Bitcoin puzzle transaction ~32 BTC prize to who solves it

[hoanghuy2912]

this's not a puzzle, this's a joke

[Bram24732]

this's not a puzzle, this's a joke

I find it funny

[E36cat]

this's not a puzzle, this's a joke

that`s what all the lottery players say, its rigged , it`s a joke, but they keep playing

[Bram24732]

this's not a puzzle, this's a joke

that`s what all the lottery players say, its rigged , it`s a joke, but they keep playing

Well this one is actually rigged.
The odds are infinitely higher for people who know what they are doing

[kTimesG]

this's not a puzzle, this's a joke

that`s what all the lottery players say, its rigged , it`s a joke, but they keep playing

Well this one is actually rigged.
The odds are infinitely higher for people who know what they are doing

The odds are the same for everyone no matter if they know what they're doing. Just proportional to their investment.

Why are you not afraid of someone coming up tomorrow and doing the exact same thing you are doing right now?

[Bram24732]

this's not a puzzle, this's a joke

that`s what all the lottery players say, its rigged , it`s a joke, but they keep playing

Well this one is actually rigged.
The odds are infinitely higher for people who know what they are doing

The odds are the same for everyone no matter if they know what they're doing. Just proportional to their investment.

Why are you not afraid of someone coming up tomorrow and doing the exact same thing you are doing right now?

Well I beg to differ.
The prefix dudes with python scripts don’t have the same hash per watt, or per dollar.
If someone does the same thing as me good for them. It’s also taken into account into the statistical modelling.just another risk factor really.

[E36cat]

this's not a puzzle, this's a joke

that`s what all the lottery players say, its rigged , it`s a joke, but they keep playing

Well this one is actually rigged.
The odds are infinitely higher for people who know what they are doing

I believe in my luck and i think i will get the key before you do

[Bram24732]

this's not a puzzle, this's a joke

that`s what all the lottery players say, its rigged , it`s a joke, but they keep playing

Well this one is actually rigged.
The odds are infinitely higher for people who know what they are doing

I believe in my luck and i think i will get the key before you do

I’m happy whoever gets the key really.
I’m just happier if it’s me

[kTimesG]

this's not a puzzle, this's a joke

that`s what all the lottery players say, its rigged , it`s a joke, but they keep playing

Well this one is actually rigged.
The odds are infinitely higher for people who know what they are doing

The odds are the same for everyone no matter if they know what they're doing. Just proportional to their investment.

Why are you not afraid of someone coming up tomorrow and doing the exact same thing you are doing right now?

Well I beg to differ.
The prefix dudes with python scripts don’t have the same hash per watt, or per dollar.
If someone does the same thing as me good for them. It’s also taken into account into the statistical modelling.just another risk factor really.

Choosing the strategy, just like education is for life, is part of the investment. Obviously, using some Python script and (un)intentionally slowing down things (in hopes of a miracle) simply means you are not investing too much. But I believe the chances are still identical for everyone, proportional to their investment, in all aspects. Money does not buy faster code, for example.

[Bram24732]

this's not a puzzle, this's a joke

that`s what all the lottery players say, its rigged , it`s a joke, but they keep playing

Well this one is actually rigged.
The odds are infinitely higher for people who know what they are doing

The odds are the same for everyone no matter if they know what they're doing. Just proportional to their investment.

Why are you not afraid of someone coming up tomorrow and doing the exact same thing you are doing right now?

Well I beg to differ.
The prefix dudes with python scripts don’t have the same hash per watt, or per dollar.
If someone does the same thing as me good for them. It’s also taken into account into the statistical modelling.just another risk factor really.

Choosing the strategy, just like education is for life, is part of the investment. Obviously, using some Python script and (un)intentionally slowing down things (in hopes of a miracle) simply means you are not investing too much. But I believe the chances are still identical for everyone, proportional to their investment, in all aspects. Money does not buy faster code, for example.

I don’t agree with this, but it’s probably off topic.
We all have a different ability to learn / understand - and those inequalities are further compounded by our socio economic backgrounds.
I don’t think equality of investment means equality of outcomes. The context matters way too much.

[POD5]

I don’t agree with this, but it’s probably off topic.
We all have a different ability to learn / understand - and those inequalities are further compounded by our socio economic backgrounds.
I don’t think equality of investment means equality of outcomes. The context matters way too much.

I totally agree with you.

[cctv5go]

Let's guess puzzle 69, how long will it take to solve this problem?Six months, one year, three years or even longer.
Regarding prefixes:Is it faster to use the birthday argument to find hash160?Has anyone paid attention to this?

[Dulocer]

Does anyone know how to use CUDA for calculations?

[kTimesG]

Let's guess puzzle 69, how long will it take to solve this problem?Six months, one year, three years or even longer.
Regarding prefixes:Is it faster to use the birthday argument to find hash160?Has anyone paid attention to this?

I can do it in 29671 days, I only need around 10 $ every day, to keep a steady rate. I'm already at 0.003276% of the scan. Are you in?

Yes, you can definitely force the H160 values/prefixes to repeat to your liking so that birthday argument applies. It's totally wrong to think that the birthday paradox simply applies for two people sharing the same birthday, whichever birthday it may be. It of course applies to two people that share the exact birthday you want them to have. Your mentor / ocult clan leader that obliges you people to pollute this thread every time the air starts to clean itself up,  is spot on!

[uyrova818]

i found a key that matches the first 7 characters of the target prefix (61eb8a5...) and the last 3 characters (...5aa). will this work?

[farou9]

Let's guess puzzle 69, how long will it take to solve this problem?Six months, one year, three years or even longer.
Regarding prefixes:Is it faster to use the birthday argument to find hash160?Has anyone paid attention to this?

I can do it in 29671 days, I only need around 10 $ every day, to keep a steady rate. I'm already at 0.003276% of the scan. Are you in?

Yes, you can definitely force the H160 values/prefixes to repeat to your liking so that birthday argument applies. It's totally wrong to think that the birthday paradox simply applies for two people sharing the same birthday, whichever birthday it may be. It of course applies to two people that share the exact birthday you want them to have. Your mentor / ocult clan leader that obliges you people to pollute this thread every time the air starts to clean itself up,  is spot on!

i dont understand how we imply the birthday paradox in kangaroo method how is a random jumps will yield the same point at some STEP

[kTimesG]

Let's guess puzzle 69, how long will it take to solve this problem?Six months, one year, three years or even longer.
Regarding prefixes:Is it faster to use the birthday argument to find hash160?Has anyone paid attention to this?

I can do it in 29671 days, I only need around 10 $ every day, to keep a steady rate. I'm already at 0.003276% of the scan. Are you in?

Yes, you can definitely force the H160 values/prefixes to repeat to your liking so that birthday argument applies. It's totally wrong to think that the birthday paradox simply applies for two people sharing the same birthday, whichever birthday it may be. It of course applies to two people that share the exact birthday you want them to have. Your mentor / ocult clan leader that obliges you people to pollute this thread every time the air starts to clean itself up,  is spot on!

i dont understand how we imply the birthday paradox in kangaroo method how is a random jumps will yield the same point at some STEP

The analysis of the Kangaroo method does not use the birthday paradox. Close but not exactly. The math behind it is clearly explained in many papers.

But this has nothing to do with address-only puzzles, which are simply brute-force problems. Anything else than this, if proven, automatically implies that secp256k1, SHA, and RIPEMD are all broken, since their cryptographic guarantees would be thrown at the trash.

[Bram24732]

Let's guess puzzle 69, how long will it take to solve this problem?Six months, one year, three years or even longer.
Regarding prefixes:Is it faster to use the birthday argument to find hash160?Has anyone paid attention to this?

I can do it in 29671 days, I only need around 10 $ every day, to keep a steady rate. I'm already at 0.003276% of the scan. Are you in?

Yes, you can definitely force the H160 values/prefixes to repeat to your liking so that birthday argument applies. It's totally wrong to think that the birthday paradox simply applies for two people sharing the same birthday, whichever birthday it may be. It of course applies to two people that share the exact birthday you want them to have. Your mentor / ocult clan leader that obliges you people to pollute this thread every time the air starts to clean itself up,  is spot on!

i dont understand how we imply the birthday paradox in kangaroo method how is a random jumps will yield the same point at some STEP

The analysis of the Kangaroo method does not use the birthday paradox. Close but not exactly. The math behind it is clearly explained in many papers.

But this has nothing to do with address-only puzzles, which are simply brute-force problems. Anything else than this, if proven, automatically implies that secp256k1, SHA, and RIPEMD are all broken, since their cryptographic guarantees would be thrown at the trash.

Terminology question : isn’t birthday paradox the search of collision of 2 subsets of size sqrt(n) ?
If so I don’t really get how kangaroo is different ? By different do you mean implementation details like DP etc… or something else ?

[kTimesG]

Let's guess puzzle 69, how long will it take to solve this problem?Six months, one year, three years or even longer.
Regarding prefixes:Is it faster to use the birthday argument to find hash160?Has anyone paid attention to this?

I can do it in 29671 days, I only need around 10 $ every day, to keep a steady rate. I'm already at 0.003276% of the scan. Are you in?

Yes, you can definitely force the H160 values/prefixes to repeat to your liking so that birthday argument applies. It's totally wrong to think that the birthday paradox simply applies for two people sharing the same birthday, whichever birthday it may be. It of course applies to two people that share the exact birthday you want them to have. Your mentor / ocult clan leader that obliges you people to pollute this thread every time the air starts to clean itself up,  is spot on!

i dont understand how we imply the birthday paradox in kangaroo method how is a random jumps will yield the same point at some STEP

The analysis of the Kangaroo method does not use the birthday paradox. Close but not exactly. The math behind it is clearly explained in many papers.

But this has nothing to do with address-only puzzles, which are simply brute-force problems. Anything else than this, if proven, automatically implies that secp256k1, SHA, and RIPEMD are all broken, since their cryptographic guarantees would be thrown at the trash.

Terminology question : isn’t birthday paradox the search of collision of 2 subsets of size sqrt(n) ?
If so I don’t really get how kangaroo is different ? By different do you mean implementation details like DP etc… or something else ?

You can't know if the unknown kangaroos are inside the set, or they exited it, so you can't apply b-day paradox to that analysis. Besides, it's not like a jump can select any element with equal chances, as it only goes forward, and it also has a maximum jump size.

B-day paradox is used by Gaudry-Schost method (which uses sets), not by Kangaroo. RC's Kangaroo is not technically a Kangaroo method.

[farou9]

The analysis of the Kangaroo method does not use the birthday paradox. Close but not exactly. The math behind it is clearly explained in many papers.

But this has nothing to do with address-only puzzles, which are simply brute-force problems. Anything else than this, if proven, automatically implies that secp256k1, SHA, and RIPEMD are all broken, since their cryptographic guarantees would be thrown at the trash.

I'm not referring to the addresses , iam talking about points , how a random jumps give us a collision on the same point after O(sqrt(N))