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Author Topic: Alternative Electricity for Mining  (Read 28066 times)
chipless (OP)
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January 08, 2019, 05:39:51 AM
 #101

your missing the point if you want to run this free then put a prop on your wind turbine it then becomes free this system is replacing the prop with an electric motor to reduce the power cost not to make it free instead of driving the wind generator with wind you are driving it with an electric motor

you can't replace 2000w of wind power with 500w of electric power and expect the same output.

i'm still not seeing any proof provided here. i wonder why? Smiley

I didnt know the wind contained watts. I did know it uses energy in the form of movement and in a tornado the wind can be circular until it runs out of energy. But never knew it contained watts.

you don't seem to know a lot of things....

1W = 1J/s. it's literally energy per second.

next you'll tell us that you didn't know wind had energy.  Cheesy Cheesy Cheesy

Fine you win put the blades on it and then use your leaf blower to blow some air on it and now you have your full wind system with 150mph wind. Now your only cost is to run your leaf blower unless you can keep blowing so much air yourself

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gsrcrxsi314
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January 08, 2019, 05:51:37 AM
 #102

and now you've proven you're trolling.

that's all folks! glad no one else will be stupid enough to try this.
chipless (OP)
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January 08, 2019, 05:57:48 AM
 #103

and now you've proven you're trolling.

that's all folks! glad no one else will be stupid enough to try this.

I caught your wife trollin sent her on her way though something smelt a little fishy.

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mattstyle
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January 08, 2019, 05:58:42 AM
 #104

I see this.

http://mwands.com/store/freedom-ii-hydro-pmg-permanent-magnet-generator?search=hydro

900 rpms  to charge at 48v  and is rated for 2800 watts the electric 1/4 hp motor does 1750 rpms

I just so happen to have a 48v golf cart next to 4 mining rigs running on a 230v PDU consuming 13.3 amps (~3000 watts)..  would be pretty easy to test this..

Planning on adding solar / wind eventually so will use components for that..




maybe there's too much resistance added though when there is a LOAD on these things.. .
chipless (OP)
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January 08, 2019, 06:04:49 AM
 #105

I see this.

http://mwands.com/store/freedom-ii-hydro-pmg-permanent-magnet-generator?search=hydro

900 rpms  to charge at 48v  and is rated for 2800 watts the electric 1/4 hp motor does 1750 rpms

I just so happen to have a 48v golf cart next to 4 mining rigs running on a 230v PDU consuming 13.3 amps (~3000 watts)..  would be pretty easy to test this..

Planning on adding solar / wind eventually so will use components for that..






If you need things look at missouri wind and solar they have a nice variety and reasonable prices. Golf cart batts work great  Grin they take a good beating

This site is good for configuring the pulley system

https://www.blocklayer.com/pulley-belteng.aspx


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solarforce
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January 08, 2019, 06:09:31 AM
Last edit: January 08, 2019, 06:41:41 AM by solarforce
 #106

I see this.

http://mwands.com/store/freedom-ii-hydro-pmg-permanent-magnet-generator?search=hydro

900 rpms  to charge at 48v  and is rated for 2800 watts the electric 1/4 hp motor does 1750 rpms

I just so happen to have a 48v golf cart next to 4 mining rigs running on a 230v PDU consuming 13.3 amps (~3000 watts)..  would be pretty easy to test this..

Planning on adding solar / wind eventually so will use components for that..





atleast you comprehend if you look at the chart in the link you posted you will see in the picture the wind speed to power conversion now convert that wind speed to rpm and you will know at what rpm the generator will need to spin at to get the desired output wattage at its rated voltage you will need approximately 47 mph wind speed to produce 2000 watts convert 47 mph to rpm and use an electric motor with a pulley drive ratio to achieve that rpm for example a motor with 1725 rpm at 1 to 3 would result in 5175 rpm
chipless (OP)
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January 08, 2019, 06:25:28 AM
Last edit: January 08, 2019, 06:41:47 AM by chipless
 #107

1750 motor rpm at 1:4.5 ratio will get you 7875 rpm which gives you a surface speed of 4123.3 fpm when you convert 4123.3 fpm you get a rotational speed of 46.8556818 mph which is enough speed to run the generator head at full output. So a 9 inch pulley on motor and 2 inch on generator is the only thing to configure for the simulated wind speed. If you use different pulleys then you need to make sure you stay at or above the same fpm travel on the belt surface speed

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solarforce
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January 08, 2019, 06:26:46 AM
Last edit: January 08, 2019, 06:39:09 AM by solarforce
 #108

I see this.

http://mwands.com/store/freedom-ii-hydro-pmg-permanent-magnet-generator?search=hydro

900 rpms  to charge at 48v  and is rated for 2800 watts the electric 1/4 hp motor does 1750 rpms

I just so happen to have a 48v golf cart next to 4 mining rigs running on a 230v PDU consuming 13.3 amps (~3000 watts)..  would be pretty easy to test this..

Planning on adding solar / wind eventually so will use components for that..





atleast you comprehend if you look at the chart in the link you posted you will see in the picture the wind speed to power conversion now convert that wind speed to rpm and you will know at what rpm the generator will need to spin at to get the desired output wattage at its rated voltage you will need approximately 47 mph wind speed to produce 2000 watts convert 47 mph to rpm and use an electric motor with a pulley drive ratio to achieve that rpm for example a motor with 1725 rpm at 1 to 3 would result in 5175 rpm
24 volts at 2000 watts is approx 83 amps output
mattstyle
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January 08, 2019, 08:53:14 AM
 #109

sounds cool.. BUT before spending thousands, I'm going to try this on a SMALL scale..

using this cool little generator and some pulleys.. 
https://www.amazon.com/gp/product/B075NQ7GC1/

hydro seems the way to go if you have a river...

mattcode
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January 08, 2019, 10:35:37 AM
 #110

Spoilers: chipless works at a major battery manufacturer

Or a mental asylum.

... How are you going to apply 500W of power to rotating a generator and expect the generator to be able to output more than the input 500W (theoretical 100% efficiency) Huh

Your not directly but with the pullies you can.

What do you think your pulleys/gears/whatevers do? They balance speed and torque, you don't magically get more power at the other end.
chipless (OP)
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January 08, 2019, 06:00:02 PM
 #111

Spoilers: chipless works at a major battery manufacturer

Or a mental asylum.

... How are you going to apply 500W of power to rotating a generator and expect the generator to be able to output more than the input 500W (theoretical 100% efficiency) Huh

Your not directly but with the pullies you can.

What do you think your pulleys/gears/whatevers do? They balance speed and torque, you don't magically get more power at the other end.

Thats because you are stupid or playing stupid then because it has been stated how it is done.

You are not applying 500w you are using 500w to turn the motor which in return is creating the rotational speed of 1750 rpm.

So i am applying 500w of rotational speed that is then converted to the equivelent of 47 mph wind with a pulley

The 47mph simulated wind speed is then turning the GENERATOR which from 47mph speed produces 2000 watts of power
now I am using the 2000w to energize the batteries which in return powers the inverter.

Which again converts the 2000w into usable ac. 24vdc @2200 watts with a battery bank of 8x 150ah gives you 1166 amps which when converted to ac 220 gives you 127a of useable ac @220v

SO the only power you need is to keep the battery bank charged 2000w of charging power is 83 amps as long as you dont go over using the 83 amp charging power you are fine if you do your batteries discharge at a slow rate eventually stopping at the charge input power. If you need more power you add a second generator head to the mix and now have 166 amps charging power and so on.

YOU clearly do not understand this process or how a charging and inverter system works when a battery is involved.

A grade school kid can understand this process and how it works so come on some of you are grown adults and you are arguing it cant happen.

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Metroid
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January 08, 2019, 06:19:02 PM
Last edit: January 08, 2019, 06:37:40 PM by Metroid
 #112


You are not applying 500w you are using 500w to turn the motor which in return is creating the rotational speed of 1750 rpm.

So i am applying 500w of rotational speed that is then converted to the equivelent of 47 mph wind with a pulley

I want to ask and i already said that an extractor of air that consumes 150 watts has 1750rpm. How is that different from consuming 500 watts instead of 150 watts? As I see what we need is 1750 rpm right to give air blowing speed of 47mph?

also to convert rpm to mph, https://sciencing.com/convert-rpm-mph-calculator-2854.html

Quote
For example, if the rotational speed is 100 rpm, enter "100." Multiply this number by 60 to convert it from feet per minute to feet per hour. Divide this number by 5,280, which converts feet per hour to miles per hour. Push the equal sign to see the speed in mph.

Using that webpage to calculate it, it gave me the number of 20 mph, 1750 x 60 =105.000, divide by 5280 = 19.88 mph.

Maybe your 500 watts 1750rpm is not 1750rpm, more like 4200rpm. That explains why it uses 500 watts. 3 x 150w = 450 watts.

The noise a 4200rpm generates kill everything in few meters.

Also what i think is the most important is the cfm and the cfm is related to diameter and rpm.

Generating electricity from wasting electricity, i wonder is that is really viable or just a waste of time.

The wind turbine works better with? 30cm, 40cm, 50cm, 60cm, 70cm exhaustor? and I guess it has to be very close or with a good connection with pipes, cause it can not have any leaks.

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chipless (OP)
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January 08, 2019, 06:37:14 PM
 #113


You are not applying 500w you are using 500w to turn the motor which in return is creating the rotational speed of 1750 rpm.

So i am applying 500w of rotational speed that is then converted to the equivelent of 47 mph wind with a pulley

I want to ask and i already said that an extractor of air that consumes 150 watts has 1750rpm. How is that different from consuming 500 watts instead of 150 watts? As I see what we need is 1750 rpm right to give air blowing speed of 47mph?

also to convert rpm to mph, https://sciencing.com/convert-rpm-mph-calculator-2854.html

Quote
For example, if the rotational speed is 100 rpm, enter "100." Multiply this number by 60 to convert it from feet per minute to feet per hour. Divide this number by 5,280, which converts feet per hour to miles per hour. Push the equal sign to see the speed in mph.

Using that webpage to calculate it, it gave me the number of 20 mph, 1750 x 60 =105.000, divide by 5280 = 19.88 mph.

You didnt take into account the pulley ratio of 1:4.5 we are not building a direct drive unit

The 1750 rpm is the starting point for the rpm the 1:4.5 pulley ratio turns your 1750 rpm into 7875 rpm which is then enough to power the generator at full power.

A simple bathroom fan dont have enough torque that is why you use a bigger motor that does have some torque to it and if it uses 5 amps great if it uses 10 amps ok and so on.

The goal is to use the least amount of energy to get the 7875 rpm needed to turn the generator head.

The belt surface speed needs to be at 7875 rpm which is equivalent to a 47 mph wind. Now you have 83 amps of charging power instead of 500 watts of charging power that you initially started with.

A car alternator for example does not run at the rpm the engine is running at the pulley configuration takes the 2000 rpm from the cars engine and turns it into about 6000rpm at the alternator.

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dhmctrader
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January 08, 2019, 06:38:26 PM
 #114

I'm still not getting it...

So, your motor and generator can provide 2000 W...

This 2000 W is available to power the inverter and charge the batteries...

The inverter is 90% efficient...

If it is consuming the entire 2000 W available then at 90% efficiency it is only making 1800 W for the mining rig.

chipless (OP)
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January 08, 2019, 06:46:54 PM
 #115

I'm still not getting it...

So, your motor and generator can provide 2000 W...

This 2000 W is available to power the inverter and charge the batteries...

The inverter is 90% efficient...

If it is consuming the entire 2000 W available then at 90% efficiency it is only making 1800 W for the mining rig.



The motor and generator head alone nothing else attached can produce 2000 watts if you use 500 watts to turn the generator head then you are saving 1500 watts worth or money right there. Now when you throw batteries and inverter in the mix you can increase the 2000 watts to much more power while still using only 500w to spin the motor. Yes you will have some power loss no doubt but as long as you are putting out more energy then it takes to get you to that point you are saving money

I also have designed a hydro type unit but that one is fully self powering and runs on water but those designs wont be released since I do sell many of them to lake home owner to power their dock lights.

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January 08, 2019, 06:49:15 PM
 #116


You didnt take into account the pulley ratio of 1:4.5 we are not building a direct drive unit

The 1750 rpm is the starting point for the rpm the 1:4.5 pulley ratio turns your 1750 rpm into 7875 rpm which is then enough to power the generator at full power.

A simple bathroom fan dont have enough torque that is why you use a bigger motor that does have some torque to it and if it uses 5 amps great if it uses 10 amps ok and so on.

The goal is to use the least amount of energy to get the 7875 rpm needed to turn the generator head.

The belt surface speed needs to be at 7875 rpm which is equivalent to a 47 mph wind. Now you have 83 amps of charging power instead of 500 watts of charging power that you initially started with.

In theory and how you explained makes sense but if it does exactly how you say is something else.

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chipless (OP)
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January 08, 2019, 06:53:33 PM
Last edit: January 08, 2019, 07:05:24 PM by chipless
 #117


You didnt take into account the pulley ratio of 1:4.5 we are not building a direct drive unit

The 1750 rpm is the starting point for the rpm the 1:4.5 pulley ratio turns your 1750 rpm into 7875 rpm which is then enough to power the generator at full power.

A simple bathroom fan dont have enough torque that is why you use a bigger motor that does have some torque to it and if it uses 5 amps great if it uses 10 amps ok and so on.

The goal is to use the least amount of energy to get the 7875 rpm needed to turn the generator head.

The belt surface speed needs to be at 7875 rpm which is equivalent to a 47 mph wind. Now you have 83 amps of charging power instead of 500 watts of charging power that you initially started with.

In theory and how you explained makes sense but if it does exactly how you say is something else.

It does exactly what I say it does... If it didnt there wouldnt be people using off-grid systems. Al I am doing is replacing the wind with a motor to do the winds job. A motor cost to run so it is not free but if you had enough constant wind you can run it by wind

There are similar units that run from a bicycle.

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solarforce
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January 08, 2019, 07:17:02 PM
Last edit: January 08, 2019, 07:31:33 PM by solarforce
 #118

I'm still not getting it...

So, your motor and generator can provide 2000 W...

This 2000 W is available to power the inverter and charge the batteries...

The inverter is 90% efficient...

If it is consuming the entire 2000 W available then at 90% efficiency it is only making 1800 W for the mining rig.


the generators power output is rpm dependent basically the faster you spin it the more the power it produces.
so at peak rpm at 24 volts it would produce 2000 watts if you convert watts to amps that would give approximately 83 amps of output power.
if you ran 2 generators in parallel you would produce the same 24 volts but now 2 times the amperage or 2000 + 2000 is 4000 watts / 24 volts
 =about 166 amps. we would then have 166 amps of charge power at 24 volts to charge the battery bank the battery bank is used to power the power inverter.
without going into detail about my knowledge or what i do for a living i can tell you this does and will work.
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January 08, 2019, 07:54:47 PM
 #119

This idiot keeps saying all you need to do is keep the batteries charged.

If you are discharging the batteries at a rate of 60kW, the batteries have to be charged by at least 60kW. Yes, I agree if you have a 60kW generator like this one http://www.generac.com/Industrial/products/diesel-generators/configured/60kw-diesel-generator and hook some batteries up to it, you can put out 60kW of electricity. According to this article: https://www.ablesales.com.au/blog/diesel-generator-fuel-consumption-chart-in-litres.html a 60kW generator will require 4.25 gallons of Diesel per hour. Diesel is generally $3/gal, so you're looking at $13/hr in Diesel.

That gives you 21 cents per kWh. That's well more expensive than grid electricity. Any electricity you're not inputting from a generator, you're inputting from the grid. There is no configuation of battery/generator/grid/converter/alternator/whatever that gets around this middle school fact. Seriously, you're talking to people with science degrees with absolutely no knowledge of what you're saying. If you're happy paying a diesel bill rather than an electric bill, good for you. But it's not cheaper, so just fucking stop. For anyone gullible, think of the wattage as the actual ENERGY, dont get bogged down by "amperage, current, voltage, resistance, efficiency" etc. It all comes down to energy. Inverters/Batteries obviously dont create energy. So ask yourself, if he's running 10 x 1800w rigs, where's the actual ENERGY (not current, not amperage, not voltage, literal capacity to do work, energy) coming from? Is it coming from the generator? Or is it coming from the grid? Those are the ONLY TWO things contributing ENERGY (besides some people pointing out solar panels which pay for themselves after some years). Every fucking watt you're not pulling from the wall, you have to pull from a generator. Not amps, not volts, watts. If you pull 1800w from the wall, you HAVE to pull 9 x 1800w out of a fucking generator to run 10 rigs. The only other possible way is if you're running the rigs till all the batteries are totally dead after a few minutes, and then slowly recharging them over the course of a day.

Think about it this way, you're using your phone and it requires 18W to run. He's trying to convince you that plugging your phone in to the wall with a 12v 0.5A charger will keep the phone running perpetully. That's fucking stupid, you know your phone battery will still die unless you turn it off or get a beefier charger for it.
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January 08, 2019, 07:58:26 PM
 #120


You didnt take into account the pulley ratio of 1:4.5 we are not building a direct drive unit

The 1750 rpm is the starting point for the rpm the 1:4.5 pulley ratio turns your 1750 rpm into 7875 rpm which is then enough to power the generator at full power.

A simple bathroom fan dont have enough torque that is why you use a bigger motor that does have some torque to it and if it uses 5 amps great if it uses 10 amps ok and so on.

The goal is to use the least amount of energy to get the 7875 rpm needed to turn the generator head.

The belt surface speed needs to be at 7875 rpm which is equivalent to a 47 mph wind. Now you have 83 amps of charging power instead of 500 watts of charging power that you initially started with.

In theory and how you explained makes sense but if it does exactly how you say is something else.
No it does not, but please feed the troll more, this is awesome.
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