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Evil-Knievel (OP)
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January 28, 2015, 07:00:23 PM
Last edit: April 17, 2016, 08:00:44 PM by Evil-Knievel
 #1

This message was too old and has been purged
coinsocieties
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io.ezystayz.com


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January 28, 2015, 07:04:52 PM
 #2

Excellent!

Will try to Solve it.




                                                                                                                                             
     ████████                                         ▄▄▄▄                                                                       
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     ██████              ▄██▀   ██     ██     ▀██▄      ██████   ██      ██       ██     ██           ▄██▀
     ██                  ▄██▀       ██     ██         ▀██▄      ██       ██      ██       ██     ██       ▄██▀   
     ██              ▄██▀           ██     ██  ▄▄       ██      ██       ██      ██       ██     ██   ▄██▀       
     ████████  ████████    ▀█████   ███████      ██▄█   ███████▄█    ▀█████   ████████
                                         █▄    ▄██       ▀▀▀▀           ▀▀       ▀▀▀▀  ▀▀   █▄    ▄██                  
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redsn0w
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January 28, 2015, 07:12:44 PM
 #3

Can you sign a message from the bitcoin address (18b2no9rBkovhv5gf3vkd5VQ9MKxHvqSzu) ?
Evil-Knievel (OP)
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January 28, 2015, 07:14:15 PM
Last edit: April 17, 2016, 08:00:38 PM by Evil-Knievel
 #4

This message was too old and has been purged
redsn0w
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January 28, 2015, 07:15:34 PM
 #5

Can you sign a message from the bitcoin address (18b2no9rBkovhv5gf3vkd5VQ9MKxHvqSzu) ?

If you tell me how I can do that in Amory, I will. I am trying hard for the last 15 minutes  Wink


I've find this thread : https://bitcointalk.org/index.php?topic=252848.0  maybe it will be helpful for you  ( I don't use armory , I prefer electrum).
Evil-Knievel (OP)
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January 28, 2015, 07:28:48 PM
Last edit: April 17, 2016, 08:00:30 PM by Evil-Knievel
 #6

This message was too old and has been purged
redsn0w
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January 28, 2015, 07:33:19 PM
 #7

No idea if this helps, buts that is what I got when I followed the instructions in the referenced thread :-D

Code:
-----BEGIN BITCOIN SIGNED MESSAGE-----
Comment: Signed by Bitcoin Armory v0.92.3

Evilknievel just posted a 30 BTC bounty on Bitcointalk.org.
-----BEGIN BITCOIN SIGNATURE-----


G2LzJDlSBkzeCpZptys8LeDJfKS47Xgfu+d3/EvUEILmFljOoJPVKh/0iYo3yKBJ
EAqeAou/qsH5e9ZM7GCJMlQ=
=oRUP
-----END BITCOIN SIGNATURE-----


Yes , I've verified on  https://brainwallet.github.io/#verify  :



Code:
-----BEGIN BITCOIN SIGNED MESSAGE-----
Evilknievel just posted a 30 BTC bounty on Bitcointalk.org.
-----BEGIN SIGNATURE-----
18b2no9rBkovhv5gf3vkd5VQ9MKxHvqSzu
G2LzJDlSBkzeCpZptys8LeDJfKS47Xgfu+d3/EvUEILmFljOoJPVKh/0iYo3yKBJEAqeAou/qsH5e9ZM7GCJMlQ=
-----END BITCOIN SIGNED MESSAGE-----

PS: I removed the =oRUP , I don't know why the sign process gives  you that.
coinsocieties
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January 28, 2015, 07:35:26 PM
 #8

No idea if this helps, buts that is what I got when I followed the instructions in the referenced thread :-D

Code:
-----BEGIN BITCOIN SIGNED MESSAGE-----
Comment: Signed by Bitcoin Armory v0.92.3

Evilknievel just posted a 30 BTC bounty on Bitcointalk.org.
-----BEGIN BITCOIN SIGNATURE-----


G2LzJDlSBkzeCpZptys8LeDJfKS47Xgfu+d3/EvUEILmFljOoJPVKh/0iYo3yKBJ
EAqeAou/qsH5e9ZM7GCJMlQ=
=oRUP
-----END BITCOIN SIGNATURE-----


Yes , I've verified on  https://brainwallet.github.io/#verify  :



Code:
-----BEGIN BITCOIN SIGNED MESSAGE-----
Evilknievel just posted a 30 BTC bounty on Bitcointalk.org.
-----BEGIN SIGNATURE-----
18b2no9rBkovhv5gf3vkd5VQ9MKxHvqSzu
G2LzJDlSBkzeCpZptys8LeDJfKS47Xgfu+d3/EvUEILmFljOoJPVKh/0iYo3yKBJEAqeAou/qsH5e9ZM7GCJMlQ=
-----END BITCOIN SIGNED MESSAGE-----

PS: I removed the =oRUP , I don't know why the sign process gives  you that.

Yes the second one is verified with brainwallet. No need of =oRUP



                                                                                                                                             
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     ████████  ████████    ▀█████   ███████      ██▄█   ███████▄█    ▀█████   ████████
                                         █▄    ▄██       ▀▀▀▀           ▀▀       ▀▀▀▀  ▀▀   █▄    ▄██                  
                                           ▀███▀                                                          ▀███▀                    



















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haploid23
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January 28, 2015, 07:49:34 PM
 #9

Everything there is gibberish to me, but it does reminds me of this riddle below. Quite entertaining to follow even if you understood none of it.

https://bitcointalk.org/index.php?topic=661781.0


david123
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January 28, 2015, 07:53:46 PM
 #10

Quote
Being a some constant, further assume that we
are in a factor ring (basically all operations modulo some sumber p).
What do you mean with “a factor ring“? Any ring is a factor ring.
I assume you mean the ring Z/pZ for some nat. number p?
If so, is this p supposed to be prime (as the letter suggests)?

You always have to start with x=9.
Consider the following recursive formula:

Code:
new_x = (x²-1)² / (4*x*(x²+a*x+1))

How often do you have to perform this operation to get a specific x (basically getting the new_x and feeding it back into the formula to get another new_x, and so on)?

Let f:Z/pZ -> Z/pZ be the map given by your assignment
x |-> new_x. Then you basically ask for a map g:Z/pZ -> N
s.t. f^(g(y))(9) = y for all y in Z/pZ, right?

Note: You can start multiple such chains beginning at x=9, and add the resulting x values
using the addition algorithm from http://en.wikipedia.org/wiki/Montgomery_curve (Montgomery arithmetic section).
Note, that the x value, is the value you get at the end of such calculation-chain, and the z value is always 1.

I don't know what you mean with all of this.. Could you put it in more
mathematical terms?
Be also advised that the referenced addition “algorithm“ is not specific
to Montgomery curves, so it would be better to link to the wikipedia article
for elliptic curves where it is also described.
Do you try to consider elliptic curves over F_p? I have the impression,
but you should reformulate your question..
Evil-Knievel (OP)
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January 28, 2015, 07:59:09 PM
Last edit: April 17, 2016, 08:00:24 PM by Evil-Knievel
 #11

This message was too old and has been purged
david123
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January 28, 2015, 08:05:43 PM
 #12

I still missed the part where the elliptic curve comes in. You need one
if you want to apply this addition method.
If you can describe your problem more formally, I might be able to
help.
pythonpro1337
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January 29, 2015, 02:40:59 AM
 #13

14DFu1bW6DSPPuJYnZLn9EfgKeFYcLaFAN
14DFu1bW6DSPPuJYnZLn9EfgKeFYcLaFAN
14DFu1bW6DSPPuJYnZLn9EfgKeFYcLaFAN

i just sent you a pm with the appropriate script on how to compute and find your solution please send my bounty the addy above thanks you!
izanagi narukami
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January 29, 2015, 02:48:12 AM
 #14

I have a friend that might interest for this Bounty.

Will let you no when I got respond from him

Smiley
pythonpro1337
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January 29, 2015, 02:48:29 AM
 #15

14DFu1bW6DSPPuJYnZLn9EfgKeFYcLaFAN
14DFu1bW6DSPPuJYnZLn9EfgKeFYcLaFAN
14DFu1bW6DSPPuJYnZLn9EfgKeFYcLaFAN

i just sent you a pm with the appropriate script on how to compute and find your solution please send my bounty the addy above thanks you!

@OP:You can run it yourself in a .html file just copy and paste it into notepad. Of course over 100000 is kinda slow on my computer so there are some limitations to it. If I was to have it calculated I would run the above script as php and then use that to generate the javascript code to give me an answer.

there your problem is solved in your pm please send me the bounty and close this thread
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January 29, 2015, 02:52:01 AM
 #16


Problem Description:

Being a some constant, further assume that we
are in a factor ring (basically all operations modulo some sumber p). Note, that the division below is a multiplication by the modular inverse.
You always have to start with x=9.
Consider the following recursive formula:

Code:
new_x = (x²-1)² / (4*x*(x²+a*x+1))

How often do you have to perform this operation to get a specific x (basically getting the new_x and feeding it back into the formula to get another new_x, and so on)?
Note: You can start multiple such chains beginning at x=9, and add the resulting x values
using the addition algorithm from http://en.wikipedia.org/wiki/Montgomery_curve (Montgomery arithmetic section).
Note, that the x value, is the value you get at the end of such calculation-chain, and the z value is always 1.



Is this really solvable at all?
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January 29, 2015, 02:55:50 AM
 #17

yes i just sent him how to solve it in pm
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January 29, 2015, 03:29:54 AM
 #18

so the bounty is @ 34 for me now? Wink please check your messages form me ive finished this bounty thanks!
GLBrim
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January 29, 2015, 03:32:44 AM
 #19

so the bounty is @ 34 for me now? Wink please check your messages form me ive finished this bounty thanks!

so you mean you already got the answer? Huh
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January 29, 2015, 03:39:55 AM
 #20

yeah ive given him the instructions to find his answer and how to do it in which languages thank you!
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