bitspill
Legendary
Offline
Activity: 2087
Merit: 1015
|
|
January 31, 2015, 02:43:47 PM |
|
Was just reading more on the Montgomery curve under the arithmetic section, I think we are safe to "ignore" z, him saying z=1 allows us to say X=x and that's all we need the z for. A point P=(x,y) on the elliptic curve in the Montgomery form By^2 = x^3 + Ax^2 + x can be represented in Montgomery coordinates P=(X:Z), where P=(X:Z) are projective coordinates and x=X/Z for Z!=0
|
|
|
|
ndnh
Legendary
Offline
Activity: 1302
Merit: 1005
New Decentralized Nuclear Hobbit
|
|
January 31, 2015, 02:46:36 PM |
|
Was just reading more on the Montgomery curve under the arithmetic section, I think we are safe to "ignore" z, him saying z=1 allows us to say X=x and that's all we need the z for. A point P=(x,y) on the elliptic curve in the Montgomery form By^2 = x^3 + Ax^2 + x can be represented in Montgomery coordinates P=(X:Z), where P=(X:Z) are projective coordinates and x=X/Z for Z!=0 yes, that seems a reasonable interpretation. Should i ignore a as given by ncsupanda. I don't think that ignoring 'a' is right. Mathematically as long as the "a" value remains constant during each new iteration then the effect it has is constant - it's not unnecessary, it just doesn't need to be evaluated for, so it should be fine to set as any integer and leave it alone.
As got the results you got, I don't think you are substituting the equation back into itself for each new x value, I think you are just increasing x by 1 and then repeating the calculation. What you want to be doing is leaving x constant (in this case 9) and then reevaluating each iteration until your new x value matches the next incremented integer value of x (in this case 10).
If I've misunderstood anything, feel free to correct me. That's just how I understand it.
Also, is this the right formula? If so, A=a?
|
|
|
|
ndnh
Legendary
Offline
Activity: 1302
Merit: 1005
New Decentralized Nuclear Hobbit
|
|
January 31, 2015, 02:51:39 PM |
|
How often do you have to perform this operation to get a specific x (basically getting the new_x and feeding it back into the formula to get another new_x, and so on)? that is the exact operation I did. So I was not wrong? I also get an impression that, each one has multiple solutions? which probably explains You can start multiple such chains beginning at x=9, and add the resulting x values ?
|
|
|
|
bitspill
Legendary
Offline
Activity: 2087
Merit: 1015
|
|
January 31, 2015, 03:19:40 PM |
|
Should i ignore a as given by ncsupanda. I don't think that ignoring 'a' is right. Mathematically as long as the "a" value remains constant during each new iteration then the effect it has is constant - it's not unnecessary, it just doesn't need to be evaluated for, so it should be fine to set as any integer and leave it alone.
Also, is this the right formula? If so, A=a? I think 'a' is an arbitrary constant provided by Evil-Knievel From the problem description "Being a some constant," I think is meant to be interpreted as How often do you have to perform this operation to get a specific x (basically getting the new_x and feeding it back into the formula to get another new_x, and so on)? that is the exact operation I did. So I was not wrong? Here's my thinking on the question... x_0 is always 9 a is an arbitrary constant G is the end goal, also an arbitrary number chosen by Evil-Knievel _i is the number of steps through the recursive function you must take to reach G Evil-Knievel is looking for a way to solve '_i' provided any 'a' and any 'G' EDIT: That's not just standard division, it's as he mentioned using inverse modular multiplication, but visually it's depicted as division.
|
|
|
|
crazykiddo
|
|
January 31, 2015, 03:38:06 PM |
|
Did someone solve the problem and get the bounty? What was that mathematical formula for? I heard evil wants to crack bitcoin. This formula is useful for cracking bitcoin?
|
|
|
|
bitspill
Legendary
Offline
Activity: 2087
Merit: 1015
|
|
January 31, 2015, 03:40:19 PM |
|
Did someone solve the problem and get the bounty? What was that mathematical formula for? I heard evil wants to crack bitcoin. This formula is useful for cracking bitcoin?
|
|
|
|
ndnh
Legendary
Offline
Activity: 1302
Merit: 1005
New Decentralized Nuclear Hobbit
|
|
January 31, 2015, 04:38:54 PM |
|
Should i ignore a as given by ncsupanda. I don't think that ignoring 'a' is right. Mathematically as long as the "a" value remains constant during each new iteration then the effect it has is constant - it's not unnecessary, it just doesn't need to be evaluated for, so it should be fine to set as any integer and leave it alone.
Also, is this the right formula? If so, A=a? I think 'a' is an arbitrary constant provided by Evil-Knievel From the problem description "Being a some constant," I think is meant to be interpreted as How often do you have to perform this operation to get a specific x (basically getting the new_x and feeding it back into the formula to get another new_x, and so on)? that is the exact operation I did. So I was not wrong? Here's my thinking on the question... x_0 is always 9 a is an arbitrary constant G is the end goal, also an arbitrary number chosen by Evil-Knievel _i is the number of steps through the recursive function you must take to reach G Evil-Knievel is looking for a way to solve '_i' provided any 'a' and any 'G' EDIT: That's not just standard division, it's as he mentioned using inverse modular multiplication, but visually it's depicted as division. I think you are right. thanks for clarifying it. lol. Been seeing a lot of people asking the same thing.
|
|
|
|
koelen3
Legendary
Offline
Activity: 1022
Merit: 1007
Sooner or later, a man who wears two faces forgets
|
|
January 31, 2015, 08:16:52 PM |
|
Maths always seemed to hard for me But i'll try it
|
|
|
|
redsn0w
Legendary
Offline
Activity: 1778
Merit: 1043
#Free market
|
|
February 01, 2015, 08:21:09 PM Last edit: February 01, 2015, 08:54:21 PM by redsn0w |
|
|
|
|
|
jsmit332
|
|
February 01, 2015, 08:24:44 PM |
|
I would like to know what the winning solution was.
|
|
|
|
brituspol
Sr. Member
Offline
Activity: 458
Merit: 250
From nothing to nothing
|
|
February 01, 2015, 08:42:23 PM |
|
I'm totally confused.
Where is x and y?
Edit: The winners?
|
|
|
|
bitspill
Legendary
Offline
Activity: 2087
Merit: 1015
|
|
February 01, 2015, 08:47:38 PM |
|
There is no winner yet.
|
|
|
|
jsmit332
|
|
February 01, 2015, 08:48:05 PM |
|
There is no winner yet.
Where have the funds gone then? Why has Evil-Kinevel moved the BTC?
|
|
|
|
brituspol
Sr. Member
Offline
Activity: 458
Merit: 250
From nothing to nothing
|
|
February 01, 2015, 08:49:15 PM |
|
There is no winner yet.
Where have the funds gone then? Why has Evil-Kinevel moved the BTC? Lol, Those two transactions are not found in blockchain. Found.
|
|
|
|
bitspill
Legendary
Offline
Activity: 2087
Merit: 1015
|
|
February 01, 2015, 08:53:53 PM |
|
There is no winner yet.
Where have the funds gone then? Why has Evil-Kinevel moved the BTC? Look at replies 45, 46, 65, 66 and a few others. The balance was selected by his wallet to pay one of his other bounties
|
|
|
|
caga
Full Member
Offline
Activity: 238
Merit: 100
www.secondstrade.com - 190% return Binary option
|
|
February 01, 2015, 09:38:00 PM |
|
I emember op requested for the solution to be messaged to him in private. He might have got the solution, and might now share. But I was hoping to see a confirmation if there was a winner.
|
|
|
|
Watoshi-Dimobuto
|
|
February 02, 2015, 05:18:22 AM |
|
There is no winner yet.
Where have the funds gone then? Why has Evil-Kinevel moved the BTC? Look at replies 45, 46, 65, 66 and a few others. The balance was selected by his wallet to pay one of his other bounties Put that in a large font size. Too many people asking the same question. Don't bother answering them all. Solution not yet found.
|
|
|
|
chronicsky
Legendary
Offline
Activity: 2828
Merit: 1222
Just looking for peace
|
|
February 04, 2015, 10:28:06 AM |
|
Can the OP confirm if the solution has still not been found?
|
|
|
|
Evil-Knievel (OP)
Legendary
Offline
Activity: 1260
Merit: 1168
|
|
February 04, 2015, 10:32:40 AM Last edit: April 17, 2016, 07:58:27 PM by Evil-Knievel |
|
This message was too old and has been purged
|
|
|
|
Evil-Knievel (OP)
Legendary
Offline
Activity: 1260
Merit: 1168
|
|
February 04, 2015, 10:33:04 AM Last edit: April 17, 2016, 07:58:20 PM by Evil-Knievel |
|
This message was too old and has been purged
|
|
|
|
|