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Author Topic: Shouldn't bitcoins be square?  (Read 3085 times)
Paperweight
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June 25, 2011, 04:47:54 PM
 #1

Not round? Just sayin'
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June 25, 2011, 04:52:46 PM
 #2

I think they should be octangcircusquarigal.  Grin
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June 25, 2011, 05:02:06 PM
 #3

Electron orbits are round, not square Smiley
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June 25, 2011, 05:03:04 PM
 #4

Not round? Just sayin'
 they are not round just look like it because they have an indefinitely amount of corners.
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June 25, 2011, 05:20:24 PM
 #5

they should be the shape of an electron cloud
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June 25, 2011, 09:39:26 PM
 #6

Electron orbits are round, not square Smiley

Wow. The Bohr model...

A clue to the vintage of your worldview right there.
+1

ns orbitals are round, not square Smiley

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June 25, 2011, 09:42:04 PM
 #7

They should have the shape of a cloud of probability and be defined by the Schrödinger equation.

Ryland R. Taylor-Almanza
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June 25, 2011, 09:44:24 PM
 #8

Maybe they should be the shape of a key?
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June 25, 2011, 09:54:58 PM
 #9

Remember: There is no Bitcoin!

...only transactions Smiley
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June 25, 2011, 10:04:34 PM
 #10

perhaps they should form the shape of an elliptic curve

Will

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June 25, 2011, 10:34:21 PM
 #11

Shouldn't they be shaped like a burgler to keep everyone vigilant?  Wink

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June 26, 2011, 12:48:49 AM
 #12

Electrons in semiconductors are delocalized and have no definite orbitals, and electrons themselves are indivisible elementary particles: something bitcoins are not.
Although... bitcoins are like fuzzy objects that are sometimes not there when their owners look for them, as well as catlike objects that resist being put back in the bag...

What are, like bitcoins, mineable (by breeding), infinitely divisible (by fur), easily transferable (by purpose or negligence), and more? Cats.

Therefore, I propose that the official shape of bitcoins be the furball.
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June 26, 2011, 01:09:32 AM
 #13

There is no denying that it's hip to be square.

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June 26, 2011, 01:19:07 AM
 #14

They should have the shape of a cloud of probability and be defined by the Schrödinger equation.

I like that.

They don't have a value until you look at them.

Wouldn't the market collapse by observing it?
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June 26, 2011, 01:34:54 AM
 #15

It should be torus shaped.
Reflecting the [seemingly] infinite adress space.

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June 26, 2011, 07:53:50 AM
 #16

Wave function collapse? When I made my weekly "portfolio" check in Mt. Gox a few days ago, Bitcoins were at $17 and slowly going up. I put in a buy order for $100 and ten minutes later they were at 1 cent.

Although stocks usually go down right after I buy them, like when I lost my entire portfolio of $2500 in eight days last year, this is a little more like a lightning strike from Hermes.
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June 26, 2011, 07:58:58 AM
 #17

1. When I saw the title I had a feeling someone didn't understand some science.

2. When I read the OP, I had a feeling someone would screw up and use the Bohr model of the atom to justify roundness.

3. When someone finally did use the Bohr model, I had a feeling I'd end up being the one who explained how and why they were wrong.

When someone not only proved me wrong on #3 but went on to make Schroedinger jokes about the market collapsing when observed I finally realized EXACTLY how right for me this community is.

You guys rock.

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June 26, 2011, 08:06:04 AM
 #18

Wave function collapse is not that bad, look at the Quantum Zeno Effect:

If Bitcoin has a finite, gaussian decaying lifetime, we simply need to observe the market often and fast to make it stay  Grin

I think we're going to need a LOT more market volume Wink

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June 26, 2011, 08:06:07 AM
 #19

Therefore, I propose that the official shape of bitcoins be the furball.

I nominate myself!

"MOOOOOOOM! SOME MYTHICAL WOLFBEAST GUY IS MAKING FUN OF ME ON THE INTERNET!!!!"
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June 26, 2011, 08:16:54 AM
 #20

I'd like to Imagine it being Like a "BuckyBall". Smiley

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