Pollard's kangaroo ECDLP solver

[Minase]

Sure,
I will just give a simple example.
Lets say you get the key close to the N half, lets take for example a random point 7fffffffffffffffffffffffffffffff5d1777e13d618b66b81ee5de17cf885a (we pushed for example 120 puzzle to this k) which results in
K = 0269da924844fcc5852ef6808f0e0bc9e851bd7b6b23d6e55d4b152ab0101fedfd
The diff between N/2 and our point is 3ff6921a42c4b727ca4968504b9846
With a big enough hash table which we need to compute as we want (random/incremental), lets say we compute from 7FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF5D576E7357A4501DDFE92F46681A20A0 to 7FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF5D576E7357A4501DDFE92F46681B20A0 (small example) then our table will contain 0x10000 public keys, but in reality it is 0x20000 (double).
If we discard Y or parity from our K computation when we generate random steps (increments) we have a double change to get it right.
If our random increment difference  was bigger than normal hash table size (but not bigger than double) than we will have a match and we can easily compute the right k from the known K.

Dont know if i was clear enough, if not i will try to illustrate it 

[1715428432]

1715428432

[WanderingPhilospher]

Sure,
I will just give a simple example.
Lets say you get the key close to the N half, lets take for example a random point 7fffffffffffffffffffffffffffffff5d1777e13d618b66b81ee5de17cf885a (we pushed for example 120 puzzle to this k) which results in
K = 0269da924844fcc5852ef6808f0e0bc9e851bd7b6b23d6e55d4b152ab0101fedfd
The diff between N/2 and our point is 3ff6921a42c4b727ca4968504b9846
With a big enough hash table which we need to compute as we want (random/incremental), lets say we compute from 7FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF5D576E7357A4501DDFE92F46681A20A0 to 7FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF5D576E7357A4501DDFE92F46681B20A0 (small example) then our table will contain 0x10000 public keys, but in reality it is 0x20000 (double).
If we discard Y or parity from our K computation when we generate random steps (increments) we have a double change to get it right.
If our random increment difference  was bigger than normal hash table size (but not bigger than double) than we will have a match and we can easily compute the right k from the known K.

Dont know if i was clear enough, if not i will try to illustrate it 

Made need the illustration now

But one quick question, if we push as you said and the diff between N/2 and our point is 3ff6921a42c4b727ca4968504b9846, would that be big enough to solve since 120 starting range is
800000000000000000000000000000?  120s pubkey added to 7FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF5D576E7357A4501DDFE92F46681B20A0 should at least be a difference of 800000000000000000000000000000, right?

[COBRAS]

This was previously posted in this thread but deleted for some reason, it's a snippet from iceland2k14's Github that divides a pubkey by an arbitrary number and returning all the parts in between. I polished it a bit to print the compressed and uncompressed keys: https://gist.github.com/ZenulAbidin/286a652b160086b3b0f184a886ba68ca

Here's the script output when called with a random (uninteresting - with no balance) pubkey, divided by 48. The keys divided by 0, 1, 2, 3 and so on are printed in order:

Code:

>>> shiftdown("0267830f83723fa565ccb8677c14d13f7d47bf1008fea826833359f27f866632ab", 48)
023f81e98df59d891264d3fca9bca16552feaf1c7dba1bebd9a774c5fd6041f248 043f81e98df59d891264d3fca9bca16552feaf1c7dba1bebd9a774c5fd6041f24873afd6e4fe6e2e93db77f96f04428dc8f66831960a6122c81e8a6095428f8b94
03b7d16572d1c71e629645c311078ca3cfbdd15b752de69ac606d9b0076f8373ca 04b7d16572d1c71e629645c311078ca3cfbdd15b752de69ac606d9b0076f8373ca90d73ee0e478d1f9440ce9ae6a08d65d35a7f0c3b1b34d14e7d1bce7f51b3fc1
0227216fdb90bd046064c3b93d10270a047233d17073ec6dae0ece6fe5d5f3942c 0427216fdb90bd046064c3b93d10270a047233d17073ec6dae0ece6fe5d5f3942c4813f1e70df2d6222bc3c5fd822cd750ed63bc899651f89fe39d6630999360e4
033b9934491df1cd5308886498dcc2be62a7a38093a372dd9355d45625a50c5407 043b9934491df1cd5308886498dcc2be62a7a38093a372dd9355d45625a50c54075b2d3d5e12b0c892016f9d30e44f98fad0e9bf35ee6897b9278fabad3eb6f9ab
0236bd119cd3471b5dab8599b0963fafa39972139a9c0cf11d57ff88e4449c15ce 0436bd119cd3471b5dab8599b0963fafa39972139a9c0cf11d57ff88e4449c15ceecea8c7018281b1b7efe9571623a1656e929999064a8a38288e743158645b638
03dfacf1392ee2a08655897f64563cdbbc9f8d700425f5d47a789fdbab028061db 04dfacf1392ee2a08655897f64563cdbbc9f8d700425f5d47a789fdbab028061dbd5c479f1e6fc35d3db8088791a740b52d0324a034e76789b01f813d75aac184d
0375bb11d9936856d2a081847bf121cf6ba4b687ca1ed890e46662ec26d626514b 0475bb11d9936856d2a081847bf121cf6ba4b687ca1ed890e46662ec26d626514b8f517daf3b05802849bfd51d23b60104c185be840bd481289800b957aa1bbc3d
02d4524b803c225a177449263b024bb6b2b7196fed3cb6905dbe02f9a54b4cfa53 04d4524b803c225a177449263b024bb6b2b7196fed3cb6905dbe02f9a54b4cfa53529f8e7328cdf85fca6727e4d44e45402d43480e65c11117ae0041aa8978a1c4
03d71a03b483720655d327983a64dbedf6f3d4b29a0545907e8894a9d575d5e004 04d71a03b483720655d327983a64dbedf6f3d4b29a0545907e8894a9d575d5e0046c7bfc0f84767f43ddc51015469aa09108ca1b1369305c3430f6651b245c415d
0284ef6b14ba3accb84d467c5f39c3d6bee2b1b972f260283ef29a3391ff44cc92 0484ef6b14ba3accb84d467c5f39c3d6bee2b1b972f260283ef29a3391ff44cc92e191dd65da677a85c858795c6995a164a2c4c35ccd27dfdd7f14af515e679b4a
02afb52737d6ffc033455fcd93aac81b7f9744fdcb6393553a8c1ab5f0c7540f2e 04afb52737d6ffc033455fcd93aac81b7f9744fdcb6393553a8c1ab5f0c7540f2ec78c5e51b4eb89dab380cc62912d861084ad587b7530f6276a37ad206adfea4e
03e872311ae7200f33bff94d33159596e716a5d149547d4c8b5cc0319e69272006 04e872311ae7200f33bff94d33159596e716a5d149547d4c8b5cc0319e69272006fdf7c325e3e06e9fd666afb0af6e280d461a608e04614a2921a6d5ab41fc2491
0204f555a02d8e439e216f6f906ecb3f18a3156ac27a52b8be50241e94a4ad1b5b 0404f555a02d8e439e216f6f906ecb3f18a3156ac27a52b8be50241e94a4ad1b5be4f1c6ca003b968f1c34d055d4fb2d7bbdc152f2632dde308b0c08ba64e1636e
02f38ef3d039a01f254dfea5c526cd7fbac66ba4f119f4f079b023b358c966c88f 04f38ef3d039a01f254dfea5c526cd7fbac66ba4f119f4f079b023b358c966c88fc67031c67a9698df456693055b1e7f5905180f6d4f1ac050dd599d87614acd72
03e68a481b261229bc326522334573acedc08def4e27156625b67fc3618ab37865 04e68a481b261229bc326522334573acedc08def4e27156625b67fc3618ab37865fc00b314a85033f24e610fce633d3f0034dc07ced7bab805ddd4882ba385a411
037edc3ad44ab06b71a8c15cce4cf366411cd24d4017b4195a757aadf71b2bf79e 047edc3ad44ab06b71a8c15cce4cf366411cd24d4017b4195a757aadf71b2bf79e0ce8524931e85be88aef99081775e20140c19d8b62075e6216f211c5d977c3eb
029c864308910b3ac3856e71c1261018fff180f0340c19addfb62d277ccb6ae730 049c864308910b3ac3856e71c1261018fff180f0340c19addfb62d277ccb6ae73073625826e7e8cae06cbed7384ae158c584f7ce49e65f859da5ed3b8fada338de
02d7ca55e58d070e78126bb3bd2ed75825627775c9fddd032d35082c15131deebd 04d7ca55e58d070e78126bb3bd2ed75825627775c9fddd032d35082c15131deebd419621117f642ebdebf3d284ddaf8b10bbf601759ea6943032981b0240001f00
02ef9af103205ed92432df2a7d07241615a6566f80743fb5673bb6d6dee5d8b4f1 04ef9af103205ed92432df2a7d07241615a6566f80743fb5673bb6d6dee5d8b4f1e0e321db29fa0c9d550fcb08aed871ee6d9d25f670f5bbfad973048033db6cea
03ad7aaf4595b3afbf432cded4e394583d093b6c25049e5f3134c95358e3588745 04ad7aaf4595b3afbf432cded4e394583d093b6c25049e5f3134c95358e35887458a6dae6d5614abd980f56245ee45975ad72957bd800b6e0335382c2a59ed91c9
03ddb8447d948936dd4760cec2dd6cd273c7cf50ca4d5d381044b36ec8741b22c5 04ddb8447d948936dd4760cec2dd6cd273c7cf50ca4d5d381044b36ec8741b22c5a008a1b0cb8e41a1a376db4cf750bdd93b5dabb1458b58555c22de3d11693321
02a510ab53586dd366388ce5e83dd566dfa036fa5cea5b2ac50c0470ec39d952d5 04a510ab53586dd366388ce5e83dd566dfa036fa5cea5b2ac50c0470ec39d952d5715d568b37ecc1f1d2073482cb6fe48d5e44b03ac7340fcd04d8e0785461d20e
03f76ffb506b5757398a43d41ab98d2613b0df0e4637e3d266278395a7b578d09c 04f76ffb506b5757398a43d41ab98d2613b0df0e4637e3d266278395a7b578d09c0be238cfd2b54079d47ab5db419bba96c44ea0f7fce5a01a79da2c432c398597
02ca39a54157c35b04b1fee81710a867ed862fa279e2302662a720c8f46c5b4d7b 04ca39a54157c35b04b1fee81710a867ed862fa279e2302662a720c8f46c5b4d7b6bc7d7f2d980e86cac28bb5b63076a0dd0aa5fae87fa302d9fd4ad1e7c15269a
02ede8c8e81369cfeb0abb53de9511896d2d7c9e8e5ed40928bd356d7287c5d9b8 04ede8c8e81369cfeb0abb53de9511896d2d7c9e8e5ed40928bd356d7287c5d9b8bd74498e1cfb9b6d96bfe31c13179af6d92b84700353351d372939fe0c7eb41e
03920a3695485fd70304b37ebb7d8ee72c27d9052bdc1c59e1224cd9fa6124fc44 04920a3695485fd70304b37ebb7d8ee72c27d9052bdc1c59e1224cd9fa6124fc443281843227790e8f3ba432d58b32d0a156e6547f8b41ffa747b922abb709be55
0347d1765f1a5627a8c16041bbdf14d88abfbefed90aa8672ead83a6eff3b9f2e7 0447d1765f1a5627a8c16041bbdf14d88abfbefed90aa8672ead83a6eff3b9f2e7db8669de83cfb8c20454dc2197875c5bcfb499c47bd227c28a61d569bc02bf7f
0215f893d55929a8a101be21c6071f706d1be874af95a33eea23b7fc7a283d6f75 0415f893d55929a8a101be21c6071f706d1be874af95a33eea23b7fc7a283d6f759f1cf84d6b9bbd6bc97c41256b1f12a12ffacd00a1f915a92567318260ee3b38
027bd4d04d02759b7cddb134d6eb88b9ef54ea950c42b929b050e431e32dcc4276 047bd4d04d02759b7cddb134d6eb88b9ef54ea950c42b929b050e431e32dcc42768569e2c75663956d932c9ab6af8e33dd1b5922100ccd86b74065ca187da18e4a
022c5062793956267056d8420aff1e7628533cf9d0e4d30416aea06c8ffa57075a 042c5062793956267056d8420aff1e7628533cf9d0e4d30416aea06c8ffa57075ae55c7e00e8d3502960abc07df0462bac678d50fa0283423b6501c5cf384b4292
03d9e8fdea0f739a5a67585c801e24b8ae5f528e64ca9268ac2703dd96ef9640f3 04d9e8fdea0f739a5a67585c801e24b8ae5f528e64ca9268ac2703dd96ef9640f32f4e6e1c4780e7ee0e24b03edb514a1eb42b9311ae69f15c2933ea4bf1993e5b
02fa1e16af956474cdb52eb069012813ebfe508ac50e16bb7bef6c2233605c3709 04fa1e16af956474cdb52eb069012813ebfe508ac50e16bb7bef6c2233605c37093780172eeb613c2c19836f63bba7d7ac164420130c7d71dd06bd11e00f465db4
0361b28c079e403ec070efe4247ca22c652f4feee414cc361b1a70b6c8bd753f48 0461b28c079e403ec070efe4247ca22c652f4feee414cc361b1a70b6c8bd753f4890e76066c3a07d6514dab89784b7847d3967ea77e70322373cb485313c13f009
0347cbf63b2849c894f9c22660c766034226ac6c61ae76b220b5df7831cc9b9e0b 0447cbf63b2849c894f9c22660c766034226ac6c61ae76b220b5df7831cc9b9e0b91a3017cb6a8ed5744bbb30af37d984209a489f94c4c85629cfa1ef7ff3f5131
03a452116d43720f3fd28243e2a114ff145f8475016b34a378af021946e2a3f87b 04a452116d43720f3fd28243e2a114ff145f8475016b34a378af021946e2a3f87b28649a7d5a2559a5092d52c697c66aa04beb7f5d1ddc171003e50dea58b6674d
032a9c89f590aba176ef0d1a69dab1121fdf4d925900d3fa58676267b02c538567 042a9c89f590aba176ef0d1a69dab1121fdf4d925900d3fa58676267b02c5385672974e58f4b1073c60c89e2e7d1a1d39494cbe10e3fcfa2ed07843c078cc1af07
03385b50a489bebc64d8b989c55756ab8db18cbc9bedb3119d020de02ea728b8f0 04385b50a489bebc64d8b989c55756ab8db18cbc9bedb3119d020de02ea728b8f03dd3d75614a806a8aa9e691bfcb8e407e3b60713d2dea8209e577647ce502bb3
036b54187fd9bbbfa4839f0a8cd22117bb25c32d0488005efd2932748ca6b170b4 046b54187fd9bbbfa4839f0a8cd22117bb25c32d0488005efd2932748ca6b170b42776916233d8ebb1e7f8ced8ed49dded5c5431891f4cada816bd09f77ab965b1
03b02a39d64581de4644a9dabf7b82d39e56ab3451325be2d6297ef04bd41ae8d4 04b02a39d64581de4644a9dabf7b82d39e56ab3451325be2d6297ef04bd41ae8d4a35e244188dbf0bf733089259d4806eb6e6c7e9b623af719e6aec28a23e18301
0301df71ddf8bffee835dcaf0c8d40625b297b972fc65c9fc528bde11782f78056 0401df71ddf8bffee835dcaf0c8d40625b297b972fc65c9fc528bde11782f780569ec37a656613d99f2a5b828def9e7d9997766077f6dc734802e99e6458ba211f
03719a27faa6d659cbb05a19f8e194ee393b19ad2be8975a459afa67ff1e83f60f 04719a27faa6d659cbb05a19f8e194ee393b19ad2be8975a459afa67ff1e83f60fee4cb7b2dc564a9bf1646fe947d7f0a03b5e86a8824211d0ff81e092928612af
02c59315d3c212c3f5fac3c543f123e01a84968700563387838093b713255bc719 04c59315d3c212c3f5fac3c543f123e01a84968700563387838093b713255bc719ed2cdb661626657ed5dd4952a740ec3479c0f8c0c002c554b064ec61bc2d229e
036f7a6354b572e5d916977036a05080e8f1b4d4b9318ff01e2d34d1c2d23d74a8 046f7a6354b572e5d916977036a05080e8f1b4d4b9318ff01e2d34d1c2d23d74a80becc560cd7e25710dba8b091629bfd187baafcdfefedf85d571411ac00e0073
03171895c9e5014231367bcc5a4dfa7a627130766c8ee156be591f08406aad0559 04171895c9e5014231367bcc5a4dfa7a627130766c8ee156be591f08406aad05598dc268607c44ae9d4b778e33ae1c4a9df1b4e861c62007c3521f2973f3321ef7
027cea24324d9a75b087b0e4edfe9010e4344b82d031ea5aada98b76d8e3be195d 047cea24324d9a75b087b0e4edfe9010e4344b82d031ea5aada98b76d8e3be195d16eb15dc757870c79b18bc0ed6a73957ff1b0c0c0b453d92e37a950c1747fc26
02242dda2b724f4d591656be1385e1fa12b0f14058f018bfec4d43ff381de4fa71 04242dda2b724f4d591656be1385e1fa12b0f14058f018bfec4d43ff381de4fa712552b2a971ca452b757c9b50bb21c79d3cccfeb5b6959adf2d03c7007d4e630c
03c2966edf6fbc5d4fac3374bb2efa742866b172f7615e0bd344da40802e8d5f19 04c2966edf6fbc5d4fac3374bb2efa742866b172f7615e0bd344da40802e8d5f192e50a8745d87bcbd60d5f4e66615bb5f73399eea3aa831e510c91a614e7c0bb7
03762c522915bbf095256a81d5e4f727e5de10adeefae46a29aa145245cdfeb1aa 04762c522915bbf095256a81d5e4f727e5de10adeefae46a29aa145245cdfeb1aaf38fe17a77bea18c35f8597a58e3b5581c35ccfe07cd66b61c20b1858c21c905
03eae5e964c71aad0103e47ad1c51dfd176dc79d7723065809b9030898ced99138 04eae5e964c71aad0103e47ad1c51dfd176dc79d7723065809b9030898ced99138c34a46c6f2585b6760b04516323d89e01d7a3af1df27e84df18dfa58973c823d

*edit: some text was cut off*

Good Day. This sryptic is worked ? Then i divide 30 bytes, I got only 109 pubkeys (((

[WanderingPhilospher]

This was previously posted in this thread but deleted for some reason, it's a snippet from iceland2k14's Github that divides a pubkey by an arbitrary number and returning all the parts in between. I polished it a bit to print the compressed and uncompressed keys: https://gist.github.com/ZenulAbidin/286a652b160086b3b0f184a886ba68ca

Here's the script output when called with a random (uninteresting - with no balance) pubkey, divided by 48. The keys divided by 0, 1, 2, 3 and so on are printed in order:

Code:

>>> shiftdown("0267830f83723fa565ccb8677c14d13f7d47bf1008fea826833359f27f866632ab", 48)
023f81e98df59d891264d3fca9bca16552feaf1c7dba1bebd9a774c5fd6041f248 043f81e98df59d891264d3fca9bca16552feaf1c7dba1bebd9a774c5fd6041f24873afd6e4fe6e2e93db77f96f04428dc8f66831960a6122c81e8a6095428f8b94
03b7d16572d1c71e629645c311078ca3cfbdd15b752de69ac606d9b0076f8373ca 04b7d16572d1c71e629645c311078ca3cfbdd15b752de69ac606d9b0076f8373ca90d73ee0e478d1f9440ce9ae6a08d65d35a7f0c3b1b34d14e7d1bce7f51b3fc1
0227216fdb90bd046064c3b93d10270a047233d17073ec6dae0ece6fe5d5f3942c 0427216fdb90bd046064c3b93d10270a047233d17073ec6dae0ece6fe5d5f3942c4813f1e70df2d6222bc3c5fd822cd750ed63bc899651f89fe39d6630999360e4
033b9934491df1cd5308886498dcc2be62a7a38093a372dd9355d45625a50c5407 043b9934491df1cd5308886498dcc2be62a7a38093a372dd9355d45625a50c54075b2d3d5e12b0c892016f9d30e44f98fad0e9bf35ee6897b9278fabad3eb6f9ab
0236bd119cd3471b5dab8599b0963fafa39972139a9c0cf11d57ff88e4449c15ce 0436bd119cd3471b5dab8599b0963fafa39972139a9c0cf11d57ff88e4449c15ceecea8c7018281b1b7efe9571623a1656e929999064a8a38288e743158645b638
03dfacf1392ee2a08655897f64563cdbbc9f8d700425f5d47a789fdbab028061db 04dfacf1392ee2a08655897f64563cdbbc9f8d700425f5d47a789fdbab028061dbd5c479f1e6fc35d3db8088791a740b52d0324a034e76789b01f813d75aac184d
0375bb11d9936856d2a081847bf121cf6ba4b687ca1ed890e46662ec26d626514b 0475bb11d9936856d2a081847bf121cf6ba4b687ca1ed890e46662ec26d626514b8f517daf3b05802849bfd51d23b60104c185be840bd481289800b957aa1bbc3d
02d4524b803c225a177449263b024bb6b2b7196fed3cb6905dbe02f9a54b4cfa53 04d4524b803c225a177449263b024bb6b2b7196fed3cb6905dbe02f9a54b4cfa53529f8e7328cdf85fca6727e4d44e45402d43480e65c11117ae0041aa8978a1c4
03d71a03b483720655d327983a64dbedf6f3d4b29a0545907e8894a9d575d5e004 04d71a03b483720655d327983a64dbedf6f3d4b29a0545907e8894a9d575d5e0046c7bfc0f84767f43ddc51015469aa09108ca1b1369305c3430f6651b245c415d
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02f38ef3d039a01f254dfea5c526cd7fbac66ba4f119f4f079b023b358c966c88f 04f38ef3d039a01f254dfea5c526cd7fbac66ba4f119f4f079b023b358c966c88fc67031c67a9698df456693055b1e7f5905180f6d4f1ac050dd599d87614acd72
03e68a481b261229bc326522334573acedc08def4e27156625b67fc3618ab37865 04e68a481b261229bc326522334573acedc08def4e27156625b67fc3618ab37865fc00b314a85033f24e610fce633d3f0034dc07ced7bab805ddd4882ba385a411
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029c864308910b3ac3856e71c1261018fff180f0340c19addfb62d277ccb6ae730 049c864308910b3ac3856e71c1261018fff180f0340c19addfb62d277ccb6ae73073625826e7e8cae06cbed7384ae158c584f7ce49e65f859da5ed3b8fada338de
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02ef9af103205ed92432df2a7d07241615a6566f80743fb5673bb6d6dee5d8b4f1 04ef9af103205ed92432df2a7d07241615a6566f80743fb5673bb6d6dee5d8b4f1e0e321db29fa0c9d550fcb08aed871ee6d9d25f670f5bbfad973048033db6cea
03ad7aaf4595b3afbf432cded4e394583d093b6c25049e5f3134c95358e3588745 04ad7aaf4595b3afbf432cded4e394583d093b6c25049e5f3134c95358e35887458a6dae6d5614abd980f56245ee45975ad72957bd800b6e0335382c2a59ed91c9
03ddb8447d948936dd4760cec2dd6cd273c7cf50ca4d5d381044b36ec8741b22c5 04ddb8447d948936dd4760cec2dd6cd273c7cf50ca4d5d381044b36ec8741b22c5a008a1b0cb8e41a1a376db4cf750bdd93b5dabb1458b58555c22de3d11693321
02a510ab53586dd366388ce5e83dd566dfa036fa5cea5b2ac50c0470ec39d952d5 04a510ab53586dd366388ce5e83dd566dfa036fa5cea5b2ac50c0470ec39d952d5715d568b37ecc1f1d2073482cb6fe48d5e44b03ac7340fcd04d8e0785461d20e
03f76ffb506b5757398a43d41ab98d2613b0df0e4637e3d266278395a7b578d09c 04f76ffb506b5757398a43d41ab98d2613b0df0e4637e3d266278395a7b578d09c0be238cfd2b54079d47ab5db419bba96c44ea0f7fce5a01a79da2c432c398597
02ca39a54157c35b04b1fee81710a867ed862fa279e2302662a720c8f46c5b4d7b 04ca39a54157c35b04b1fee81710a867ed862fa279e2302662a720c8f46c5b4d7b6bc7d7f2d980e86cac28bb5b63076a0dd0aa5fae87fa302d9fd4ad1e7c15269a
02ede8c8e81369cfeb0abb53de9511896d2d7c9e8e5ed40928bd356d7287c5d9b8 04ede8c8e81369cfeb0abb53de9511896d2d7c9e8e5ed40928bd356d7287c5d9b8bd74498e1cfb9b6d96bfe31c13179af6d92b84700353351d372939fe0c7eb41e
03920a3695485fd70304b37ebb7d8ee72c27d9052bdc1c59e1224cd9fa6124fc44 04920a3695485fd70304b37ebb7d8ee72c27d9052bdc1c59e1224cd9fa6124fc443281843227790e8f3ba432d58b32d0a156e6547f8b41ffa747b922abb709be55
0347d1765f1a5627a8c16041bbdf14d88abfbefed90aa8672ead83a6eff3b9f2e7 0447d1765f1a5627a8c16041bbdf14d88abfbefed90aa8672ead83a6eff3b9f2e7db8669de83cfb8c20454dc2197875c5bcfb499c47bd227c28a61d569bc02bf7f
0215f893d55929a8a101be21c6071f706d1be874af95a33eea23b7fc7a283d6f75 0415f893d55929a8a101be21c6071f706d1be874af95a33eea23b7fc7a283d6f759f1cf84d6b9bbd6bc97c41256b1f12a12ffacd00a1f915a92567318260ee3b38
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03d9e8fdea0f739a5a67585c801e24b8ae5f528e64ca9268ac2703dd96ef9640f3 04d9e8fdea0f739a5a67585c801e24b8ae5f528e64ca9268ac2703dd96ef9640f32f4e6e1c4780e7ee0e24b03edb514a1eb42b9311ae69f15c2933ea4bf1993e5b
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0361b28c079e403ec070efe4247ca22c652f4feee414cc361b1a70b6c8bd753f48 0461b28c079e403ec070efe4247ca22c652f4feee414cc361b1a70b6c8bd753f4890e76066c3a07d6514dab89784b7847d3967ea77e70322373cb485313c13f009
0347cbf63b2849c894f9c22660c766034226ac6c61ae76b220b5df7831cc9b9e0b 0447cbf63b2849c894f9c22660c766034226ac6c61ae76b220b5df7831cc9b9e0b91a3017cb6a8ed5744bbb30af37d984209a489f94c4c85629cfa1ef7ff3f5131
03a452116d43720f3fd28243e2a114ff145f8475016b34a378af021946e2a3f87b 04a452116d43720f3fd28243e2a114ff145f8475016b34a378af021946e2a3f87b28649a7d5a2559a5092d52c697c66aa04beb7f5d1ddc171003e50dea58b6674d
032a9c89f590aba176ef0d1a69dab1121fdf4d925900d3fa58676267b02c538567 042a9c89f590aba176ef0d1a69dab1121fdf4d925900d3fa58676267b02c5385672974e58f4b1073c60c89e2e7d1a1d39494cbe10e3fcfa2ed07843c078cc1af07
03385b50a489bebc64d8b989c55756ab8db18cbc9bedb3119d020de02ea728b8f0 04385b50a489bebc64d8b989c55756ab8db18cbc9bedb3119d020de02ea728b8f03dd3d75614a806a8aa9e691bfcb8e407e3b60713d2dea8209e577647ce502bb3
036b54187fd9bbbfa4839f0a8cd22117bb25c32d0488005efd2932748ca6b170b4 046b54187fd9bbbfa4839f0a8cd22117bb25c32d0488005efd2932748ca6b170b42776916233d8ebb1e7f8ced8ed49dded5c5431891f4cada816bd09f77ab965b1
03b02a39d64581de4644a9dabf7b82d39e56ab3451325be2d6297ef04bd41ae8d4 04b02a39d64581de4644a9dabf7b82d39e56ab3451325be2d6297ef04bd41ae8d4a35e244188dbf0bf733089259d4806eb6e6c7e9b623af719e6aec28a23e18301
0301df71ddf8bffee835dcaf0c8d40625b297b972fc65c9fc528bde11782f78056 0401df71ddf8bffee835dcaf0c8d40625b297b972fc65c9fc528bde11782f780569ec37a656613d99f2a5b828def9e7d9997766077f6dc734802e99e6458ba211f
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036f7a6354b572e5d916977036a05080e8f1b4d4b9318ff01e2d34d1c2d23d74a8 046f7a6354b572e5d916977036a05080e8f1b4d4b9318ff01e2d34d1c2d23d74a80becc560cd7e25710dba8b091629bfd187baafcdfefedf85d571411ac00e0073
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027cea24324d9a75b087b0e4edfe9010e4344b82d031ea5aada98b76d8e3be195d 047cea24324d9a75b087b0e4edfe9010e4344b82d031ea5aada98b76d8e3be195d16eb15dc757870c79b18bc0ed6a73957ff1b0c0c0b453d92e37a950c1747fc26
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03762c522915bbf095256a81d5e4f727e5de10adeefae46a29aa145245cdfeb1aa 04762c522915bbf095256a81d5e4f727e5de10adeefae46a29aa145245cdfeb1aaf38fe17a77bea18c35f8597a58e3b5581c35ccfe07cd66b61c20b1858c21c905
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*edit: some text was cut off*

Good Day. This sryptic is worked ? Then i divide 30 bytes, I got only 109 pubkeys (((

Yes it works, can't help you if we don't know how you ran the script.  30 bytes doesn't make sense, should be in integers with this script.

[COBRAS]

This was previously posted in this thread but deleted for some reason, it's a snippet from iceland2k14's Github that divides a pubkey by an arbitrary number and returning all the parts in between. I polished it a bit to print the compressed and uncompressed keys: https://gist.github.com/ZenulAbidin/286a652b160086b3b0f184a886ba68ca

Here's the script output when called with a random (uninteresting - with no balance) pubkey, divided by 48. The keys divided by 0, 1, 2, 3 and so on are printed in order:

Code:

>>> shiftdown("0267830f83723fa565ccb8677c14d13f7d47bf1008fea826833359f27f866632ab", 48)
023f81e98df59d891264d3fca9bca16552feaf1c7dba1bebd9a774c5fd6041f248 043f81e98df59d891264d3fca9bca16552feaf1c7dba1bebd9a774c5fd6041f24873afd6e4fe6e2e93db77f96f04428dc8f66831960a6122c81e8a6095428f8b94
03b7d16572d1c71e629645c311078ca3cfbdd15b752de69ac606d9b0076f8373ca 04b7d16572d1c71e629645c311078ca3cfbdd15b752de69ac606d9b0076f8373ca90d73ee0e478d1f9440ce9ae6a08d65d35a7f0c3b1b34d14e7d1bce7f51b3fc1
0227216fdb90bd046064c3b93d10270a047233d17073ec6dae0ece6fe5d5f3942c 0427216fdb90bd046064c3b93d10270a047233d17073ec6dae0ece6fe5d5f3942c4813f1e70df2d6222bc3c5fd822cd750ed63bc899651f89fe39d6630999360e4
033b9934491df1cd5308886498dcc2be62a7a38093a372dd9355d45625a50c5407 043b9934491df1cd5308886498dcc2be62a7a38093a372dd9355d45625a50c54075b2d3d5e12b0c892016f9d30e44f98fad0e9bf35ee6897b9278fabad3eb6f9ab
0236bd119cd3471b5dab8599b0963fafa39972139a9c0cf11d57ff88e4449c15ce 0436bd119cd3471b5dab8599b0963fafa39972139a9c0cf11d57ff88e4449c15ceecea8c7018281b1b7efe9571623a1656e929999064a8a38288e743158645b638
03dfacf1392ee2a08655897f64563cdbbc9f8d700425f5d47a789fdbab028061db 04dfacf1392ee2a08655897f64563cdbbc9f8d700425f5d47a789fdbab028061dbd5c479f1e6fc35d3db8088791a740b52d0324a034e76789b01f813d75aac184d
0375bb11d9936856d2a081847bf121cf6ba4b687ca1ed890e46662ec26d626514b 0475bb11d9936856d2a081847bf121cf6ba4b687ca1ed890e46662ec26d626514b8f517daf3b05802849bfd51d23b60104c185be840bd481289800b957aa1bbc3d
02d4524b803c225a177449263b024bb6b2b7196fed3cb6905dbe02f9a54b4cfa53 04d4524b803c225a177449263b024bb6b2b7196fed3cb6905dbe02f9a54b4cfa53529f8e7328cdf85fca6727e4d44e45402d43480e65c11117ae0041aa8978a1c4
03d71a03b483720655d327983a64dbedf6f3d4b29a0545907e8894a9d575d5e004 04d71a03b483720655d327983a64dbedf6f3d4b29a0545907e8894a9d575d5e0046c7bfc0f84767f43ddc51015469aa09108ca1b1369305c3430f6651b245c415d
0284ef6b14ba3accb84d467c5f39c3d6bee2b1b972f260283ef29a3391ff44cc92 0484ef6b14ba3accb84d467c5f39c3d6bee2b1b972f260283ef29a3391ff44cc92e191dd65da677a85c858795c6995a164a2c4c35ccd27dfdd7f14af515e679b4a
02afb52737d6ffc033455fcd93aac81b7f9744fdcb6393553a8c1ab5f0c7540f2e 04afb52737d6ffc033455fcd93aac81b7f9744fdcb6393553a8c1ab5f0c7540f2ec78c5e51b4eb89dab380cc62912d861084ad587b7530f6276a37ad206adfea4e
03e872311ae7200f33bff94d33159596e716a5d149547d4c8b5cc0319e69272006 04e872311ae7200f33bff94d33159596e716a5d149547d4c8b5cc0319e69272006fdf7c325e3e06e9fd666afb0af6e280d461a608e04614a2921a6d5ab41fc2491
0204f555a02d8e439e216f6f906ecb3f18a3156ac27a52b8be50241e94a4ad1b5b 0404f555a02d8e439e216f6f906ecb3f18a3156ac27a52b8be50241e94a4ad1b5be4f1c6ca003b968f1c34d055d4fb2d7bbdc152f2632dde308b0c08ba64e1636e
02f38ef3d039a01f254dfea5c526cd7fbac66ba4f119f4f079b023b358c966c88f 04f38ef3d039a01f254dfea5c526cd7fbac66ba4f119f4f079b023b358c966c88fc67031c67a9698df456693055b1e7f5905180f6d4f1ac050dd599d87614acd72
03e68a481b261229bc326522334573acedc08def4e27156625b67fc3618ab37865 04e68a481b261229bc326522334573acedc08def4e27156625b67fc3618ab37865fc00b314a85033f24e610fce633d3f0034dc07ced7bab805ddd4882ba385a411
037edc3ad44ab06b71a8c15cce4cf366411cd24d4017b4195a757aadf71b2bf79e 047edc3ad44ab06b71a8c15cce4cf366411cd24d4017b4195a757aadf71b2bf79e0ce8524931e85be88aef99081775e20140c19d8b62075e6216f211c5d977c3eb
029c864308910b3ac3856e71c1261018fff180f0340c19addfb62d277ccb6ae730 049c864308910b3ac3856e71c1261018fff180f0340c19addfb62d277ccb6ae73073625826e7e8cae06cbed7384ae158c584f7ce49e65f859da5ed3b8fada338de
02d7ca55e58d070e78126bb3bd2ed75825627775c9fddd032d35082c15131deebd 04d7ca55e58d070e78126bb3bd2ed75825627775c9fddd032d35082c15131deebd419621117f642ebdebf3d284ddaf8b10bbf601759ea6943032981b0240001f00
02ef9af103205ed92432df2a7d07241615a6566f80743fb5673bb6d6dee5d8b4f1 04ef9af103205ed92432df2a7d07241615a6566f80743fb5673bb6d6dee5d8b4f1e0e321db29fa0c9d550fcb08aed871ee6d9d25f670f5bbfad973048033db6cea
03ad7aaf4595b3afbf432cded4e394583d093b6c25049e5f3134c95358e3588745 04ad7aaf4595b3afbf432cded4e394583d093b6c25049e5f3134c95358e35887458a6dae6d5614abd980f56245ee45975ad72957bd800b6e0335382c2a59ed91c9
03ddb8447d948936dd4760cec2dd6cd273c7cf50ca4d5d381044b36ec8741b22c5 04ddb8447d948936dd4760cec2dd6cd273c7cf50ca4d5d381044b36ec8741b22c5a008a1b0cb8e41a1a376db4cf750bdd93b5dabb1458b58555c22de3d11693321
02a510ab53586dd366388ce5e83dd566dfa036fa5cea5b2ac50c0470ec39d952d5 04a510ab53586dd366388ce5e83dd566dfa036fa5cea5b2ac50c0470ec39d952d5715d568b37ecc1f1d2073482cb6fe48d5e44b03ac7340fcd04d8e0785461d20e
03f76ffb506b5757398a43d41ab98d2613b0df0e4637e3d266278395a7b578d09c 04f76ffb506b5757398a43d41ab98d2613b0df0e4637e3d266278395a7b578d09c0be238cfd2b54079d47ab5db419bba96c44ea0f7fce5a01a79da2c432c398597
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*edit: some text was cut off*

Good Day. This sryptic is worked ? Then i divide 30 bytes, I got only 109 pubkeys (((

Yes it works, can't help you if we don't know how you ran the script.  30 bytes doesn't make sense, should be in integers with this script.

I try sript with 30 and 34. Then 30 I got 109 pubkeys, then 32 - 137 pubkeys. And Yes - script hard to run, requirements are give me strange errors...

[Minase]

it was just an example (random k generated)

from 120 puzzle we substract the starting range 800000000000000000000000000000 and we obtain the following K 03D943C68C5F958B14524CDBEF68168D6C018E101F4F7074E0C31686384A82F52F

N/2 - above K = 026C25951D1BB97C7DE3020DF0F725487FC33CC1210A155755514B7BF384AACFAD

From this K which is basically N/2 - Puz120 K + START-RANGE we add random K in the interval (0x1 - 7FFFFFFFFFFFFFFFFFFFFFFFFFFFFF)
We compute 10kk points in the range (N/2 - 10kk, N/2), points which cover the following range if we exclude parity (N/2 - 10kk, N/2 + 10kk)
Maybe i will draw something tomorrow for better understanding.

PS: I'm not saying this method will be exponentially "better" but it will double the chances to find k

[WanderingPhilospher]

I try sript with 30 and 34. Then 30 I got 109 pubkeys, then 32 - 137 pubkeys. And Yes - script hard to run, requirements are give me strange errors...

If you are using Python 3.x, all you have to change is:

pubkey = '03a2efa402fd5268400c77c20e574ba86409ededee7c4020e4b9f0edbee53de0d4'

to whatever pubkey you want

and at the bottom

shiftdown(pubkey, 32)

change the 32 to however many pubkeys you want.

[WanderingPhilospher]

it was just an example (random k generated)

from 120 puzzle we substract the starting range 800000000000000000000000000000 and we obtain the following K 03D943C68C5F958B14524CDBEF68168D6C018E101F4F7074E0C31686384A82F52F

N/2 - above K = 026C25951D1BB97C7DE3020DF0F725487FC33CC1210A155755514B7BF384AACFAD

From this K which is basically N/2 - Puz120 K + START-RANGE we add random K in the interval (0x1 - 7FFFFFFFFFFFFFFFFFFFFFFFFFFFFF)
We compute 10kk points in the range (N/2 - 10kk, N/2), points which cover the following range if we exclude parity (N/2 - 10kk, N/2 + 10kk)
Maybe i will draw something tomorrow for better understanding.

PS: I'm not saying this method will be exponentially "better" but it will double the chances to find k

Why subtract the starting range when we are going to be adding back to it? Is there a specific reason for that?

I'd just add 120 pubkey straight to N/2 and then do incremental additions.

In your opinion is it better to start below N/2 and then pass through (above N/2) to kind of straddle N/2 on both sides?

I guess I don't understand the excluding parity/y you mentioned earlier and how each pub doubles chance to find K.

EDIT:  Ok, regardless of start range subtraction (I get it), how does this possibly speed things up? You would still have to search for key from N/2-whatever through N/2 +1, using kangaroo or BSGS or some other key finder, right? I'm interested, I just don't understand how it speeds it up (however small or big), not saying it doesn't, I'm just trying to understand it better. Thanks.

[COBRAS]

I try sript with 30 and 34. Then 30 I got 109 pubkeys, then 32 - 137 pubkeys. And Yes - script hard to run, requirements are give me strange errors...

If you are using Python 3.x, all you have to change is:

pubkey = '03a2efa402fd5268400c77c20e574ba86409ededee7c4020e4b9f0edbee53de0d4'

to whatever pubkey you want

and at the bottom

shiftdown(pubkey, 32)

change the 32 to however many pubkeys you want.

yes, I do it. I try now find a privkey....

edit: I wright understand what 30,32 etc is a power of 2 ? so If we talk about 120 pubkey, then I use this scripts with "30" I will get pubkey diveded by 2^30 ? so result will be "pubkey of 2^90" ?

[WanderingPhilospher]

I try sript with 30 and 34. Then 30 I got 109 pubkeys, then 32 - 137 pubkeys. And Yes - script hard to run, requirements are give me strange errors...

If you are using Python 3.x, all you have to change is:

pubkey = '03a2efa402fd5268400c77c20e574ba86409ededee7c4020e4b9f0edbee53de0d4'

to whatever pubkey you want

and at the bottom

shiftdown(pubkey, 32)

change the 32 to however many pubkeys you want.

yes, I do it. I try now find a privkey....

edit: I wright understand what 30,32 etc is a power of 2 ? so If we talk about 120 pubkey, then I use this scripts with "30" I will get pubkey diveded by 2^30 ? so result will be "pubkey of 2^90" ?

No, I don't think so. The number 32 represents 2^5, so to get down to 2^90, you would need to enter 1073741824 (2^30), NotATether can answer if this is wrong or not

[COBRAS]

I try sript with 30 and 34. Then 30 I got 109 pubkeys, then 32 - 137 pubkeys. And Yes - script hard to run, requirements are give me strange errors...

If you are using Python 3.x, all you have to change is:

pubkey = '03a2efa402fd5268400c77c20e574ba86409ededee7c4020e4b9f0edbee53de0d4'

to whatever pubkey you want

and at the bottom

shiftdown(pubkey, 32)

change the 32 to however many pubkeys you want.

yes, I do it. I try now find a privkey....

edit: I wright understand what 30,32 etc is a power of 2 ? so If we talk about 120 pubkey, then I use this scripts with "30" I will get pubkey diveded by 2^30 ? so result will be "pubkey of 2^90" ?

No, I don't think so. The number 32 represents 2^5, so to get down to 2^90, you would need to enter 1073741824 (2^30), NotATether can answer if this is wrong or not

NotATether, answer please ?

EDIT:

I'm realy not understand how many exact sustracted from pubkey this code:


# This function makes all the downscaled pubkeys obtained from subtracting
# numbers between 0 and divisor, before dividing the pubkeys by divisor.
def shiftdown(pubkey, divisor):
    Q = pub2point(pubkey)
    # k = 1/divisor
    k = pow(divisor, N - 2, N)
    for i in range(divisor+1):
       P = Q - (i * G)
        P = k * P
        if (P.y % 2 == 0):
            prefix = "02"
        else:
            prefix = "03"
        hx = hex(P.x)[2:].zfill(64)
        hy = hex(P.y)[2:].zfill(64)
        print(prefix+hx, "04"+hx+hy)



so, if devisor = 5 this mean a just FIVE not any ^ and 2^5 etc.....

[BitcoinADAB]

Is there a list with devices/cards and related jumps/sec?

What we need are asics

not to mine coins but for more jumps/sec



and

look at this, may be interesting: Calculating Satoshi's coins https://bitcointalk.org/index.php?topic=5347791.0

[COBRAS]

Is there a list with devices/cards and related jumps/sec?

What we need are asics

not to mine coins but for more jumps/sec



and

look at this, may be interesting: Calculating Satoshi's coins https://bitcointalk.org/index.php?topic=5347791.0

Let's go to China ? They can make a BSGS for usb I think. ?

I'm work now with 861 811 060 385 455 217 keys/s but this is not helpful for 120 !!!

[BitcoinADAB]

...

Let's go to China ? They can make a BSGS for usb I think. ?

There is no need at the moment. Only for us to solve #120 #125 ... they wouldn't produce it.

But if we can build that network 'Calculating Satoshi's coins' https://bitcointalk.org/index.php?topic=5347791.0 then it would become interesting to produce it.

[COBRAS]

...

Let's go to China ? They can make a BSGS for usb I think. ?

There is no need at the moment. Only for us to solve #120 #125 ... they wouldn't produce it.

But if we can build that network 'Calculating Satoshi's coins' https://bitcointalk.org/index.php?topic=5347791.0 then it would become interesting to produce it.

Satochi ccoin is a 0.00001 btc per address

[WanderingPhilospher]

NotATether, answer please ?

EDIT:

I'm realy not understand how many exact sustracted from pubkey this code:


# This function makes all the downscaled pubkeys obtained from subtracting
# numbers between 0 and divisor, before dividing the pubkeys by divisor.
def shiftdown(pubkey, divisor):
    Q = pub2point(pubkey)
    # k = 1/divisor
    k = pow(divisor, N - 2, N)
    for i in range(divisor+1):
       P = Q - (i * G)
        P = k * P
        if (P.y % 2 == 0):
            prefix = "02"
        else:
            prefix = "03"
        hx = hex(P.x)[2:].zfill(64)
        hy = hex(P.y)[2:].zfill(64)
        print(prefix+hx, "04"+hx+hy)



so, if devisor = 5 this mean a just FIVE not any ^ and 2^5 etc.....

Cobra, why not just put 5 at the bottom and run it, see if you get 5 or 32 pubkeys?  Put 10 at the bottom and run it, see if you get 10 or 1024 pubkeys...
DO NOT mess with the code up top, I told you the two areas to tweak, pubkey and qty.

[COBRAS]

NotATether, answer please ?

EDIT:

I'm realy not understand how many exact sustracted from pubkey this code:


# This function makes all the downscaled pubkeys obtained from subtracting
# numbers between 0 and divisor, before dividing the pubkeys by divisor.
def shiftdown(pubkey, divisor):
    Q = pub2point(pubkey)
    # k = 1/divisor
    k = pow(divisor, N - 2, N)
    for i in range(divisor+1):
       P = Q - (i * G)
        P = k * P
        if (P.y % 2 == 0):
            prefix = "02"
        else:
            prefix = "03"
        hx = hex(P.x)[2:].zfill(64)
        hy = hex(P.y)[2:].zfill(64)
        print(prefix+hx, "04"+hx+hy)



so, if devisor = 5 this mean a just FIVE not any ^ and 2^5 etc.....

Cobra, why not just put 5 at the bottom and run it, see if you get 5 or 32 pubkeys?  Put 10 at the bottom and run it, see if you get 10 or 1024 pubkeys...
DO NOT mess with the code up top, I told you the two areas to tweak, pubkey and qty.

I was divide 120/30, in ECSPcallc.jar, and not foud pubkey in result of scrip work with param 30... not use this script now.

[batareyka]

Hello everybody.
  Is there a way to check public keys at the same time?
how bitcrack checks addresses.
Maybe a kangaroo is a multi-key or something like that?
Or tell me how you check for example 100,000-1,000,000 keys?
It's unrealistic with your hands.

[WanderingPhilospher]

Hello everybody.
  Is there a way to check public keys at the same time?
how bitcrack checks addresses.
Maybe a kangaroo is a multi-key or something like that?
Or tell me how you check for example 100,000-1,000,000 keys?
It's unrealistic with your hands.

Running Kangaroo, checking pub keys at the same time, not without recoding. Or you can check one for awhile. Stop. Check the next one. Rinse and repeat.

You can use BSGS to check multiple keys in one run, however when you get above the 2^48, 2^52 range, it becomes time consuming. So you can break larger range down into smaller 2^40, 2^44 chunks and it's pretty fast, but if you have 1,000,000 pubkeys, expect an average of 10-15 keys checked per second; 1,000,000 / 15 = 18 hours to check them all (in the smaller range)

Or you can convert your 100,000-1,000,000 keys into addresses and use bitcrack or another brute force type program.

[NotATether]

~

Good Day. This sryptic is worked ? Then i divide 30 bytes, I got only 109 pubkeys (((

That is strange. The for loop guarantees that the number of pubkeys printed should be the number you divided by.

It's kind of impractical for divisor >20 though as your disk space quickly fills up after that.

P.S. I'm not the original script author, it was posted and then deleted by rkvishvam

Hello everybody.
  Is there a way to check public keys at the same time?
how bitcrack checks addresses.
Maybe a kangaroo is a multi-key or something like that?
Or tell me how you check for example 100,000-1,000,000 keys?
It's unrealistic with your hands.

Yeah it's possible. Just put all the keys on one line each in the input file, after the two lines for start and end range.


Edit:

I try sript with 30 and 34. Then 30 I got 109 pubkeys, then 32 - 137 pubkeys. And Yes - script hard to run, requirements are give me strange errors...

If you are using Python 3.x, all you have to change is:

pubkey = '03a2efa402fd5268400c77c20e574ba86409ededee7c4020e4b9f0edbee53de0d4'

to whatever pubkey you want

and at the bottom

shiftdown(pubkey, 32)

change the 32 to however many pubkeys you want.

yes, I do it. I try now find a privkey....

edit: I wright understand what 30,32 etc is a power of 2 ? so If we talk about 120 pubkey, then I use this scripts with "30" I will get pubkey diveded by 2^30 ? so result will be "pubkey of 2^90" ?

No, I don't think so. The number 32 represents 2^5, so to get down to 2^90, you would need to enter 1073741824 (2^30), NotATether can answer if this is wrong or not

Don't enter it like that, the divisor also represents the exponent so you have to enter it as 30, maybe that's why you got this strange number (it could also be integer overflow inside the loop).

Wait I think you actually are right, given my example was done with 48 as the divisor which is not a power of two, and to generate the 2^110 shrunk pubkeys I called it with 2**10.