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Author Topic: script for check requirements for next rank v2  (Read 671 times)
fillippone
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June 27, 2019, 11:30:51 AM
 #21

this is the output for bob123

Code:
Profile: https://bitcointalk.org/index.php?action=profile;u=579628
UID 579628
Nick: bob123
-----
Merits: 1150
Activity: 938
Position: Hero Member
-----
SignUp: October 22, 2015, 04
Last: Today at 11
Mail: hidden
-----
Calculate luck
66.0
Missing: ('Merits:', -150, 'Activity:', -163)

luck 66%


output for not Hero Member is
Code:
Profile: https://bitcointalk.org/index.php?action=profile;u=889300
UID 889300
Nick: giammangiato
-----
Merits: 25
Activity: 144
Position: Member
-----
SignUp: August 16, 2016, 11
Last: Today at 11
Mail: hidden
-----
Next Position: Full Member
Missing: ('Merits:', 75, 'Activity:', -24)

Hello,
Nice to see some improvements:
Thinks I would do:

  • better formatting of time (both in signup and last) using the hh:mm format
  • “last active”, not on “last”
  • No negative merits or activity. When negative numbers put “0” instead, or “-“ or “Fulfilled”
  • If required activity>0 then add a “minimum upgrade date” taking care of activity cycles on the forum.


.
.HUGE.
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In order to get the maximum amount of activity points possible, you just need to post once per day on average. Skipping days is OK as long as you maintain the average.
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bob123
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June 27, 2019, 11:33:33 AM
 #22

this is the output for bob123

[...]

luck 66%

This number says how probable it is to get legendary within 775 and X activity.
But it does not say how probable it is to get an rank up with the next update, which would be a bit more useful i think.

But regardless of that, nice work.

giammangiato (OP)
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June 27, 2019, 12:18:37 PM
 #23

Thank you guys, i mean @filippone and @bob123

I'll do the improvements and release the script soon!

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fillippone
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June 27, 2019, 12:50:58 PM
 #24

this is the output for bob123

[...]

luck 66%

This number says how probable it is to get legendary within 775 and X activity.
But it does not say how probable it is to get an rank up with the next update, which would be a bit more useful i think.

But regardless of that, nice work.

Sorry,
As per the formula the number should indicate the probability to be ranked up on next activity cycle.
So, basically in 14 days or less you’ll be legendary in the 66% of cases.
Check again the formula....

.
.HUGE.
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bob123
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June 28, 2019, 07:20:29 AM
Merited by DdmrDdmr (2)
 #25

Sorry,
As per the formula the number should indicate the probability to be ranked up on next activity cycle.
So, basically in 14 days or less you’ll be legendary in the 66% of cases.
Check again the formula....

This can't be the case.
The activity where i rank up is a random number between 938 and  (including) 1030.

Activity increases by 14 each cycle. This means there are 7 more cycles in which i could get legendary.
The chance for me to get legendary in the next cycle therefore is 1/7 = 14%. The next cycle the chance would be 1/6 = 17%.


Based on your statement i should be legendary in 3 cycles.
But that can not be said if there are 7 more cycles to come.

I'd have a 50% chance to get an uprank in the next '3.5' cycles.


What your formula does, is to calculate the chance of getting legendary within 775 and X activity (in the quoted calculation above: between 775 and 938).

fillippone
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June 28, 2019, 07:51:30 AM
Last edit: June 28, 2019, 08:11:38 AM by fillippone
Merited by bob123 (1)
 #26

Sorry,
As per the formula the number should indicate the probability to be ranked up on next activity cycle.
So, basically in 14 days or less you’ll be legendary in the 66% of cases.
Check again the formula....

This can't be the case.
The activity where i rank up is a random number between 938 and  (including) 1030.

Activity increases by 14 each cycle. This means there are 7 more cycles in which i could get legendary.
The chance for me to get legendary in the next cycle therefore is 1/7 = 14%. The next cycle the chance would be 1/6 = 17%.


Based on your statement i should be legendary in 3 cycles.
But that can not be said if there are 7 more cycles to come.

I'd have a 50% chance to get an uprank in the next '3.5' cycles.


What your formula does, is to calculate the chance of getting legendary within 775 and X activity (in the quoted calculation above: between 775 and 938).

Dear lord, you are right!
Is this the heatwave over Europe affecting my brain?

Here you go
Pls note that the first activity where you get a chance to get promoted on next cycle is 14*55=770

if activity>770 then 
luck numerator=rounddown((activity-770)/14,0)+1 
 luck denominator= rounddown((1030-770)/14,0) 
luck=1/(luckdenominator-lucknumerator+1)


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.HUGE.
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bob123
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June 28, 2019, 08:43:21 AM
Last edit: June 28, 2019, 08:53:44 AM by bob123
 #27

Pls note that the first activity where you get a chance to get promoted on next cycle is 14*55=770

Why?

Legendary requires 775. So theoretically with 775-14=761 you'd already have a chance.

Note that the activity has not to be divisible by 14. The activity is min(posts, time*14).
If your theoretical activity would be higher (e.g. 1000+), but you'd have 761 posts, your activity would be 761.



By the way, it is still slightly off

Quote
luck numerator=rounddown((activity-770)/14,0)+1
 luck denominator= rounddown((1030-770)/14,0)
luck=1/(luckdenominator-lucknumerator+1)


Take me (activity 938) for example, my probability is roughly 1/7 (14.3 %). But based on your formula, i get:

luck numerator = 13
luck denominator = 18
luck = 1/6


The correct formula is:
Code:
luck = 14 / (1030-activity)


Quite sad that it took us multiple posts and (way too much) thinking to find that (extremely easy) formula  Grin Grin


Edit: to be more precise regarding the script:

Code:
#call getLuck when activity > 760

def getLuck(activity):
    luck = 14 / ( 1030 - activity)
    if luck > 1:
        luck = 1
    return luck

fillippone
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June 28, 2019, 08:55:58 AM
 #28

Pls note that the first activity where you get a chance to get promoted on next cycle is 14*55=770

Why?

Legendary requires 775. So theoretically with 775-14=761 you'd already have a chance.

Note that the activity has not to be divisible by 14. The activity is min(posts, time*14).
If your theoretical activity would be higher (e.g. 1000+), but you'd have 761 posts, your activity would be 761.

Ok, the activity would be lower if you posted less than 14 posts in an activity cycle.
Something that doesn't happen so much, I guess.
Take you: your activity is 67*14=938...


Quote
By the way, it is still slightly off

Quote
luck numerator=rounddown((activity-770)/14,0)+1
 luck denominator= rounddown((1030-770)/14,0)
luck=1/(luckdenominator-lucknumerator+1)

Yes, because there's a typo here:
luck denominator= rounddown((1030-770)/14,0) +1

So in your case:

Take me (activity 938) for example, my probability is roughly 1/7 (14.3 %). But based on your formula, i get:

luck numerator = 13
luck denominator = 19
luck = 14.29%

Quote
The correct formula is:
Code:
luck = 14 / (1030-activity)


Quite sad that it took us multiple posts and (way too much) thinking to find that (extremely easy) formula  Grin Grin

If my activity were 1022, next cycle I would be legendary as activity it will be 1036.
So luck is 100%, but with your formula I get 175%.

If my activity were 1008, I would be legendary either at 1022 or at 1036, hence my luck=50%.
But with your formula is 63%...

I still don't get it...
I do agree it is sad.

.
.HUGE.
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bob123
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June 28, 2019, 09:04:21 AM
Merited by fillippone (2)
 #29

If my activity were 1022, next cycle I would be legendary as activity it will be 1036.
So luck is 100%, but with your formula I get 175%.

Therefore the if luck > 1: luck = 1 statement  Grin



If my activity were 1008, I would be legendary either at 1022 or at 1036, hence my luck=50%.
But with your formula is 63%...

Well, that's what i thought at the beginning too..

But it is more probable to get promoted in the first cycle than in the second.

If max legendary activity is 1030:
There are 14 activity-points between 1008 and 1022
There are 8 activity-points between 1022 and 1030.

If the number is random between 1008 and 1030, it is 'almost' twice as probable for it to be between 1008 and 1022 (probability: 14 / (8+14).
And this is 0.636363..  what basically my formula says  Cheesy


Edit:
A better example:

With 1015 activity, the chance of getting a rank-up is 'close to 100%'.
This basically comes down to a random number between 1 and 15. Probability: (14/15) that it is below 15.

Therefore with the formula:
luck = 14 / (1030-activity)
luck = 14 / (1030 - 1015) = 14 / 15

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June 28, 2019, 09:13:48 AM
 #30

If my activity were 1022, next cycle I would be legendary as activity it will be 1036.
So luck is 100%, but with your formula I get 175%.

Therefore the if luck > 1: luck = 1 statement  Grin



If my activity were 1008, I would be legendary either at 1022 or at 1036, hence my luck=50%.
But with your formula is 63%...

Well, that's what i thought at the beginning too..

But it is more probable to get promoted in the first cycle than in the second.

If max legendary activity is 1030:
There are 14 activity-points between 1008 and 1022
There are 8 activity-points between 1022 and 1030.

If the number is random between 1008 and 1030, it is 'almost' twice as probable for it to be between 1008 and 1022 (probability: 14 / (8+14).
And this is 0.636363..  what basically my formula says  Cheesy


Edit:
A better example:

With 1015 activity, the chance of getting a rank-up is 'close to 100%'.
This basically comes down to a random number between 1 and 15. Probability: (14/15) that it is below 15.

Therefore with the formula:
luck = 14 / (1030-activity)
luck = 14 / (1030 - 1015) = 14 / 15

Ok, let's end this embarrassing discussion here and adopt your simpler formula!

.
.HUGE.
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giammangiato (OP)
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Merit: 1236



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June 28, 2019, 10:23:43 AM
 #31

with bob123 formula

Code:
Calculate luck
15.0

this is the code
Code:
def calculateLuck(activity):
  luck = 100 * 14 / (1030 - int(activity))
  print math.floor(luck)

for me not working

Code:
Merits: 1156
Activity: 938
Position: Hero Member

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giammangiato (OP)
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June 28, 2019, 10:50:10 AM
 #32

“last active”, not on “last”
done

better formatting of time (both in signup and last) using the hh:mm format

for an user
Code:
Profile: https://bitcointalk.org/index.php?action=profile;u=579629
UID 579629
Nick: flash45
-----
Merits: 0
Activity: 5
Position: Newbie
-----
SignUp: 2015-10-22 04:00:00
Last Active: 2015-10-25 07:00:00
Mail: hidden
-----
Next Position: Jr Member
Missing: ('Merits:', 1, 'Activity:', 25)

No negative merits or activity. When negative numbers put “0” instead, or “-“ or “Fulfilled”

done
Code:
Profile: https://bitcointalk.org/index.php?action=profile;u=889300
UID 889300
Nick: giammangiato
-----
Merits: 36
Activity: 147
Position: Member
-----
SignUp: 2016-08-16 11:00:00
Last Active: Today at 10
Mail: hidden
-----
Next Position: Full Member
Missing: ('Merits:', 64, 'Activity:', 'FULLFILLED')

If required activity>0 then add a “minimum upgrade date” taking care of activity cycles on the forum.

i dont understand this

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.
.Duelbits.
..........UNLEASH..........
THE ULTIMATE
GAMING EXPERIENCE
DUELBITS
FANTASY
SPORTS
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/// PLAY FOR  FREE  ///
WIN FOR REAL
..PLAY NOW..
fillippone
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Activity: 2142
Merit: 15397


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June 28, 2019, 10:56:45 AM
 #33



If required activity>0 then add a “minimum upgrade date” taking care of activity cycles on the forum.

i dont understand this

Please check this thread where it explain how activity work:
https://bitcointalk.org/index.php?topic=2766177.0

There's a spreadsheet with activity cycles.
If I am not wrong I will become Hero on the first post (the first post triggers activity update) after UNIX time 1571790000 or 10/23/2019 0:20:00.


.
.HUGE.
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bob123
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Merit: 2481



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June 28, 2019, 11:19:37 AM
 #34

with bob123 formula

Code:
Calculate luck
15.0

this is the code
Code:
def calculateLuck(activity):
  luck = 100 * 14 / (1030 - int(activity))
  print math.floor(luck)

for me not working

Code:
Merits: 1156
Activity: 938
Position: Hero Member


What exactly does not work?

This works without problems for me:

Code:
def calculateLuck(activity):
        luck = 100 * 14 / (1030 - int(activity))
        print (luck)

calculateLuck(938)

And you don't need to use math.floor()  in fact you shouldn't because this can create quite some wrong results.


If you want to have only 2 decimal places, add round:


Code:
luck = round (100 * 14 / (1030 - int(activity)), 2)



Your function should then look like this:

Code:
def calculateLuck(activity):
        luck = round (100 * 14 / (1030 - int(activity)), 2)
        if (luck > 100):
                luck = 100
        return (luck)

bitart
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June 28, 2019, 08:35:54 PM
 #35

...
If I am not wrong I will become Hero on the first post (the first post triggers activity update) after UNIX time 1571790000 or 10/23/2019 0:20:00.


I think you will be a Hero on 9th October 2019.
You need 102 activity points to become a Hero.
This means (102/14) 7,3 activity periods, so you need 8 activity periods.
The next activity period starts on 2nd July 2019 (next Tuesday), the 8th activity period starts on 9th October 2019.
But I can also be wrong Smiley
fillippone
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June 29, 2019, 12:32:32 PM
Last edit: June 29, 2019, 12:57:24 PM by fillippone
 #36

...
If I am not wrong I will become Hero on the first post (the first post triggers activity update) after UNIX time 1571790000 or 10/23/2019 0:20:00.


I think you will be a Hero on 9th October 2019.
You need 102 activity points to become a Hero.
This means (102/14) 7,3 activity periods, so you need 8 activity periods.
The next activity period starts on 2nd July 2019 (next Tuesday), the 8th activity period starts on 9th October 2019.
But I can also be wrong Smiley
Yeah, you are right. 480 activity is needed, not 500...
This thread is the lowest point in my whole btctlk career

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giammangiato (OP)
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July 01, 2019, 08:06:56 AM
 #37


What exactly does not work?

This works without problems for me:

Code:
def calculateLuck(activity):
        luck = 100 * 14 / (1030 - int(activity))
        print (luck)

calculateLuck(938)

And you don't need to use math.floor()  in fact you shouldn't because this can create quite some wrong results.


If you want to have only 2 decimal places, add round:


Code:
luck = round (100 * 14 / (1030 - int(activity)), 2)



Your function should then look like this:

Code:
def calculateLuck(activity):
        luck = round (100 * 14 / (1030 - int(activity)), 2)
        if (luck > 100):
                luck = 100
        return (luck)


Ah ok thank you!!! I will update the script soon. I will remove Math.floor.

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.Duelbits.
..........UNLEASH..........
THE ULTIMATE
GAMING EXPERIENCE
DUELBITS
FANTASY
SPORTS
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/// PLAY FOR  FREE  ///
WIN FOR REAL
..PLAY NOW..
babo
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July 09, 2019, 10:24:21 AM
 #38

i reuse your code for do other stuffs Smiley

creative recycling


i'm very lazy eheh

.
.BLACKJACK ♠ FUN.
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