Can you show the math on this? My gut feeling tells me this should produce much less than 128 bits entropy, but my statistics is rusty.
I can show you the math, but you need the gut feeling to be confident, so just think of this: in 99 rolls, you are still going to get about 25 rolls that are not a 5. To crack your sequence, an attacker doesn't just have to guess that 74 of the rolls are 5s; they have to guess which 25 rolls are the non-5s (there are massive combinations of just placing 25 items in 99 slots), and then they have to guess what specific number (1, 2, 3, 4, or 6) each of those 25 rolls landed on. The sheer combination of where the rare rolls happen, and what they are, easily eclipses the 2^128 possibilities.
C(99, 25) = 6.44 x 10^23, or 644 sextillion different ways just to arrange the positions of the non-5 rolls.
Once the attacker guesses the correct 25 slots, they have to guess what specific number landed in each of those slots. Since the dice has six sides and we know these aren't 5s, there are 5 remaining possibilities (1, 2, 3, 4, or 6) for each of the 25 slots.
That's 5^25 = 2.98 x 10^17. That is another 298 quadrillion possibilities just for the values of those rare rolls.
In total, that's 1.92 x 10^41 unique ways to roll exactly 25 non-fives and 74 fives on 99 dice. For the record, 2^128 is 3.4 x 10^38.