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Author Topic: 4.10 BTC for Macbook Pro 2014-2015  (Read 455 times)
smith coins (OP)
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November 27, 2015, 06:37:01 PM
 #1

Offering 4.10BTC for a Macbook Pro 2015 512GB Storage and Dual GPU.

I will put the money in escrow, if you don't own you can buy it, ship to yourself and then ship it to me.

I am located in Europe, and the offer is only today during the black friday.

Thank you.
TheButterZone
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November 27, 2015, 09:16:14 PM
 #2

Is it really a black friday offer? I suppose if you're willing to up your BTC a bit for someone to proxy buy you www.ebay.fr/itm/272056794483

Saying that you don't trust someone because of their behavior is completely valid.
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November 28, 2015, 04:00:38 AM
 #3

Huh It looks like the computer you want is selling for ~$1,800 plus tax, (and plus shipping to you), but you are offering roughly $1,455 worth of bitcoin. One might be able to get one for ~$200 less at a non-apple retail store, however that would still be well over what you are offering.

I don't see why anyone would consider buying one of these and selling it to you for 4.1BTC....

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smith coins (OP)
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November 28, 2015, 10:15:44 AM
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Is it really a black friday offer? I suppose if you're willing to up your BTC a bit for someone to proxy buy you www.ebay.fr/itm/272056794483

I was misinformed because of bitcoinblackfriday info scam where i saw that amazon gift cards 'were sold' for 25% that's why i came here and asked people if they can buy it and then ship it to me (as that item has no option for shipping internationally)

Huh It looks like the computer you want is selling for ~$1,800 plus tax, (and plus shipping to you), but you are offering roughly $1,455 worth of bitcoin. One might be able to get one for ~$200 less at a non-apple retail store, however that would still be well over what you are offering.

I don't see why anyone would consider buying one of these and selling it to you for 4.1BTC....

I calculated and 4.1BTC 'were enough' for the "25% off" deal as i mentioned in this post, locking this thread as i know that this offer does/did not exists.
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