118127/how-to-recover-and-sweep-p2pk-coins

[pbies]

In the end I've written Python script to create raw TX for p2pk:

Code:

#!/usr/bin/env python3

import sys
import struct
import json
import binascii

txid="4e9e28b2e7d9b28824ab19f02ace19dff86aed90d8fb422c640279a6fe82e0af"
vout=0
pubkey="02396543d7ab32e75c6682b4fca35c0e68f0694b0dde355de5cc2a7f8fa4affc62"
amount=0.067

tx = bytearray()
tx = tx + binascii.unhexlify('0100000001') # one input tx - last digit
txb = bytes.fromhex(txid)
seqno = 1
txb=txb[::-1]
tx = tx + bytes(txb)
tx = tx + struct.pack('<I',vout)
tx = tx + b'\x00'
tx = tx + struct.pack('<i',seqno)
tx = tx + bytes([1]) # ?
pk = pubkey
v = amount
if len(pk) != 66:
    raise ValueError("pk not 33 bytes (66 hex digits) - it has bytes: "+str(len(pk)/2))
v = int(100000000 * v)
tx = tx + struct.pack('<Q',v)
tx = tx + b'\x23'
tx = tx + b'\x21'
tx = tx + binascii.unhexlify(pk)
tx = tx + b'\xac'
tx = tx + binascii.unhexlify('00000000')
print(binascii.hexlify(tx))

Obviously to sign the TX you need to have private key in Base58Check form already to provide while signing TX in Bitcoin Core or this UTXO in wallet.