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April 17, 2014, 05:49:15 PM |
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As I understand, the difficulty is the number of hashes, divided by 2^32, required (in average) in order to get a SHA-256 below a target value T. And further, that the target value is actually what is adjusted in the algorithm. Is it then correct that D*(2^32)=(2^256)/T ? Or have I got it wrong here?
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