[ROLLIN.IO] Rollin 2016 New Year // Contests & Giveaways!! / CLOSED.

[LoyceV]

Bet for it Contest Code : S1

Win (profit) or lose more than 50 mBTC in a single bet.
Prizes. 12 mBTC x 10 winners*

I'm going for the consolation prize

This was my first click, 55 mbtc >11: red

I keep telling myself to hit the greedy button! Oh well, 12 mBTC happily needed

[1713985778]

1713985778

[1713985778]

1713985778

[1713985778]

1713985778

[flatswhiskey]

Roll the number contest II. Code : S2
https://rollin.io/dice/history/1770523258
username: flatswhiskey

[kshyzer]

Roll the number contest II. Code : S2
username: kshyzer
https://rollin.io/dice/history/1770534712

[FARxYodakota77]

Code S1 user ~Bumpy https://rollin.io/dice/history/1775794169
Thanks!

[ndnh]

I'm going for the consolation prize

This was my first click, 55 mbtc >11: red

I keep telling myself to hit the greedy button! Oh well, 12 mBTC happily needed

Loyce wins 12 mBTC

Roll the number contest II. Code : S2
https://rollin.io/dice/history/1770523258
username: flatswhiskey

flatswhiskey wins 10 mBTC

Roll the number contest II. Code : S2
username: kshyzer
https://rollin.io/dice/history/1770534712

kshyzer wins 10 mBTC

Code S1 user ~Bumpy https://rollin.io/dice/history/1775794169
Thanks!

Bumpy wins 12 mBTC


All prizes credited.

[ndnh]

On-thread Trivia!




aaaand the question for today is:

Q. X, who has wagered 98,456 mBTC has a balance of 6,234 mBTC at Rollin at the time. He bets half of the balance at 49% win chance and loses and then goes all-in at 49% win chance and wins. What is his profit or loss? Show working.



Post your answer(s) with your Rollin account. Rollin account should be at least level 2 OR the bitcointalk account full member and above.
First to answer correctly, to the point wins the prize of 10 mBTC.

Remember, no edits.

[karakhan]

username :karakhan
code : XMAS

[karakhan]

On-thread Trivia!




aaaand the question for today is:

Q. X, who has wagered 98,456 mBTC has a balance of 6,234 mBTC at Rollin at the time. He bets half of the balance at 49% win chance and loses and then goes all-in at 49% win chance and wins. What is his profit or loss? Show working.



Post your answer(s) with your Rollin account. Rollin account should be at least level 2 OR the bitcointalk account full member and above.
First to answer correctly, to the point wins the prize of 10 mBTC.

Remember, no edits.

he has zero profit zero loss

[Himea]

On-thread Trivia!




aaaand the question for today is:

Q. X, who has wagered 98,456 mBTC has a balance of 6,234 mBTC at Rollin at the time. He bets half of the balance at 49% win chance and loses and then goes all-in at 49% win chance and wins. What is his profit or loss? Show working.



Post your answer(s) with your Rollin account. Rollin account should be at least level 2 OR the bitcointalk account full member and above.
First to answer correctly, to the point wins the prize of 10 mBTC.

Remember, no edits.

he has zero profit zero loss

since he has 98456 mBTC wagered so it mean he now at lvl 6 and has 0.9% HE
the first roll is half of the balance 6234 mBTC x 50 % = 3117 mBTC and lose
the second roll the remaining balance 3117 mBTC x (100-0,9)/49 = 6303,97347

so total profit the last balance - initial balance = 6303.9734 mBTC - 6234 mBTC = 69,97347 mBTC

so at the end his profit is 69,97347 mBTC

username: himea

[karakhan]

username karakhan
0.00317-0.003117=0.000053

[CASlO]

balance 6234 mb (1/2 = 3117mB)

wagered = 98456mB = lvl 6 = 0.9% house edge

first roll: 3117mB on 49%; loss total wagered: 101573mb = lvl 7 =0.88% house edge = -3117mB profit

second roll : 3117 mB on 49% , @ 0.88 house edge win

= +3188.2 mB profit

total session profit = -3117mB + 3188.24571mB

                          =+71.24571mB

[CASlO]

balance 6234 mb (1/2 = 3117mB)

wagered = 98456mB = lvl 6 = 0.9% house edge

first roll: 3117mB on 49%; loss total wagered: 101573mb = lvl 7 =0.88% house edge = -3117mB profit

second roll : 3117 mB on 49% , @ 0.88 house edge win

= +3188.2 mB profit

total session profit = -3117mB + 3188.24571mB

                          =+71.24571mB

sorry if process is a bit blurry, had to do it fast, haha! hope its correct though..

USERNAME: CASIO

[Himea]

balance 6234 mb (1/2 = 3117mB)

wagered = 98456mB = lvl 6 = 0.9% house edge

first roll: 3117mB on 49%; loss total wagered: 101573mb = lvl 7 =0.88% house edge = -3117mB profit

second roll : 3117 mB on 49% , @ 0.88 house edge win

= +3188.2 mB profit

total session profit = -3117mB + 3188.24571mB

                          =+71.24571mB

sorry if process is a bit blurry, had to do it fast, haha! hope its correct though..

USERNAME: CASIO

i think this one is correct -_- i forgot to add the first roll into the wagered amount

[forfuna]

at first , he wagged 98456mB <=> lv6 <=> 0.9 HE
he bet half (3117) and lost , till now the profit is -3117
he got lv up ( lv 7 = 100000mB+ , he got 101573 after he bet  ) <=> 0.88 HE
he bet again and won

so it's gonna be (3117*(100-0.88)/49-1) = 3188.24571

=> total sesion profit : 3188.24571 + (-3117) = 71.24571

this is my most detailed solution for your questions

[LoyceV]

balance 6234 mb (1/2 = 3117mB)

wagered = 98456mB = lvl 6 = 0.9% house edge

first roll: 3117mB on 49%; loss total wagered: 101573mb = lvl 7 =0.88% house edge = -3117mB profit

second roll : 3117 mB on 49% , @ 0.88 house edge win

= +3188.2 mB profit

total session profit = -3117mB + 3188.24571mB

                          =+71.24571mB

Loyce here, I agree
Although you could argue the house edge 0.9% is totally irrelevant for the first roll. House edge only matters if you win.
Bonus Solution: X could get an extra 12 mBTC profit by entering the Bet for it Contest Code S1, either one of the bets would qualify. That would bring the total profit to 83.24571 mBTC 

[CASlO]

haha! yes, the 0.9 house edge can be ignored... i was just showing all the given data before proceeding to the solution..
also it was not stated that he joined the contest for the 12 mB prize.. sooo.. 

[kshyzer]

Q. X, who has wagered 98,456 mBTC has a balance of 6,234 mBTC at Rollin at the time . He bets half of the balance at 49% win chance and loses (Step1) and then goes all-in at 49% win chance and wins (Step2). What is his profit or loss? Show working. (Step 3)

1   1.00 %   0.00500 m฿   0 m฿  <<<---
2   0.98 %   0.01000 m฿   500 m฿
3   0.96 %   0.01500 m฿   1000 m฿

Wager = 98,456 mBTC = Level 1

Initial Balance = 6,234m฿

---> Step 1 (Playing 49% win with half of initial balance)
Half of Balance = 3,117m฿
Playing at 49% win with 3,117m฿ (lost it)
Balance = 3,117m฿

---> Step 2 (Playing all-in at 49% win with remain balance)
Remain Balance = 3,117m฿
Playing at 49% win with 3,117m฿ = +3.18061m฿ profit (win)
Balance = 3,117m฿ + 3.18061m฿ = 6,29761m฿

---> Step 3 (his final profit or loss)
Initial Balance = 6,234m฿
Balance = 6,29761m฿
Final Balance = 6,29761m฿ - 6,234m฿ = 0,06361m฿

[fumblingperch]

On-thread Trivia!




aaaand the question for today is:

Q. X, who has wagered 98,456 mBTC has a balance of 6,234 mBTC at Rollin at the time. He bets half of the balance at 49% win chance and loses and then goes all-in at 49% win chance and wins. What is his profit or loss? Show working.



Post your answer(s) with your Rollin account. Rollin account should be at least level 2 OR the bitcointalk account full member and above.
First to answer correctly, to the point wins the prize of 10 mBTC.

Remember, no edits.

Total Wager is 98456 mbtc
Level 6 - House Edge is 0.90%

Playing half of 6234mbtc and lost, so he have 3117mbtc now

Total Wager is 101573mbtc, now he is level 7 with house edge on 0.88%

Now he plays 3117mbtc 49% win chance with 0.88% house edge = 3117mbtc * (100 - 0.88) / 49 = 6305.24571mbtc

his profit is 6305.24571mbtc - 6234mbtc = 71.24571 mbtc

[skierchewing]

Roll the number contest III. Code : S3
Link: https://rollin.io/dice/history/1777781211
Username: skierchewing

[klutzbelgian]

Code : S3
user: klutzbelgian
https://rollin.io/dice/history/1777811965