digaran
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February 23, 2023, 07:12:47 AM |
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Guys I just found the true identity of Satoshi, here take a look: https://en.m.wikipedia.org/wiki/Satoshi_MatsuokaGo read his published articles from 2007, 2008 and 2009, it's all hinting at bitcoin. Maybe we could use his super computer to solve these puzzles? Lol. No need to hide any more dear Satoshi, come out come out wherever you are. You never thought creating a challenge to test the strength of your implementation could actually result in a identity revelation did you? Now gimme my prize!🤣
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JDScreesh
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February 27, 2023, 09:39:24 AM |
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Hello there Congratulations to the solver of the Puzzle #120 I wonder which is the private key.
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digaran
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February 28, 2023, 12:26:00 PM Last edit: February 28, 2023, 01:01:14 PM by digaran |
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WOW, guys look what I found, seek and you shall find; 13zb1hQbWVsc2S7ZTZnP2G4undNPCTfqJZ 13zb1hQbWVsc2S7ZTZnP2G4undNP7kEP7M 13zb1hQbWVsc2S7ZTZnP2G4undNNwgQut1 13zb1hQbWVsc2S7ZTZnP2G4undNNvZeouk 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so 13zb1hQbWVsc2S7ZTZnP2G4undNNgMUm4n 13zb1hQbWVsc2S7ZTZnP2G4undNNViSuhK 13zb1hQbWVsc2S7ZTZnP2G4undNNTCnWQi 13zb1hQbWVsc2S7ZTZnP2G4undNNMNtEnp 13zb1hQbWVsc2S7ZTZnP2G4undNNEaaHF4 13zb1hQbWVsc2S7ZTZnP2G4undNPNuwE3h 13zb1hQbWVsc2S7ZTZnP2G4undNPQxu217 13zb1hQbWVsc2S7ZTZnP2G4undNPZxBxnH 13zb1hQbWVsc2S7ZTZnP2G4undNPf3VD6N 13zb1hQbWVsc2S7ZTZnP2G4undNPnJ2jFS 13zb1hQbWVsc2S7ZTZnP2G4undNPsJ7T9P 13zb1hQbWVsc2S7ZTZnP2G4undNPygXueW 13zb1hQbWVsc2S7ZTZnP2G4undNQ59XjMk 13zb1hQbWVsc2S7ZTZnP2G4undNQGH2W2c 13zb1hQbWVsc2S7ZTZnP2G4undNQPnwQJw 1111111111111111111114oLvT2 11111111111111111111BZbvjr 11111111111111111111HeBAGj 11111111111111111111QekFQw 11111111111111111111UpYBrS 11111111111111111111g4hiWR 11111111111111111111jGyPM8 11111111111111111111o9FmEC 11111111111111111111ufYVpS 1111111111111111111127DiY8B 111111111111111111112BEH2ro 111111111111111111112KWC9yd 111111111111111111112MbYeKK 111111111111111111112WhxnQF 111111111111111111112czxoHN 111111111111111111112kmzDG2 111111111111111111112xT3273 1111111111111111111135LjaTk 111111111111111111113BCNaZA 111111111111111111113MEMrbm 111111111111111111113UauxVS 111111111111111111113Vsgn16 111111111111111111113h6eYvj 111111111111111111113iqSWm1 111111111111111111113twUjvB 111111111111111111114gFexwh 111111111111111111114mA2k9d 111111111111111111114ry6XwB 111111111111111111114ysyUW1 111111111111111111115719xWh 111111111111111111115GZoCZK 111111111111111111115Jk6jSN 111111111111111111115Vdmk4z 111111111111111111115bqgQLs 111111111111111111115hA977A 111111111111111111116WGuH8i 111111111111111111116ayzEtU 111111111111111111116iBpJVP 111111111111111111116p9wW39 111111111111111111116xyhaXw 111111111111111111116zvHYMP 1111111111111111111178p8Uvz 111111111111111111117HhpFr4 111111111111111111117MncoQu 111111111111111111117TDMMQQ 111111111111111111118GEJCAf
Only if I knew how to automate this process!
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cryptoDEADBEEFFFFF
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February 28, 2023, 02:23:02 PM |
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WOW, guys look what I found, seek and you shall find; 13zb1hQbWVsc2S7ZTZnP2G4undNPCTfqJZ 13zb1hQbWVsc2S7ZTZnP2G4undNP7kEP7M 13zb1hQbWVsc2S7ZTZnP2G4undNNwgQut1 13zb1hQbWVsc2S7ZTZnP2G4undNNvZeouk 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so 13zb1hQbWVsc2S7ZTZnP2G4undNNgMUm4n 13zb1hQbWVsc2S7ZTZnP2G4undNNViSuhK 13zb1hQbWVsc2S7ZTZnP2G4undNNTCnWQi 13zb1hQbWVsc2S7ZTZnP2G4undNNMNtEnp 13zb1hQbWVsc2S7ZTZnP2G4undNNEaaHF4 13zb1hQbWVsc2S7ZTZnP2G4undNPNuwE3h 13zb1hQbWVsc2S7ZTZnP2G4undNPQxu217 13zb1hQbWVsc2S7ZTZnP2G4undNPZxBxnH 13zb1hQbWVsc2S7ZTZnP2G4undNPf3VD6N 13zb1hQbWVsc2S7ZTZnP2G4undNPnJ2jFS 13zb1hQbWVsc2S7ZTZnP2G4undNPsJ7T9P 13zb1hQbWVsc2S7ZTZnP2G4undNPygXueW 13zb1hQbWVsc2S7ZTZnP2G4undNQ59XjMk 13zb1hQbWVsc2S7ZTZnP2G4undNQGH2W2c 13zb1hQbWVsc2S7ZTZnP2G4undNQPnwQJw 1111111111111111111114oLvT2 11111111111111111111BZbvjr 11111111111111111111HeBAGj 11111111111111111111QekFQw 11111111111111111111UpYBrS 11111111111111111111g4hiWR 11111111111111111111jGyPM8 11111111111111111111o9FmEC 11111111111111111111ufYVpS 1111111111111111111127DiY8B 111111111111111111112BEH2ro 111111111111111111112KWC9yd 111111111111111111112MbYeKK 111111111111111111112WhxnQF 111111111111111111112czxoHN 111111111111111111112kmzDG2 111111111111111111112xT3273 1111111111111111111135LjaTk 111111111111111111113BCNaZA 111111111111111111113MEMrbm 111111111111111111113UauxVS 111111111111111111113Vsgn16 111111111111111111113h6eYvj 111111111111111111113iqSWm1 111111111111111111113twUjvB 111111111111111111114gFexwh 111111111111111111114mA2k9d 111111111111111111114ry6XwB 111111111111111111114ysyUW1 111111111111111111115719xWh 111111111111111111115GZoCZK 111111111111111111115Jk6jSN 111111111111111111115Vdmk4z 111111111111111111115bqgQLs 111111111111111111115hA977A 111111111111111111116WGuH8i 111111111111111111116ayzEtU 111111111111111111116iBpJVP 111111111111111111116p9wW39 111111111111111111116xyhaXw 111111111111111111116zvHYMP 1111111111111111111178p8Uvz 111111111111111111117HhpFr4 111111111111111111117MncoQu 111111111111111111117TDMMQQ 111111111111111111118GEJCAf
Only if I knew how to automate this process! Can you share at least two private key from each list to be sure there is a process to begin with?
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digaran
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February 28, 2023, 05:05:01 PM |
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Can you share at least two private key from each list to be sure there is a process to begin with? With the speed which I am progressing, you'd need to wait 40,000 years before I can get a single private key for one of the addresses, and that would be the address for #66, given everybody know exactly where to look.🤣
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cryptoDEADBEEFFFFF
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March 02, 2023, 03:42:39 PM |
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Can you share at least two private key from each list to be sure there is a process to begin with? With the speed which I am progressing, you'd need to wait 40,000 years before I can get a single private key for one of the addresses, and that would be the address for #66, given everybody know exactly where to look.🤣 This is so inspiring! Thank you!
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The_Prof
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March 02, 2023, 04:18:44 PM |
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Only if I knew how to automate this process!
Could you at least share the process, maybe some code somewhere can help you automate it.
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Look over there...
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zielar (OP)
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March 02, 2023, 06:04:28 PM |
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Congratulations to the person who found key #120. I am impressed and I will be grateful if this person publicly discloses the private key and provides information on how he found the key, or provided this information in a private message if he wants to remain anonymous, and that I complete this information in the table in the main post on his behalf.
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If you want - you can send me a donation to my BTC wallet address 31hgbukdkehcuxcedchkdbsrygegyefbvd
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cryptoDEADBEEFFFFF
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March 02, 2023, 06:16:24 PM |
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Only if I knew how to automate this process!
Could you at least share the process, maybe some code somewhere can help you automate it. +1 I am also interested but I think it's just playing with the ripemd160 hash
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Lolo54
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March 02, 2023, 07:28:23 PM |
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Congratulations to the person who found key #120. I am impressed and I will be grateful if this person publicly discloses the private key and provides information on how he found the key, or provided this information in a private message if he wants to remain anonymous, and that I complete this information in the table in the main post on his behalf.
the same I am impressed because only those who ignore the difficulty do not express themselves while it remains a feat / an event !! I just say congratulations to the one who succeeded but it would be nice if he at least gave the key! you zielar you said how you succeeded congratulations to you
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digaran
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March 02, 2023, 11:57:52 PM |
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+1 I am also interested but I think it's just playing with the ripemd160 hash
You think? Lol. Could you at least share the process, maybe some code somewhere can help you automate it. Convert each of them into hash160 and look at the last hex characters, change their values in an orderly fashion to be amazed by the beauty of order amongst the chaos. Have you seen websites providing an online(totally unsafe) service where you could just insert your desired private key in hex format and see all the corresponding properties such as addresses, public/ private keys even for many coins etc? It would be great if we could build an algorithm specifically designed to do the same for addresses only, this way we wouldn't need to count from 1 up to 2^256, we'd only need to represent 2^160.8 (more or less) total number of addresses with hexadecimal values, so when you search for the address #0 you'd get 1111111111111111111114oLvT2 for #1 you'd get 11111111111111111111BZbvjr and so on until you reach the end of the address range. This is just for entertainment and would have no use case for storing bitcoins because you don't know the private keys, you might only know the private keys which you had generated before, i.e, using a wallet etc. If we could manage to do something like that, imagine the awe of the beholder! Being present at such a mesmerizing sight! Just don't forget to include my address on the footer of the site for donations, make sure to name me as the cofounder . Lol. And remember, no offensive words, no sacrilegious words, we wouldn't wanna upset the boss up stairs, so we should skip 4 to 8 percent of addresses.
This message is for @satoshi aka the author of this challenge, "Live long in prosperity under the bluish violet dome". Now could you create a new challenge with riddles and equations for us to seek and solve please? We're bored honestly and it could light up the mood in crypto-community ushering new methods and never ending possibilities. Though not something that someone could solve them all with one go, maybe make them in episode where each riddle's answer is just a small piece of the greater puzzle. ❤👏💯
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albert0bsd
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March 03, 2023, 04:16:04 AM |
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This message is for @satoshi aka the author of this challenge, "Live long in prosperity under the bluish violet dome".
Now could you create a new challenge with riddles and equations for us to seek and solve please? We're bored honestly and it could light up the mood in crypto-community ushering new methods and never ending possibilities. Though not something that someone could solve them all with one go, maybe make them in episode where each riddle's answer is just a small piece of the greater puzzle. ❤👏💯
Do you expected a new Cicada 3301 ? I really want some challenges like that, but diffucults please.
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mr. k0c
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March 05, 2023, 07:39:02 AM |
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It is a real shame that the solver of #120 still didn't give us the private key. Dude, if you're out there, please find a way to communicate it
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zielar (OP)
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March 06, 2023, 01:01:05 AM Merited by albert0bsd (1) |
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It is a real shame that the solver of #120 still didn't give us the private key. Dude, if you're out there, please find a way to communicate it
There are various reasons why we still don't have the key: 1. The finder wishes to remain anonymous 2. Someone has a tool to find #125 soon 3. The withdrawal was made by someone outside the forum 4. Someone has some other purpose in it, so as not to reveal themselves. It is certainly puzzling that BCH and BTG have not been paid out from this wallet so far, while the payment was made to the address without any other transaction before, nor was it sent further - which also raises the suspicion that the finder could use some tool that worked for a long time -> found the right key and made the withdrawal, but the initiator himself still does not know that he found solution #120. A lot of unknowns, but I believe that eventually someone will somehow provide a solution, because the solution #120 without indicating the key to the public will simply be a blow to the whole history of these puzzles.
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If you want - you can send me a donation to my BTC wallet address 31hgbukdkehcuxcedchkdbsrygegyefbvd
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pbies
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March 06, 2023, 05:05:56 PM |
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I made some computations. Used Python 3. I was curious if the next puzzle can be ax+b=y. d1, d2, d3 are corresponding private keys from puzzle. Needed to compute a and b. First script for puzzle 66: #!/usr/bin/env python3 import math
d1=0x0000000000000000000000000000000000000000000000007cce5efdaccf6808 d2=0x000000000000000000000000000000000000000000000000f7051f27b09112d4 d3=0x000000000000000000000000000000000000000000000001a838b13505b26867
asqr=(d2-(d2/d1))/d1 a=math.sqrt(asqr) print("a =",a) b=d2/(a*d1) print("b =",b) d4=a*d3+b print("next =",hex(int(d4))) Second script for puzzle 120: #!/usr/bin/env python3 import math
d1=0x000000000000000000000000000000000000016f14fc2054cd87ee6396b33df3 d2=0x00000000000000000000000000000000000035c0d7234df7deb0f20cf7062444 d3=0x0000000000000000000000000000000000060f4d11574f5deee49961d9609ac6
asqr=(d2-(d2/d1))/d1 a=math.sqrt(asqr) print("a =",a) b=d2/(a*d1) print("b =",b) d4=a*d3+b print("next =",hex(int(d4))) The output is however strange, because a=b! This means the next puzzle is multiplied and added to it the same value, I mean the multiplicator and later adding a number are the same. First script gives: a = 1.4068509690560507 b = 1.4068509690560507 next = 0x254d0fd348f800000 Second script gives: a = 6.122671382779787 b = 6.122671382779785 next = 0x251a1b44dd0e160000000000000000 What can mean that just raising the value(s) of a and b can give next puzzle private key!
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BTC: bc1qmrexlspd24kevspp42uvjg7sjwm8xcf9w86h5k
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albert0bsd
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March 07, 2023, 12:26:53 PM |
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Hi @zielar, nice to see you here 2. Someone has a tool to find #125 soon
As we know the puzzle 125 is 32 times bigger than puzzle 120 but prize is only a 4% bigger, i doubt about that such "magic" tool exists. But we don't have way to know. If that exists it should be a mathematical approach. I made some computations. Used Python 3. I was curious if the next puzzle can be ax+b=y. d1, d2, d3 are corresponding private keys from puzzle. Needed to compute a and b.
We already know that puzzles a random and there is not math relationship between them
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zielar (OP)
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March 07, 2023, 12:43:27 PM |
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Hi @zielar, nice to see you here 2. Someone has a tool to find #125 soon
As we know the puzzle 125 is 32 times bigger than puzzle 120 but prize is only a 4% bigger, i doubt about that such "magic" tool exists. But we don't have way to know. If that exists it should be a mathematical approach. Nice to see you too :-) Despite the passage of time and the fact that people who are more active in the subject know each other only from here - there is a smile on your face knowing that everything is fine with you :-) It is also certain that no matter how much time passes - the solution of the next thresholds will certainly take place, whether it is due to the fact that the technology will develop further or because the value of assets, despite being only 4% more - will be much higher in terms of physical currency than today. Time will tell. I also believe that we will get to know the finder of solution 120 and how he did it, how much time he needed for it, or at least the private key to complete the list of keys of solved addresses. Greetings!
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If you want - you can send me a donation to my BTC wallet address 31hgbukdkehcuxcedchkdbsrygegyefbvd
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noecp
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March 07, 2023, 02:02:21 PM |
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Not a 32 times bigger but √32 like ~5.65. this not full space search, this birthday collision check. You can compare 'expected operations' for 115 2^58.1 120 2^60.61 125 2^63.10 130 2^65.61 ...
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digaran
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March 08, 2023, 04:29:00 AM |
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Guys I'm telling you, Satoshi solved the puzzle, few days after I pointed him to this thread, he did it with his super GPU computer, and I bet he is busy with the next one #125. I just didn't expect him to take the loots alone, we were partners.🤣 at least let me loot the garbage coins. Lol.
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kalos15btc
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April 05, 2023, 05:08:16 PM Last edit: April 05, 2023, 05:22:40 PM by kalos15btc |
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hi guys, im working on puzzle 125 for a long time, today, i have substracted the public key (im always test and substract by random) of 125 to a smaller range randomly i found a substracted key his hash160 start with the same 4 lettres as a hash160 of an adress in the range 110 bit, so, am i close to find it ? if i search this substracted public key in 110 bit range will i found it ? the probleme im runing 7TerraK per sec its slow, and if anyone can help we will split the reward of the puzzle 125, 02a0397a2b74177e0f101ab1cbe9d560ac384c01fd69d7e19593d1ab3155f9ad73 2000000000000000000000000000:3fffffffffffffffffffffffffff if you have better speed search from 1f00000000000000000000000000:7fffffffffffffffffffffffffff from 109 to 111 bits, if you have good speed and can finish this range in 1hour, you wont lose nothing, we will split the reward thank you
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