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Mabsark (OP)
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June 21, 2013, 01:05:44 AM |
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The link you provided shows BKKCoins saying that each PCIE cable can only power one K16: A K16 will use around 32W, so a K64 will need about 128W each (with 4 leads). They're designed to take a PCIe 6 pin connector much like a GPU. I would guess that you could run a K64 off each PCIe lead from the PSU with splitters to feed each of the 4 sections.
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pajak666
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June 21, 2013, 01:09:31 AM |
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will 1x sata -> 1x pcie work? I mean how much watt can sata cable provide?
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kendog77
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June 21, 2013, 01:11:03 AM |
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One pci-e lead from the power supply typically contains two pci-e connectors. A k64 contains four k16 boards, so one pci-e lead with two splitters can power one k64 board.
I believe what I originally said was correct.
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Mabsark (OP)
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June 21, 2013, 02:38:54 AM |
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will 1x sata -> 1x pcie work? I mean how much watt can sata cable provide?
Good question. That's something I didn't even consider. From the Wikipedia article for Serial ATA: A third voltage is supplied, 3.3 V, in addition to the traditional 5 V and 12 V. However, few current disk drives use the 3.3 V line. Each voltage is transmitted through three pins grouped together, because the small contacts by themselves cannot supply sufficient current for some devices. (Each pin should be able to carry 1.5 A.) So, a SATA cable should be able to provide 12V * 3 * 1.5A = 54 W. It seems to me, that powering 16 K16s is going to be more complicated and expensive than I first thought.
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Mabsark (OP)
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June 21, 2013, 02:49:57 AM |
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One pci-e lead from the power supply typically contains two pci-e connectors. A k64 contains four k16 boards, so one pci-e lead with two splitters can power one k64 board.
I believe what I originally said was correct.
I don't believe it can. A 6 pin PCIE cable has 3 x 12V lines providing 6.25A and a maximum wattage of 75W. A K16 uses 32W so you'd only be able to power 2 K16s from a PCIE cable.
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pajak666
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June 21, 2013, 05:46:15 PM |
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Anyone figured out some solution to actually turn on those PSU? I mean they don't have power on/off switch, I wonder if I bought two K16 boards will I be able to give power on signal to my PSU? If yes, how?
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andrewsg
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June 28, 2013, 08:35:38 AM |
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I would really like something like that for Klondikes, but a Lancelot uses less power and has a different power plug / lead, so I don't think it would work "out of the box".
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Bicknellski
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June 28, 2013, 09:11:06 AM Last edit: June 28, 2013, 10:16:10 AM by Bicknellski |
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I would really like something like that for Klondikes, but a Lancelot uses less power and has a different power plug / lead, so I don't think it would work "out of the box".
This is a complete DIY solution... where has anyone found a out of the box solution for a Klondike array being powered? Please let me know. I think you are missing what this can do... has nothing to do with the "power" of the Lancelots... have a closer look. You can make these wires yourself order some PCI-e 6 to 8 pin or SATA wires I would hope... checking now to find something.
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turtle83
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June 28, 2013, 05:21:18 PM |
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I would really like something like that for Klondikes, but a Lancelot uses less power and has a different power plug / lead, so I don't think it would work "out of the box".
This is a complete DIY solution... where has anyone found a out of the box solution for a Klondike array being powered? Please let me know. I think you are missing what this can do... has nothing to do with the "power" of the Lancelots... have a closer look. You can make these wires yourself order some PCI-e 6 to 8 pin or SATA wires I would hope... checking now to find something. I realized, my excitement over the adapter may have been immature, so maybe we need to rethink the adapter. When i hooked up more than 5 ztex quad, overnight the ATX PSU would auto shutdown. Did not have the time to investigate why that happens. Maybe it was not designed for ~40W per lead.... Once im back home, I will try using 2 leads per board and report back if im able to max out the ATX or not.
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ionstorm
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July 14, 2013, 07:56:45 PM |
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ok I got a few psu's laying around but I am unsure how to power on the power supplies without a host pc, what I'd like to do is have a nexus 7 or netbook run cgminer, how do I switch the power supply on? is there a switch I can buy for this?
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turtle83
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July 14, 2013, 07:59:03 PM |
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ok I got a few psu's laying around but I am unsure how to power on the power supplies without a host pc, what I'd like to do is have a nexus 7 or netbook run cgminer, how do I switch the power supply on? is there a switch I can buy for this?
http://www.techpowerup.com/articles/other/22
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Bitoy
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July 15, 2013, 08:46:20 AM |
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One pci-e lead from the power supply typically contains two pci-e connectors. A k64 contains four k16 boards, so one pci-e lead with two splitters can power one k64 board.
I believe what I originally said was correct.
I don't believe it can. A 6 pin PCIE cable has 3 x 12V lines providing 6.25A and a maximum wattage of 75W. A K16 uses 32W so you'd only be able to power 2 K16s from a PCIE cable. Yes you can only power 2 x k16 with one 6 pin pcie. But a psu usually have 2 x 6 pin pcie so you can power a k64. On another note. How about an 8 pin pcie with 3 splitter to power 1 k64?
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trigeek
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July 15, 2013, 02:56:52 PM |
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Yes you can only power 2 x k16 with one 6 pin pcie. But a psu usually have 2 x 6 pin pcie so you can power a k64.
On another note. How about an 8 pin pcie with 3 splitter to power 1 k64?
Yes, that will work. 6-pin connectors are rated to deliver 75W. 8-pin are rated to deliver 150W. Also note that these are nominal ratings- the physical connector is OK for more than double that. It would *probably* be safe to run three or four K16's off of a single 6-pin, but that will require some experimentation. Lots more information here: http://www.tomshardware.com/reviews/power-supply-specifications-atx-reference,3061-12.htmlAlso, one of the most important things to look at when picking a PSU- make sure it is single rail. With cheap multi-rail power supplies, the current handling capability will be divided up across those rails, and maybe in ways that don't divide evenly by 32W.
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