Phy Challenge

[PHA_.07]

Does any one even know the span?  For ones saying they have everything except for k that is. It is not about out doing each other but i know as soon as i say something the keyboard warriors will pop off saying they already know as they furiously try to work out the other clue that they didn't even know was there. The amount is small also even if you look at it both ways wink.
For the ones that are looking crossed eyed at the pics do you have your R's?

[KarTonP]

Point R was originally included in the first message. This is because it is, in fact, a signature. Point R should not correspond to Q. If point R did correspond to Q, it would be possible to solve the puzzle with a standard attack in 1 second, given that k—which is equal to the live d—would be hidden at point R.
Therefore, the correct value of Rx is still:
0x4775BC7C8B5905E441664185F426656BBC8E05C0E780E02F1F9B3C940D06B2F8

[PHA_.07]

Point R was originally included in the first message. This is because it is, in fact, a signature. Point R should not correspond to Q. If point R did correspond to Q, it would be possible to solve the puzzle with a standard attack in 1 second, given that k—which is equal to the live d—would be hidden at point R.
Therefore, the correct value of Rx is still:
0x4775BC7C8B5905E441664185F426656BBC8E05C0E780E02F1F9B3C940D06B2F8

What does it span? R native bc1q if you got this side wheres the other.

[kTimesG]

This phrase provides two clues right away.

The third one helps as well. But anyway, all the clues I've given were already in the puzzle, since the puzzle is already self-explaining itself. The smart approach can find the correct solution in 4 milliseconds. The matrix coefficients probabilistic activation approach seems to be struggling for 3+ months so far, so who wins? Don't get fooled by AI hype, that shit's corporate marketing, it can't do anything by itself unless someone else already did it before. Once you understand that, better for you.

[detechs]

This phrase provides two clues right away.

The third one helps as well. But anyway, all the clues I've given were already in the puzzle, since the puzzle is already self-explaining itself. The smart approach can find the correct solution in 4 milliseconds. The matrix coefficients probabilistic activation approach seems to be struggling for 3+ months so far, so who wins? Don't get fooled by AI hype, that shit's corporate marketing, it can't do anything by itself unless someone else already did it before. Once you understand that, better for you.

is the 34 marks around the bitcoin relevant? Most of them line up perfectly with a single emoji, the only other thing I thought of trying was moving the image as if it was a pillowed cube.

The other things in the OP I'm not sure what you do with them, like the differences to the whitepaper and which version of the whitepaper was referenced, and that one number that was added by you to the whitepaper part

[PHA_.07]

yes the 34 ticks, i have the pic that lines up the emojis for a/b from the ticks and make a perfect set up.and what about the = above BTC and below. so above and below that's why i was going about it a different way also the R difference. Which says the same thing.  Look at the shine on the left upper it dont match to what it should. There guys saying they got everything but the k dont think so.

I like op  message and we already know what was inside.
  and there is a prize (as of today). If you reach a state where you believe "this cannot be solved", it means you are missing the direct and indirect clues along the way.

A final useful sign (the password's already mentioned).

Code:

-----BEGIN PGP MESSAGE-----

jA0ECQMKVwglgSLxlRn/0jcBn0f9h3kbilK/NDDWZCkuONpev7JZbbw+l6uVZC0N
aJFXTLG6sbLXr6t0z3scptSM3vWBCmOU
=D+ub
-----END PGP MESSAGE-----

[KarTonP]

He was referring to this line here:
J0d1vHyLWQXkQWZBhfQmZWu8jgXA54DgLx+bPJQNBrL4AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAABbiQspK6Gr2bE

He originally made a mistake with the space, and there was no “J” there—just throw your LLM in the trash already)))

The signature that outputs “.” and is converted to z = is a step we've already gone through.

2026-07-30 edit: fixed BACKSPACE cat incident (missing "J" character)

s: 0x5B890B292BA1ABD9B1
r: 0x4775BC7C8B5905E441664185F426656BBC8E05C0E780E02F1F9B3C940D06B2F8
e: 0xBC4FDA25213E0528C531760D82529FD2AC59570EE028F9909F1C83915E481D3F
Q: 02425afdd1716149faf414b6fdb96d5e7afc8ce42496042f4df559c80a7c6650eb

I’ll repeat once more that all these values are mutually consistent.
Consequently, we see that r = is valid for this (s⋅R=e⋅G+r⋅Q)
Therefore, the formula d=(k⋅s−e)⋅r−1(modN)
will yield the correct answer.
d = Qpub
kTimesG, I right?

What questions could there possibly be? Stop looking for conspiracy theories against you.
I'll leave this for those who need it. Especially for PHA.07, for his deleted, nonsensical posts.

[detechs]

He was referring to this line here:
J0d1vHyLWQXkQWZBhfQmZWu8jgXA54DgLx+bPJQNBrL4AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAABbiQspK6Gr2bE

He originally made a mistake with the space, and there was no “J” there—just throw your LLM in the trash already)))

The signature that outputs “.” and is converted to z = is a step we've already gone through.

2026-07-30 edit: fixed BACKSPACE cat incident (missing "J" character)

s: 0x5B890B292BA1ABD9B1
r: 0x4775BC7C8B5905E441664185F426656BBC8E05C0E780E02F1F9B3C940D06B2F8
e: 0xBC4FDA25213E0528C531760D82529FD2AC59570EE028F9909F1C83915E481D3F
Q: 02425afdd1716149faf414b6fdb96d5e7afc8ce42496042f4df559c80a7c6650eb

I’ll repeat once more that all these values are mutually consistent.
Consequently, we see that r = is valid for this (s⋅R=e⋅G+r⋅Q)
Therefore, the formula d=(k⋅s−e)⋅r−1(modN)
will yield the correct answer.
d = Qpub
kTimesG, I right?

What questions could there possibly be? Stop looking for conspiracy theories against you.
I'll leave this for those who need it. Especially for PHA.07, for his deleted, nonsensical posts.

you can get k this way as well


k = e * (s - r*c)^-1 mod n

c = d * k^-1 mod n


e = the message hash

s = the posted s

r = the posted r

n = the curve order

k = the nonce

d = the private key

c = d over k

it comes from the one relation, s * k = e + r * d mod n, with d replaced by c * k

the test of a candidate c is one point multiply: c * R == Q, where R = k * G and Q = d * G

[kTimesG]

This is a hint.

[KarTonP]

This is a hint.

The clue is that we should have looked for an alternative formula from the start—the one detechs provided
as an example with the letter C =—which, according to the formula, would correspond to?
c·R = Q
k = e * (s - r*c)^-1 mod n
c = d * k^-1 mod n
We’ve actually checked this as well. But to be honest, we haven’t found the correct value for C yet.

[detechs]

This is a hint.

Is posting 11 seconds before the equinox relevant? Is the wind blowing now?

[unaimous]

Code:

+----------------------+--------------+------+
| Event                | Date / Value | Tag  |
+----------------------+--------------+------+
| Original Post        | June 05      | F₅   |
| ASCII 8 Accident     | 8            | F₆   |
| ROT-13               | 13           | F₇   |
| Funded               | June 21      | F₈   |
| 34 ticks on BTC logo | 34           | F₉   |
+----------------------+--------------+------+

Probably nothing.

[PHA_.07]

Yes the offset or c as you are calling it now. not the we only need missing k fanboys.   He did not quote  with his latest post what would that tell you

[clark2346547]

This is a hint.

Hey, I was thinking about your hint regarding the 'two classes' needing exactly one bit to separate them. I initially assumed the two classes were just the two spiral arms (odd vs even indices). But since the 258 - i pairs always stay on the same arm, an odd/even rule doesn't cleanly assign a unique sign to a pair. Did I completely misidentify what the two classes are, or am I applying the 1-bit separator to the wrong part of the math?