The 7950s have two 6-Pin entries and the leads from the PSU have 6-Pins and also another 6-Pin going out from those 6-Pin. (I hope its clear what i am trying to say.)
Do i have to put two single 6-Pin leads on every GPU or just one and use this extra 6-Pin for the other entry of the GPU?
Just did some calculations and even at a difficulty of 200, I should still break even in 2 months.
However, does anyone know how the difficulty is calculated? because if it's proportional to network hashrate then it could go much higher than 200 (a jump in hash rate to 6 Th/s looks probable in the next few days, which would mean difficulty of 200 in the same timeframe). Oh God.