BHWallet
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August 27, 2022, 07:13:31 PM |
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So there are 2^96 different private keys in the entire 2^256 space that can "unlock" for example this address: 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (Puzzle 64)? Can anyone confirm this?
Yes exactly and for a simple fact : 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (and every other wallet address of this type) is encoded on 160 bits (and not on 256 bits like the majority of other crypto parameters in bitcoin protocol) 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN is base58 encoded and is 3ee4133d991f52fdf6a25c9834e0745ac74248a4 (20*8bytes = 160bits) in hexadecimal ( Unlike public keys that are encoded on 256 bitsa simple wallet address (p2pkh) is simply obtained by the function hash160(public_key) So if you have the possibility to browse the entire 1-2^256 space and to compute the hash160 function for every hash160(public_key) derived from 1-2^256 private keys you will find an average of 2^(256-160) = 2^96 public key with hash160=16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN . But even if 2^96 seems big its far away smaller from 2^256. And it's pretty impossible to have a collision between two random public key in the using age of bitcoin. But theoretically if you find any public key derived from a private key with hash160(public_key)= '16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN' or = to any other non zero wallet address you will able to unlock the coins. Because the verification in the bitcoin protocol to prove that you are the owner of the private key is simply "have you signed the transaction with the private key associated to a public key that gives 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (or any other target address) with hash160 function Thanks for the reply! I'm missing something...So these addresses will have different public keys or not? Can one private key control 2^96 different wallets? For example when I import some random private key in Electrum wallet and click on "sweep funds" am I sweeping one wallet or 2^96 different wallets?
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Evillo
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So there are 2^96 different private keys in the entire 2^256 space that can "unlock" for example this address: 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (Puzzle 64)? Can anyone confirm this?
Yes exactly and for a simple fact : 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (and every other wallet address of this type) is encoded on 160 bits (and not on 256 bits like the majority of other crypto parameters in bitcoin protocol) 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN is base58 encoded and is 3ee4133d991f52fdf6a25c9834e0745ac74248a4 (20*8bytes = 160bits) in hexadecimal ( Unlike public keys that are encoded on 256 bitsa simple wallet address (p2pkh) is simply obtained by the function hash160(public_key) So if you have the possibility to browse the entire 1-2^256 space and to compute the hash160 function for every hash160(public_key) derived from 1-2^256 private keys you will find an average of 2^(256-160) = 2^96 public key with hash160=16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN . But even if 2^96 seems big its far away smaller from 2^256. And it's pretty impossible to have a collision between two random public key in the using age of bitcoin. But theoretically if you find any public key derived from a private key with hash160(public_key)= '16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN' or = to any other non zero wallet address you will able to unlock the coins. Because the verification in the bitcoin protocol to prove that you are the owner of the private key is simply "have you signed the transaction with the private key associated to a public key that gives 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (or any other target address) with hash160 function Thanks for the reply! I'm missing something...So these addresses will have different public keys or not? Can one private key control 2^96 different wallets? For example when I import some random private key in Electrum wallet and click on "sweep funds" am I sweeping one wallet or 2^96 different wallets? You simply got it backwards .. One private key does NOT open 2^96 addresses instead, One address can be opened by 2^96 private keys See the difference?
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Cool Story Bro. BTC: 1EviLLo1Y5VeNn2Lajv9tdZTkUuVgePVYN
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BHWallet
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August 29, 2022, 09:19:17 AM |
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So there are 2^96 different private keys in the entire 2^256 space that can "unlock" for example this address: 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (Puzzle 64)? Can anyone confirm this?
Yes exactly and for a simple fact : 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (and every other wallet address of this type) is encoded on 160 bits (and not on 256 bits like the majority of other crypto parameters in bitcoin protocol) 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN is base58 encoded and is 3ee4133d991f52fdf6a25c9834e0745ac74248a4 (20*8bytes = 160bits) in hexadecimal ( Unlike public keys that are encoded on 256 bitsa simple wallet address (p2pkh) is simply obtained by the function hash160(public_key) So if you have the possibility to browse the entire 1-2^256 space and to compute the hash160 function for every hash160(public_key) derived from 1-2^256 private keys you will find an average of 2^(256-160) = 2^96 public key with hash160=16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN . But even if 2^96 seems big its far away smaller from 2^256. And it's pretty impossible to have a collision between two random public key in the using age of bitcoin. But theoretically if you find any public key derived from a private key with hash160(public_key)= '16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN' or = to any other non zero wallet address you will able to unlock the coins. Because the verification in the bitcoin protocol to prove that you are the owner of the private key is simply "have you signed the transaction with the private key associated to a public key that gives 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (or any other target address) with hash160 function Thanks for the reply! I'm missing something...So these addresses will have different public keys or not? Can one private key control 2^96 different wallets? For example when I import some random private key in Electrum wallet and click on "sweep funds" am I sweeping one wallet or 2^96 different wallets? You simply got it backwards .. One private key does NOT open 2^96 addresses instead, One address can be opened by 2^96 private keys See the difference? Yeah I get it thanks. Still the odds of finding one remain almost the same if you scan through 2^255
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Evillo
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August 29, 2022, 04:01:33 PM Last edit: August 29, 2022, 08:54:11 PM by Evillo |
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So there are 2^96 different private keys in the entire 2^256 space that can "unlock" for example this address: 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (Puzzle 64)? Can anyone confirm this?
Yes exactly and for a simple fact : 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (and every other wallet address of this type) is encoded on 160 bits (and not on 256 bits like the majority of other crypto parameters in bitcoin protocol) 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN is base58 encoded and is 3ee4133d991f52fdf6a25c9834e0745ac74248a4 (20*8bytes = 160bits) in hexadecimal ( Unlike public keys that are encoded on 256 bitsa simple wallet address (p2pkh) is simply obtained by the function hash160(public_key) So if you have the possibility to browse the entire 1-2^256 space and to compute the hash160 function for every hash160(public_key) derived from 1-2^256 private keys you will find an average of 2^(256-160) = 2^96 public key with hash160=16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN . But even if 2^96 seems big its far away smaller from 2^256. And it's pretty impossible to have a collision between two random public key in the using age of bitcoin. But theoretically if you find any public key derived from a private key with hash160(public_key)= '16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN' or = to any other non zero wallet address you will able to unlock the coins. Because the verification in the bitcoin protocol to prove that you are the owner of the private key is simply "have you signed the transaction with the private key associated to a public key that gives 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN (or any other target address) with hash160 function Thanks for the reply! I'm missing something...So these addresses will have different public keys or not? Can one private key control 2^96 different wallets? For example when I import some random private key in Electrum wallet and click on "sweep funds" am I sweeping one wallet or 2^96 different wallets? You simply got it backwards .. One private key does NOT open 2^96 addresses instead, One address can be opened by 2^96 private keys See the difference? Yeah I get it thanks. Still the odds of finding one remain almost the same if you scan through 2^255 I wouldn't say that with 100% confidence .. any address that starts with the number "1" (i mean a p2pkh address) is prone to 160 bit range attack using private key cracking tools .. it is well known that this entire first 160 bit range has all addresses (including the 40+ millions with balance) .. this is the problem with hashing public keys .. coz you basically reduced cracking difficulty down from 256 bits to 160 bits .. however, this doesn't mean that bitcoin security got any loopholes .. just watch how only 64 bits are beating the hell out of all crackers trying to solve one address within it .. trying to go through the entire 64 bits, you would have to traverse 18 million trillion private keys .. this number is so huge that the average person will never hear about it in their lifetime coz most likely they will never need to .. ok going forward, getting out of this range and moving up one bit to 65 bit range .. is double that number .. keep doubling on every bit until you reach 160 bits and you would have to crack one quindecillion private keys .. in case you wonder, one quindecillion is a number consisting of 49 digits (1 followed by 48 zeros) .. no machine in our world is known to be able to even count through this whole range within like what, a million generations lifetime? let alone trying to convert each pvt key to public key hash .. in simple words: practically impossible Update: edited some wrong calcs.
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Cool Story Bro. BTC: 1EviLLo1Y5VeNn2Lajv9tdZTkUuVgePVYN
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Siyam37
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August 31, 2022, 12:45:26 AM |
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I would like to present an interval ECDLP solver based on the Pollard's kangaroo method. This program is fully open source and available on GitHub: https://github.com/JeanLucPons/KangarooIt has GPU support (CUDA Only) and works on both Linux and Windows. This program is currently under development. Thanks to test it and to share ideas of improvements here Wink He is stealing the post
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PowerGlove
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August 31, 2022, 03:42:30 AM Last edit: September 01, 2022, 01:42:46 AM by PowerGlove |
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He is stealing the post
Thanks for spotting, I've reported it here. So many post thieves lately, hopefully this one gets banned! [ update: user has been banned] ![Smiley](https://bitcointalk.org/Smileys/default/smiley.gif) I hate being so suspicious, but your very first post on this forum being a plagiarism spot feels off to me. Are you stealing posts with one account and then "reporting" it with another to try and get some merit? ![Undecided](https://bitcointalk.org/Smileys/default/undecided.gif)
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NotATether
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August 31, 2022, 07:19:17 AM |
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He is stealing the post
Thanks for spotting, I've reported it here. So many post thieves lately, hopefully this one gets banned! ![Smiley](https://bitcointalk.org/Smileys/default/smiley.gif) I hate being so suspicious, but your very first post on this forum being a plagiarism spot feels off to me. Are you stealing posts with one account and then "reporting" it with another to try and get some merit? ![Undecided](https://bitcointalk.org/Smileys/default/undecided.gif) Just use "report to moderator" button that's under the post, mods will find it much quicker than when you post it in a thread. It's pretty lame plagiarism though, links and emoticons were not copied.
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PowerGlove
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September 01, 2022, 01:42:33 AM |
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Just use "report to moderator" button that's under the post, mods will find it much quicker than when you post it in a thread.
Yeah, I already do that. I've found the most reliable method (most likely to result in a ban) to be a double-barreled approach! ![Smiley](https://bitcointalk.org/Smileys/default/smiley.gif) I first document the plagiarism in LoyceV's topic and then I use "Report to moderator" on the offending post and include a link back to my "report" post.
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dlystyr
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September 06, 2022, 02:12:14 AM |
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Just out of interest.
If I was to create a bitcoin address randomly with Bitcoin Core, Would that be created in a particular higher keyspace - 8000000000000000000000000000000000000000...ffffffffffffffffffffffffffffffffffff ffff (2159...2160-1) for example? or higher? or could it be anywhere in the whole keyspace?
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Crack Puzzle #66 Pool - http://www.ttdsales.com/66bit/index.php
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Evillo
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September 06, 2022, 02:46:27 PM |
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Just out of interest.
If I was to create a bitcoin address randomly with Bitcoin Core, Would that be created in a particular higher keyspace - 8000000000000000000000000000000000000000...ffffffffffffffffffffffffffffffffffff ffff (2159...2160-1) for example? or higher? or could it be anywhere in the whole keyspace?
I would be comfortable to say it will at least be in the 254 to 256 bit range 99% of the time You would have to intentionally create an address in the weak 160 bit range or below to be able to receive such weak address .. fun fact is though, even the strongest private key (256 bit) will generate an address that can be opened by another private key in the first 160 bit range .. good luck finding one of those copycats though
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Cool Story Bro. BTC: 1EviLLo1Y5VeNn2Lajv9tdZTkUuVgePVYN
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PawGo
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September 06, 2022, 02:52:56 PM |
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You have 50% chance it is 2^256 and 50% chance it is less. You have 25% chance it is 2^255 and 25% chance it is less. You have 12.5% chance it is 2^254 and 12.5% chance it is less. You have 6.25% chance it is 2^253 and 6.25% chance it is less. etc.
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wedom
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September 10, 2022, 02:46:26 AM |
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Congratulations to the winner! The solution is not my. I was looking in a different range.
Puzzle #64 PrivKey Hex: 000000000000000000000000000000000000000000000000F7051F27B09112D4 Pubkey Compressed: 03100611c54dfef604163b8358f7b7fac13ce478e02cb224ae16d45526b25d9d4d Address: 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN
Congratulations!!!
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pooya87
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September 10, 2022, 03:00:39 AM |
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Congratulations to the winner! The solution is not my. I was looking in a different range.
Puzzle #64 PrivKey Hex: 000000000000000000000000000000000000000000000000F7051F27B09112D4 Pubkey Compressed: 03100611c54dfef604163b8358f7b7fac13ce478e02cb224ae16d45526b25d9d4d Address: 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN
Congratulations!!!
Which puzzle did this come from? I couldn't find the address among the outputs of this tx and the "puzzle" I know of is from at least 2015 but the first transaction this address received is from 2020.
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pooya87
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September 10, 2022, 03:22:38 AM Last edit: September 10, 2022, 03:35:29 AM by pooya87 |
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That's weird blockchair.com only shows transactions from 2020 and up. https://blockchair.com/bitcoin/address/16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQNThis is the last tx it shows at the bottom of the page and there is no page numbers or load more buttons available either: ![](https://ip.bitcointalk.org/?u=https%3A%2F%2Fi.imgur.com%2FxmQqs3y.png&t=665&c=pf9m_7o-Obmbng) Edit: it seems like something is wrong my Google Chrome, Firefox works fine and shows the load button at the bottom!
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wedom
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September 10, 2022, 03:43:36 AM |
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I wonder if the author of the solution will be found.
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bigvito19
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September 10, 2022, 10:35:05 AM |
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![](https://ip.bitcointalk.org/?u=https%3A%2F%2Fi.ibb.co%2Fk0CpLVs%2Fheader4.png&t=665&c=ebYvtCGH8ZQXUw) No. |=========PRIVATE KEY IN HEX (if it was found and known)========== |===========WALLET ADDRESS===========| ===============UPPER RANGE LIMIT================ | ===================COMPRESSED PUBLIC KEY IN HEX=================== | ==SOLVED DATE== 01 | 0000000000000000000000000000000000000000000000000000000000000001 | 1BgGZ9tcN4rm9KBzDn7KprQz87SZ26SAMH | 1 | 0279be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798 | 2015-01-15 02 | 0000000000000000000000000000000000000000000000000000000000000003 | 1CUNEBjYrCn2y1SdiUMohaKUi4wpP326Lb | 3 | 02f9308a019258c31049344f85f89d5229b531c845836f99b08601f113bce036f9 | 2015-01-15 03 | 0000000000000000000000000000000000000000000000000000000000000007 | 19ZewH8Kk1PDbSNdJ97FP4EiCjTRaZMZQA | 7 | 025cbdf0646e5db4eaa398f365f2ea7a0e3d419b7e0330e39ce92bddedcac4f9bc | 2015-01-15 04 | 0000000000000000000000000000000000000000000000000000000000000008 | 1EhqbyUMvvs7BfL8goY6qcPbD6YKfPqb7e | 15 | 022f01e5e15cca351daff3843fb70f3c2f0a1bdd05e5af888a67784ef3e10a2a01 | 2015-01-15 05 | 0000000000000000000000000000000000000000000000000000000000000015 | 1E6NuFjCi27W5zoXg8TRdcSRq84zJeBW3k | 31 | 02352bbf4a4cdd12564f93fa332ce333301d9ad40271f8107181340aef25be59d5 | 2015-01-15 06 | 0000000000000000000000000000000000000000000000000000000000000031 | 1PitScNLyp2HCygzadCh7FveTnfmpPbfp8 | 63 | 03f2dac991cc4ce4b9ea44887e5c7c0bce58c80074ab9d4dbaeb28531b7739f530 | 2015-01-15 07 | 000000000000000000000000000000000000000000000000000000000000004C | 1McVt1vMtCC7yn5b9wgX1833yCcLXzueeC | 127 | 0296516a8f65774275278d0d7420a88df0ac44bd64c7bae07c3fe397c5b3300b23 | 2015-01-15 08 | 00000000000000000000000000000000000000000000000000000000000000E0 | 1M92tSqNmQLYw33fuBvjmeadirh1ysMBxK | 255 | 0308bc89c2f919ed158885c35600844d49890905c79b357322609c45706ce6b514 | 2015-01-15 09 | 00000000000000000000000000000000000000000000000000000000000001D3 | 1CQFwcjw1dwhtkVWBttNLDtqL7ivBonGPV | 511 | 0243601d61c836387485e9514ab5c8924dd2cfd466af34ac95002727e1659d60f7 | 2015-01-15 10 | 0000000000000000000000000000000000000000000000000000000000000202 | 1LeBZP5QCwwgXRtmVUvTVrraqPUokyLHqe | 1023 | 03a7a4c30291ac1db24b4ab00c442aa832f7794b5a0959bec6e8d7fee802289dcd | 2015-01-15 11 | 0000000000000000000000000000000000000000000000000000000000000483 | 1PgQVLmst3Z314JrQn5TNiys8Hc38TcXJu | 2047 | 038b05b0603abd75b0c57489e451f811e1afe54a8715045cdf4888333f3ebc6e8b | 2015-01-15 12 | 0000000000000000000000000000000000000000000000000000000000000A7B | 1DBaumZxUkM4qMQRt2LVWyFJq5kDtSZQot | 4095 | 038b00fcbfc1a203f44bf123fc7f4c91c10a85c8eae9187f9d22242b4600ce781c | 2015-01-15 13 | 0000000000000000000000000000000000000000000000000000000000001460 | 1Pie8JkxBT6MGPz9Nvi3fsPkr2D8q3GBc1 | 8191 | 03aadaaab1db8d5d450b511789c37e7cfeb0eb8b3e61a57a34166c5edc9a4b869d | 2015-01-15 14 | 0000000000000000000000000000000000000000000000000000000000002930 | 1ErZWg5cFCe4Vw5BzgfzB74VNLaXEiEkhk | 16383 | 03b4f1de58b8b41afe9fd4e5ffbdafaeab86c5db4769c15d6e6011ae7351e54759 | 2015-01-15 15 | 00000000000000000000000000000000000000000000000000000000000068F3 | 1QCbW9HWnwQWiQqVo5exhAnmfqKRrCRsvW | 32767 | 02fea58ffcf49566f6e9e9350cf5bca2861312f422966e8db16094beb14dc3df2c | 2015-01-15 16 | 000000000000000000000000000000000000000000000000000000000000C936 | 1BDyrQ6WoF8VN3g9SAS1iKZcPzFfnDVieY | 65535 | 029d8c5d35231d75eb87fd2c5f05f65281ed9573dc41853288c62ee94eb2590b7a | 2015-01-15 17 | 000000000000000000000000000000000000000000000000000000000001764F | 1HduPEXZRdG26SUT5Yk83mLkPyjnZuJ7Bm | 131071 | 033f688bae8321b8e02b7e6c0a55c2515fb25ab97d85fda842449f7bfa04e128c3 | 2015-01-15 18 | 000000000000000000000000000000000000000000000000000000000003080D | 1GnNTmTVLZiqQfLbAdp9DVdicEnB5GoERE | 262143 | 020ce4a3291b19d2e1a7bf73ee87d30a6bdbc72b20771e7dfff40d0db755cd4af1 | 2015-01-15 19 | 000000000000000000000000000000000000000000000000000000000005749F | 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BHWallet
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September 14, 2022, 01:14:38 PM |
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Someone with tons of computing power, what's the average time your kangaroo is showing for solving #120?
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Evillo
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Two things you should never abandon: Family & BTC
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September 14, 2022, 02:11:01 PM |
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Someone with tons of computing power, what's the average time your kangaroo is showing for solving #120?
I honestly don't think this is necessarily the case, i mean if you had 1000 people looking in micro random 64 bit ranges, inevitably, one of them is gonna land on the right range and solve the key.. Although no one really knows if that was what happened, but you have to know that the bigger the range, the more it's gonna be about luck than about computing power .. you need couple hundred Telsa 100 to solve puzzle #120 within two months . If such computing power was available to a single person already, he would have sold more than just #120 .. he would have used them to crack open small range puzzles as well .. so i guess those who have huge computing power are busy doing something else making them way more money than our beloved puzzle would .. Lucky for us though, otherwise we stand no chance with our teeny tiny personal rigs
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Cool Story Bro. BTC: 1EviLLo1Y5VeNn2Lajv9tdZTkUuVgePVYN
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BHWallet
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Offline
Activity: 62
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September 14, 2022, 04:33:39 PM |
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Someone with tons of computing power, what's the average time your kangaroo is showing for solving #120?
I honestly don't think this is necessarily the case, i mean if you had 1000 people looking in micro random 64 bit ranges, inevitably, one of them is gonna land on the right range and solve the key.. Although no one really knows if that was what happened, but you have to know that the bigger the range, the more it's gonna be about luck than about computing power .. you need couple hundred Telsa 100 to solve puzzle #120 within two months . If such computing power was available to a single person already, he would have sold more than just #120 .. he would have used them to crack open small range puzzles as well .. so i guess those who have huge computing power are busy doing something else making them way more money than our beloved puzzle would .. Lucky for us though, otherwise we stand no chance with our teeny tiny personal rigs So how many years is your rig showing? for example I;m getting around 1000 years on a laptop
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