ARG Puzzle with 3.5 BTC Private Key Prize, Game Over

[S4VV4S]

So did anybody manage to get the Tor link yet??

Can I have it?

[1714914522]

1714914522

[1714914522]

1714914522

[shorena]

So did anybody manage to get the Tor link yet??

Can I have it?

tor link?

[S4VV4S]

So did anybody manage to get the Tor link yet??

Can I have it?

tor link?

Have you not played Cicada games before?

Trust me, the data will lead to a tor link which will guide you for the next step.
I could be wrong but I doubt it.....

[shorena]

So did anybody manage to get the Tor link yet??

Can I have it?

tor link?

Have you not played Cicada games before?

Trust me, the data will lead to a tor link which will guide you for the next step.
I could be wrong but I doubt it.....

Nope, first time and I am all out of ideas.

[Krona Rev]

This has roped me in today too, but I'm hitting a dead end. Clearly I'm no Hiro Protagonist. Here are some notes in case it helps someone.

Since the address was given in a fairly direct way (1HXU...), my first thought was that the private key is given in WIF/base58 format somehow using letters and numbers in the picture. However, there's evidence against this. There are characters O (capital o) and I (capital i) which do not belong in base58. A WIF private key would start with 5 and, if I'm not mistaken, would continue with H, J or K, and be 51 characters total. There are two fives in the picture but neither is near an H, J or K. One of the 5s is near a small h and a small k, so I considered reversing the capital and small letters (unless it leads to a letter which is not a base58 character). Doing this makes it possible to get started with something that might be a WIF private key (e.g., 5KAH...), but at that point it feels like I'm grasping at straws to force there to be a WIF there.

I'm using some lisp code to test whether something is a private key. It's my implementation of bip0032:
https://github.com/kronarev/bip0032sbcl
It doesn't actually have a function to check if a string is a proper WIF key, but this can be easily defined after loading the relevant files:

Code:

(load "config")                                                                                                                                                                             
(load "secp256k1")                                                                                                                                                                            
(load "hdw")
(defun checkwif (w) (let ((x (frombase58 w))) (and (= (ash x -288) 128) (let* ((k1 (ash x -32)) (sh1 (sha256num k1 33)) (sh2 (sha256num sh1 32)) (sh24 (ash sh2 -224))) (= sh24 (logand x #xFFFFFFFF))))))

I also looked at the sources of the jpg itself and the file she linked to as being relevant. (It said view source on all files.) I didn't find anything though. No onion links and nothing that said "Hey, here's the private key." It's of course possible I missed something. I suspect there must be something in the source.

I haven't tried taking colors into account. Good luck everyone.

[S4VV4S]

So did anybody manage to get the Tor link yet??

Can I have it?

tor link?

Have you not played Cicada games before?

Trust me, the data will lead to a tor link which will guide you for the next step.
I could be wrong but I doubt it.....

Nope, first time and I am all out of ideas.

http://en.wikipedia.org/wiki/Cicada_3301

[S4VV4S]

Crap. I didn't find any prime numbers there.

Did anybody find prime numbers in the "riddle"?

[Zuminest]

Forget the Btc, I'll take the guy on the left

[shorena]

Forget the Btc, I'll take the guy on the left

They look both cute



source: http://www.wired.com/2014/04/dark-wallet/

Well BTT:

A new TX appeared while I slept

https://blockchain.info/tx/e458b939817056c726744bd3e9b2668d1ae70bc51b097865ee857bdd2646d900

It has the same amount of BTC as the 2nd TX 0.1010101 BTC and its coming from 1AskcEemXLiwStjvHEXGkLSDEWK6CEx9sd
1AskcEem ? Maybe we ought to ask ceem?

But sadly this is all I found is a ucked  up pdf that only shows ceem in googlescache.

https://webcache.googleusercontent.com/search?q=cache:KubJpzXplTAJ:http://www.bitcoin42.com/wp-content/uploads/2014/04/press-kit-english.pdf%2Bceem+bitcoin&hl=en-DE&gbv=1&&ct=clnk

The address might as well be random or 1Ask is the hint?

Anyway the pattern of the transaction is more important IMHO. It hints towards binary again. So the red and green dots are binary data and the yellow and blue dots represent some sort of operation. I went along that road yesterday but came up with nothing. The number of bits is strange for it to be a private key (256 bit length). Well I did some things anyway

I tried yellow = ADD, blue = MUL, BLU= DIV

I came up with these operations because yellow is between red and green on the RGB spectrum

results are in the middle, just because
This resulted in nothing btw, but something that might be another address. Its empty though.

Code:

101010000001                                                      = 2689
+01001                                                            = 9
+010101                                                           = 21
+101010000101000100011111001                                      = 88246521
+0110101011111                                                    = 3423
+11                                                               = 3
+001                                                              = 1
+10                                                               = 2
+1                                                                = 1
+101010000                                                        = 336
++00001110111001000                                               = 7624
+1                                                                = 1
+1100010101100010100111000011011001011001001101010101101          = 27779496739117741
+10111000                                                         = 184
+1011                                                             = 11
+0                                                                = 0
+000                                                              = 0
+100100                                                           = 36
+11011010101110001000010101                                       = 57336341
+0001111                                                          = 15
+10000110                                                         = 134
+001                                                              = 1
+0                                                                = 0
+01010                                                            = 10
+11100011101010000110000100001111001001                           = 244445627337
=================================================================================
1100010101100011000011100001101111100101000001000101001           = 27779741330342441


MUL   = 27779741330342441 * 976412029                             = 27124473597454822081622789
= 1dQdPgy7t4BFZrcc9vo6L in base58check
= 6ZhXtndRJRsV1nL in base58
DIV   = 27779741330342441 / 976412029                             = 28450838.893078038
= 1EdYnSf96SxzWSjt2tJ9Dk65AbKxMd8 in base58check (valid address?)
= 35p4xA7JkAtLikBSwuKs32U2j in base58

11110                                                             = 30
+110000                                                           = 48
+0100000                                                          = 32
+10001100011                                                      = 1123
+++000                                                            = 0
+00111100011000101                                                = 30917
+0111010001100001000101010000010                                  = 976259714
+0100010                                                          = 34
+01                                                               = 1
+11110100101010                                                   = 15658
+00                                                               = 0
+11110101110110                                                   = 15734
+1100                                                             = 12
+0001001                                                          = 9
+0010101101010001101                                              = 88717
===============================================================================
                                                                  = 976412029

btw 27779741330342441^976412029 takes at least several minutes on my calc, so I asked wolfram alpha
https://www.wolframalpha.com/input/?i=27779741330342441^976412029
and well the result is way to big as expected.
Wolfram alpha also confirmed that neither
https://www.wolframalpha.com/input/?i=976412029
nor
https://www.wolframalpha.com/input/?i=27779741330342441

are primes.

[fryarminer]

Ok so I spent a while on this - this is the OP's first post. Could it be for real, or is it just art?
It's certainly a challenge!

[S4VV4S]

Ok so I spent a while on this - this is the OP's first post. Could it be for real, or is it just art?
It's certainly a challenge!

It's for real.

I have played games like this before.

Quite fun, but like one of the commandments say: Prepare for sleepless nights and unproductive days.....

[e1ghtSpace]

This the most awesome thing I have ever seen. I hope someone finds out the secret.

[S4VV4S]

Guys, line 8,3 I think that is a blue (turquoise) dot not green.

[S4VV4S]

0101011111101011010101001010111101011101110000011010010010111111100110101010111 1111100010001101110001110101100011011001111001001101001101100101011011010100011 1010011110110110010010101000111011110101011100000111100111011010100011100010101 1110011110111100001101100000100111110111110111001110011111000011100111010100010 1110011110111010101111101101110110000010110101011100001010001010011111011011010 10010101110010

The green and red dots.

Green = 0
Red = 1

I made green 0 because the transaction starts with 0 and it's the first dot.

[S4VV4S]

0101 0 1111 110 1011 0 10101 0
010 1 0 111 1 01011 1 0 111000 001
10 10010 01011 111 1 1 001 1 0 1
01010 11 11 1 11100010 0 011011 1 0
00 111010110001 10 1100011110 01001
1 01 0 0 1101 10 01 0101 101 101
01 00 01 1 1 0 100 1 111 011 01
1 (0) 01 00 1 010100011101111 010 10
1110000 011 11001 11 0 1 10
101 0 00111 0 0010101 1
11 001111011 110 000 11
0110 0000 1 0011 11
1 01111 1 01 1 1001
1100 111 1100 0 0
111 00111010 100 010 11
1 00111 101 1 10101 0 1
111 1 01 10 111 0 1
10 000 0 1 01101
0101 1 1 00 0 0
10 100 01 01
0 011 11101
10 1 1 010 10
010101 110010

The same as above broken in lines as they appear.

Notice the () on line 8 it's because I am unable to determine if it's green or not.

[S4VV4S]

I have managed to extract the following key: 5JBWatUuGLcKwTkhG2ejXmdPoV9idq2XqztCRQGi6y5cqEHoTeh
which corresponds to the following address: 1N5BmwhL8o9GVXtZXqZEUST7N5UMpJKrFn
which is 0 balance  


The following address also popped up: 15PpMsJnw7eNznH7wH1H2oSi6Sj9Wq1hyB

Also 0 balance but interesting hash

[S4VV4S]

Got another: KxqPaZqwuKHprZVkzZvfdn4wf9dXMYf6NrcTHZGYp3NymoFZ8uRo

Also empty

[S4VV4S]

Yet another: 5JBx2Gi4tWuzZAVw9FpKzWyeJfPSJBf95EJAbfgfHgUL4RQJ6GB

[micaman]

Is it possible to generate a public key from a ECDSA coordinates pair?
As there is only one blue dot, it could be a separator...

[S4VV4S]

And this: KxqPaaEERJRNCfTFZXZCJTZsTUB78iLFPAxyCtQAgqz6ryVK7w8w

And this: KxqP7S6pRpp7sKjcAcmeJ6BGHGJHrU8i4dTJui1sa6wRJ6Mv4tij

And this: 5JBvS38gNjyBRgcKx69tNJQ5Lu9SE6pnkvuBbNgr4ZesPhBhy2w

And this: KxsCqW2gjVCLTq3AwWmzJu1g61h6T4zZTeZVVy6J5cVAUKotw8gU

And this: 1zjT5yvcLbDsPXPpKTc1maUmKeHF26mn

And this: 121rKKo6Qw8siuvyF5FL1g8AuFPk3WryM

And this: 142SmZ4KSh6ukcZhUxL7LByhQMvNav

And this: 121vvzaUR3BCNXDoSvr2yzp41f7ruPTJ6

And this: 1gkFfxHuiss2jfRmt4korjYwWgvW

And this: 19piArY5stiEMnGgFihXNgYyNbY

And this: 175Hk926jLiPYbe9Jac6maa

And this: 12M6KZcTQiDeAxMS9gjm36

This too: 1TovuQNX1rxGh5znF2kj6axa

And this: 1TGT26XM4SxWKfLjoCiFEHWT


EDIT: And this: KxsKrcLBQhhwHP1hdXfxGjyaJD7ohqeNDEvZJvYkXvfrnyVenFXX

KxqPaZqwvTQfXKvFmMHzWCLXjCfxpav5AihxqW9iQu7hVGAHu4Sd

5JBx2Gi4xBAusrRQB9LYDt9pr5jR2YSP86wpsndHB58UNPZD2b7

KxJHfrJiBoVzfrFFVbFubQfdJSEP99nggUG3GJZdi6BVakRgMkot

5J4TtPwvLkh6P3YhTnKseoUSz4gYJLq3say49e9RfkhiSvJkLWj

KxJHCcNKrGZUyTedbYyV9DTMnjgEFKJBCcECXcwdmaDNPXVL7UiA

5JBUtWGWQ8ozAi6Wt6mAW8aH2urLAC2RbrKEtyYykeuaXo5FLGD

13wCMKP8aeXjpWWANkCcpwQccyybx1Sv8n

15PpN93pUu3DSftfC9Sz2jMKAWRUotm11h


Yeah, nope.......