Here is how you should have solved the puzzle.
We have
- the ECDSA equation (
![](https://ip.bitcointalk.org/?u=https%3A%2F%2Fwikimedia.org%2Fapi%2Frest_v1%2Fmedia%2Fmath%2Frender%2Fsvg%2F555b9413ed5f0828b6bc27f3c0ba5ec74c255306&t=665&c=x-U0u1CPMrEn_A)
[
1])
- Base64 signature with a recid so we had:
- r = 0x37bb22d3f7afe8668e9b28561332d9e3734a8139bfe139d2c094741456403609
- s = 0x50ca4a3efdeb86e9252b4c32114d77ae71911f4f5ed3ce13e5f82bdfd30658ab
- v = 0x01
- z aka e is calculated easily from the message: 0xfb917a8e7c3dd70b329d7671cc388329749f5e90a39b7f2670a1311e90bb516a
- k = 2020
Also the above equation could be changed to by knowing the
basic properties of modular arithmetic:
s*k=z+rdA (mod n) =>
s*k - z = rdA (mod n) =>
(s*k - z)r-1 = dA (mod n)First thing to know is that all of the above is "modular arithmetic" so x
-1 or 1/x is not as simple as 1 divided by x. It is
modular multiplicative inverse. That means 1/2 (mod n) is not 0.5 but instead it is 57896044618658097711785492504343953926418782139537452191302581570759080747169
ModInverse() method is found in all cryptography libraries.
With that we can calculate d
A (that is the private key) as
0xc5b25300c3f76cd0142b5bcca95fe307eb1cda05df153f81039edaa92ef96afd
But if you get the P2PKH address from this key you'll get 1CNvS7ivEFrZWSbSSSc6fvQFgY7KNG16Aq (compressed pubkey) or as hatshepsut93 found 13LDi5Sb5YG2MAebUNkAB58t1DcFPCAaxZ (uncompressed pubkey).
By the way when redid-27 is bigger than 4 that means the compressed public key was used.
So something must have been wrong. It takes us back to recid. recid-27 is 5 and when you subtract 4 (the fixed value added to indicate compressed public key) you'll get 1. This could be an indication that negative s was used instead.
As I posted above, In bitcoin to prevent malleability there is a consensus rule that mandates usage of
low S values in signatures. Which is basically a simple modular subtraction.
With the new (s = secp256k1.N - s) we get a new key value:
0x53616e746120436c61757320626974636f696e2070726976617465206b657921
Now if you get the P2PKH address of this key you'll get 14B3NsuKDk5piqnw71U9kDuSmvMJnYprnr which is the correct address.
But where is the reward?
A single private key corresponds to a single public key point and from that public key you can create multiple script types (for simplicity addresses) one of which is P2WPKH which is known as a native SegWit address.
private key: Kz1nt4DTapTZdBhRCNca7QazvC4WSA2rCTk1prmGxtHDYqNehZNe
public key: 022c17a18e7e6b625506ee24f09ed0e4475ae399cd7b16d25693490c07ab2fe94f
address: bc1qyt8g2aucnnd00wmwruxzw6eluf5ut4cmd0ljuz
And the final "mystery" was that if you look at the private key posted here more closely or with another "eye" you can see that it is a simple human readable string! All you have to do is to convert the base58 or base16 to UTF8 to get:
Santa Claus bitcoin private key!