The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE!

[captainnoob]

@Itod, so in your opinion the "The_____iskeyfile" message is the intended message?

Well, I have a theory didn't want to mention before while trying to find the proof. The message "THEfm_aurISKEYFILE" can hardly be a collision, and the bold scrambled part is intentionally left there to be de-scrambled in the same way other bit-streams should be de-scrambled to get a key. If you come across the stream of bytes from private key you may not notice something is scrambled, but if you find something like plaintext quoted above it's pretty obvious something is wrong. So to answer you: yes I think it's intentionally left there scrambled/corrupted to show the way.

Anything can be the way to de-scramble it in a coherent message. The current path I'm working are the chessboard fields affected by Phoenix fire. It looks to me that those chessboard fields that should be dark are somehow lighter with this bright blue Phoenix color then the white ones, so some bits associated with those chessboard fields should be inverted in raw bit-streams. I believe if we invert some bits from the "THEfm_aurISKEYFILE" bit-stream, in this way I've described, we will get coherent message from this bit-stream, and then we should apply this same transformation to colors bit-streams to get the private key.

AUR makes me think of Arch User Repository. Maybe there is a package in there that has some information?

Was there more than just this string in the output?

[1714678413]

1714678413

[1714678413]

1714678413

[1714678413]

1714678413

[1714678413]

1714678413

[CompNeuro]

When read according to the drips clockwise, the very start of the decode you get the following word relevant to the painting:
*MPSRI*
Prism.

Can you please elaborate on this? I've been trying to explore decoding via this method over the past day or so, but I haven't had much luck. I also do not understand how DNA/RNA codons are supposed to be paired (I mean obviously in groups of three, but how are you proposing those groups of three be created?). I wrote some more, fairly badly executed, code that can decode the flames based on the amino acids (posted below) and I've tried reading the flames in all sorts of ways, But haven't found anything interesting..., So I'm curious by what you mean according to the drips?


For anyone who wants it.., although I'm sure you could do better, here is my shitty code. To use it for DNA/RNA decypher: ./debacon -f filename -D | less

The File must be a text file containing no more then 16 lines. Also, It doesn't recognize dna/rna codons via the letters atcg or aucg, but instead c is either b or p (depending if you wanna call the color purple or blue), a is o (for orange, maybe it's red, but I think the flames look orange), t or u is y (for yellow), and g is still g (for green)

Sample input for a track of flames: ypygygogyp

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>

void shift(char* string);
int getlines(FILE* stream, char** line, ssize_t* nread, int* ntot, size_t len);
char* normalize(char* string, int nflag);
void clean(char* string);
void divideString(char* string, int n);
void debacon(char* string, int btype);
void flip(char* string);
void deHex(char* string);
void deRNA(char* string);
int verbose = 0;


int main(int argc, char* argv[]){
	FILE* scram;
	int opt;
	int fcheck = 0;
	int nflag = 0;
	int btype = 0;
	int bitflip = 0;
	char** line = malloc(sizeof(char *) * 16);
	int i = 0;
	int j = 0;
	int k = 0;
	size_t len = 0;
	ssize_t nread[16];
	int ntot = 0;
	char buffer[1024];
	char temp[1024];
	int runBacon = 0;
	int runHex = 0;
	int runDNA = 0;

	while((opt = getopt(argc, argv, "hvf:a:n:i:HBD")) != -1){
		switch(opt){
			case 'h':
				printf("\nUSAGE: ./decode -f path_to_input_file type_of_decode options\n");
				printf("OPTIONS: -f [FILENAME] to specify input file\n");
				printf("OPTIONS: -v for verbose mode\n");
				printf("OPTIONS: -a [a or b] to specify which type of bacon alphebet (Bacon Cypher Only)\n");
				printf("OPTIONS: -n [0 or 1 or 2 or 3] to specify how the bitstring should be read\n");
				printf("OPTIONS: -i [t or f] to specify how 0's and 1's are read from the bitstring\n");
				printf("OPTIONS: -B for Bacon Cypher\n");
				printf("OPTIONS: -H for HEX conversion\n");
				printf("OPTIONS: -D for DNA RNA Stop Codon Cypher\n");
				printf("OPTIONS: -h displays this menu\n");
				printf("\nEXAMPLE: ./decode -f file -B -a b -n 2 -i f -v\n");
				exit(EXIT_SUCCESS);
			case 'f':
				scram = fopen(optarg, "r");
				fcheck = 1;
				break;
			case 'v':
				printf("\nTurning on Verbose Mode...\n");
				verbose = 1;
				break;
			case 'a':
				if(optarg[0] == 'a' || optarg[0] == 'A'){
					btype = 0;
				} else if(optarg[0] == 'b' || optarg[0] == 'B'){
					btype = 1;
				} else{
					printf("\nERROR: Invalid argument for for -a option, must be a or b\n");
					exit(EXIT_FAILURE);
				}
				break;
			case 'n':
				if(atoi(optarg) < 4){
					nflag = atoi(optarg);
				} else{
					printf("\nERROR: Invalid argument for -n option, must be 0, 1, 2, or 3\n");
				}
				break;
			case 'i':
				if(optarg[0] == 't' || optarg[0] == 'T'){
					bitflip = 1;
				}
				break;
			case 'B':
				if(runHex == 1){
					printf("\nERROR: Cannot run Bacon Cypher and Hex conversion together\n");
					exit(EXIT_FAILURE);
				} else if(runDNA == 1){
					printf("\nERROR: Cannot run Bacon Cypher and DNA RNA conversion together\n");
					exit(EXIT_FAILURE);
				} else{
					runBacon = 1;
				}
				break;
			case 'H':
				if(runBacon == 1){
					printf("\nERROR: Cannot run Bacon Cypher and Hex conversion together\n");
					exit(EXIT_FAILURE);
				} else if(runDNA== 1){
					printf("\nERROR: Cannot run DNA RNA Cypher and Hex conversion together\n");
					exit(EXIT_FAILURE);
				} else{
					runHex = 1;
				}
				break;
			case 'D':
				if(runHex == 1){
					printf("\nERROR: Cannot run Hex conversion and DNA RNA Cypher together\n");
					exit(EXIT_FAILURE);
				} else if(runBacon == 1){
					printf("\nERROR: Cannot run Bacon Cypher and DNA RNA Cypher together\n");
					exit(EXIT_FAILURE);
				} else{
					runDNA = 1;
				}
				break;
			default:
				printf("ERROR: Unrecognized option, try -h\n");
				exit(EXIT_FAILURE);
		}
	}

	if(fcheck == 0){
		printf("ERROR: Must specify input file, try -h\n");
		exit(EXIT_FAILURE);
	} else if(argc <=3){
		printf("ERROR: Must specify -H, -B, or -D.., try -h for help\n");
	}

	i = getlines(scram, line, nread, &ntot, len);
	
	if(verbose == 1){
		for(j = 0; j < i; j++){
			printf("Retrieved line of length %zu:\n", nread[j]);
			printf("line %i is: %s\n", j, line[j]);
		}
		printf("Total Characters Read: %i\n\n", ntot);
		j = 0;
	}

	if(runDNA == 1){
		for(j = 0; j < i; j++){
			line[j] = normalize(line[j], 8);
		}
		j = 1;
		strcpy(buffer, line[0]);
		for(j = 1; j < i; j++){
			strcat(buffer, line[j]);
		}

		if(verbose == 1){
			printf("\nCombined String: %s\n", buffer);
		}

		for(k = 0; k <= strlen(buffer); k++){
			divideString(buffer, 3);
			if(verbose == 1){
				printf("\nString split into 3's for decoding:\n");
				printf("%s\n", buffer);
				printf("\nDNA RNA Cypher Decode\n");
			}
			deRNA(buffer);
			shift(buffer);			
		}
		for(j = 0; j <= i; j++){
			free(line[j]);
		}
		fclose(scram);	
		return 0;
	}

	for(j = 0; j < i; j++){
        	if(verbose == 1){
                	printf("Normalizeing line %i\n", j);
                }
                if(bitflip == 1){
                	flip(line[j]);
                }
                line[j] = normalize(line[j], nflag);
                if(verbose == 1){
                	printf("Line %i is now: %s\n", j, line[j]);
                }
	}
        
        j = 1;
        strcpy(buffer, line[0]);
        for(j = 1; j < i; j++){
        	strcat(buffer, line[j]);
        }
        
        if(verbose == 1){
        	printf("\nCombined String: %s\n", buffer);
        }


	if(runBacon == 1){
		for(k = 0; k <= strlen(buffer); k++){
			divideString(buffer, 5);
			if(verbose == 1){
				printf("\nString split into 5's for decoding:\n");
				printf("%s\n", buffer);
	
				printf("\nDebaconing:\n");
			}
			debacon(buffer, btype);
	
			shift(buffer);
		}
	}

	if(runHex == 1){
		for(k = 0; k <= strlen(buffer); k++){
			if(strlen(buffer)%4 != 0){
				switch(strlen(buffer)%4){
					case 1:
						temp[0] = '0';
						temp[1] = '0';
						temp[2] = '0';
						temp[3] = '\0';
						strcat(temp, buffer);
						break;
					case 2:
						temp[0] = '0';
						temp[1] = '0';
						temp[2] = '\0';
						strcat(temp, buffer);
						break;
					case 3:
						temp[0] = '0';
						temp[1] = '\0';
						strcat(temp, buffer);
						break;
					default:
						printf("Something bad happened...\n");
						break;
				}	
			} else{
				strcpy(temp, buffer);
			}
			divideString(temp, 4);
			if(verbose == 1){
				printf("\nString split into 4's\n");
				printf("%s\n", temp);
				printf("\nConverting to Hex:\n");
			}
			deHex(temp);
			clean(temp);
			shift(buffer);
			
		}
	}
	j = 0;
	for(j = 0; j <= i; j++){
		free(line[j]);
	}
	free(line);
	fclose(scram);
	return 0;
}

void flip(char *string){
	char *i;
	for(i=string; *i; i++){
		if(*i == '1'){
			*i = '0';
		} else if(*i == '0'){
			*i = '1';
		}
	}
}

void deRNA(char *string){
	char buffer[4];
	int i = 0;

	while(string[i] != '\0'){
		buffer[0] = string[i];
		i++;
		buffer[1] = string[i];
		i++;
		buffer[2] = string[i];
		buffer[3] = '\0';
		i+=2;

		if(strcmp(buffer, "yyy") == 0 || strcmp(buffer, "YYY") == 0 || strcmp(buffer, "ttt") == 0 || strcmp(buffer, "TTT") == 0 || strcmp(buffer, "uuu") == 0 || strcmp(buffer, "UUU") == 0){
			printf("F");
		} if(strcmp(buffer, "yyp") == 0 || strcmp(buffer, "YYP") == 0 || strcmp(buffer, "yyb") == 0 || strcmp(buffer, "YYB") == 0){
			printf("F");
		} if(strcmp(buffer, "yyo") == 0 || strcmp(buffer, "YYO") == 0){
			printf("L");
		} if(strcmp(buffer, "yyg") == 0 || strcmp(buffer, "YYG") == 0){
			printf("L");
		} if(strcmp(buffer, "pyy") == 0 || strcmp(buffer, "PYY") == 0 || strcmp(buffer, "byy") == 0 || strcmp(buffer, "BYY") == 0){
			printf("L");
		} if(strcmp(buffer, "pyp") == 0 || strcmp(buffer, "PYP") == 0 || strcmp(buffer, "byb") == 0 || strcmp(buffer, "BYB") == 0){
			printf("L");
		} if(strcmp(buffer, "pyo") == 0 || strcmp(buffer, "PYO") == 0 || strcmp(buffer, "byr") == 0 || strcmp(buffer, "BYR") == 0){
			printf("L");
		} if(strcmp(buffer, "pyg") == 0 || strcmp(buffer, "PYG") == 0 || strcmp(buffer, "pyg") == 0 || strcmp(buffer, "PYG") == 0){
			printf("L");
		} if(strcmp(buffer, "oyy") == 0 || strcmp(buffer, "OYY") == 0){
			printf("I");
		} if(strcmp(buffer, "oyp") == 0 || strcmp(buffer, "OYP") == 0 || strcmp(buffer, "ryb") == 0 || strcmp(buffer, "RYB") == 0){
			printf("I");
		} if(strcmp(buffer, "oyo") == 0 || strcmp(buffer, "OYO") == 0){
			printf("I");
		} if(strcmp(buffer, "oyg") == 0 || strcmp(buffer, "OYG") == 0){
			printf(" - M - ");
		} if(strcmp(buffer, "gyy") == 0 || strcmp(buffer, "GYY") == 0){
			printf("V");
		} if(strcmp(buffer, "gyp") == 0 || strcmp(buffer, "GYP") == 0 || strcmp(buffer, "gyb") == 0 || strcmp(buffer, "GYB") == 0){
			printf("V");
		} if(strcmp(buffer, "gyo") == 0 || strcmp(buffer, "GYO") == 0){
			printf("V");
		} if(strcmp(buffer, "gyg") == 0 || strcmp(buffer, "GYG") == 0){
			printf("V");
		} if(strcmp(buffer, "ypy") == 0 || strcmp(buffer, "YPY") == 0 || strcmp(buffer, "yby") == 0 || strcmp(buffer, "YBY") == 0){
			printf("S");
		} if(strcmp(buffer, "ypp") == 0 || strcmp(buffer, "YPP") == 0 || strcmp(buffer, "ybb") == 0 || strcmp(buffer, "YBB") == 0){
			printf("S");
		} if(strcmp(buffer, "ypo") == 0 || strcmp(buffer, "YPO") == 0 || strcmp(buffer, "ybr") == 0 || strcmp(buffer, "YBR") == 0){
			printf("S");
		} if(strcmp(buffer, "ypg") == 0 || strcmp(buffer, "YPG") == 0 || strcmp(buffer, "ybg") == 0 || strcmp(buffer, "YBG") == 0){
			printf("S");
		} if(strcmp(buffer, "ppy") == 0 || strcmp(buffer, "PPY") == 0 || strcmp(buffer, "bby") == 0 || strcmp(buffer, "BBY") == 0){
			printf("P");
		} if(strcmp(buffer, "ppp") == 0 || strcmp(buffer, "PPP") == 0 || strcmp(buffer, "bbb") == 0 || strcmp(buffer, "BBB") == 0){
			printf("P");
		} if(strcmp(buffer, "ppo") == 0 || strcmp(buffer, "PPO") == 0 || strcmp(buffer, "bbr") == 0 || strcmp(buffer, "BBR") == 0){
			printf("P");
		} if(strcmp(buffer, "ppg") == 0 || strcmp(buffer, "PPG") == 0 || strcmp(buffer, "bbg") == 0 || strcmp(buffer, "BBG") == 0){
			printf("P");
		} if(strcmp(buffer, "opy") == 0 || strcmp(buffer, "OPY") == 0 || strcmp(buffer, "rby") == 0 || strcmp(buffer, "RBY") == 0){
			printf("T");
		} if(strcmp(buffer, "opp") == 0 || strcmp(buffer, "OPP") == 0 || strcmp(buffer, "rbb") == 0 || strcmp(buffer, "RBB") == 0){
			printf("T");
		} if(strcmp(buffer, "opo") == 0 || strcmp(buffer, "OOO") == 0 || strcmp(buffer, "rbr") == 0 || strcmp(buffer, "RBR") == 0){
			printf("T");
		} if(strcmp(buffer, "opg") == 0 || strcmp(buffer, "OPG") == 0 || strcmp(buffer, "rbg") == 0 || strcmp(buffer, "RBG") == 0){
			printf("T");
		} if(strcmp(buffer, "gpy") == 0 || strcmp(buffer, "GPY") == 0 || strcmp(buffer, "gby") == 0 || strcmp(buffer, "GBY") == 0){
			printf("A");
		} if(strcmp(buffer, "gpp") == 0 || strcmp(buffer, "GPP") == 0 || strcmp(buffer, "gbb") == 0 || strcmp(buffer, "GBB") == 0){
			printf("A");
		} if(strcmp(buffer, "gpo") == 0 || strcmp(buffer, "GPO") == 0 || strcmp(buffer, "gbr") == 0 || strcmp(buffer, "GBR") == 0){
			printf("A");
		} if(strcmp(buffer, "gpg") == 0 || strcmp(buffer, "GPG") == 0 || strcmp(buffer, "gbg") == 0 || strcmp(buffer, "GBG") == 0){
			printf("A");
		} if(strcmp(buffer, "yoy") == 0 || strcmp(buffer, "YOY") == 0){
			printf("Y");
		} if(strcmp(buffer, "yop") == 0 || strcmp(buffer, "YOP") == 0 || strcmp(buffer, "yrb") == 0 || strcmp(buffer, "YRB") == 0){
			printf("Y");
		} if(strcmp(buffer, "yoo") == 0 || strcmp(buffer, "YOO") == 0){
			printf(" STOP ");
		} if(strcmp(buffer, "yog") == 0 || strcmp(buffer, "YOG") == 0){
			printf(" STOP ");
		} if(strcmp(buffer, "poy") == 0 || strcmp(buffer, "POY") == 0 || strcmp(buffer, "bry") == 0 || strcmp(buffer, "BRY") == 0){
			printf("H");
		} if(strcmp(buffer, "pop") == 0 || strcmp(buffer, "POP") == 0 || strcmp(buffer, "brb") == 0 || strcmp(buffer, "BRB") == 0){
			printf("H");
		} if(strcmp(buffer, "poo") == 0 || strcmp(buffer, "POO") == 0 || strcmp(buffer, "brr") == 0 || strcmp(buffer, "BRR") == 0){
			printf("Q");
		} if(strcmp(buffer, "pog") == 0 || strcmp(buffer, "POG") == 0 || strcmp(buffer, "brg") == 0 || strcmp(buffer, "BRG") == 0){
			printf("Q");
		} if(strcmp(buffer, "ooy") == 0 || strcmp(buffer, "OOY") == 0){
			printf("N");
		} if(strcmp(buffer, "oop") == 0 || strcmp(buffer, "OOP") == 0 || strcmp(buffer, "rrb") == 0 || strcmp(buffer, "RRB") == 0){
			printf("N");
		} if(strcmp(buffer, "ooo") == 0 || strcmp(buffer, "OOO") == 0){
			printf("K");
		} if(strcmp(buffer, "oog") == 0 || strcmp(buffer, "OOG") == 0){
			printf("K");
		} if(strcmp(buffer, "goy") == 0 || strcmp(buffer, "GOY") == 0){
			printf("D");
		} if(strcmp(buffer, "gop") == 0 || strcmp(buffer, "GOP") == 0 || strcmp(buffer, "grb") == 0 || strcmp(buffer, "GRB") == 0){
			printf("D");
		} if(strcmp(buffer, "goo") == 0 || strcmp(buffer, "GOO") == 0){
			printf("E");
		} if(strcmp(buffer, "gog") == 0 || strcmp(buffer, "GOG") == 0){
			printf("E");
		} if(strcmp(buffer, "ygy") == 0 || strcmp(buffer, "YGY") == 0){
			printf("C");
		} if(strcmp(buffer, "ygp") == 0 || strcmp(buffer, "YGP") == 0 || strcmp(buffer, "ygb") == 0 || strcmp(buffer, "YGB") == 0){
			printf("C");
		} if(strcmp(buffer, "ygo") == 0 || strcmp(buffer, "YGO") == 0){
			printf(" STOP ");
		} if(strcmp(buffer, "ygg") == 0 || strcmp(buffer, "YGG") == 0){
			printf("W");
		} if(strcmp(buffer, "pgy") == 0 || strcmp(buffer, "PGY") == 0 || strcmp(buffer, "bgy") == 0 || strcmp(buffer, "BGY") == 0){
			printf("R");
		} if(strcmp(buffer, "pgp") == 0 || strcmp(buffer, "PGP") == 0 || strcmp(buffer, "bgb") == 0 || strcmp(buffer, "BGB") == 0){
			printf("R");
		} if(strcmp(buffer, "pgo") == 0 || strcmp(buffer, "PGO") == 0 || strcmp(buffer, "bgr") == 0 || strcmp(buffer, "BGR") == 0){
			printf("R");
		} if(strcmp(buffer, "pgg") == 0 || strcmp(buffer, "PGG") == 0 || strcmp(buffer, "bgg") == 0 || strcmp(buffer, "BGG") == 0){
			printf("R");
		} if(strcmp(buffer, "ogy") == 0 || strcmp(buffer, "OGY") == 0){
			printf("S");
		} if(strcmp(buffer, "ogp") == 0 || strcmp(buffer, "OGP") == 0 || strcmp(buffer, "rgb") == 0 || strcmp(buffer, "RGB") == 0){
			printf("S");
		} if(strcmp(buffer, "ogo") == 0 || strcmp(buffer, "OGO") == 0){
			printf("R");
		} if(strcmp(buffer, "ogg") == 0 || strcmp(buffer, "OGG") == 0){
			printf("R");
		} if(strcmp(buffer, "ggy") == 0 || strcmp(buffer, "GGY") == 0){
			printf("G");
		} if(strcmp(buffer, "ggp") == 0 || strcmp(buffer, "GGP") == 0 || strcmp(buffer, "ggb") == 0 || strcmp(buffer, "GGB") == 0){
			printf("G");
		} if(strcmp(buffer, "ggo") == 0 || strcmp(buffer, "GGO") == 0){
			printf("G");
		} if(strcmp(buffer, "ggg") == 0 || strcmp(buffer, "GGG") == 0){
			printf("G");
		} else{
			printf(" ");
		}
	}	
	printf("\n");
}

void deHex(char *string){
	char buffer[5];
	int i = 0;

	while(string[i] != '\0'){
		buffer[0] = string[i];
		i++;
		buffer[1] = string[i];
		i++;
		buffer[2] = string[i];
		i++;
		buffer[3] = string[i];
		buffer[4] = '\0';
		i+=2;

		if(strcmp(buffer, "0000") == 0){
			printf("0");
		} else if(strcmp(buffer, "0001") == 0){
			printf("1");
		} else if(strcmp(buffer, "0010") == 0){
			printf("2");
		} else if(strcmp(buffer, "0011") == 0){
			printf("3");
		} else if(strcmp(buffer, "0100") == 0){
			printf("4");
		} else if(strcmp(buffer, "0101") == 0){
			printf("5");
		} else if(strcmp(buffer, "0110") == 0){
			printf("6");
		} else if(strcmp(buffer, "0111") == 0){
			printf("7");
		} else if(strcmp(buffer, "1000") == 0){
			printf("8");
		} else if(strcmp(buffer, "1001") == 0){
			printf("9");
		} else if(strcmp(buffer, "1010") == 0){
			printf("A");
		} else if(strcmp(buffer, "1011") == 0){
			printf("B");
		} else if(strcmp(buffer, "1100") == 0){
			printf("C");
		} else if(strcmp(buffer, "1101") == 0){
			;printf("D");
		} else if(strcmp(buffer, "1110") == 0){
			printf("E");
		} else if(strcmp(buffer, "1111") == 0){
			printf("F");
		} else{
			printf(" ");
		}
	}
	printf("\n");
}

void debacon(char *string, int btype){
	char buffer[6];
	int i = 0;

	while(string[i] != '\0'){

		buffer[0] = string[i];
		i++;
		buffer[1] = string[i];		
		i++;
		buffer[2] = string[i];
		i++;
		buffer[3] = string[i];
		i++;
		buffer[4] = string[i];
		buffer[5] = '\0';
		i+=2;

		if(btype == 0){
			if(strcmp(buffer, "00000") == 0){
				printf("A");
			} else if(strcmp(buffer, "00001") == 0){
				printf("B");
			} else if(strcmp(buffer, "00010") == 0){
				printf("C");
			} else if(strcmp(buffer, "00011") == 0){
				printf("D");
			} else if(strcmp(buffer, "00100") == 0){
				printf("E");
			} else if(strcmp(buffer, "00101") == 0){
				printf("F");
			} else if(strcmp(buffer, "00110") == 0){
				printf("G");
			} else if(strcmp(buffer, "00111") == 0){
				printf("H");
			} else if(strcmp(buffer, "01000") == 0){
				printf("J");
			} else if(strcmp(buffer, "01001") == 0){
				printf("K");
			} else if(strcmp(buffer, "01010") == 0){
				printf("L");
			} else if(strcmp(buffer, "01011") == 0){
				printf("M");
			} else if(strcmp(buffer, "01100") == 0){
				printf("N");
			} else if(strcmp(buffer, "01101") == 0){
				printf("O");
			} else if(strcmp(buffer, "01110") == 0){
				printf("P");
			} else if(strcmp(buffer, "01111") == 0){
				printf("Q");
			} else if(strcmp(buffer, "10000") == 0){
				printf("R");
;			} else if(strcmp(buffer, "10001") == 0){
				printf("S");
			} else if(strcmp(buffer, "10010") == 0){
				printf("T");
			} else if(strcmp(buffer, "10011") == 0){
				printf("V");
			} else if(strcmp(buffer, "10100") == 0){
				printf("W");
			} else if(strcmp(buffer, "10101") == 0){
				printf("X");
			} else if(strcmp(buffer, "10110") == 0){
				printf("Y");
			} else if(strcmp(buffer, "10111") == 0){
				printf("Z");
			} else{
				printf(" ");
			}
		}
		if(btype == 1){
			if(strcmp(buffer, "00000") == 0){
				printf("A");
			} else if(strcmp(buffer, "00001") == 0){
				printf("B");
			} else if(strcmp(buffer, "00010") == 0){
				printf("C");
			} else if(strcmp(buffer, "00011") == 0){
				printf("D");
			} else if(strcmp(buffer, "00100") == 0){
				printf("E");
			} else if(strcmp(buffer, "00101") == 0){
				printf("F");
			} else if(strcmp(buffer, "00110") == 0){
				printf("G");
			} else if(strcmp(buffer, "00111") == 0){
				printf("H");
			} else if(strcmp(buffer, "01000") == 0){
				printf("I");
			} else if(strcmp(buffer, "01001") == 0){
				printf("J");
			} else if(strcmp(buffer, "01010") == 0){
				printf("K");
			} else if(strcmp(buffer, "01011") == 0){
				printf("L");
			} else if(strcmp(buffer, "01100") == 0){
				printf("M");
			} else if(strcmp(buffer, "01101") == 0){
				printf("N");
			} else if(strcmp(buffer, "01110") == 0){
				printf("O");
			} else if(strcmp(buffer, "01111") == 0){
				printf("P");
			} else if(strcmp(buffer, "10000") == 0){
				printf("Q");
			} else if(strcmp(buffer, "10001") == 0){
				printf("R");
			} else if(strcmp(buffer, "10010") == 0){
				printf("S");
			} else if(strcmp(buffer, "10011") == 0){
				printf("T");
			} else if(strcmp(buffer, "10100") == 0){
				printf("U");
			} else if(strcmp(buffer, "10101") == 0){
				printf("V");
			} else if(strcmp(buffer, "10110") == 0){
				printf("W");
			} else if(strcmp(buffer, "10111") == 0){
				printf("X");
			} else if(strcmp(buffer, "11000") == 0){
				printf("Y");
			} else if(strcmp(buffer, "11001") == 0){
				printf("Z");
			} else{
				printf(" ");
			}
		}
	}
	printf("\n");
}

void divideString(char *string, int n){
	int size = strlen(string);
	int i = 1;
	int j = 1;
	char buffer[1024];
	
	strcpy(buffer,string);
	string[0] = buffer[0];

	for(i = 1; j < size; i++){
		if(j%n == 0){
			string[i] = ' ';
			i++;
		}
			string[i] = buffer[j];
			j++;
	}
	string[i] = '\0';
}

char* normalize(char* string, int nflag){
	char *i;
	switch(nflag){
		case 0:
			for(i=string; *i; i++){
				if(*i == 'y' || *i == 'Y'){
					*i = '1';
				} else if(*i == 'o' || *i == 'O'){
					*i = '0';
				} else if(*i == 'g' || *i == 'G'){
					*i = '1';
				} else if(*i == 'p' || *i == 'P' || *i == 'b' || *i == 'B'){
					*i = '0';
				} else if(*i == '\n'){
					*i = '\0';
				}
			}
			return string;
		case 1:
			for(i=string; *i; i++){
				if(*i == 'y' || *i == 'Y'){
					*i = '0';
				} else if(*i == 'o' || *i == 'O'){
					*i == '1';
				} else if(*i == 'g' || *i == 'G'){
					*i = '1';
				} else if(*i == 'p' || *i == 'P' || *i == 'b' || *i == 'B'){
					*i = '0';
				} else if(*i == '\n'){
					*i == '\0';
				}
			}
			return string;
		case 2:
			for(i=string; *i; i++){
				if(*i == 'y' || *i == 'Y'){
					*i = '1';
				} else if(*i == 'o' || *i == 'O'){
					*i = '0';
				} else if(*i == 'g' || *i == 'G'){
					*i == '0';
				} else if(*i == 'p' || *i == 'P' || *i == 'b' || *i == 'B'){
					*i == '1';
				} else if(*i == '\n'){
					*i = '\0';
				}
			}
			return string;
		case 3:
			for(i=string; *i; i++){
				if(*i == 'y' || *i == 'Y'){
					*i = '0';
				} else if(*i == 'o' || *i == 'O'){
					*i = '1';
				} else if(*i == 'g' || *i == 'G'){
					*i = '0';
				} else if(*i == 'p' || *i == 'P' || *i == 'b' || *i == 'B'){
					*i = '1';
				} else if(*i == '\n'){
					*i = '\0';
				}
			}
			return string;
;		case 8:
			for(i=string; *i; i++){
				if(*i == '\n'){
					*i = '\0';
				}
			}
			return string;
		default:
			printf("\nERROR: Could not normalize stirng\n");
			return string;
	}
}

int getlines(FILE* stream, char** line, ssize_t* nread, int* ntot, size_t len){
	int i = 0;
	for(i = 0; i < 16; i++){
		nread[i] = getline(&line[i], &len, stream);
		if(nread[i] == -1){
			break;
		}
		*ntot += nread[i];
	}
	
	return i;
}

void clean(char* string){
	char *nospace = string;
	char *temp = string;

        if(verbose == 1){
	        printf("\nRemoving Spaces\n");
	}
	while(*temp != 0){
		*nospace = *temp++;
		if(*nospace != ' '){
			nospace++;
		}
	}
	*nospace = 0;
}

void shift(char* string){
	char *nospace = string;
	char *temp = string;
	char buffer[1024];

	char t;
	int i = 0;
	int size;

	if(verbose == 1){
		printf("\nRemoving Spaces\n");
	}
	while(*temp != 0){
		*nospace = *temp++;
		if(*nospace != ' '){
			nospace++;
		}
	}
	*nospace = 0;
	if(verbose == 1){
		printf("\n%s\n", string);
		printf("\nShifting String\n");
	}
	strcpy(buffer, string);
	if(verbose == 1){
		printf("Buffer: \n%s\n\n", buffer);
	}
	t = string[0];
	size = strlen(string);
	for(i = 0; i < (size-1); i++){
		string[i] = buffer[i+1];
	}
	string[i] = t;
	string[i+1] = '\0';
	if(verbose == 1){
		printf("%s\n", string);
	}
}

There is also this
https://www.nature.com/polopoly_fs/7.38631.1472212682!/image/DNA_storage_graphic_WEB.jpg_gen/derivatives/landscape_630/DNA_storage_graphic_WEB.jpg

Took a look at this. There's a problem with this kind of rotating encoding though.
https://images.techhive.com/images/article/2016/04/screen-shot-2016-04-11-at-12.37.07-pm-100655391-orig.png

It's built so you never have "repeats" of a DNA element. (A will never follow A).
In the flames, you have repeats of up to 3 flames in a row. So it doesn't match the data.
It could be a modified version, though, some kind of quaternary rotating encoding.

[sini]

Just as an opinion, what I've learned from Cicada Liber Primus solving is that you need to catalog EVERYTHING you do. It gets really crazy with what people are trying versus what hasn't been tried yet.

Doing something like unit tests or just uploading the code is really useful.

[RealOnTheMF]

@Itod, so in your opinion the "The_____iskeyfile" message is the intended message?

Well, I have a theory didn't want to mention before while trying to find the proof. The message "THEfm_aurISKEYFILE" can hardly be a collision, and the bold scrambled part is intentionally left there to be de-scrambled in the same way other bit-streams should be de-scrambled to get a key. If you come across the stream of bytes from private key you may not notice something is scrambled, but if you find something like plaintext quoted above it's pretty obvious something is wrong. So to answer you: yes I think it's intentionally left there scrambled/corrupted to show the way.

Anything can be the way to de-scramble it in a coherent message. The current path I'm working are the chessboard fields affected by Phoenix fire. It looks to me that those chessboard fields that should be dark are somehow lighter with this bright blue Phoenix color then the white ones, so some bits associated with those chessboard fields should be inverted in raw bit-streams. I believe if we invert some bits from the "THEfm_aurISKEYFILE" bit-stream, in this way I've described, we will get coherent message from this bit-stream, and then we should apply this same transformation to colors bit-streams to get the private key.

Why "keyfile" though?

Perhaps the odd word choice was needed to create/preserve the 0x1x1x0x1x1x0 pattern.

This is the one thing that's tough to reconcile. The message overlaps with the pattern bits which would indicate it's not really there. The original dataset was only 2GB large. Presuming mostly random data the chance of finding just the "iskeyfile" text in that small of a search space is 0.098%. Both eventualities are equally unlikely.

[RealOnTheMF]

@kn0w0n3 If you disable the newbie PM protection I'd like to chat more in PM.

[neogabe]

Just as an opinion, what I've learned from Cicada Liber Primus solving is that you need to catalog EVERYTHING you do. It gets really crazy with what people are trying versus what hasn't been tried yet.

Doing something like unit tests or just uploading the code is really useful.

I think that when someone hits a clear path, every followed step will be cataloged, at least for himself. At this point, and I am following the thread from almost the start (and the other chats that appeared), only thoughts and theories are being tested. This puzzle is using a different logic than previous ones.

[bug.lady]

This is the original:

I don't know how it is in US but here in Europe you would keep neither oil nor acrylic painting behind glass. You keep paper paintings behind glass (like watercolours etc.) but you don't paint oil on paper.

The fact that on your photo the painting IS kept behind glass, I think it indicates one of two things, the second one being really interesting:
1. either this is not the original
2. or the original was first painted with oil or acrylic and the photoed or scanned and then messed with some more in Photoshop or whatever and then printed on regular paper. And then put behind the glass for savekeeping

[kn0w0n3]

@kn0w0n3 If you disable the newbie PM protection I'd like to chat more in PM.

Disabled it and sent you a PM.

[feedo]

I don't know how it is in US but here in Europe you would keep neither oil nor acrylic painting behind glass. You keep paper paintings behind glass (like watercolours etc.) but you don't paint oil on paper.

The fact that on your photo the painting IS kept behind glass, I think it indicates one of two things, the second one being really interesting:
1. either this is not the original
2. or the original was first painted with oil or acrylic and the photoed or scanned and then messed with some more in Photoshop or whatever and then printed on regular paper. And then put behind the glass for savekeeping

LOL BugLady.. this shit has no value at all, it's free and everyone can download and print it.

maybe that stupid put it behind the glass to protect it thinking that he owns a Rembrandt masterpiece that worth millions

[feedo]

This puzzle is using a different logic than previous ones.

A very important message to those in the stupid blinds camp.

[chubbychew]

I've got a theory I've been working on for a couple of days. It almost feels like a Eureka moment with no payoff *yet. I'm wondering if anyone else wants to help me see if I'm on the right track or if I'm close but got off somewhere. I really feel like I'm on to something here:

 it starts by looking at this "statement" with the ampersand: https://imgur.com/a/NfjBI

1) It appears that the statement is saying: "flames and leaves" but not the colored flames, the little white orange ones we've all been ignoring.

2) There are three leaves on/near the ampersand: pointing left, up and down

3) There are three leaves on the left side border pointing: left, up and down

4) There are orange flames touching these leaves. The one pointing left is touched by 1 orange/white flame. The one pointing up is touched by 2 orange/white flames. The one pointing down is being touched by 3 orange white flames

5) The one pointing left appears to me to be indicating flame height (tall). If it was pointing to an actual flame it would appear ambiguous (pointing at color or height?) as you'll see shortly. Also the leaf on the top border is also being touched by 1 orange white flame, it appears to be indicate flame height (short) and is not pointing at a colored flame.

6) The one pointing up and touched by 2 orange white flames appears to indicate outer flame color (yellow)

7) The leaf pointing down and touched by 3 orange white flames appears to indicate inner flame color.

So: it looks to me like it's saying 123 -> height, outer color, inner color

So where to start looking at this pattern? Take the Alphabet Canary path starting with the inner track at the upper left corner and go clockwise, then counter clockwise on the outer track. Using my own notation of outer corners as Captital and inner as lowercase as shown in the image abdcaACDBA

If you take that path and rotate what you are looking at each flame height(tall) outer color (yellow) inner color (green), then the binary string you get starts with 011010. Off to a good start! Since the alphabet_canary found pattern of short flame every six flames, you would always get a 0 for those flames. A fixed value followed by 5 binary values. That could be a hint to check the bacon cypher which would have been an obscure clue before coin_artist posted the poem link now it's a no brainer.

I'm not sure I did it right but when I checked the bacon cypher doing everything as described above taking 6 values (always with a zero up front) and making that a Bacon character i got jibberish. "?JAYWUZUZVY?FM?IQISN?VZ?D" to be exact. It did occur to me that there are 152 flames and if you do this type of thing (looking for three different properties on a rotational basis) you could extract all the data from the flames and end up with a 456 bit binary stream because 152%3 is 2. But I haven't gotten any results that seem promising but my eyes are untrained compared to some of those here.

[chubbychew]

If you decide that starting on the inner track top where that one leaf is pointing to the inner color, you can go CCW and get 011010 as well. Starting at this position and going CCW matches the right hand spirals I think. Again, I've not seen anything obvious come out of this but it would be great if I missed something and someone else here can catch it.

[kn0w0n3]

I've got a theory I've been working on for a couple of days. It almost feels like a Eureka moment with no payoff *yet. I'm wondering if anyone else wants to help me see if I'm on the right track or if I'm close but got off somewhere. I really feel like I'm on to something here:

 it starts by looking at this "statement" with the ampersand: https://imgur.com/a/NfjBI

1) It appears that the statement is saying: "flames and leaves" but not the colored flames, the little white orange ones we've all been ignoring.

2) There are three leaves on/near the ampersand: pointing left, up and down

3) There are three leaves on the left side border pointing: left, up and down

4) There are orange flames touching these leaves. The one pointing left is touched by 1 orange/white flame. The one pointing up is touched by 2 orange/white flames. The one pointing down is being touched by 3 orange white flames

5) The one pointing left appears to me to be indicating flame height (tall). If it was pointing to an actual flame it would appear ambiguous (pointing at color or height?) as you'll see shortly. Also the leaf on the top border is also being touched by 1 orange white flame, it appears to be indicate flame height (short) and is not pointing at a colored flame.

6) The one pointing up and touched by 2 orange white flames appears to indicate outer flame color (yellow)

7) The leaf pointing down and touched by 3 orange white flames appears to indicate inner flame color.

So: it looks to me like it's saying 123 -> height, outer color, inner color

So where to start looking at this pattern? Take the Alphabet Canary path starting with the inner track at the upper left corner and go clockwise, then counter clockwise on the outer track. Using my own notation of outer corners as Captital and inner as lowercase as shown in the image abdcaACDBA

If you take that path and rotate what you are looking at each flame height(tall) outer color (yellow) inner color (green), then the binary string you get starts with 011010. Off to a good start! Since the alphabet_canary found pattern of short flame every six flames, you would always get a 0 for those flames. A fixed value followed by 5 binary values. That could be a hint to check the bacon cypher which would have been an obscure clue before coin_artist posted the poem link now it's a no brainer.

I'm not sure I did it right but when I checked the bacon cypher doing everything as described above taking 6 values (always with a zero up front) and making that a Bacon character i got jibberish. "?JAYWUZUZVY?FM?IQISN?VZ?D" to be exact. It did occur to me that there are 152 flames and if you do this type of thing (looking for three different properties on a rotational basis) you could extract all the data from the flames and end up with a 456 bit binary stream because 152%3 is 2. But I haven't gotten any results that seem promising but my eyes are untrained compared to some of those here.

I'm not discrediting your ideas with the leaves and the orange flames. You may be onto something there.

That said, i have already seperated out lengths (all lengths total, as well as odd lengths only), inner colors, and outer colors. I then combined said strings in every possible combination (without dividing strings into smaller strings) and ran bacon cyphers (v1 and v2) on those combinations from every possible starting point. I've also repeated that process with every possible way of interpretting colors as 0 and 1 (assuming 4 colors), as well as reading everything backwards. I can confidently say there is no bacon message (occasional random word, sure) to be found going this route. Unless you start xoring bits, or reading bits in a different order or some combination of both.

[feedo]

Suppose that your theory is correct, what to do with the rest of leaves?!!
They simply don't have a place in your theory, that's why I don't buy this theory

[chubbychew]

Well, if you do take the path I suggest, height(H) Outer color (O) Inner Color (I) and go around the aforementioned path HOIHOIHOIHOI etc..., then xor that result with the repeating ribbon 011010, then bacon that result, you end up with ONLY A's and B's (interesting result?) which if you Bacon that again, you get..... jibberjabber (maybe)

SMEKCXBE_RGUQY_GGAREQ_PS_ZUUFB

[chubbychew]

I dunno, maybe it's not bacon. That's why I wanted to see if I was missing something with that bitstream ie..converting to hex, converting to base58 (Not sure how to do this) converting to base 63 (because there's 63 squares on the board).

[kn0w0n3]

Well, if you do take the path I suggest, height(H) Outer color (O) Inner Color (I) and go around the aforementioned path HOIHOIHOIHOI etc..., then xor that result with the repeating ribbon 011010, then bacon that result, you end up with ONLY A's and B's (interesting result?) which if you Bacon that again, you get..... jibberjabber (maybe)

SMEKCXBE_RGUQY_GGAREQ_PS_ZUUFB

I take back what I said as I misunderstood you. You are saying you built your bitstring by taking a height bit, then outer color bit, then inner color bit and repeating?  I have not tried that.

[chubbychew]

Well, if you do take the path I suggest, height(H) Outer color (O) Inner Color (I) and go around the aforementioned path HOIHOIHOIHOI etc..., then xor that result with the repeating ribbon 011010, then bacon that result, you end up with ONLY A's and B's (interesting result?) which if you Bacon that again, you get..... jibberjabber (maybe)

SMEKCXBE_RGUQY_GGAREQ_PS_ZUUFB

I take back what I said as I misunderstood you. You are saying you built your bitstring by taking a height bit, then outer color bit, then inner color bit and repeating?  I have not tried that.

correct, that's how I'm building it. If you start at the inner track upper left corner and go CW you get 011010 which is why I thought that was a good place to start. If you start in the middle of the inner top (where the leaf is pointing) and go CCW, you get 011010 which I thought was good also, but I don't know how to look deeply into the resulting binary stream so I posted hoping there really is something there but I can't see it.

[feedo]

Well, if you do take the path I suggest, height(H) Outer color (O) Inner Color (I) and go around the aforementioned path HOIHOIHOIHOI etc..., then xor that result with the repeating ribbon 011010, then bacon that result, you end up with ONLY A's and B's (interesting result?) which if you Bacon that again, you get..... jibberjabber (maybe)

SMEKCXBE_RGUQY_GGAREQ_PS_ZUUFB

I take back what I said as I misunderstood you. You are saying you built your bitstring by taking a height bit, then outer color bit, then inner color bit and repeating?  I have not tried that.

So what are you waiting? Go ahead you have a big homework and weeks ahead to play with your lovely flames  

[chubbychew]

I got ahead of myself and the xor only ab thing is a simple code error on my part...