xxxcoin
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October 06, 2011, 04:16:52 PM |
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Arrived today Looks pretty good in the bag, will see how it works in the box Plugged in and churning away. Turns out it's about 2" short of making the card mount nicely on a side card mount in the case so I'm running it open right now. Going to order a PCI-e x1 extender to make it fit better. Will have to reconfigure some fans but then I will have managed to squeeze every last drop of hashing out of this particular box... for now
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Bitcraft
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October 09, 2011, 12:40:56 AM |
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Most of my risers I just paid a few bucks each for on ebay. I did however buy a $25 riser with molex from cablesaurus. It works great, and the shipping was fast, but $25 is still a complete ripoff.
Supply and demand?
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what@3 (OP)
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October 10, 2011, 02:38:40 AM |
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Most of my risers I just paid a few bucks each for on ebay. I did however buy a $25 riser with molex from cablesaurus. It works great, and the shipping was fast, but $25 is still a complete ripoff.
Supply and demand? supply and demand would only justify his pricing IF there were a LIMITED supply, which is clearly not the case.
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MadHacker
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October 10, 2011, 05:17:37 PM |
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Most of my risers I just paid a few bucks each for on ebay. I did however buy a $25 riser with molex from cablesaurus. It works great, and the shipping was fast, but $25 is still a complete ripoff.
Supply and demand? supply and demand would only justify his pricing IF there were a LIMITED supply, which is clearly not the case. actually supply and demand is a factor... demand is low... primarily it is only used by miners. supply is also low... each molex connector is soldered on by hand which raises cost. then it boils down to how much do want to gain in profit, how much time does it take to add a molex connector. i add my molex connectors differently so it takes me at least 1/2 hour just to do 1 cable. if i were to sell them i would be charging a lot more since i think my time is worth a lot. but i don't sell them... I think I'm rambling now.
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patrixiorey
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October 11, 2011, 12:39:03 AM |
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Raiser 1X can be purchaser for less than U$s4 on Dealextreme!!! Check Out!!!
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what@3 (OP)
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October 11, 2011, 06:06:54 AM |
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Most of my risers I just paid a few bucks each for on ebay. I did however buy a $25 riser with molex from cablesaurus. It works great, and the shipping was fast, but $25 is still a complete ripoff.
Supply and demand? supply and demand would only justify his pricing IF there were a LIMITED supply, which is clearly not the case. actually supply and demand is a factor... demand is low... primarily it is only used by miners. supply is also low... each molex connector is soldered on by hand which raises cost. then it boils down to how much do want to gain in profit, how much time does it take to add a molex connector. i add my molex connectors differently so it takes me at least 1/2 hour just to do 1 cable. if i were to sell them i would be charging a lot more since i think my time is worth a lot. but i don't sell them... I think I'm rambling now. I figured that it was well known that demand was also very limited hence not worth mentioning, I should have made it more clear. There is also VERY little demand and a very little limit to his supply. Also, 1/2 hr?? geez care to post a pic of what you're doing that merits a half hour?? Each once runs me ~6 minutes.
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MadHacker
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October 12, 2011, 05:21:08 AM |
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Most of my risers I just paid a few bucks each for on ebay. I did however buy a $25 riser with molex from cablesaurus. It works great, and the shipping was fast, but $25 is still a complete ripoff.
Supply and demand? supply and demand would only justify his pricing IF there were a LIMITED supply, which is clearly not the case. actually supply and demand is a factor... demand is low... primarily it is only used by miners. supply is also low... each molex connector is soldered on by hand which raises cost. then it boils down to how much do want to gain in profit, how much time does it take to add a molex connector. i add my molex connectors differently so it takes me at least 1/2 hour just to do 1 cable. if i were to sell them i would be charging a lot more since i think my time is worth a lot. but i don't sell them... I think I'm rambling now. I figured that it was well known that demand was also very limited hence not worth mentioning, I should have made it more clear. There is also VERY little demand and a very little limit to his supply. Also, 1/2 hr?? geez care to post a pic of what you're doing that merits a half hour?? Each once runs me ~6 minutes. Unfortunately the ones i have are in machines. have to make some this weekend however... but this is what i do i carefully cut the ribbon down where the 12V lines are on both sides (A2 & A3, B1, B2 & B3) then i cut them away from the base of the card edge... and strip the wire ends. solder a 16 gauge wire to it and connect the other end to a molex connector. this completely isolates the 12V away from the motherboard and no power is pulled from the motherboard. hard part is leaving the A1 wire (PRSNT1#) intact and not get it damaged or cut. i have cut it once by accident and had to fix the wire.
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what@3 (OP)
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October 12, 2011, 02:42:13 PM |
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Seems like there will be a lot of unnecessary components which would be powered up ( idling ) which is a waste of energy.
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what@3 (OP)
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October 12, 2011, 06:54:25 PM |
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Most of my risers I just paid a few bucks each for on ebay. I did however buy a $25 riser with molex from cablesaurus. It works great, and the shipping was fast, but $25 is still a complete ripoff.
Supply and demand? supply and demand would only justify his pricing IF there were a LIMITED supply, which is clearly not the case. actually supply and demand is a factor... demand is low... primarily it is only used by miners. supply is also low... each molex connector is soldered on by hand which raises cost. then it boils down to how much do want to gain in profit, how much time does it take to add a molex connector. i add my molex connectors differently so it takes me at least 1/2 hour just to do 1 cable. if i were to sell them i would be charging a lot more since i think my time is worth a lot. but i don't sell them... I think I'm rambling now. I figured that it was well known that demand was also very limited hence not worth mentioning, I should have made it more clear. There is also VERY little demand and a very little limit to his supply. Also, 1/2 hr?? geez care to post a pic of what you're doing that merits a half hour?? Each once runs me ~6 minutes. Unfortunately the ones i have are in machines. have to make some this weekend however... but this is what i do i carefully cut the ribbon down where the 12V lines are on both sides (A2 & A3, B1, B2 & B3) then i cut them away from the base of the card edge... and strip the wire ends. solder a 16 gauge wire to it and connect the other end to a molex connector. this completely isolates the 12V away from the motherboard and no power is pulled from the motherboard. hard part is leaving the A1 wire (PRSNT1#) intact and not get it damaged or cut. i have cut it once by accident and had to fix the wire. i carefully cut the ribbon down where the 12V lines are on both sides (A2 & A3, B1, B2 & B3) Thats the same way I made a few of my previous ones but I really hated that free floating A1 So here is my solution http://tinyurl.com/4xu7tnqhttp://tinyurl.com/3k72u3mbut not cutting any of the wires the riser is no longer required to use additional molexs ( 12V+'s ) except when its required. The current draw will always take the path of least resistance - http://tinyurl.com/aynwg http://tinyurl.com/aynwg"Where does the current flow? Current will always try to seek out the source, be it normal current or fault current. As for taking the path of least resistance, that is partially correct. Electrical current will take any and all paths available to try to return to its source. If several paths are available for current to flow, it will divide and the resistance of each path will determine how much current will flow on each particular path." The molex plug is rigidly attached resulting in less flexing of the ribbons ( more importantly the solder joints which have no strain reliefs ) No more of this Zip Tie BS http://image.bayimg.com/fakfhaadh.jpgAssembly time is now ~2 minutes ( assuming I have to wait for the soldering iron / rework station to heat up. ) This is an extra btw if anyone wants it 3.25 BTC gets it to you w/ FREE S&H to the lower 48 via USPS http://tinyurl.com/4xu7tnqhttp://tinyurl.com/3k72u3m
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MadHacker
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October 12, 2011, 07:14:49 PM |
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2 issues i see 1) your not connecting up all the 12V lines. there are total of 5. so it may still pull power from the motherboard. 2) path of least resistance... between getting power from motherboard or from the molex connector the difference in resistance is very small. possibly measurable in milliohms. so it may still pull power from the motherboard.
I'm no electronics technician so i can't say for sure.
but i do know that hen i physically cut the ribbon wire and plug the 12v wires into a molex connector i am for sure not drawing any power from the motherboard.
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what@3 (OP)
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October 13, 2011, 04:01:41 AM |
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2 issues i see 1) your not connecting up all the 12V lines. there are total of 5. so it may still pull power from the motherboard. 2) path of least resistance... between getting power from motherboard or from the molex connector the difference in resistance is very small. possibly measurable in milliohms. so it may still pull power from the motherboard.
I'm no electronics technician so i can't say for sure.
but i do know that hen i physically cut the ribbon wire and plug the 12v wires into a molex connector i am for sure not drawing any power from the motherboard.
Did I ever say I wanted to prevent power from being draw from the mother board?? Nope, didn't. You're living in a ridiculously paranoid world if you're worried about drawing any power through the mother board, its just plan silly to avoid it entirely, and you gain absolutely nothing from avoiding it, need I repeat, NOTHING. The PCI slots are designed to provided power for pci cards, so if you create additional pathways for current to flow then you will lower the amount traveling on each pathway, thus in turn increasing to total amount of current able to be drawn w/o damaging components ( traces and wires ); its really a pretty basic concept, re-read the articles I posted, http://tinyurl.com/aynwg http://tinyurl.com/5s5llfohave you ever check these pins A2 & A3, B1, B2 & B3 for continuity ?? They are all connected on the cards PCB - all the the same copper pad. I can assure you that by isolating those 5 wires and detaching them from the riser / mobo entirely and reducing them to 1 - 16awg wire you are in fact decreasing the amount of current carrying capacity. You would be so much better off just leaving them connected to riser and the mother board and just have an additional 12v molex at your disposal. All Wires can be though of as resistors, b/c they all have some inherent amount of resistance. Resistors in Parallel http://upload.wikimedia.org/wikipedia/commons/2/2a/Resistorsparallel.pngIn a parallel circuit, current is divided among multiple paths. This means that two resistors in parallel have a lower equivalent resistance than either of the parallel resistors, since both resistors allow current to pass. Two resistors in parallel will be equivalent to a resistor that is twice as wide: http://upload.wikimedia.org/wikibooks/en/math/3/7/6/3760f431a4d755d2181151b4046d80a7.pngSince conductances (the inverse of resistance) add in parallel, you get the following equation: http://upload.wikimedia.org/wikibooks/en/math/b/7/d/b7d797059343dbd0d2f8f8d09b06f1c2.pngFor example, two 4 O resistors in parallel have an equivalent resistance of only 2 O. To simplify mathematical equations, resistances in parallel can be represented with two vertical lines "||" (as in geometry). For two resistors the parallel formula simplifies to: http://upload.wikimedia.org/wikibooks/en/math/b/2/2/b22693aac2a2de84160944e7f0ee4fec.pngAnother useful read http://tinyurl.com/3u5crbb"Electrical resistance Voltage can be thought of as the pressure pushing charges along a conductor, while the electrical resistance of a conductor is a measure of how difficult it is to push the charges along. Using the flow analogy, electrical resistance is similar to friction. For water flowing through a pipe, a long narrow pipe provides more resistance to the flow than does a short fat pipe. The same applies for flowing currents: long thin wires provide more resistance than do short thick wires. " Also, 2 issues i see 1) your not connecting up all the 12V lines. there are total of 5. so it may still pull power from the motherboard. 2) path of least resistance... between getting power from motherboard or from the molex connector the difference in resistance is very small. possibly measurable in milliohms. so it may still pull power from the motherboard.
1) *face palm* 2) Pins B10, A9 & A10 pull power through the mother board, so better pull those too 3) 1 milliohms = .001ohms In the image below Red indicates power source Yellow Line = .3 ohms Green Line = .3 ohms Yellow & Green Line = .2 ohms point - less resistance http://image.bayimg.com/lakggaadh.jpgAnother thing, Notice how in this picture all the lines are intact and the molex is just soldered to one side of the board. http://image.bayimg.com/fakfhaadh.jpgIn any case the additional molex is just there to as a supplemental power inclusion point - not a replacement for all power going to the edge card ( pcie end that is )
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Blade Rage
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October 15, 2011, 02:13:32 AM |
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Can you confirm that these powered cables are necessary when using 4 or 5 gpus?
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what@3 (OP)
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October 15, 2011, 04:39:15 PM |
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Can you confirm that these powered cables are necessary when using 4 or 5 gpus?
That is all dependent on the quality of the motherboard and gpu's power consumption.
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Blade Rage
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October 15, 2011, 10:11:47 PM |
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Ok. Can you confirm that the card will draw power from the power supply before the motherboard? Or do we assume that every card draws 75 watts from the mobo 1st?
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what@3 (OP)
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October 16, 2011, 03:22:58 AM |
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Ok. Can you confirm that the card will draw power from the power supply before the motherboard? Or do we assume that every card draws 75 watts from the mobo 1st?
There is ~375 Ohms between pins A2, A3, B1, B2 & B3 and the 6 pin molex's on the back of the card. Meaning different parts of the card are getting energized in different ways, and the 375 Ohms between A2 & A3, B1, B2 & B3 and the 6 pin molex's is there to prevent part of the card from routing ( drawing ) power through the entire card and damaging other components. So to answer your question, both get power first while they don't at the same time and the number 42. I have not personally had any problems, I can confirm that I've read about wires smoking and board sockets melting. I strongly believe that the vast majority of problems related to electrical failures and wire overloads has a lot more to do with poor connections and damaged wires ( internally ). If your card is getting power from a plug that is not making sufficient contact with the psu resistance will increase making that wire hotter thus becoming a worse conductor and the worse the conductor the higher the resistance; a cascading failure. 75W @ 12V = 6.25A So are you asking why people use the raisers with the additional molex?
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Blade Rage
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October 16, 2011, 05:25:55 PM |
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Thanks for the replies. I've been trying to figure out if I need to use the molex powered extender cables. I think I'll try adding cards slowly and see if it's stable before adding another card. I'd like to save the $, but if it's required then I'll consider using your service
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aggrojosh
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October 17, 2011, 03:45:11 PM |
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I bought some $2 ebay ones and they have been working with my 5770's no prob no molex power but they're lower-powered cards
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