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Author Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it  (Read 415175 times)
SecretAdmirere
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February 26, 2026, 11:59:25 PM
 #12681

If you look at it from a pedagogical point of view, yes, but if you look at it from a competitive point of view, to increase your chances, you need a huge financial investment, like RC or others. But most people here talk about top speeds, kernels, achievements, and don't publish code, which makes me think they're still stuck in the competitive trap of blind hope, and not in sharing their ideas.

Let's be honest, if you use farms, sharing fast code puts you at a disadvantage, but if you're here purely for leisure, I don't see the point in not sharing the code for those supposed "achievements".

True, very true.  To increase the chance, it is either a huge financial investment for computing power, a mathematical-algorithmic advantage that still requires a huge financial investment for computing power, or one GPU luck - highly unlikely, by an order of magnitude unlikely, like throwing a dart from the moon and aiming to hit a grain of sand on Earth unlikely.  But anyway, we all know that.

In my case, the code I am working on is not ready for publishing, and I am not even confident enough to publish it.  No matter how many tests I run, I am not confident enough that it is good and correct.  Even now, when it passes all of the tests I can think of, I am always thinking "What if that, when this, will give the expected result".  So for now, it is only for personal use and development.  Also, I am new to all of this.  I would not even know where to begin.  It would require a lot of work to make it somewhat widely usable and not architectural and CUDA version specific.  What runs great on one GPU architecture does not necessarily run the best on a different one.  The use of newer CUDA versions will not compile for older CUDA versions, and I am working with CUDA 13 and using features like "enable_smem_spilling" that were introduced in CUDA 13, which is useless for me since I have a compute capability 8.6 compile to 122 registers used and 0 spills while everything is fully inlined, but that is just an example of how newer CUDA features would require rewriting to make it compilable in older CUDA versions.  Or I could simply publish it as "Ampere specific CUDA 13 - this is the performance".  I would also need access to a lot of different GPUs, which I cannot have at the moment (financially, I cannot have them), so I am stuck with compute capability 8.6, more specifically, a 3070 Ti.

So I do not know, maybe one day.  Or maybe I am just complaining too much now?  You are correct on all of the things you mentioned.  But I still enjoy coding, gaining knowledge, and looking at those Mkey/s numbers.

bc1q67nxvkge5ylq7fsvkhujmpvnut2a3964jqn4el
WanderingPhilospher
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February 27, 2026, 04:50:15 AM
 #12682

...
When creator or whoever topped up puzzles #1, #066-#160 with 872.19BTC, worth around ~26.4 million $$, that's an exchange rate of ~30,286$/BTC, their investment to amplify puzzle's prizes was already quite huge.

And you guys seriously hope or ask for more, at now a little more than double the exchange rate? Hilarious...

I took the liberty to fix the topic's text, at least for my own post.


and PKH is
F6E712D61FD09E6B7FF56D659CB37B0CE27070BA
How does this hex private key fall in the 270 bit range for puzzle #71?

Maybe I had too much bear already, but I can't even get your public key from this PK.
If you considering puzzle 70 fund with 7.0 and puzzle 71 with 7.1, remember it's symbolically assign, in actual puzzle 71 have double bit range then puzzle 70,
2nd if see behind solved puzzle 115 by zeiller and JLP, they used 1000 gpu 2080ti,  that time to now , new hardware 5090ti and prices hike more then 10x, electricity cost and other expenses also hike more then 10x , and same time example unsolved 135 from 130 bit range 32x
If we assume puzzle 130 solved by 1000 gpu 4090ti , at same level 32x hardware's approximately 32000 gpu cost and time and electricity etc all more then 32x,
Please reconsider calculate, these facts in my view effect for finding and making distance between people's and puzzle

Where did you come up with 135 from 130 bit range is 32x? If you are using brute force, sure, but using kangaroo, it's more like 5.65x, no?
brainless
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February 27, 2026, 06:09:55 AM
 #12683

...
When creator or whoever topped up puzzles #1, #066-#160 with 872.19BTC, worth around ~26.4 million $$, that's an exchange rate of ~30,286$/BTC, their investment to amplify puzzle's prizes was already quite huge.

And you guys seriously hope or ask for more, at now a little more than double the exchange rate? Hilarious...

I took the liberty to fix the topic's text, at least for my own post.


and PKH is
F6E712D61FD09E6B7FF56D659CB37B0CE27070BA
How does this hex private key fall in the 270 bit range for puzzle #71?

Maybe I had too much bear already, but I can't even get your public key from this PK.
If you considering puzzle 70 fund with 7.0 and puzzle 71 with 7.1, remember it's symbolically assign, in actual puzzle 71 have double bit range then puzzle 70,
2nd if see behind solved puzzle 115 by zeiller and JLP, they used 1000 gpu 2080ti,  that time to now , new hardware 5090ti and prices hike more then 10x, electricity cost and other expenses also hike more then 10x , and same time example unsolved 135 from 130 bit range 32x
If we assume puzzle 130 solved by 1000 gpu 4090ti , at same level 32x hardware's approximately 32000 gpu cost and time and electricity etc all more then 32x,
Please reconsider calculate, these facts in my view effect for finding and making distance between people's and puzzle

Where did you come up with 135 from 130 bit range is 32x? If you are using brute force, sure, but using kangaroo, it's more like 5.65x, no?
No
Let me explain you again
70 bit  10 people's run kangaroo, everyone get key on same hardware gpu but find times are different even in millisecond
That's not fixed, exact,
Bc kangaroo finding depand on hope, same you extend bit range too 100 bit and same 10 people's same 10 hardware, everyone calc in different time frame
Finally we will calculate time zone by complete bit range
Next example
70 bit could find by kangaroo in 1 min reward is 7.0 btc
And 140 bit rewards is 14.0 btc but bit range is multibillions size more then 70 bit range
In previous finding 115 to 130
Solver claimed used 1000 and more gpu farms to run months for finding definitely use kangaroo type formulation
But no one can say their exact time for completetion of kangaroo jobs, but can tell calculate time after finding
At currently puzzle 71 and puzzle 135 in front of all
Kangaroo can't apply to 71, next calc 71 reward is 7.1btc not a double from puzzle 70 rewards, (but range double then 70 bit range) and doest not matter creator funded 1000 btc,
99 % people will follow, brute force, like lottery winning, it's kill soul of btc cracking strength by community words
1% will apply strategy inside brute force, by calc some areas of total bit range to find by scanning specific areas
Could write more in all aspects but hope these words have meaning

13sXkWqtivcMtNGQpskD78iqsgVy9hcHLF
kTimesG
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February 27, 2026, 08:56:38 AM
 #12684

Quote from: brainless link=topic=130698 3 .msg66452934#msg66452934 date=1772172595
Where did you come up with 135 from 130 bit range is 32x? If you are using brute force, sure, but using kangaroo, it's more like 5.65x, no?
No
Let me explain you again

Yes. Because c * sqrt(x * 32) / (c * sqrt(x)) is always going to end up as 5.65.

brainless
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February 27, 2026, 09:26:10 AM
Last edit: February 27, 2026, 09:11:54 PM by Mr. Big
 #12685

Quote from: brainless link=topic=130698 3 .msg66452934#msg66452934 date=1772172595
Where did you come up with 135 from 130 bit range is 32x? If you are using brute force, sure, but using kangaroo, it's more like 5.65x, no?
No
Let me explain you again

Yes. Because c * sqrt(x * 32) / (c * sqrt(x)) is always going to end up as 5.65.
Equation is fixed if we need answer of equation, but when finding by hope first it's need complete the 5.65, (100%) then it will take 500% till to generate hope and finding
Example
81 /9 both have same sqrt for... Every one could do it in 1/1000 sec
If it's
81 / 13 every one get different time zone for result, due to floating point also takes times to process
Simple open your installed kangaroo tool search 70bit 3 different pubkeys
Counts every searched pubkey with 3 data, total time, total hope, total %  in +- 2^35
You will get answer in practical in your hand



Quote from: brainless link=topic=130698 3 .msg66452934#msg66452934 date=1772172595
Where did you come up with 135 from 130 bit range is 32x? If you are using brute force, sure, but using kangaroo, it's more like 5.65x, no?
No
Let me explain you again

Yes. Because c * sqrt(x * 32) / (c * sqrt(x)) is always going to end up as 5.65.
Equation is fixed if we need answer of equation, but when finding by hope first it's need complete the 5.65, (100%) then it will take 500% till to generate hope and finding
Example
81 /9 both have same sqrt for... Every one could do it in 1/1000 sec
If it's
81 / 13 every one get different time zone for result, due to floating point also takes times to process
Simple open your installed kangaroo tool search 70bit 3 different pubkeys
Counts every searched pubkey with 3 data, total time, total hope, total %  in +- 2^35
You will get answer in practical in your hand

More
If 5.65 fixed result
Example RC use 1000 gpu 4090ti for 3 month get result for 13.0 btc and save 3 btc after all expence
Now 5650 gpu for 3 month if resulted and get 13.5 btc, could you calc cost of operation
Hope you understand operation and reward,
For these reason we request Creator to build up some better reward,

13sXkWqtivcMtNGQpskD78iqsgVy9hcHLF
kTimesG
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February 27, 2026, 11:44:43 AM
 #12686

If 5.65 fixed result...

It's not an "if", it's the square root of the value 32 (the result of the proportion of difficulties).

Hope is an exact number, it's exactly "c * sqrt(space)" to reach 50% chance of success (also called "on average"). This number reaches infinity as you approach 100% (which is never reachable for a non-deterministic algorithm).

It doesn't matter if you do the computations on paper, on 1 GPU, on 10.000 ASICs, or in your brain. The difficulty increase factor, on average, between two keyspaces having a proportion of 32, is the square root.

walletrecovery
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February 27, 2026, 02:03:43 PM
 #12687

More
If 5.65 fixed result
Example RC use 1000 gpu 4090ti for 3 month get result for 13.0 btc and save 3 btc after all expence
Now 5650 gpu for 3 month if resulted and get 13.5 btc, could you calc cost of operation
Hope you understand operation and reward,
For these reason we request Creator to build up some better reward,

[/quote]

I want to try to find the key. What is the most modern program for Nvidia GPU version now?

GinnyBanzz
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February 28, 2026, 10:00:12 AM
 #12688

More
If 5.65 fixed result
Example RC use 1000 gpu 4090ti for 3 month get result for 13.0 btc and save 3 btc after all expence
Now 5650 gpu for 3 month if resulted and get 13.5 btc, could you calc cost of operation
Hope you understand operation and reward,
For these reason we request Creator to build up some better reward,


I want to try to find the key. What is the most modern program for Nvidia GPU version now?
[/quote]

Lol yeah, the "creator" isn't gonna do shit buddy, deal with it.
napros
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February 28, 2026, 11:41:49 AM
 #12689

MY Prediction for Puzzle 135

  Start:
    Decimal:             23,239,725,590,828,274,043,206,201,010,000,000,000,000
    Hex:     444BA0576AB304B7D5F2FADC4AF7A52000
  End:
    Decimal:             35,080,600,283,013,590,507,885,810,740,000,000,000,000
    Hex:     6717B5DAEF45F9CEE8BAA2CE5332C74000
  Width:                 11,840,874,692,185,316,464,679,609,730,000,000,000,000
  Scale:                 11.84 duodecillion

Will be interesting to compare how close or how far off my 'prediction' is when solved
E36cat
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February 28, 2026, 07:06:17 PM
 #12690

MY Prediction for Puzzle 135

  Start:
    Decimal:             23,239,725,590,828,274,043,206,201,010,000,000,000,000
    Hex:     444BA0576AB304B7D5F2FADC4AF7A52000
  End:
    Decimal:             35,080,600,283,013,590,507,885,810,740,000,000,000,000
    Hex:     6717B5DAEF45F9CEE8BAA2CE5332C74000
  Width:                 11,840,874,692,185,316,464,679,609,730,000,000,000,000
  Scale:                 11.84 duodecillion

Will be interesting to compare how close or how far off my 'prediction' is when solved
thats more than half of the range ... your dizzy or something Smiley)
napros
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February 28, 2026, 10:28:05 PM
 #12691

MY Prediction for Puzzle 135

  Start:
    Decimal:             23,239,725,590,828,274,043,206,201,010,000,000,000,000
    Hex:     444BA0576AB304B7D5F2FADC4AF7A52000
  End:
    Decimal:             35,080,600,283,013,590,507,885,810,740,000,000,000,000
    Hex:     6717B5DAEF45F9CEE8BAA2CE5332C74000
  Width:                 11,840,874,692,185,316,464,679,609,730,000,000,000,000
  Scale:                 11.84 duodecillion

Will be interesting to compare how close or how far off my 'prediction' is when solved
thats more than half of the range ... your dizzy or something Smiley)

45.63% reduction and is not the full area of the search range, its where I predict the solution will land. Somewhere between. That's why its a 'prediction' not a 'suggestion' of where you set your processing app to.
E36cat
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March 01, 2026, 02:10:39 AM
 #12692

MY Prediction for Puzzle 135

  Start:
    Decimal:             23,239,725,590,828,274,043,206,201,010,000,000,000,000
    Hex:     444BA0576AB304B7D5F2FADC4AF7A52000
  End:
    Decimal:             35,080,600,283,013,590,507,885,810,740,000,000,000,000
    Hex:     6717B5DAEF45F9CEE8BAA2CE5332C74000
  Width:                 11,840,874,692,185,316,464,679,609,730,000,000,000,000
  Scale:                 11.84 duodecillion

Will be interesting to compare how close or how far off my 'prediction' is when solved
thats more than half of the range ... your dizzy or something Smiley)

45.63% reduction and is not the full area of the search range, its where I predict the solution will land. Somewhere between. That's why its a 'prediction' not a 'suggestion' of where you set your processing app to.
there`s no reduction thats a prediction, are you a medium or something Smiley
walletrecovery
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March 02, 2026, 02:51:25 PM
 #12693

Thank you, smart and caring member of this forum, for your mathematical calculations and assumptions! I hope that your calculations will help us get closer to solving the puzzle. There are geniuses who refuse money, for example you can read here: https://en.wikipedia.org/wiki/Grigori_Perelman
I'm interested in the question of what is the most modern program for RANDOM range enumeration today. I'd like to try to find the key.

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March 02, 2026, 03:09:21 PM
 #12694

I've given a list a little while back:

FixedPaul's: https://github.com/FixedPaul/VanitySearch-Bitcrack
RCKangaroo: https://github.com/RetiredC/RCKangaroo
Keyhunt: https://github.com/manyunya/KeyHunt-Cuda
WanderingPhilosopher's: https://github.com/WanderingPhilosopher/VanBitCrackenRandom2 (Not open-source)
BitCrack: https://github.com/djmuratb/BitCrack2
Cyclone: https://github.com/Dookoo2/Cyclone
CUDACyclone: https://github.com/Dookoo2/CUDACyclone
Ecloop: https://github.com/vladkens/ecloop

Thank you, smart and caring member of this forum, for your mathematical calculations and assumptions! I hope that your calculations will help us get closer to solving the puzzle. There are geniuses who refuse money, for example you can read here: https://en.wikipedia.org/wiki/Grigori_Perelman
I'm interested in the question of what is the most modern program for RANDOM range enumeration today. I'd like to try to find the key.

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Hmm...


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March 04, 2026, 07:10:51 AM
 #12695

Message to the creator: Decrypt the message using the private key 155

Ephemeral Public Key: AulmdLezGK0dTLYAZmrx+Fe3HYk6rW5aEWhVgyRS8N0N

Nonce: uz+Nem7CwHERiCHC

Ciphertext: sa9MS5/fUL05U+TvoVy46IQ/8b0hN6yM80Q14AtDwwTBRnPaVQmnPA
UoPU28e+NoP38CAnXv3c9l8adebTBWmnGPzAQe3fNTq+9TQDwbjwXdZd698dd1
wHI46OB8gMnGPV+vFzb6dXQnGmTFZgQdAts8G2/8sC7xmA5Vsw2pHY5xTs5XH
Xb70UvBUvN9PUegmfoz72YiR9dxP57rH3LGtX5VRIorCNYpCFcKptoeMsumE1BHi3
vpyU+OFWXfnGaKW4YxmRb6GXiInM4Zmbn9IRhn0RRPUiW+mzA1iH56g2QqlyHYw
4NbhwmYNEBBLeDn9ZiamsCpWRJHr8XQRuMO2QAZ936skMPrzmwLbUjNtFZU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bhQRFxM0LNJrBoIO4Eky3ncmxBIXU8nWk8ghNAkjtGPtvp95eP5
1pBFFcUgT8C1JObf3gO87W7fRqPpC8s49pex0owRRpLKsqbXjIFF
pyPoLqsGXBXNtSV6hvq/v3N5PS/u8y78N7LTsLUQz+rzLnEkIKhCrLX
F8T/Wl0bjE28IQSAWrPFszTGKzKj2xA+lc+qrecQDPw3Swq+//rPhhn3G
GZqOJ6oDKdM/p6AvsSsex6570Pcwna8qBZDuGQtf7Q3N82Cd95LTxS
VmSDTB65uTHiFHvW2Qe/O7gw7W7YB3cB68C1oX2D4v4etmeiIxYm
oL2C5pdP5nuQuuPVPUB9FLKSjmA7NenDxDsuXUaP/fKgZnugi2Kwn
iHHv0xDfrlTRdw1jvFe3Wtdsa1bQ90UkfD6Zhi/1I+tA2hMmg4W08btmswuJbw3T
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March 04, 2026, 12:34:35 PM
 #12696

Message to the creator: Decrypt the message using the private key 155

Ephemeral Public Key: AulmdLezGK0dTLYAZmrx+Fe3HYk6rW5aEWhVgyRS8N0N

Nonce: uz+Nem7CwHERiCHC

Ciphertext: sa9MS5/fUL05U+TvoVy46IQ/8b0hN6yM80Q14AtDwwTBRnPaVQmnPA
UoPU28e+NoP38CAnXv3c9l8adebTBWmnGPzAQe3fNTq+9TQDwbjwXdZd698dd1
wHI46OB8gMnGPV+vFzb6dXQnGmTFZgQdAts8G2/8sC7xmA5Vsw2pHY5xTs5XH
Xb70UvBUvN9PUegmfoz72YiR9dxP57rH3LGtX5VRIorCNYpCFcKptoeMsumE1BHi3
vpyU+OFWXfnGaKW4YxmRb6GXiInM4Zmbn9IRhn0RRPUiW+mzA1iH56g2QqlyHYw
4NbhwmYNEBBLeDn9ZiamsCpWRJHr8XQRuMO2QAZ936skMPrzmwLbUjNtFZU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bhQRFxM0LNJrBoIO4Eky3ncmxBIXU8nWk8ghNAkjtGPtvp95eP5
1pBFFcUgT8C1JObf3gO87W7fRqPpC8s49pex0owRRpLKsqbXjIFF
pyPoLqsGXBXNtSV6hvq/v3N5PS/u8y78N7LTsLUQz+rzLnEkIKhCrLX
F8T/Wl0bjE28IQSAWrPFszTGKzKj2xA+lc+qrecQDPw3Swq+//rPhhn3G
GZqOJ6oDKdM/p6AvsSsex6570Pcwna8qBZDuGQtf7Q3N82Cd95LTxS
VmSDTB65uTHiFHvW2Qe/O7gw7W7YB3cB68C1oX2D4v4etmeiIxYm
oL2C5pdP5nuQuuPVPUB9FLKSjmA7NenDxDsuXUaP/fKgZnugi2Kwn
iHHv0xDfrlTRdw1jvFe3Wtdsa1bQ90UkfD6Zhi/1I+tA2hMmg4W08btmswuJbw3T

Invalid key : youranidiot
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March 04, 2026, 02:59:08 PM
Last edit: March 04, 2026, 03:10:36 PM by NUCLEAR7.1
 #12697

Message to the creator: Decrypt the message using the private key 155

Ephemeral Public Key: AulmdLezGK0dTLYAZmrx+Fe3HYk6rW5aEWhVgyRS8N0N

Nonce: uz+Nem7CwHERiCHC

Ciphertext: sa9MS5/fUL05U+TvoVy46IQ/8b0hN6yM80Q14AtDwwTBRnPaVQmnPA
UoPU28e+NoP38CAnXv3c9l8adebTBWmnGPzAQe3fNTq+9TQDwbjwXdZd698dd1
wHI46OB8gMnGPV+vFzb6dXQnGmTFZgQdAts8G2/8sC7xmA5Vsw2pHY5xTs5XH
Xb70UvBUvN9PUegmfoz72YiR9dxP57rH3LGtX5VRIorCNYpCFcKptoeMsumE1BHi3
vpyU+OFWXfnGaKW4YxmRb6GXiInM4Zmbn9IRhn0RRPUiW+mzA1iH56g2QqlyHYw
4NbhwmYNEBBLeDn9ZiamsCpWRJHr8XQRuMO2QAZ936skMPrzmwLbUjNtFZU
L66mr8VG/drHTCtMJ0lvJK9VkgDzFF/N+N4u7wW05Do72t42Ds62adCMGIVj1Gk
OybwmVyzI6yLMTt4b39RWS9rEtMOnL3tqVwFy/XfVMBFapA97+Kdqb9lKA23aGCGv
C6rKtXb8KDbo4ebGGjiWtdyNxu1Jd+Yws+va+DTBKFJFaf7x2GvDN3mr5lJKaSyXJR
YpODtKUQBcOV7hD1HJ704u0xxOOn0rc8WVqbJyzYlqrdnDuOzptdbWHsT1EEQDuQ
MrJPmOtBZMvlSlw857AHHfMG+3/wWF21JQdo/xLXUksn2eDikPvJ6Bmr1YTHyGde
c3Pot1kxfuzIHKc7Jjbtd4XIDfF4rDqmDI/ozwPqYuYNUrSfqz178v62KhmlxczQlhQrjEig
S6zLAdGHcXZnjiHYWIm7aw+glF6HgZzhcggFsVsFG5Ju66U7uwDIezgFpJwND/Awf
Vfd1b3IbQUtsn4OIgfffTsaPo61OuQtKgv8ZR8pF8vOOMsEuFOVavIcD+14EDxnlK2xB
NAQEIVuZkbhRPXjlA3TULDKU1IWZgHk6ShHZGCdGrRf4jBV72e36+n8fVXibGEsMID
Gp3AMdJ1Oc2mQ377fbDEouvnW2+Iu2DZJBhIMkDfD45tjIe0B+SrnxHnKBFuwZtq4dL
6pmr2QCD6DVxeZHQIo6x3xjNDojS6trND8BtGnSNTXM21Y/KDtBbF1bSQtu2
lpMTyTcDO1tRnAN9nExhDqI2gR2Fsez70Z9xF5mH1PX1OC
bhQRFxM0LNJrBoIO4Eky3ncmxBIXU8nWk8ghNAkjtGPtvp95eP5
1pBFFcUgT8C1JObf3gO87W7fRqPpC8s49pex0owRRpLKsqbXjIFF
pyPoLqsGXBXNtSV6hvq/v3N5PS/u8y78N7LTsLUQz+rzLnEkIKhCrLX
F8T/Wl0bjE28IQSAWrPFszTGKzKj2xA+lc+qrecQDPw3Swq+//rPhhn3G
GZqOJ6oDKdM/p6AvsSsex6570Pcwna8qBZDuGQtf7Q3N82Cd95LTxS
VmSDTB65uTHiFHvW2Qe/O7gw7W7YB3cB68C1oX2D4v4etmeiIxYm
oL2C5pdP5nuQuuPVPUB9FLKSjmA7NenDxDsuXUaP/fKgZnugi2Kwn
iHHv0xDfrlTRdw1jvFe3Wtdsa1bQ90UkfD6Zhi/1I+tA2hMmg4W08btmswuJbw3T

Invalid key : youranidiot
    What is your problem? Did you try to decrypt it without permission?
Only the creator can read it. Don't waste your time
CrabStick1
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March 05, 2026, 04:58:01 PM
 #12698

477007882A8842614B   1PWo3JeB9jTUxadvYh1wXCYUpH2CsyD27E             
477009EA4543BFFAFB   1PWo3JeB9jtL4RK2wpYczGygdkn3v4ZjcR
47700B794FABB04B8A   1PWo3JeB9jK4jourU5YGZYEtnAKDsNwYzQ   
477011D6C809817D9F   1PWo3JeB9jwaCQkp9rvKDNd4QaXr5Jrh5S


Yeah, it's a lot of 1PWo3JeB9j all over the range 400000000000000000:7fffffffffffffffff  Tongue
Yes. We've already checked the entire range from 40x to 477x. And there are a lot of them... here's the latest:
4778AF41E8842B0652   1PWo3JeB9jbdqjJP6TYhNiweRjfeMoCfhv



Hey, did you use sequential or random mode for scanning from 40x to 477x Huh
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March 09, 2026, 12:59:17 AM
 #12699

What is your problem? Did you try to decrypt it without permission?
Only the creator can read it. Don't waste your time
post another message with same cipher but with know PK (45 for example). hard to recognize crypto method.
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March 09, 2026, 09:13:02 AM
 #12700

I've given a list a little while back:

FixedPaul's: https://github.com/FixedPaul/VanitySearch-Bitcrack
RCKangaroo: https://github.com/RetiredC/RCKangaroo
Keyhunt: https://github.com/manyunya/KeyHunt-Cuda
WanderingPhilosopher's: https://github.com/WanderingPhilosopher/VanBitCrackenRandom2 (Not open-source)
BitCrack: https://github.com/djmuratb/BitCrack2
Cyclone: https://github.com/Dookoo2/Cyclone
CUDACyclone: https://github.com/Dookoo2/CUDACyclone
Ecloop: https://github.com/vladkens/ecloop

Thank you, smart and caring member of this forum, for your mathematical calculations and assumptions! I hope that your calculations will help us get closer to solving the puzzle. There are geniuses who refuse money, for example you can read here: https://en.wikipedia.org/wiki/Grigori_Perelman
I'm interested in the question of what is the most modern program for RANDOM range enumeration today. I'd like to try to find the key.


Here are a couple more links.
https://github.com/Etayson/Etarkangaroo (certainly not as fast as RCKangaroo)

Although BSGS is probably useless for 135 (compared to Kangaroo), but this is an original solution - random, implemented if you can call it "kind of the other way around."
https://github.com/Etayson/fraction-bsgs
At least it's quite interesting. Besides, it works on a graphics card.

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