d3m0n1q_733rz


February 09, 2012, 01:43:39 AM 

Hey everyone! I've decided to add Diapolo's GOFFSET option to Phatk2. In some cases, it works better, in others, it doesn't. Enable it to find out via GOFFSET! This kernel is for Phoenix 2.0.0. Currently, I test kernels on an ATI HD5450 graphics card. If anyone wants to help further my OpenCL expertise, I happily welcome donations to 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq. They'll be put towards a new GPU or two (VLIW and GCN) and programming guides so I can compile optimum code. I already have the ideas, now I just need to get them out in the open. I'll also be helping Diapolo test his kernel and donate to help him out. (A day's worth of hashing each week should be enough) // This file is in the public domain
#ifdef VECTORS8 typedef uint8 u; #elif defined VECTORS4 typedef uint4 u; #elif defined VECTORS typedef uint2 u; #else typedef uint u; #endif
__constant uint K[64] = { 0x428a2f98, 0x71374491, 0xb5c0fbcf, 0xe9b5dba5, 0x3956c25b, 0x59f111f1, 0x923f82a4, 0xab1c5ed5, 0xd807aa98, 0x12835b01, 0x243185be, 0x550c7dc3, 0x72be5d74, 0x80deb1fe, 0x9bdc06a7, 0xc19bf174, 0xe49b69c1, 0xefbe4786, 0x0fc19dc6, 0x240ca1cc, 0x2de92c6f, 0x4a7484aa, 0x5cb0a9dc, 0x76f988da, 0x983e5152, 0xa831c66d, 0xb00327c8, 0xbf597fc7, 0xc6e00bf3, 0xd5a79147, 0x06ca6351, 0x14292967, 0x27b70a85, 0x2e1b2138, 0x4d2c6dfc, 0x53380d13, 0x650a7354, 0x766a0abb, 0x81c2c92e, 0x92722c85, 0xa2bfe8a1, 0xa81a664b, 0xc24b8b70, 0xc76c51a3, 0xd192e819, 0xd6990624, 0xf40e3585, 0x106aa070, 0x19a4c116, 0x1e376c08, 0x2748774c, 0x34b0bcb5, 0x391c0cb3, 0x4ed8aa4a, 0x5b9cca4f, 0x682e6ff3, 0x748f82ee, 0x78a5636f, 0x84c87814, 0x8cc70208, 0x90befffa, 0xa4506ceb, 0xbef9a3f7, 0xc67178f2 };
__constant uint ConstW[128] = { 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x80000000U, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000280U, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000,
0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x80000000U, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000100U, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000 };
__constant uint H[8] = { 0x6a09e667, 0xbb67ae85, 0x3c6ef372, 0xa54ff53a, 0x510e527f, 0x9b05688c, 0x1f83d9ab, 0x5be0cd19 };
#ifdef BITALIGN #pragma OPENCL EXTENSION cl_amd_media_ops : enable #define rot(x, y) amd_bitalign(x, x, (uint)(32  y)) #else #define rot(x, y) rotate(x, (uint)y) #endif
// Some AMD devices have the BFI_INT opcode, which behaves exactly like the // SHA256 Ch function, but provides it in exactly one instruction. If // detected, use it for Ch. Otherwise, use bitselect() for Ch.
#ifdef BFI_INT // Well, slight problem... It turns out BFI_INT isn't actually exposed to // OpenCL (or CAL IL for that matter) in any way. However, there is // a similar instruction, BYTE_ALIGN_INT, which is exposed to OpenCL via // amd_bytealign, takes the same inputs, and provides the same output. // We can use that as a placeholder for BFI_INT and have the application // patch it after compilation.
// This is the BFI_INT function #define Ch(x, y, z) amd_bytealign(x,y,z) // Ma can also be implemented in terms of BFI_INT... #define Ma(z, x, y) amd_bytealign(z^x,y,x) #else #define Ch(x, y, z) bitselect(z,y,x) #define Ma(x, y, z) bitselect(x,y,(z^x)) #endif
//Various intermediate calculations for each SHA round #define s0(n) (S0(Vals[(0 + 128  (n)) % 8])) #define S0(n) (rot(n, 30u)^rot(n, 19u)^rot(n,10u))
#define s1(n) (S1(Vals[(4 + 128  (n)) % 8])) #define S1(n) (rot(n, 26u)^rot(n, 21u)^rot(n, 7u))
#define ch(n) Ch(Vals[(4 + 128  (n)) % 8],Vals[(5 + 128  (n)) % 8],Vals[(6 + 128  (n)) % 8]) #define maj(n) Ma(Vals[(1 + 128  (n)) % 8],Vals[(2 + 128  (n)) % 8],Vals[(0 + 128  (n)) % 8])
//t1 calc when W is already calculated #define t1(n) K[(n) % 64] + Vals[(7 + 128  (n)) % 8] + W[(n)] + s1(n) + ch(n)
//t1 calc which calculates W #define t1W(n) K[(n) % 64] + Vals[(7 + 128  (n)) % 8] + W(n) + s1(n) + ch(n)
//Used for constant W Values (the compiler optimizes out zeros) #define t1C(n) (K[(n) % 64]+ ConstW[(n)]) + Vals[(7 + 128  (n)) % 8] + s1(n) + ch(n)
//t2 Calc #define t2(n) maj(n) + s0(n)
#define rotC(x,n) (x<<n  x >> (32n))
//W calculation used for SHA round #define W(n) (W[n] = P4(n) + P3(n) + P2(n) + P1(n))
//Partial W calculations (used for the begining where only some values are nonzero) #define P1(n) ((rot(W[(n)2],15u)^rot(W[(n)2],13u)^((W[(n)2])>>10U))) #define P2(n) ((rot(W[(n)15],25u)^rot(W[(n)15],14u)^((W[(n)15])>>3U))) #define p1(x) ((rot(x,15u)^rot(x,13u)^((x)>>10U))) #define p2(x) ((rot(x,25u)^rot(x,14u)^((x)>>3U))) #define P3(n) W[n7] #define P4(n) W[n16]
//Partial Calcs for constant W values #define P1C(n) ((rotC(ConstW[(n)2],15)^rotC(ConstW[(n)2],13)^((ConstW[(n)2])>>10U))) #define P2C(n) ((rotC(ConstW[(n)15],25)^rotC(ConstW[(n)15],14)^((ConstW[(n)15])>>3U))) #define P3C(x) ConstW[x7] #define P4C(x) ConstW[x16]
//SHA round with built in W calc #define sharoundW(n) Barrier1(n); Vals[(3 + 128  (n)) % 8] += t1W(n); Vals[(7 + 128  (n)) % 8] = t1W(n) + t2(n);
//SHA round without W calc #define sharound(n) Barrier2(n); Vals[(3 + 128  (n)) % 8] += t1(n); Vals[(7 + 128  (n)) % 8] = t1(n) + t2(n);
//SHA round for constant W values #define sharoundC(n) Barrier2(n); Vals[(3 + 128  (n)) % 8] += t1C(n); Vals[(7 + 128  (n)) % 8] = t1C(n) + t2(n);
//The compiler is stupid... I put this in there only to stop the compiler from (de)optimizing the order #define Barrier1(n) t1 = t1C((n+1)) #define Barrier2(n) t1 = t1C((n))
__kernel //removed this to allow detection of invalid work size //__attribute__((reqd_work_group_size(WORKSIZE, 1, 1))) void search( const uint state0, const uint state1, const uint state2, const uint state3, const uint state4, const uint state5, const uint state6, const uint state7, const uint B1, const uint C1, const uint D1, const uint F1, const uint G1, const uint H1, #ifndef GOFFSET const u base, #endif const uint W16, const uint W17, const uint PreVal4, const uint PreVal0, const uint PreW31, const uint PreW32, const uint PreW19, const uint PreW20, __global uint * output) {
u W[124]; u Vals[8];
//Dummy Variable to prevent compiler from reordering between rounds u t1;
//Vals[0]=state0; Vals[1]=B1; Vals[2]=C1; Vals[3]=D1; //Vals[4]=PreVal4; Vals[5]=F1; Vals[6]=G1; Vals[7]=H1;
W[16] = W16; W[17] = W17;
#ifdef VECTORS8 #ifdef GOFFSET W[3] = ((uint)get_global_id(0) << 3) + (u)(0, 1, 2, 3, 4, 5, 6, 7); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); #else W[3] = base + (uint)(get_local_id(0)) * 8u + (uint)(get_group_id(0)) * (WORKSIZE * 8u); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); //Since only the 2 LSB is opposite between the nonces, we can save an instruction by flipping the 4 bits in W18 rather than the 1 bit in W3 W[18] = PreW20 + (u){r, r ^ 0x2004000U, r ^ 0x4008000U, r ^ 0x600C000U, r ^ 0x8010000U, r ^ 0xA050000U, r ^ 0xC090000U, r ^ 0xE0D0000U}; #endif
#elif defined VECTORS4 #ifdef GOFFSET W[3] = ((uint)get_global_id(0) << 2) + (u)(0, 1, 2, 3); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); #else
//Less dependencies to get both the local id and group id and then add them W[3] = base + (uint)(get_local_id(0)) * 4u + (uint)(get_group_id(0)) * (WORKSIZE * 4u); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); //Since only the 2 LSB is opposite between the nonces, we can save an instruction by flipping the 4 bits in W18 rather than the 1 bit in W3 W[18] = PreW20 + (u){r, r ^ 0x2004000U, r ^ 0x4008000U, r ^ 0x600C000U}; #endif #elif defined VECTORS #ifdef GOFFSET W[3] = ((uint)get_global_id(0) << 1) + (u)(0, 1,); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); #else W[3] = base + (uint)(get_local_id(0)) * 2u + (uint)(get_group_id(0)) * (WORKSIZE * 2u); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); W[18] = PreW20 + (u){r, r ^ 0x2004000U}; #endif #else #ifdef GOFFSET W[3] = ((uint)get_global_id(0)); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); #else W[3] = base + get_local_id(0) + get_group_id(0) * (WORKSIZE); u r = rot(W[3],25u)^rot(W[3],14u)^((W[3])>>3U); W[18] = PreW20 + r; #endif #endif //the order of the W calcs and Rounds is like this because the compiler needs help finding how to order the instructions
Vals[4] = PreVal4 + W[3]; Vals[0] = PreVal0 + W[3];
sharoundC(4); W[19] = PreW19 + W[3]; sharoundC(5); W[20] = P4C(20) + P1(20); sharoundC(6); W[21] = P1(21); sharoundC(7); W[22] = P3C(22) + P1(22); sharoundC(8); W[23] = W[16] + P1(23); sharoundC(9); W[24] = W[17] + P1(24); sharoundC(10); W[25] = P1(25) + P3(25); W[26] = P1(26) + P3(26); sharoundC(11); W[27] = P1(27) + P3(27); W[28] = P1(28) + P3(28); sharoundC(12); W[29] = P1(29) + P3(29); sharoundC(13); W[30] = P1(30) + P2C(30) + P3(30); W[31] = PreW31 + (P1(31) + P3(31)); sharoundC(14); W[32] = PreW32 + (P1(32) + P3(32)); sharoundC(15); sharound(16); sharound(17); sharound(18); sharound(19); sharound(20); sharound(21); sharound(22); sharound(23); sharound(24); sharound(25); sharound(26); sharound(27); sharound(28); sharound(29); sharound(30); sharound(31); sharound(32); sharoundW(33); sharoundW(34); sharoundW(35); sharoundW(36); sharoundW(37); sharoundW(38); sharoundW(39); sharoundW(40); sharoundW(41); sharoundW(42); sharoundW(43); sharoundW(44); sharoundW(45); sharoundW(46); sharoundW(47); sharoundW(48); sharoundW(49); sharoundW(50); sharoundW(51); sharoundW(52); sharoundW(53); sharoundW(54); sharoundW(55); sharoundW(56); sharoundW(57); sharoundW(58); sharoundW(59); sharoundW(60); sharoundW(61); sharoundW(62); sharoundW(63);
W[64]=state0+Vals[0]; W[65]=state1+Vals[1]; W[66]=state2+Vals[2]; W[67]=state3+Vals[3]; W[68]=state4+Vals[4]; W[69]=state5+Vals[5]; W[70]=state6+Vals[6]; W[71]=state7+Vals[7];
const u Temp = (0xb0edbdd0U + K[0]) + W[64]; Vals[0]=H[0]; Vals[1]=H[1]; Vals[2]=H[2]; Vals[3]=0xa54ff53aU + Temp; Vals[4]=H[4]; Vals[5]=H[5]; Vals[6]=H[6]; Vals[7]=0x08909ae5U + Temp;
#define P124(n) P2(n) + P1(n) + P4(n)
W[80] = P2(80) + P4(80); sharound(65); W[81] = P1C(81) + P2(81) + P4(81); sharound(66); W[82] = P124(82); sharound(67); W[83] = P124(83); sharound(68); W[84] = P124(84); sharound(69); W[85] = P124(85); sharound(70); W[86] = P4(86) + P3C(86) + P2(86) + P1(86); sharound(71); W[87] = P4(87) + P3(87) + P2C(87) + P1(87); sharoundC(72); W[88] = P1(88) + P4C(88) + P3(88); sharoundC(73); W[89] = P3(89) + P1(89); sharoundC(74); W[90] = P3(90) + P1(90); sharoundC(75); W[91] = P3(91) + P1(91); sharoundC(76); W[92] = P3(92) + P1(92); sharoundC(77); W[93] = P1(93) + P3(93); W[94] = P3(94) + P2C(94) + P1(94); sharoundC(78); W[95] = P4C(95) + P3(95) + P2(95) + P1(95); sharoundC(79); sharound(80); sharound(81); sharound(82); sharound(83); sharound(84); sharound(85); sharound(86); sharound(87); sharound(88); sharound(89); sharound(90); sharound(91); sharound(92); sharound(93); sharound(94); sharound(95); sharoundW(96); sharoundW(97); sharoundW(98); sharoundW(99); sharoundW(100); sharoundW(101); sharoundW(102); sharoundW(103); sharoundW(104); sharoundW(105); sharoundW(106); sharoundW(107); sharoundW(108); sharoundW(109); sharoundW(110); sharoundW(111); sharoundW(112); sharoundW(113); sharoundW(114); sharoundW(115); sharoundW(116); sharoundW(117); sharoundW(118); sharoundW(119); sharoundW(120); sharoundW(121); sharoundW(122);
u v = W[117] + W[108] + Vals[3] + Vals[7] + P2(124) + P1(124) + Ch((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123),Vals[1],Vals[2]); u g = (K[60] + H[7])  S1((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123));
uint nonce = 0; #ifdef VECTORS8 if (v.s0 == g.s0) { nonce = W[3].s0; } if (v.s1 == g.s1) { nonce = W[3].s1; } if (v.s2 == g.s2) { nonce = W[3].s2; } if (v.s3 == g.s3) { nonce = W[3].s3; } if (v.s4 == g.s4) { nonce = W[3].s4; } if (v.s5 == g.s5) { nonce = W[3].s5; } if (v.s6 == g.s6) { nonce = W[3].s6; } if (v.s7 == g.s7) { nonce = W[3].s7; } #elif defined VECTORS4 if (v.s0 == g.s0) { nonce = W[3].s0; } if (v.s1 == g.s1) { nonce = W[3].s1; } if (v.s2 == g.s2) { nonce = W[3].s2; } if (v.s3 == g.s3) { nonce = W[3].s3; } #elif defined VECTORS if (v.s0 == g.s0) { nonce = W[3].s0; } if (v.s1 == g.s1) { nonce = W[3].s1; } #else if (v == g) { nonce = W[3]; } #endif if(nonce) { //Faster to shift the nonce by 2 due to 4DWORD addressing and does not add more collisions output[WORKSIZE] = nonce; output[get_local_id(0)] = nonce; } } As you may be able to tell, I've started adding VECTORS8 to the code as well, but I am having difficulty keeping it from spilling over into memory. If someone could assist me with this, I would appreciate it.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq








Goat says: "Bitcoin is NOT Illegal in Thailand. There is no law against Bitcoin in Thailand!"



Advertised sites are not endorsed by the Bitcoin Forum. They may be unsafe, untrustworthy, or illegal in your jurisdiction. Advertise here.




d3m0n1q_733rz


February 09, 2012, 02:43:05 AM 

Gah...I need to toss in an init file...crud. I'll mess with it later.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



ssateneth
Legendary
Offline
Activity: 1330
Merit: 1004


February 09, 2012, 02:44:08 AM 

oh, and I was just going to test this kernel too to see what the hell goffset did for hashes




gat3way


February 09, 2012, 09:17:42 AM 

I'd advise you to change this: #ifdef VECTORS8 if (v.s0 == g.s0) { nonce = W[3].s0; } if (v.s1 == g.s1) { nonce = W[3].s1; } if (v.s2 == g.s2) { nonce = W[3].s2; } if (v.s3 == g.s3) { nonce = W[3].s3; } if (v.s4 == g.s4) { nonce = W[3].s4; } if (v.s5 == g.s5) { nonce = W[3].s5; } if (v.s6 == g.s6) { nonce = W[3].s6; } if (v.s7 == g.s7) { nonce = W[3].s7; } #elif defined VECTORS4
To this: #ifdef VECTORS8 uint8 eq=(v==g); if (any(eq)) { eq = select(g,(uint8)0,eq); nonce = (eq.s0+eq.s1+eq.s2+eq.s3+eq.s4+eq.s5+eq.s6+eq.s7); } #elif defined VECTORS4
A branchless version would be: #ifdef VECTORS8 uint8 eq; eq = select(g,(uint8)0,(v==g)); nonce = (eq.s0+eq.s1+eq.s2+eq.s3+eq.s4+eq.s5+eq.s6+eq.s7); #elif defined VECTORS4
It incurs a penalty of several more ALU ops which might be acceptable or might not as compared to the onebranch version and this needs to be profiled. Anyway, having 8 branches is a bad idea, even without divergence, this introduces at least 8 clauses and clause latency is ~40 cycles on VLIW hardware. Should be better on GCN though.




d3m0n1q_733rz


February 09, 2012, 11:17:27 AM 

I'll try changing this for VECTORS8, 4 and 2 as there should be similar effects if it does as you say. I'm also working on getting that darn GOFFSET put into the init file. Not fun.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



bulanula


February 09, 2012, 11:19:01 AM 

oh, and I was just going to test this kernel too to see what the hell goffset did for hashes
Yeah interested as well. Can we expect like a massive performance increase from 440 mhash/s for a 5870 to 700 mhash/s ? Guess not but let us know !




d3m0n1q_733rz


February 09, 2012, 11:33:08 AM 

oh, and I was just going to test this kernel too to see what the hell goffset did for hashes
Yeah interested as well. Can we expect like a massive performance increase from 440 mhash/s for a 5870 to 700 mhash/s ? Guess not but let us know ! I doubt it'll be a major increase, but it should be mild to modest if I can get everything working properly. You can test GOFFSET now, but I can't promise that it'll do what it's supposed to without the init file. Though, the option is there and it does accept the shares that it outputs.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



d3m0n1q_733rz


February 09, 2012, 12:10:33 PM 

I'd advise you to change this: #ifdef VECTORS8 if (v.s0 == g.s0) { nonce = W[3].s0; } if (v.s1 == g.s1) { nonce = W[3].s1; } if (v.s2 == g.s2) { nonce = W[3].s2; } if (v.s3 == g.s3) { nonce = W[3].s3; } if (v.s4 == g.s4) { nonce = W[3].s4; } if (v.s5 == g.s5) { nonce = W[3].s5; } if (v.s6 == g.s6) { nonce = W[3].s6; } if (v.s7 == g.s7) { nonce = W[3].s7; } #elif defined VECTORS4
To this: #ifdef VECTORS8 uint8 eq=(v==g); if (any(eq)) { eq = select(g,(uint8)0,eq); nonce = (eq.s0+eq.s1+eq.s2+eq.s3+eq.s4+eq.s5+eq.s6+eq.s7); } #elif defined VECTORS4
A branchless version would be: #ifdef VECTORS8 uint8 eq; eq = select(g,(uint8)0,(v==g)); nonce = (eq.s0+eq.s1+eq.s2+eq.s3+eq.s4+eq.s5+eq.s6+eq.s7); #elif defined VECTORS4
It incurs a penalty of several more ALU ops which might be acceptable or might not as compared to the onebranch version and this needs to be profiled. Anyway, having 8 branches is a bad idea, even without divergence, this introduces at least 8 clauses and clause latency is ~40 cycles on VLIW hardware. Should be better on GCN though. There's something wrong with the alternatives. It won't allow uint8 to be used with eq. Another thing I would like to add is that there is a problem with efficiency of the nonce code. If nonce is a uint, there's only enough room for a single vector from W[3]. So, if we're running through the entire v==g array and happen upon v.s0==g.s0 right off the bat, it's still going through the rest of the if statements to see if it needs to replace that w[3] value in nonce yet again. My take on it is to ether stop there or make nonce large enough to hold any multiple nonce values and then introduce them into the next round as the fullsized vectors. _ Too much editing of the kernel to add in efficiency. I want to leave this up to someone more experienced with programming it if someone would be so willing. List of things to do: Increase efficiency of nonce at end. Find register spill in VECTORS8 processing and put a stop to it. Verify GOFFSET is working properly. Figure out why the heck moving around the P1 + P2 + P4 etc. increases ALUs when the preprocessor should be able to optimize the simple addition problems for speed. Achieve at least a 1/15th speed increase by code optimization. It's going to take a few days in the least to get the nonce working properly with the GOFFSET option. Since we've avoided using certain variables, it makes it difficult to weave it in. The same applies since we're skipping straight to W[3]. I don't want the new code to take up more ALUs though. It's a tough situation.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



gat3way


February 09, 2012, 01:32:53 PM 

OK, try this way: #ifdef VECTORS8 if (any(v==g)) { u eq = select(W[3],(u)0,(v==g)); nonce = (eq.s0+eq.s1+eq.s2+eq.s3+eq.s4+eq.s5+eq.s6+eq.s7); } #elif defined VECTORS4




d3m0n1q_733rz


February 10, 2012, 03:49:21 AM 

OK, try this way: #ifdef VECTORS8 if (any(v==g)) { u eq = select(W[3],(u)0,(v==g)); nonce = (eq.s0+eq.s1+eq.s2+eq.s3+eq.s4+eq.s5+eq.s6+eq.s7); } #elif defined VECTORS4
That still won't work because eq must be of type uint8 to hold the data from v==g. Why not download the AMD APP KernelAnalyzer and copypaste this code into it with the compile options of: DOUTPUT_SIZE=0x100 DOUTPUT_MASK=0xFF DBFI_INT DBITALIGN DWORKSIZE=64 DVECTORS8 That way, you can see where the errors are firsthand. Now, the problem that I've found with the original code in general is that it makes the assumption that only one pair of vectors are going to match no matter what. So it takes that match and makes it nonce. However, it continues through the if statements as though it were looking for another match. So, either A) nonce needs to be increased in size to hold multiple equivalent vectors or B) the if statements needs to be stopped once a suitable nonce is found otherwise it will only serve to overwrite the first. I could really use Phateus here to help me rewrite this portion to hold to these constraints. And I think you may be misusing select there. You see, we need to pull apart v and g into it's separate parts before figuring out which parts are equal. That is, unless we can xor v and g, pull apart v and then write any vector = 0 from the equivalent g vector. However, that doesn't answer what to do in case of multiple nonce.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



gat3way


February 10, 2012, 08:59:44 AM 

I am compiling that with clcc and it builds successfully. It should work when you have VECTORS8 defined because you have: #ifdef VECTORS8 typedef uint8 u;
and eq is defined to be of type u. So it takes that match and makes it nonce. However, it continues through the if statements as though it were looking for another match. So, either A) nonce needs to be increased in size to hold multiple equivalent vectors or B) the if statements needs to be stopped once a suitable nonce is found otherwise it will only serve to overwrite the first.
Yes, that's a valid point, but having nonce as a vector means you should be also increasing the output buffer (vector width) times. This in turn means you'd need (vector width) times larger devicehost transfers. People with underclocked GPU memory and PCIe extenders won't be very happy about that B) the if statements needs to be stopped once a suitable nonce is found otherwise it will only serve to overwrite the first.
Yep, that's the purpose of replacing branches with select() And I think you may be misusing select there. You see, we need to pull apart v and g into it's separate parts before figuring out which parts are equal. That is, unless we can xor v and g, pull apart v and then write any vector = 0 from the equivalent g vector.
No, you don't need to do that. The result of (v==g) is a vector where each component is 0 if the corresponding v and g components are equal. E.g you have: v = (uint8)(5,5,5,5,5,5,5,5); g = (uint8)(1,2,3,4,5,6,7,8); (v==g) would be (0,0,0,0,1,0,0,0) This is still not useful as nonce is a scalar value. Then also (I noticed that later and corrected it) nonce should equal the matching vector element from W[3], not v or g. Thus, this is the most straightforward solution: eq = select(W[3],(u)0,(v==g)) What's the idea? eq is a vector, same width as W[3], v and g. Let W[3] contain (0x10,0x20,0x30,0x40,0x50,0x60,0x70,0x80) eq would contain (0,0,0,0,0x50,0,0,0) since we need a scalar nonce, we just sum all the elements of eq and get 0+0+0+0+0x50+0+0+0 = 0x50. Of course this would break if we have more than one match between v and g components and in that case the nonce would be wrong. The probability for this is low but it could happen. This is the worst case. Overall though, I think performance improvement due to branches elimination is worth the increased percentage of wrong shares. Also, a quick check on host could prevent the miner from submitting the wrong share. And as I said, this should occur rarely.




d3m0n1q_733rz


February 10, 2012, 10:11:36 AM 

I am compiling that with clcc and it builds successfully. It should work when you have VECTORS8 defined because you have: #ifdef VECTORS8 typedef uint8 u;
and eq is defined to be of type u. So it takes that match and makes it nonce. However, it continues through the if statements as though it were looking for another match. So, either A) nonce needs to be increased in size to hold multiple equivalent vectors or B) the if statements needs to be stopped once a suitable nonce is found otherwise it will only serve to overwrite the first.
Yes, that's a valid point, but having nonce as a vector means you should be also increasing the output buffer (vector width) times. This in turn means you'd need (vector width) times larger devicehost transfers. People with underclocked GPU memory and PCIe extenders won't be very happy about that B) the if statements needs to be stopped once a suitable nonce is found otherwise it will only serve to overwrite the first.
Yep, that's the purpose of replacing branches with select() And I think you may be misusing select there. You see, we need to pull apart v and g into it's separate parts before figuring out which parts are equal. That is, unless we can xor v and g, pull apart v and then write any vector = 0 from the equivalent g vector.
No, you don't need to do that. The result of (v==g) is a vector where each component is 0 if the corresponding v and g components are equal. E.g you have: v = (uint8)(5,5,5,5,5,5,5,5); g = (uint8)(1,2,3,4,5,6,7,8); (v==g) would be (0,0,0,0,1,0,0,0) This is still not useful as nonce is a scalar value. Then also (I noticed that later and corrected it) nonce should equal the matching vector element from W[3], not v or g. Thus, this is the most straightforward solution: eq = select(W[3],(u)0,(v==g)) What's the idea? eq is a vector, same width as W[3], v and g. Let W[3] contain (0x10,0x20,0x30,0x40,0x50,0x60,0x70,0x80) eq would contain (0,0,0,0,0x50,0,0,0) since we need a scalar nonce, we just sum all the elements of eq and get 0+0+0+0+0x50+0+0+0 = 0x50. Of course this would break if we have more than one match between v and g components and in that case the nonce would be wrong. The probability for this is low but it could happen. This is the worst case. Overall though, I think performance improvement due to branches elimination is worth the increased percentage of wrong shares. Also, a quick check on host could prevent the miner from submitting the wrong share. And as I said, this should occur rarely. How about this instead? #ifdef VECTORS8 v = select(W[3],(u)0,(v==g)); uint nonce = (v.s0+v.s1+v.s2+v.s3+v.s4+v.s5+v.s6+v.s7); #elif defined VECTORS4 v = select(W[3],(u)0,(v==g)); uint nonce = (v.s0+v.s1+v.s2+v.s3); #elif defined VECTORS v = select(W[3],(u)0,(v==g)); uint nonce = (v.s0+v.s1); #else v = select(W[3],(u)0,(v==g)); uint nonce = (v); #endif So, will having partial matches in a vector cause for any problems? Also, using select is less efficient than using if statements. Any other method? And, as I suggested earlier, you might want the kernel analyzer as it will tell you the expected amount of cycles and the like. I'm not telling you that you have to, but it really does come in handy.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



gat3way


February 10, 2012, 10:48:57 AM 

Yes, this is without any branching (similar to alternative 2) from my previous post except that I had W[3] wrong. Basically the best would be to profile both and choose the faster one. With branching and without divergence, you have an additional clause (with divergence the penalty is worse as both "paths" would be serialized). However, without branching you introduce 7 dependent additions (can't pack them in two VLIW bundles as the result of the next addition depends on the previous one). I am not sure which would be faster. BTW for the scalar case, you don't need that: #else v = select(W[3],(u)0,(v==g)); uint nonce = (v);
as direct comparison might be faster, especially with predication. E.g: nonce = (v==g) ? W[3] : 0;
Unfortunately, this is not useful in the vector case. Of course you could try: nonce = (v.s0==g.s0) ? W[3].s0 : nonce; nonce = (v.s1==g.s1) ? W[3].s1 : nonce; ...
But that would generate much more inefficient code than that generated by using select(). So, will having partial matches in a vector cause for any problems?
The only problem is when you have more than one matching component pairs (v.sX and g.sX). For example v.s0==g.s0 and v.s3==g.s3. The version with branches would eventually have one of the two nonces written correctly in the output buffer (namely W[3].s3), the version with select() would have the wrong nonce written in the output buffer (W[3].s0+W[3].s3).




d3m0n1q_733rz


February 10, 2012, 01:06:08 PM 

The problem I'm seeing, though, is that select causes the most inefficient code. I'll give this other code a try and see what it comes up with. But the if statements appear to be best since it checks against what's already in the buffer. What it looks like is happening here with your new code is that it's causing writes to nonce regardless of whether or not the otherwise if statement is true. I think that's what is causing more cycles. _ So far, it looks like the if statements are most effective due to the lack of writes to and from vectors and nonce.
I just tested your new method. It DROPPED 10 ALUs! Congrats! The code is now faster.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



d3m0n1q_733rz


February 10, 2012, 01:15:55 PM 

// This file is in the public domain
#ifdef VECTORS8 typedef uint8 u; #elif defined VECTORS4 typedef uint4 u; #elif defined VECTORS typedef uint2 u; #else typedef uint u; #endif
__constant uint K[64] = { 0x428a2f98, 0x71374491, 0xb5c0fbcf, 0xe9b5dba5, 0x3956c25b, 0x59f111f1, 0x923f82a4, 0xab1c5ed5, 0xd807aa98, 0x12835b01, 0x243185be, 0x550c7dc3, 0x72be5d74, 0x80deb1fe, 0x9bdc06a7, 0xc19bf174, 0xe49b69c1, 0xefbe4786, 0x0fc19dc6, 0x240ca1cc, 0x2de92c6f, 0x4a7484aa, 0x5cb0a9dc, 0x76f988da, 0x983e5152, 0xa831c66d, 0xb00327c8, 0xbf597fc7, 0xc6e00bf3, 0xd5a79147, 0x06ca6351, 0x14292967, 0x27b70a85, 0x2e1b2138, 0x4d2c6dfc, 0x53380d13, 0x650a7354, 0x766a0abb, 0x81c2c92e, 0x92722c85, 0xa2bfe8a1, 0xa81a664b, 0xc24b8b70, 0xc76c51a3, 0xd192e819, 0xd6990624, 0xf40e3585, 0x106aa070, 0x19a4c116, 0x1e376c08, 0x2748774c, 0x34b0bcb5, 0x391c0cb3, 0x4ed8aa4a, 0x5b9cca4f, 0x682e6ff3, 0x748f82ee, 0x78a5636f, 0x84c87814, 0x8cc70208, 0x90befffa, 0xa4506ceb, 0xbef9a3f7, 0xc67178f2 };
__constant uint ConstW[128] = { 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x80000000U, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000280U, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000,
0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x80000000U, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000100U, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000, 0x00000000 };
__constant uint H[8] = { 0x6a09e667, 0xbb67ae85, 0x3c6ef372, 0xa54ff53a, 0x510e527f, 0x9b05688c, 0x1f83d9ab, 0x5be0cd19 };
#ifdef BITALIGN #pragma OPENCL EXTENSION cl_amd_media_ops : enable #define rot(x, y) amd_bitalign(x, x, (uint)(32  y)) #else #define rot(x, y) rotate(x, (uint)y) #endif
// Some AMD devices have the BFI_INT opcode, which behaves exactly like the // SHA256 Ch function, but provides it in exactly one instruction. If // detected, use it for Ch. Otherwise, use bitselect() for Ch.
#ifdef BFI_INT // Well, slight problem... It turns out BFI_INT isn't actually exposed to // OpenCL (or CAL IL for that matter) in any way. However, there is // a similar instruction, BYTE_ALIGN_INT, which is exposed to OpenCL via // amd_bytealign, takes the same inputs, and provides the same output. // We can use that as a placeholder for BFI_INT and have the application // patch it after compilation.
// This is the BFI_INT function #define Ch(x, y, z) amd_bytealign(x,y,z) // Ma can also be implemented in terms of BFI_INT... #define Ma(z, x, y) amd_bytealign(z^x,y,x) #else #define Ch(x, y, z) bitselect(z,y,x) #define Ma(x, y, z) bitselect(x,y,(z^x)) #endif
//Various intermediate calculations for each SHA round #define s0(n) (S0(Vals[(0 + 128  (n)) % 8])) #define S0(n) (rot(n, 30u)^rot(n, 19u)^rot(n,10u))
#define s1(n) (S1(Vals[(4 + 128  (n)) % 8])) #define S1(n) (rot(n, 26u)^rot(n, 21u)^rot(n, 7u))
#define ch(n) Ch(Vals[(4 + 128  (n)) % 8],Vals[(5 + 128  (n)) % 8],Vals[(6 + 128  (n)) % 8]) #define maj(n) Ma(Vals[(1 + 128  (n)) % 8],Vals[(2 + 128  (n)) % 8],Vals[(0 + 128  (n)) % 8])
//t1 calc when W is already calculated #define t1(n) K[(n) % 64] + Vals[(7 + 128  (n)) % 8] + W[(n)] + s1(n) + ch(n)
//t1 calc which calculates W #define t1W(n) K[(n) % 64] + Vals[(7 + 128  (n)) % 8] + W(n) + s1(n) + ch(n)
//Used for constant W Values (the compiler optimizes out zeros) #define t1C(n) (K[(n) % 64]+ ConstW[(n)]) + Vals[(7 + 128  (n)) % 8] + s1(n) + ch(n)
//t2 Calc #define t2(n) maj(n) + s0(n)
#define rotC(x,n) (x<<n  x >> (32n))
//W calculation used for SHA round #define W(n) (W[n] = P4(n) + P3(n) + P2(n) + P1(n))
//Partial W calculations (used for the begining where only some values are nonzero) #define P1(n) ((rot(W[(n)2],15u)^rot(W[(n)2],13u)^((W[(n)2])>>10U))) #define P2(n) ((rot(W[(n)15],25u)^rot(W[(n)15],14u)^((W[(n)15])>>3U))) #define p1(x) ((rot(x,15u)^rot(x,13u)^((x)>>10U))) #define p2(x) ((rot(x,25u)^rot(x,14u)^((x)>>3U))) #define P3(n) W[n7] #define P4(n) W[n16]
//Partial Calcs for constant W values #define P1C(n) ((rotC(ConstW[(n)2],15)^rotC(ConstW[(n)2],13)^((ConstW[(n)2])>>10U))) #define P2C(n) ((rotC(ConstW[(n)15],25)^rotC(ConstW[(n)15],14)^((ConstW[(n)15])>>3U))) #define P3C(x) ConstW[x7] #define P4C(x) ConstW[x16]
//SHA round with built in W calc #define sharoundW(n) Barrier1(n); Vals[(3 + 128  (n)) % 8] += t1W(n); Vals[(7 + 128  (n)) % 8] = t1W(n) + t2(n);
//SHA round without W calc #define sharound(n) Barrier2(n); Vals[(3 + 128  (n)) % 8] += t1(n); Vals[(7 + 128  (n)) % 8] = t1(n) + t2(n);
//SHA round for constant W values #define sharoundC(n) Barrier2(n); Vals[(3 + 128  (n)) % 8] += t1C(n); Vals[(7 + 128  (n)) % 8] = t1C(n) + t2(n);
//The compiler is stupid... I put this in there only to stop the compiler from (de)optimizing the order #define Barrier1(n) t1 = t1C((n+1)) #define Barrier2(n) t1 = t1C((n))
__kernel //removed this to allow detection of invalid work size //__attribute__((reqd_work_group_size(WORKSIZE, 1, 1))) void search( const uint state0, const uint state1, const uint state2, const uint state3, const uint state4, const uint state5, const uint state6, const uint state7, const uint B1, const uint C1, const uint D1, const uint F1, const uint G1, const uint H1, #ifndef GOFFSET const u base, #endif const uint W16, const uint W17, const uint PreVal4, const uint PreVal0, const uint PreW31, const uint PreW32, const uint PreW19, const uint PreW20, __global uint * output) {
u W[124]; u Vals[8];
//Dummy Variable to prevent compiler from reordering between rounds u t1;
W[16] = W16; W[17] = W17;
#ifdef VECTORS8 #ifdef GOFFSET W[3] = ((uint)get_global_id(0) << 3) + (u)(0, 1, 2, 3, 4, 5, 6, 7); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); #else W[3] = base + (uint)(get_local_id(0)) * 8u + (uint)(get_group_id(0)) * (WORKSIZE * 8u); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); //Since only the 2 LSB is opposite between the nonces, we can save an instruction by flipping the 4 bits in W18 rather than the 1 bit in W3 W[18] = PreW20 + (u){r, r ^ 0x2004000U, r ^ 0x4008000U, r ^ 0x600C000U, r ^ 0x8010000U, r ^ 0xA050000U, r ^ 0xC090000U, r ^ 0xE0D0000U}; #endif
#elif defined VECTORS4 #ifdef GOFFSET W[3] = ((uint)get_global_id(0) << 2) + (u)(0, 1, 2, 3); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); #else
//Less dependencies to get both the local id and group id and then add them W[3] = base + (uint)(get_local_id(0)) * 4u + (uint)(get_group_id(0)) * (WORKSIZE * 4u); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); //Since only the 2 LSB is opposite between the nonces, we can save an instruction by flipping the 4 bits in W18 rather than the 1 bit in W3 W[18] = PreW20 + (u){r, r ^ 0x2004000U, r ^ 0x4008000U, r ^ 0x600C000U}; #endif #elif defined VECTORS #ifdef GOFFSET W[3] = ((uint)get_global_id(0) << 1) + (u)(0, 1,); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); #else W[3] = base + (uint)(get_local_id(0)) * 2u + (uint)(get_group_id(0)) * (WORKSIZE * 2u); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); W[18] = PreW20 + (u){r, r ^ 0x2004000U}; #endif #else #ifdef GOFFSET W[3] = ((uint)get_global_id(0)); uint r = rot(W[3].s0,25u)^rot(W[3].s0,14u)^((W[3].s0)>>3U); #else W[3] = base + get_local_id(0) + get_group_id(0) * (WORKSIZE); u r = rot(W[3],25u)^rot(W[3],14u)^((W[3])>>3U); W[18] = PreW20 + r; #endif #endif //the order of the W calcs and Rounds is like this because the compiler needs help finding how to order the instructions
//Vals[0]=state0; Vals[0] = PreVal0 + W[3]; Vals[1]=B1; Vals[2]=C1; Vals[3]=D1; //Vals[4]=PreVal4; Vals[4] = PreVal4 + W[3]; Vals[5]=F1; Vals[6]=G1; Vals[7]=H1;
sharoundC(4); W[19] = PreW19 + W[3]; sharoundC(5); W[20] = P4C(20) + P1(20); sharoundC(6); W[21] = P1(21); sharoundC(7); W[22] = P3C(22) + P1(22); sharoundC(8); W[23] = W[16] + P1(23); sharoundC(9); W[24] = W[17] + P1(24); sharoundC(10); W[25] = P1(25) + P3(25); W[26] = P1(26) + P3(26); sharoundC(11); W[27] = P1(27) + P3(27); W[28] = P1(28) + P3(28); sharoundC(12); W[29] = P1(29) + P3(29); sharoundC(13); W[30] = P1(30) + P2C(30) + P3(30); W[31] = PreW31 + (P1(31) + P3(31)); sharoundC(14); W[32] = PreW32 + (P1(32) + P3(32)); sharoundC(15); sharound(16); sharound(17); sharound(18); sharound(19); sharound(20); sharound(21); sharound(22); sharound(23); sharound(24); sharound(25); sharound(26); sharound(27); sharound(28); sharound(29); sharound(30); sharound(31); sharound(32); sharoundW(33); sharoundW(34); sharoundW(35); sharoundW(36); sharoundW(37); sharoundW(38); sharoundW(39); sharoundW(40); sharoundW(41); sharoundW(42); sharoundW(43); sharoundW(44); sharoundW(45); sharoundW(46); sharoundW(47); sharoundW(48); sharoundW(49); sharoundW(50); sharoundW(51); sharoundW(52); sharoundW(53); sharoundW(54); sharoundW(55); sharoundW(56); sharoundW(57); sharoundW(58); sharoundW(59); sharoundW(60); sharoundW(61); sharoundW(62); sharoundW(63);
W[64]=state0+Vals[0]; W[65]=state1+Vals[1]; W[66]=state2+Vals[2]; W[67]=state3+Vals[3]; W[68]=state4+Vals[4]; W[69]=state5+Vals[5]; W[70]=state6+Vals[6]; W[71]=state7+Vals[7];
const u Temp = (0xb0edbdd0U + K[0]) + W[64]; Vals[0]=H[0]; Vals[1]=H[1]; Vals[2]=H[2]; Vals[3]=0xa54ff53aU + Temp; Vals[4]=H[4]; Vals[5]=H[5]; Vals[6]=H[6]; Vals[7]=0x08909ae5U + Temp;
#define P124(n) P2(n) + P1(n) + P4(n)
W[80] = P2(80) + P4(80); sharound(65); W[81] = P1C(81) + P2(81) + P4(81); sharound(66); W[82] = P124(82); sharound(67); W[83] = P124(83); sharound(68); W[84] = P124(84); sharound(69); W[85] = P124(85); sharound(70); W[86] = P4(86) + P3C(86) + P2(86) + P1(86); sharound(71); W[87] = P4(87) + P3(87) + P2C(87) + P1(87); sharoundC(72); W[88] = P1(88) + P4C(88) + P3(88); sharoundC(73); W[89] = P3(89) + P1(89); sharoundC(74); W[90] = P3(90) + P1(90); sharoundC(75); W[91] = P3(91) + P1(91); sharoundC(76); W[92] = P3(92) + P1(92); sharoundC(77); W[93] = P1(93) + P3(93); W[94] = P3(94) + P2C(94) + P1(94); sharoundC(78); W[95] = P4C(95) + P3(95) + P2(95) + P1(95); sharoundC(79); sharound(80); sharound(81); sharound(82); sharound(83); sharound(84); sharound(85); sharound(86); sharound(87); sharound(88); sharound(89); sharound(90); sharound(91); sharound(92); sharound(93); sharound(94); sharound(95); sharoundW(96); sharoundW(97); sharoundW(98); sharoundW(99); sharoundW(100); sharoundW(101); sharoundW(102); sharoundW(103); sharoundW(104); sharoundW(105); sharoundW(106); sharoundW(107); sharoundW(108); sharoundW(109); sharoundW(110); sharoundW(111); sharoundW(112); sharoundW(113); sharoundW(114); sharoundW(115); sharoundW(116); sharoundW(117); sharoundW(118); sharoundW(119); sharoundW(120); sharoundW(121); sharoundW(122);
u v = W[117] + W[108] + Vals[3] + Vals[7] + P2(124) + P1(124) + Ch((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123),Vals[1],Vals[2]); u g = (K[60] + H[7])  S1((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123));
// uint nonce = 0; #ifdef VECTORS8 uint nonce = (v.s0==g.s0) ? W[3].s0 : 0; nonce = (v.s1==g.s1) ? W[3].s1 : nonce; nonce = (v.s2==g.s2) ? W[3].s2 : nonce; nonce = (v.s3==g.s3) ? W[3].s3 : nonce; nonce = (v.s4==g.s4) ? W[3].s4 : nonce; nonce = (v.s5==g.s5) ? W[3].s5 : nonce; nonce = (v.s6==g.s6) ? W[3].s6 : nonce; nonce = (v.s7==g.s7) ? W[3].s7 : nonce; #elif defined VECTORS4 uint nonce = (v.s0==g.s0) ? W[3].s0 : 0; nonce = (v.s1==g.s1) ? W[3].s1 : nonce; nonce = (v.s2==g.s2) ? W[3].s2 : nonce; nonce = (v.s3==g.s3) ? W[3].s3 : nonce; #elif defined VECTORS uint nonce = (v.s0==g.s0) ? W[3].s0 : 0; nonce = (v.s1==g.s1) ? W[3].s1 : nonce; #else uint nonce = (v==g) ? W[3] : 0 #endif if(nonce>0) { //Faster to shift the nonce by 2 due to 4DWORD addressing and does not add more collisions output[WORKSIZE] = nonce; output[get_local_id(0)] = nonce; } }
Fastest code so far. Now, is there anything that can be done for multiple found nonce values? Outputting each one separately?

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



d3m0n1q_733rz


February 10, 2012, 01:49:50 PM 

Next part!
u v = W[117] + W[108] + Vals[3] + Vals[7] + P2(124) + P1(124) + Ch((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123),Vals[1],Vals[2]); u g = (K[60] + H[7])  S1((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123));
Can we simplify these since they both contain (Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123)) ? It would certainly reduce calculations a bit. The only problem I see is Vals[1] and Vals[2] is inside of the parenthesis. Now, I'm not familiar with the comma symbolization here, but if the parenthesis can be put on the inside next to the ch(123), it's as easy as dividing by ((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123)) to remove it and make the math simpler for the GPU.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



d3m0n1q_733rz


February 10, 2012, 02:17:01 PM 

Next part!
u v = W[117] + W[108] + Vals[3] + Vals[7] + P2(124) + P1(124) + Ch((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123),Vals[1],Vals[2]); u g = (K[60] + H[7])  S1((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123));
Can we simplify these since they both contain (Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123)) ? It would certainly reduce calculations a bit. The only problem I see is Vals[1] and Vals[2] is inside of the parenthesis. Now, I'm not familiar with the comma symbolization here, but if the parenthesis can be put on the inside next to the ch(123), it's as easy as dividing by ((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123)) to remove it and make the math simpler for the GPU.
I suppose not since Ch depends on that first value. >_> And then S1 rotates it. Darn, not so easy.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



gat3way


February 10, 2012, 02:36:24 PM 

I am kinda surprised that predication worked better than select(), usually it's just the opposite. Perhaps if you can send me both ISA dumps I can see what can be done to further improve that. For the second part: u v = W[117] + W[108] + Vals[3] + Vals[7] + P2(124) + P1(124) + Ch((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123),Vals[1],Vals[2]); u g = (K[60] + H[7])  S1((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123));
Can we simplify these since they both contain (Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123)) ? It would certainly reduce calculations a bit. The only problem I see is Vals[1] and Vals[2] is inside of the parenthesis. Now, I'm not familiar with the comma symbolization here, but if the parenthesis can be put on the inside next to the ch(123), it's as easy as dividing by ((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123)) to remove it and make the math simpler for the GPU.
I don't think it's worth trying. P.S I don't think ALU ops is a good performance metric. Of course that's important, but there are other factors. GPR usage and number of clauses is also very important, so you have to profile the overall result. I've seen many times situations where you have two kernels, one has a bit less ALU ops, other has just one more clause and the second one behaves much worse. Similarily, the situation with GPR usage. I am currently working on a RAR password cracking kernel and that poses some fucking paradoxes. For example I have several kernels, one keeping everything in __private memory with large GPR usage, another one that shifts some to __local memory and a third one that keeps a small lookup table in __global memory. Paradox is that the first one is the slowest, GPR usage is ~90, performance is disgusting. The one that keeps part of the data in __local memory behaves much better, 36 GPRs used, much better occupancy, but performance still not what I expected. The kernel that uses an intermediate __global memory buffer is currently the fastest one, mostly because of the cached global memory with SDK 2.6. It's twice faster than the second one and times faster than the first one. I would never expect that.




d3m0n1q_733rz


February 11, 2012, 12:06:25 AM 

I am kinda surprised that predication worked better than select(), usually it's just the opposite. Perhaps if you can send me both ISA dumps I can see what can be done to further improve that. For the second part: u v = W[117] + W[108] + Vals[3] + Vals[7] + P2(124) + P1(124) + Ch((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123),Vals[1],Vals[2]); u g = (K[60] + H[7])  S1((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123));
Can we simplify these since they both contain (Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123)) ? It would certainly reduce calculations a bit. The only problem I see is Vals[1] and Vals[2] is inside of the parenthesis. Now, I'm not familiar with the comma symbolization here, but if the parenthesis can be put on the inside next to the ch(123), it's as easy as dividing by ((Vals[0] + Vals[4]) + (K[59] + W(123)) + s1(123)+ ch(123)) to remove it and make the math simpler for the GPU.
I don't think it's worth trying. P.S I don't think ALU ops is a good performance metric. Of course that's important, but there are other factors. GPR usage and number of clauses is also very important, so you have to profile the overall result. I've seen many times situations where you have two kernels, one has a bit less ALU ops, other has just one more clause and the second one behaves much worse. Similarily, the situation with GPR usage. I am currently working on a RAR password cracking kernel and that poses some fucking paradoxes. For example I have several kernels, one keeping everything in __private memory with large GPR usage, another one that shifts some to __local memory and a third one that keeps a small lookup table in __global memory. Paradox is that the first one is the slowest, GPR usage is ~90, performance is disgusting. The one that keeps part of the data in __local memory behaves much better, 36 GPRs used, much better occupancy, but performance still not what I expected. The kernel that uses an intermediate __global memory buffer is currently the fastest one, mostly because of the cached global memory with SDK 2.6. It's twice faster than the second one and times faster than the first one. I would never expect that. I've already tested it via the kernel analyzer and it seems to be the best way to accomplish the task so far. The analyzer tells cycles, ALUs, GPRs, output, etc.

Funroll_Loops, the theoretically quicker breakfast cereal! Check out http://www.facebook.com/JupiterICT for all of your computing needs. If you need it, we can get it. We have solutions for your computing conundrums. BTC accepted! 12HWUSguWXRCQKfkPeJygVR1ex5wbg3hAq



bulanula


February 11, 2012, 12:06:57 AM 

So how much increase can we expect on a 5870 ?
Is this really the fastest kernel for a 5870 ?
Thanks !




