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Author Topic: [Free Raffle] 12 MixTum collectible cards  (Read 1899 times)
babo
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December 30, 2023, 03:02:52 PM
 #61

Thank you for this
I take the Number 3

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.BLACKJACK ♠ FUN.
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Buchi-88
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December 30, 2023, 04:07:40 PM
 #62

35 - Buchi-88

Thank you

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MoparMiningLLC
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December 30, 2023, 04:17:01 PM
 #63

34 - moparminingllc thank you!

Mine BTC @ kano.is
Offering escrow services https://bitcointalk.org/index.php?topic=5154480
All Bitcoin 3D printing needs at CryptoCloaks
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December 30, 2023, 05:37:33 PM
 #64

25 - DYING_S0UL

AoBT
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JOIN US

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HIRE US
GazetaBitcoin (OP)
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December 30, 2023, 06:25:12 PM
Merited by shasan (1)
 #65

Raffle updated once more! There is one remaining available number: 26. If it won't be filled in 1-2h or so we'll roll anyway. Good luck everybody!
There are 12 prizes and 50 spots, so the parity is 0.24. In other words, this means that each participant has almost 25% chances to win a prize Smiley

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.HUGE.
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December 30, 2023, 07:35:04 PM
 #66

Okay, let's roll with block 823593!

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.HUGE.
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paid2
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December 30, 2023, 07:45:14 PM
 #67

Okay, let's roll with block 823593!

Yeeeah  Cool
Good luck guys!

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December 30, 2023, 08:01:30 PM
Last edit: December 31, 2023, 07:59:22 AM by GazetaBitcoin
Merited by willi9974 (1), JanEmil (1), Rifmax (1)
 #68

Okay, let's roll with block 823593!

Last 2 digits of 823593 are 88. Since we don't have this number we'll take closest one => 50. JanEmil is our first winner!

Next block: 823596!



Last 2 digits of 823596 are 48. Bullion-n-BTC is our second winner!

Next block: 823598!



Last 2 digits of 823596 are 69. Since we don't have this number we'll take closest one => 49. Willi9974 is our third winner!

Next block: 823599!



Last 2 digits of 823599 are 86. Since we don't have this number we'll take closest one => 47. hopenotlate is our fourth winner!

Next block: 823602!



Last 2 digits of 823602 are 38. BABY SHOES is our fifth winner!

Next block: 823604!



Last 2 digits of 823604 are 65. Since we don't have this number we'll take closest one => 46. wwzsocki is our sixth winner!

Next block: 823610!



Last 2 digits of 823610 are 53. Since we don't have this number we'll take closest one => 45. bitbollo is our seventh winner!

Next block: 823616!



Last 2 digits of 823616 are 38, which was a previous winner block. Both 37 and 39 are at equal distance to 28, this block is invalid.

Next block: 823622!



Last 2 digits of 823622 are 49, which was a previous winner block. Since we don't have this number anymore we'll take closest one => 44. mv1986 is our eighth winner!

Next block: 823624!



Last 2 digits of 823624 are 71. Since we don't have this number anymore we'll take closest one => 43. Caribbean_Treasures is our ninth winner!

Next block: 823630!



Last 2 digits of 823630 are 28. NeuroticFish is our tenth winner!

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.HUGE.
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BlackHatCoiner
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December 30, 2023, 08:04:55 PM
 #69

Shouldn't we ignore what's higher than 50? Otherwise, the person who chooses 50 gets like way more advantage.

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.HUGE.
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December 30, 2023, 08:16:08 PM
 #70

Shouldn't we ignore what's higher than 50? Otherwise, the person who chooses 50 gets like way more advantage.

I guess since I did not state that in rules since the beginning it would be too late and not correct to do it now...

.
.HUGE.
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December 30, 2023, 08:24:38 PM
 #71

No hard feelings to correct it for me.

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December 30, 2023, 08:27:26 PM
 #72

I guess since I did not state that in rules since the beginning it would be too late and not correct to do it now...
I personally don't mind much, but it's just unfair competition. The closer you are to 50, the more odds you have to win, statistically. The last participant (in terms of selected number) gets more than 50% chance to win, always.

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December 30, 2023, 08:52:00 PM
 #73

I guess since I did not state that in rules since the beginning it would be too late and not correct to do it now...
I personally don't mind much, but it's just unfair competition. The closer you are to 50, the more odds you have to win, statistically. The last participant (in terms of selected number) gets more than 50% chance to win, always.

Yeah I agree.

The best way to do it would be like krogoth do his weekly raffles : 100 spots and a determined date to close the applications, and chose the block number no matter if all spots are full or not. 1% for everyone applying  Smiley

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December 30, 2023, 08:53:16 PM
 #74

I personally don't mind much, but it's just unfair competition. The closer you are to 50, the more odds you have to win, statistically. The last participant (in terms of selected number) gets more than 50% chance to win, always.

I apologize for this, as I apologize as well for not anticipating the possible issue raised by cygan. Please bear in mind that this is my first free raffle though and have some understanding with me. I am sorry if I did not meet the standards of Collectibles board and all strategies. The main purpose was to offer the prizes. I did not calculate thoroughly all mathematical possible issues.

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December 30, 2023, 08:57:47 PM
 #75

I apologize for this, as I apologize as well for not anticipating the possible issue raised by cygan. Please bear in mind that this is my first free raffle though and have some understanding with me. I am sorry if I did not meet the standards of Collectibles board and all strategies. The main purpose was to offer the prizes. I did not calculate thoroughly all mathematical possible issues.

You are doing great!

I mean, we just need to re-roll each block which is > 50 and use the next one if we want to be fair, everything else is perfectly fine with this raffle imo  Smiley

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December 30, 2023, 08:58:26 PM
 #76

No stress. Just because all would like to win a fine card. That is good sign.

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December 30, 2023, 09:03:00 PM
 #77

The best way to do it would be like krogoth do his weekly raffles : 100 spots and a determined date to close the applications, and chose the block number no matter if all spots are full or not. 1% for everyone applying
That requires 100 spots, which is pretty limiting. The best way to do it is to simply ignore every invalid number. For example, in our case, if a block hash ends with "05f1159", the winner is 11. If it ended with "199999", the winner is 19. If the next one ended with "000119", the winner is 01 (19 is ignored, because they already won).

The main purpose was to offer the prizes. I did not calculate thoroughly all mathematical possible issues.
I believe you can still fix this if you redo the process (e.g., plan another block to begin the raffle). I don't think anyone would disagree. It's just the fair thing to do.

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December 30, 2023, 09:07:53 PM
 #78


Last 2 digits of 823593 are 88. Since we don't have this number we'll take closest one => 50. JanEmil is our first winner!

Next block: 823596!



Last 2 digits of 823596 are 48. Bullion-n-BTC is our second winner!

Next block: 823598!



Last 2 digits of 823596 are 69. Since we don't have this number we'll take closest one => 49. Willi9974 is our third winner!

Next block: 823599!



Last 2 digits of 823599 are 86. Since we don't have this number we'll take closest one => 47. hopenotlate is our fourth winner!

Next block: 823602!



Last 2 digits of 823602 are 38. BABY SHOES is our fifth winner!

Next block: 823604!





Instead of that may I propose, (and if Mr JanEmil is volunteer ti switch his spot to spot n° 26!), to make to calculus for numbers bigger to 49 like :  

* 88 -(minus)50 = 38

* 69 - 50 = 19   etc.


So we subtract 50 for any number bigger between [50 and 99] !  Shocked







Shouldn't we ignore what's higher than 50? Otherwise, the person who chooses 50 gets like way more advantage.

I guess since I did not state that in rules since the beginning it would be too late and not correct to do it now...

But you didn't state the rules about the draw at all !

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December 30, 2023, 09:09:34 PM
 #79

OK

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December 30, 2023, 09:12:00 PM
Last edit: December 30, 2023, 09:41:27 PM by BlackHatCoiner
 #80

That solution can work too.

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