GO! (Puzzle fun :) )

[CryptoFuture]

   ;;;;;;;    ;  ; ;; ;; ;;;;;;;  
   W ;;; W `;`;W``W` W ; W ;;; W  
   W WWW W `` ``;` W`;;W W WWW W  
   W;;;;;W W W W ;`; ; W W;;;;;W  
   ;;;;; ;;;;;W`;;WW;`;;; ; ; ;  
    ```;;;W W   ;W;`W``;; `W;;`  
   ;; ;` ;`WW`;`;`;`;;;`  ;W`;;;  
      W W;``;W````WW`;``W`WW ;    
    `;;;W;;; ;;`; ; ; W```; ` WW  
   W W`;`;;`W``W`R`WW;  W ```W;`  
   W ;W `; W` `` W``; `WW;;W`    
   ;;;;;;; W`W  W WW `;W ; W ;;`  
   W ;;; W ;   `;W;W;``W;;;WW ;`  
   W WWW W W W`;;W;```;`;;W; ;;`  
   W;;;;;W W  ;W ;W;; W``;`WW;`  

[Meuh6879]

it's a trap.

[DannyHamilton]

https://blockchain.info/address/12xRyf6DUkoh3e6Bd6vaXcY8JGhniGSq8w

  ;;;;;;;    ;  ; ;; ;; ;;;;;;;  
   W ;;; W `;`;W``W` W ; W ;;; W  
   W WWW W `` ``;` W`;;W W WWW W  
   W;;;;;W W W W ;`; ; W W;;;;;W  
   ;;;;; ;;;;;W`;;WW;`;;; ; ; ;  
    ```;;;W W   ;W;`W``;; `W;;`  
   ;; ;` ;`WW`;`;`;`;;;`  ;W`;;;  
      W W;``;W````WW`;``W`WW ;    
    `;;;W;;; ;;`; ; ; W```; ` WW  
   W W`;`;;`W``W`R`WW;  W ```W;`  
   W ;W `; W` `` W``; `WW;;W`    
   ;;;;;;; W`W  W WW `;W ; W ;;`  
   W ;;; W ;   `;W;W;``W;;;WW ;`  
   W WWW W W W`;;W;```;`;;W; ;;`  
   W;;;;;W W  ;W ;W;; W``;`WW;`  

For 0.01 BTC?

Not worth the effort.

[zetaray]

This is a bit too challenging for me, but it should not be too difficult for those who can program

[E.exchanger]

  I wonder noone has every solved it, Is it really that hard to solve

[Taras]

I wonder noone has every solved it, Is it really that hard to solve

This is as far as I can decode

[roslinpl]

I wonder noone has every solved it, Is it really that hard to solve

No one want to waste a time on this perhaps

[Taras]

I wonder noone has every solved it, Is it really that hard to solve

No one want to waste a time on this perhaps

I'd waste my time on this for BTC0.001

[roslinpl]

I wonder noone has every solved it, Is it really that hard to solve

No one want to waste a time on this perhaps

I'd waste my time on this for BTC0.001

0.001 BTC is not a lot But I would say I undertand that it might be worth some time - but is less than a dollar how much time is worth?

Anyway did you solve it right already?

Regards and good luck

[Triswardhani]

It's not worth.....

[DannyHamilton]

If I've got the pattern right:

• In most cases a W represents 2 black pixels arranged vertically.
• In most cases a ; represents 2 pixels arranged vertically where the top is white and bottom is black.
• In most cases a ` represents 2 pixels arranged vertically where the top is black and bottom is white.
• In most cases a blank space represents w white pixels arranged vertically.

Following those rules, I get what looks like a QR Code.  The positioning, alignment, and timing information is all properly represented. Additionally:

• It appears to be a Version 3 (29x29) QR Code.
• It seems to be using Level L (Low) error correction.
• It appears to be using the (col%3=0) mask pattern.

I have not yet figured out what the bold R is meant to indicate.

As such, the resulting QR Code doesn't scan.

What I have so far looks like this:

[Wintervenom]

Code:

#!/usr/bin/env python3
import fileinput

def main():
    grid = []
    for line in fileinput.input():
        line = line.rstrip()
        print('   ', end='')
        columns = []
        for char in line:
            if char == 'W':
                pair = (True, True)
            elif char == ';':
                pair = (False, True)
            elif char == '`':
                pair = (True, False)
            elif char == ' ':
                pair = (False, False)
            elif char == 'R':
                pair = (True, False)
            else:
                pair = (False, False)
            columns.append(pair)

        column = []
        for top, bottom in columns:
            column.append(top)
        grid.append(column)

        column = []
        for top, bottom in columns:
            column.append(bottom)
        grid.append(column)


    print('\x1b[0m')
    print('\x1b[47m\n')
    for column in grid:
        print('\x1b[47m    ', end='')
        for cell in column:
            print('\x1b[40m  ' if cell else '\x1b[47m  ', end='')
        print('\x1b[47m')
    print('\x1b[47m\n', end='')
    print('\x1b[0m')
    print('')


if __name__ == '__main__':
    try:
        main()
    except KeyboardInterrupt:
        print('')
        pass

[TheButterZone]

Finally. Lock topic.

[mexxer]

lol this was pretty cool but couldn't join in time 

[Taras]

I wonder noone has every solved it, Is it really that hard to solve

No one want to waste a time on this perhaps

I'd waste my time on this for BTC0.001

0.001 BTC is not a lot But I would say I undertand that it might be worth some time - but is less than a dollar how much time is worth?

Anyway did you solve it right already?

Regards and good luck

0.001 BTC is not a lot
Not in 2009, not in 2014.
But what about 2020?

Congrats to whoever decoded this. It was fun to try, I'd like to see more of this

[roslinpl]

I wonder noone has every solved it, Is it really that hard to solve

No one want to waste a time on this perhaps

I'd waste my time on this for BTC0.001

0.001 BTC is not a lot But I would say I undertand that it might be worth some time - but is less than a dollar how much time is worth?

Anyway did you solve it right already?

Regards and good luck

0.001 BTC is not a lot
Not in 2009, not in 2014.
But what about 2020?

Congrats to whoever decoded this. It was fun to try, I'd like to see more of this

indeed I would like to see more too
0.001BTC is not even 1 cheap beer in my situation but quizzes like that are more interesting than 0.001BTC

[Taras]

I wonder noone has every solved it, Is it really that hard to solve

No one want to waste a time on this perhaps

I'd waste my time on this for BTC0.001

0.001 BTC is not a lot But I would say I undertand that it might be worth some time - but is less than a dollar how much time is worth?

Anyway did you solve it right already?

Regards and good luck

0.001 BTC is not a lot
Not in 2009, not in 2014.
But what about 2020?

Congrats to whoever decoded this. It was fun to try, I'd like to see more of this

indeed I would like to see more too
0.001BTC is not even 1 cheap beer in my situation but quizzes like that are more interesting than 0.001BTC

2014 = 0.001BTC -> 1 cheap beer
2016 = 0.001BTC -> 30 cheap beers

[roslinpl]

2014 = 0.001BTC -> 1 cheap beer
2016 = 0.001BTC -> 30 cheap beers

Yeees well but I will not hodl till 2016 I am not too good at hodling I am much better at spending
Anyway this was very nice quiz and price doesn't really matter.

And I love the way it was solved as I love Python.