notbatman (OP)
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July 22, 2015, 04:23:47 PM Last edit: July 25, 2015, 09:56:37 PM by notbatman |
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Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius
Please provide the answer in grams and show your work!
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Gleb Gamow
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July 22, 2015, 06:22:39 PM Last edit: July 22, 2015, 06:39:34 PM by Gleb Gamow |
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Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius
0.8/464 X 84,000 = ____ Did I do that right? Full Disclosure: I was the first one finishing the test and got a perfect 800 on the math section of the SAT back in 1978, but have probably forgotten more than half of what I've learnt back in the day. I taught myself calculus because it wasn't offered in my high school. I purchased a Timex Sinclair 1000 from Radio Shack (circa 1983), read the manual and learnt how to program a clock via Basic. Upon the first read-through, I quickly realized that I could program a clock to run backwards. Without referencing the program further, I implemented the program and it worked as I envisioned it. I then realized how boring this computer programming bullshit was, so I abandoned all future efforts. And you guys thought I was an idiot. Ironically, during the same basic timeframe on some other part of the world, some dude named Andreas Antonopoulos immersed himself with basically the same device. I wonder what ever happened to him.
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notbatman (OP)
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July 23, 2015, 06:56:10 AM |
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I'm considering adding a reward, is 0.01 BTC enough?
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Gleb Gamow
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July 23, 2015, 07:10:01 AM |
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Please provide the answer in grams and show your work!
144.82758612 gms .8/464 = 0.00172413793 0.00172413793 X 84,000 = 144.82758612
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notbatman (OP)
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July 23, 2015, 08:10:47 AM |
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Please provide the answer in grams and show your work!
144.82758612 gms .8/464 = 0.00172413793 0.00172413793 X 84,000 = 144.82758612 The merry-go-round is slowed to a fraction of its regular speed, the centripetal force countering gravity is also reduced and the average person weighs less according to your answer? I'm sorry but the average person is going to weigh more not less as the centripetal force is reduced. Consider two magnets stuck together with one of them tied to a string. If you twirl the magnets fast enough the one held on will fly off once the centripetal force exceeds the magnetic force holding them together. I do however appreciate your attempt at answering the question all-be-it a less than serious attempt.
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notbatman (OP)
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July 23, 2015, 08:20:26 AM |
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How about a 0.1 BTC reward, would that be enough to get a serious attempt at answering this question? That's almost $28 USD.
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lolnapp
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July 23, 2015, 08:28:29 AM |
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How about a 0.1 BTC reward, would that be enough to get a serious attempt at answering this question? That's almost $28 USD.
I think 0.02BTC would do. Just a small rewards for attach people
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notbatman (OP)
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July 23, 2015, 03:16:48 PM |
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I've added a 0.01 BTC reward for the first correct answer.
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sukamasoto
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July 23, 2015, 03:33:38 PM Last edit: July 23, 2015, 04:14:02 PM by sukamasoto |
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Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius
Please provide the answer in grams and show your work!
Let me try ( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram sent to here 1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3 If my answer satisfy you
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JLynn171
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July 23, 2015, 03:43:56 PM |
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0.64/ 6,371,000 =4077440 4077440x84,000= 342504960000gs?
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notbatman (OP)
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July 23, 2015, 04:44:36 PM |
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Let me try ( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram sent to here 1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3 If my answer satisfy you The centripetal force that counters the gravitational force has been reduced to a fraction of what it normally is. How can they (the average person) possibly weigh 0.3 kg less? 0.64/ 6,371,000 =4077440 4077440x84,000= 342504960000gs?
You got a nice big number so you're going in the right direction but, where did you get '0.64' from?
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notbatman (OP)
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July 23, 2015, 04:46:08 PM |
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Tip: the SI unit for force (in this case centripetal force) is the Newton. 1 newton = 101.971621 grams.
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JLynn171
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July 23, 2015, 05:02:55 PM |
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Let me try ( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram sent to here 1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3 If my answer satisfy you The centripetal force that counters the gravitational force has been reduced to a fraction of what it normally is. How can they (the average person) possibly weigh 0.3 kg less? 0.64/ 6,371,000 =4077440 4077440x84,000= ?
You got a nice big number so you're going in the right direction but, where did you get '0.64' from? 342504960000gs/101.xxx= 3358826275.7929483145119366102849gs 0.8^2?= 0.64?
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notbatman (OP)
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July 23, 2015, 07:09:38 PM Last edit: July 23, 2015, 07:33:47 PM by notbatman |
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Using the information you've provided I've formatted your response to make it readable... 0.8^2 = 0.64 0.64 / 6371000 = 4077440 4077440 * 84000 = 342504960000 342504960000 / 101.971621 = 3358826275.7929483145119366102849 grams
(velocity^2 / radius) * mass = 342,504,960,000 grams 342,504,960,000 / 101.971621 = 3,358,826,275.7929483145119366102849 newtons So based on your response your answer is about 3,358,826,276 newtons or 342,504,960 kg, is that correct? We're getting close but I don't think we've arrived at a BTC reward yet... Problems I can see: a) your giving results from your force formula in grams not newtons. b) your mass is still incorporating a velocity of 464 m/s to get 84 kg. c) many other issues.
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notbatman (OP)
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July 23, 2015, 07:49:05 PM |
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Tip: The SI unit of mass is the kilogram. Mass is not the same as weight.
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GSLynn
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July 23, 2015, 09:48:56 PM |
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Using the information you've provided I've formatted your response to make it readable... 0.8^2 = 0.64 0.64 / 6371000 = 4077440 4077440 * 84000 = 342504960000 342504960000 / 101.971621 = 3358826275.7929483145119366102849 grams
(velocity^2 / radius) * mass = 342,504,960,000 grams 342,504,960,000 / 101.971621 = 3,358,826,275.7929483145119366102849 newtons So based on your response your answer is about 3,358,826,276 newtons or 342,504,960 kg, is that correct? We're getting close but I don't think we've arrived at a BTC reward yet... Problems I can see: a) your giving results from your force formula in grams not newtons. b) your mass is still incorporating a velocity of 464 m/s to get 84 kg. c) many other issues. lol ok i will break out pen and paper now i been trying do it in my head all day
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GSLynn
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July 24, 2015, 01:16:06 AM |
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ok so mass=x 84,000=x(464^2)/6,371,000 ---- x/101= 25,202 0.64 / 6371000 = 4077440 4077440 *25,202 = 102759642880g's or 102,759,642.880Kg
^^^ I think *** am i getting closer?
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BAGOBO
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July 24, 2015, 02:25:57 AM |
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So what are you looking for ? The mass shift or looking for the exact mass ?
How about
0.8^2 / 464^2 * 84,000 = 0.2497026 gram
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googleindo
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July 24, 2015, 02:52:59 AM |
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this is going to be games and rounds section sir. i dont like math sigh ....
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Justin00
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July 24, 2015, 04:56:54 AM |
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pie squared - 2
let me know when you need my addy for reward.
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