Hi folks
I was excited to see this post on the Elliptic Curve Calculator in Armory:
https://bitcointalk.org/index.php?topic=66862.0Based on the
2-of-2 Multisig example, I was able to create a shared public key. However, I was not able to get the corresponding shared private key.
So, here is the data I have used:
1:
PUBLIC
1MFpXAU8VaYUfKxzpPvZSZXpvbZJVE34jM
de3001c3402b4ff42c91bfb60f18943a209bafc6
PRIVATE
5JvuJuiZiyjFzNqnQ16sbqmQ9wQ26dEaqsbikw734Nega4u2gYN
92b7f1f77f22afd8275cf628e71664082b442202a49eac567e7e7b37ba559e69
2:
PUBLIC
18J9jxfYQw9e9fv1YYm9QxNBkFoxyTEZix
50073f899897517dc8bc743e5690773515042432
X:fa4bb8fe6da6c646ac63361a16a142d6c04269d02fbc740eed2c4a54ba7dda26
Y:12fec352c07045d144ee96197a68a6060c89eff887ef3f8c2dfea8bff7965f33
PRIVATE
5JtTHTXeoq792C7Dy2C7ELEu6RgGQYyQiX2aQ8myWRq4GJnuKj9
8d288fef6dfed2edffb34f620256975fe9dbe2949f7e61b14b91d0be593d628a
Based on this, I've calculated the
shared public key in the EC Calculator:
==> PRIVATE 1 * PUBLIC XY 2 (second function):
X:f8c61d46fc0c7f866b6ec34e191279e9a9ef1ff9d263aadc189669cd6bb4b7db
Y:161b41cae92dbb41e7b0584be2e5adbb9c83718c19eb1c6f3f82e31a403c6d96
==>BTC:1GmWADL3wvwm6dCxgf5XxirW8bBD34rRgU
Now, I've tried calculating the
shared private key but it didn't match:
==> PRIVATE 1 * 2 (first function):
31ac197e32af979fc9010b39b7a3c84358d9bfb669f59562b4a63fc86a8bf754
==>BTC:1BjwqtjfMifRNW6dPdAYyJV7K8dV98Cbmm
Did I do something wrong? How do I achieve a matching pair of secret public/private keys?
-BeeCoin.