bitspill
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January 31, 2015, 02:43:47 PM |
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Was just reading more on the Montgomery curve under the arithmetic section, I think we are safe to "ignore" z, him saying z=1 allows us to say X=x and that's all we need the z for. A point P=(x,y) on the elliptic curve in the Montgomery form By^2 = x^3 + Ax^2 + x can be represented in Montgomery coordinates P=(X:Z), where P=(X:Z) are projective coordinates and x=X/Z for Z!=0
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ndnh
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January 31, 2015, 02:46:36 PM |
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Was just reading more on the Montgomery curve under the arithmetic section, I think we are safe to "ignore" z, him saying z=1 allows us to say X=x and that's all we need the z for. A point P=(x,y) on the elliptic curve in the Montgomery form By^2 = x^3 + Ax^2 + x can be represented in Montgomery coordinates P=(X:Z), where P=(X:Z) are projective coordinates and x=X/Z for Z!=0 yes, that seems a reasonable interpretation. Should i ignore a as given by ncsupanda. I don't think that ignoring 'a' is right. Mathematically as long as the "a" value remains constant during each new iteration then the effect it has is constant - it's not unnecessary, it just doesn't need to be evaluated for, so it should be fine to set as any integer and leave it alone.
As got the results you got, I don't think you are substituting the equation back into itself for each new x value, I think you are just increasing x by 1 and then repeating the calculation. What you want to be doing is leaving x constant (in this case 9) and then reevaluating each iteration until your new x value matches the next incremented integer value of x (in this case 10).
If I've misunderstood anything, feel free to correct me. That's just how I understand it.
Also, is this ![](https://ip.bitcointalk.org/?u=http%3A%2F%2Fi.gyazo.com%2F44c0566495e87ced1a180840c2fb9555.png&t=662&c=3y-gYSpbTi7UfQ) the right formula? If so, A=a?
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ndnh
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January 31, 2015, 02:51:39 PM |
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How often do you have to perform this operation to get a specific x (basically getting the new_x and feeding it back into the formula to get another new_x, and so on)? that is the exact operation I did. So I was not wrong? I also get an impression that, each one has multiple solutions? which probably explains You can start multiple such chains beginning at x=9, and add the resulting x values ?
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bitspill
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January 31, 2015, 03:19:40 PM |
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Should i ignore a as given by ncsupanda. I don't think that ignoring 'a' is right. Mathematically as long as the "a" value remains constant during each new iteration then the effect it has is constant - it's not unnecessary, it just doesn't need to be evaluated for, so it should be fine to set as any integer and leave it alone.
Also, is this ![](https://ip.bitcointalk.org/?u=http%3A%2F%2Fi.gyazo.com%2F44c0566495e87ced1a180840c2fb9555.png&t=662&c=3y-gYSpbTi7UfQ) the right formula? If so, A=a? I think 'a' is an arbitrary constant provided by Evil-Knievel From the problem description "Being a some constant," I think is meant to be interpreted as How often do you have to perform this operation to get a specific x (basically getting the new_x and feeding it back into the formula to get another new_x, and so on)? that is the exact operation I did. So I was not wrong? Here's my thinking on the question... ![](https://ip.bitcointalk.org/?u=https%3A%2F%2Fi.imgur.com%2FE4WgWN0.png&t=662&c=W9C_4qGFCseyAw) x_0 is always 9 a is an arbitrary constant G is the end goal, also an arbitrary number chosen by Evil-Knievel _i is the number of steps through the recursive function you must take to reach G Evil-Knievel is looking for a way to solve '_i' provided any 'a' and any 'G' EDIT: That's not just standard division, it's as he mentioned using inverse modular multiplication, but visually it's depicted as division.
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crazykiddo
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January 31, 2015, 03:38:06 PM |
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Did someone solve the problem and get the bounty? What was that mathematical formula for? I heard evil wants to crack bitcoin. This formula is useful for cracking bitcoin?
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bitspill
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January 31, 2015, 03:40:19 PM |
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Did someone solve the problem and get the bounty? What was that mathematical formula for? I heard evil wants to crack bitcoin. This formula is useful for cracking bitcoin?
![](https://ip.bitcointalk.org/?u=http%3A%2F%2Fimg2.wikia.nocookie.net%2F__cb20140808184223%2Fbloodbrothersgame%2Fimages%2Fc%2Fc7%2FImplied_facepalm.jpg&t=662&c=I-8072lZhy1G2Q)
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ndnh
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January 31, 2015, 04:38:54 PM |
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Should i ignore a as given by ncsupanda. I don't think that ignoring 'a' is right. Mathematically as long as the "a" value remains constant during each new iteration then the effect it has is constant - it's not unnecessary, it just doesn't need to be evaluated for, so it should be fine to set as any integer and leave it alone.
Also, is this ![](https://ip.bitcointalk.org/?u=http%3A%2F%2Fi.gyazo.com%2F44c0566495e87ced1a180840c2fb9555.png&t=662&c=3y-gYSpbTi7UfQ) the right formula? If so, A=a? I think 'a' is an arbitrary constant provided by Evil-Knievel From the problem description "Being a some constant," I think is meant to be interpreted as How often do you have to perform this operation to get a specific x (basically getting the new_x and feeding it back into the formula to get another new_x, and so on)? that is the exact operation I did. So I was not wrong? Here's my thinking on the question... ![](https://ip.bitcointalk.org/?u=https%3A%2F%2Fi.imgur.com%2FE4WgWN0.png&t=662&c=W9C_4qGFCseyAw) x_0 is always 9 a is an arbitrary constant G is the end goal, also an arbitrary number chosen by Evil-Knievel _i is the number of steps through the recursive function you must take to reach G Evil-Knievel is looking for a way to solve '_i' provided any 'a' and any 'G' EDIT: That's not just standard division, it's as he mentioned using inverse modular multiplication, but visually it's depicted as division. I think you are right. thanks for clarifying it. ![Smiley](https://bitcointalk.org/Smileys/default/smiley.gif) lol. ![Smiley](https://bitcointalk.org/Smileys/default/smiley.gif) Been seeing a lot of people asking the same thing.
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koelen3
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January 31, 2015, 08:16:52 PM |
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Maths always seemed to hard for me ![Sad](https://bitcointalk.org/Smileys/default/sad.gif) But i'll try it
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redsn0w
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February 01, 2015, 08:21:09 PM Last edit: February 01, 2015, 08:54:21 PM by redsn0w |
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jsmit332
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February 01, 2015, 08:24:44 PM |
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I would like to know what the winning solution was.
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brituspol
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February 01, 2015, 08:42:23 PM |
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I'm totally confused.
Where is x and y?
Edit: The winners?
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bitspill
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February 01, 2015, 08:47:38 PM |
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There is no winner yet.
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jsmit332
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February 01, 2015, 08:48:05 PM |
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There is no winner yet.
Where have the funds gone then? Why has Evil-Kinevel moved the BTC?
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brituspol
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February 01, 2015, 08:49:15 PM |
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There is no winner yet.
Where have the funds gone then? Why has Evil-Kinevel moved the BTC? Lol, Those two transactions are not found in blockchain. Found.
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bitspill
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February 01, 2015, 08:53:53 PM |
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There is no winner yet.
Where have the funds gone then? Why has Evil-Kinevel moved the BTC? Look at replies 45, 46, 65, 66 and a few others. The balance was selected by his wallet to pay one of his other bounties
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caga
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February 01, 2015, 09:38:00 PM |
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I emember op requested for the solution to be messaged to him in private. He might have got the solution, and might now share. But I was hoping to see a confirmation if there was a winner.
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Watoshi-Dimobuto
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February 02, 2015, 05:18:22 AM |
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There is no winner yet.
Where have the funds gone then? Why has Evil-Kinevel moved the BTC? Look at replies 45, 46, 65, 66 and a few others. The balance was selected by his wallet to pay one of his other bounties Put that in a large font size. Too many people asking the same question. Don't bother answering them all. Solution not yet found.
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chronicsky
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February 04, 2015, 10:28:06 AM |
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Can the OP confirm if the solution has still not been found?
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Evil-Knievel (OP)
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February 04, 2015, 10:32:40 AM Last edit: April 17, 2016, 07:58:27 PM by Evil-Knievel |
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This message was too old and has been purged
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Evil-Knievel (OP)
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February 04, 2015, 10:33:04 AM Last edit: April 17, 2016, 07:58:20 PM by Evil-Knievel |
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This message was too old and has been purged
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