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Author Topic: A lottery where there's always one winner?  (Read 568 times)
Reynaldo
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September 18, 2014, 01:26:36 AM
 #1

Imagine a Casino where you buy tickets, you and your friends go and this scheme happens:

There are 10 people buying tickets, and you and your 2 friends want to play.

Then there would be 13 tickets of a price of 1 BTC each, that means that the price for winner would be 12.83, there will be only 1 winner per round.
What do you think? would you play it?

house cut is only 1%

Reynaldo.....
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pedrog
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September 18, 2014, 01:46:56 AM
 #2

A raffle?

Nobitcoin
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September 18, 2014, 09:45:02 AM
 #3

That's 12 people right and the pot is incorrect unless the house counts as one ticket or donates 1 btc and has a ticket
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