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Author Topic: Difficulty - mh/s - difficulty  (Read 1017 times)
mrbubl3s
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August 01, 2012, 05:49:59 AM
 #1

What's the formula to determine how many BTC you can mine at ###mh/s?
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Reply with quote  #2

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August 01, 2012, 10:08:31 AM
 #2

Creating one block requires (on average) 2^48/65535*difficulty hashes, or 4295032833*difficulty, since difficulty 1 corresponds to a target of 0x00000000FFFF0000...

This means that with n MH/s, you need 4295.032833*difficulty/n seconds per block. Otherwise said, 50 BTC per (4295.032833*difficulty/n seconds), or n/(difficulty*85.90065666) BTC/s.

This equals:
  • 0.6984812728*n/difficulty BTC/minute
  • 41.90887637*n/difficulty BTC/hour
  • 1005.813033*n/difficulty BTC/day
  • 30000*n/difficulty BTC/month (approximate)
  • 367000*n/difficulty BTC/year (approximate)

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August 01, 2012, 02:00:30 PM
 #3

=(MH/difficulty)*1005.82838

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August 05, 2012, 05:22:14 AM
 #4

=(MH/difficulty)*1005.82838

per day though, not per second.

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