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Author Topic: Mining Difficulty  (Read 210 times)
xxmetalmartyrxx
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August 18, 2017, 01:25:59 AM
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Hey all, I just have a question concerning mining difficulty. I'm currently mining a multi algo coin, and I'm trying to figure out which algorithm is best to mine with. So here's my question, does difficulty scale evenly between algorithms? For instance, I mine about 21.5mh/s on the x17 algo and I mine about 71.5mh/s on the lyra2v2 algo. Now, x17 has a difficulty hovering around 400, while with lyra2v2 it hovers around 1000. Because the ration of difficulty to hash rate is lower with lyra2v2 would I be better off mining lyra2v2? Or is mining more then just hashes and difficulty?
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August 18, 2017, 01:55:57 AM
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the idea of difficulty to prevent "inflation". For example if total hashrate doubled, "difficulty" will also double to neutralize it. hashrate/diff = const (ideally).
It means that 71.5mh/s will be equivalent to 400/100*21.5=28.6mh/s. But you need to take into account prices of coins/BTC. They also tends to equalize. But you know that ideal equalizing is death Wink since cryptocurrency wolrd is still alive, some coins will be more profitable than others.
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August 18, 2017, 03:23:35 AM
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the idea of difficulty to prevent "inflation". For example if total hashrate doubled, "difficulty" will also double to neutralize it. hashrate/diff = const (ideally).
It means that 71.5mh/s will be equivalent to 400/100*21.5=28.6mh/s. But you need to take into account prices of coins/BTC. They also tends to equalize. But you know that ideal equalizing is death Wink since cryptocurrency wolrd is still alive, some coins will be more profitable than others.

Ahh alright! So in my instance, not taking into account prices of coins/btc and just number of coins, I would be better with the Lyra2v2 algo then is what I'm getting from this. It's because Verge has multiple algorithms to keep it as decentralized as possible, even the mining process. So there's scrypt, x17, myr-gr, lyra2v2 and blake2s. That's why I'm only concerned with number of coins as the price of coins is the same across algos.
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