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[vpncoin]

My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?

1) me - 80d (how far was I from win?)
2) you - 1bf
3) win - a77 (where can I see this number?)
4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"

You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.

Use getblockhash cmd to get target block's HASH:

Code:

getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If you set last N byte's "N" = 3, the right number is "461",
If you bet digit value, the right number is 11, why?
Bcz that: 4 + 6 + 1 = 11

Thank you. In my last example - the reason why I didn't win was that my bet amount was too low?

a77 = 2679 decimal (winning)
80d = 2061 decimal (me)
1bf = 447 decimal (you)

I use a single character's digit value, and them add.

[1714592160]

1714592160

[1714592160]

1714592160

[1714592160]

1714592160

[marek3ball-orig]

My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?

1) me - 80d (how far was I from win?)
2) you - 1bf
3) win - a77 (where can I see this number?)
4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"

You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.

Use getblockhash cmd to get target block's HASH:

Code:

getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If you set last N byte's "N" = 3, the right number is "461",
If you bet digit value, the right number is 11, why?
Bcz that: 4 + 6 + 1 = 11

Thank you. In my last example - the reason why I didn't win was that my bet amount was too low?

a77 = 2679 decimal (winning)
80d = 2061 decimal (me)
1bf = 447 decimal (you)

I use a single character's digit value, and them add.

This is what you mean?

(last N byte):
 a77 = 10+7+7 = 24

(last N byte)'s digit value:
 a77 = 2679

Are these both examples correct?

[Seccour]

VPNcoin can now be use on the NXT network ! The asset is own by the user yiiy on the nxtforum, proof here.

Name: vpn2nxt (vpncoin)
Asset ID:  1989622569661755686
Issuing Account: NXT-WSHC-U9Z4-BKN6-543CS
Total Assets: 40,000,000
兑换流程：
VPN-->NXT:发送vpncoin到以下地址: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4，并附加留言注明接收vpn2nxt资产的NXT钱包地址(不能使用交易平台地址，必须是自己钱包地址）。收到vpncoin后，会将同等数量的vpn2nxt资产发送到相应的nxt地址。（充值限额：1-500万）
NXT-->VPN:购买vpn2nxt资产后，将资产发送到资产的发行账号NXT-WSHC-U9Z4-BKN6-543CS，并留言注明接收vpncoin的钱包地址。收到资产后，会将同等数量的vpncoin发送到相应的vpncoin地址。

Cash flow:
VPN-->NXT.
Send vpncoin to the following address: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4, and additional message marked NXT wallet address to receiving vpn2nxt assets（Only wallet address.Trading platform address can't be use.）. After receiving vpncoin, I will send an equal number of vpn2nxt assets to the corresponding NXT address. (recharge limit: 1-5,000,000)
NXT-->VPN.
Buy vpn2nxt assets, then send assets to Issuing Account：NXT-WSHC-U9Z4-BKN6-543CS, and additional message marked receiving Vpncoin wallet address. After receiving assets, I will send the same amount of vpncoin to the corresponding vpncoin address.

Vpncoin,  www.bitnet.wang
vpn2cny, https://yuanbaohui.com/trade/vpn2cny
--------vpn2nxt QQqun 319439561------

[vpncoin]

VPNcoin can now be use on the NXT network ! The asset is own by the user yiiy on the nxtforum, proof here.

Name: vpn2nxt (vpncoin)
Asset ID:  1989622569661755686
Issuing Account: NXT-WSHC-U9Z4-BKN6-543CS
Total Assets: 40,000,000
兑换流程：
VPN-->NXT:发送vpncoin到以下地址: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4，并附加留言注明接收vpn2nxt资产的NXT钱包地址(不能使用交易平台地址，必须是自己钱包地址）。收到vpncoin后，会将同等数量的vpn2nxt资产发送到相应的nxt地址。（充值限额：1-500万）
NXT-->VPN:购买vpn2nxt资产后，将资产发送到资产的发行账号NXT-WSHC-U9Z4-BKN6-543CS，并留言注明接收vpncoin的钱包地址。收到资产后，会将同等数量的vpncoin发送到相应的vpncoin地址。

Cash flow:
VPN-->NXT.
Send vpncoin to the following address: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4, and additional message marked NXT wallet address to receiving vpn2nxt assets（Only wallet address.Trading platform address can't be use.）. After receiving vpncoin, I will send an equal number of vpn2nxt assets to the corresponding NXT address. (recharge limit: 1-5,000,000)
NXT-->VPN.
Buy vpn2nxt assets, then send assets to Issuing Account：NXT-WSHC-U9Z4-BKN6-543CS, and additional message marked receiving Vpncoin wallet address. After receiving assets, I will send the same amount of vpncoin to the corresponding vpncoin address.

Vpncoin,  www.bitnet.wang
vpn2cny, https://yuanbaohui.com/trade/vpn2cny
--------vpn2nxt QQqun 319439561------

Nice work,
Thank you very much.

[vpncoin]

My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?

1) me - 80d (how far was I from win?)
2) you - 1bf
3) win - a77 (where can I see this number?)
4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"

You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.

Use getblockhash cmd to get target block's HASH:

Code:

getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If you set last N byte's "N" = 3, the right number is "461",
If you bet digit value, the right number is 11, why?
Bcz that: 4 + 6 + 1 = 11

Thank you. In my last example - the reason why I didn't win was that my bet amount was too low?

a77 = 2679 decimal (winning)
80d = 2061 decimal (me)
1bf = 447 decimal (you)

I use a single character's digit value, and them add.

This is what you mean?

(last N byte):
 a77 = 10+7+7 = 24

(last N byte)'s digit value:
 a77 = 2679

Are these both examples correct?

Our Lottery have 2 guess type.
1, Guess a block's HASH, last N byte.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 3, then the right answer is 461.

2, Guess a block's HASH, last N byte's digit value.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12

[marek3ball-orig]

My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?

1) me - 80d (how far was I from win?)
2) you - 1bf
3) win - a77 (where can I see this number?)
4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"

You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.

Use getblockhash cmd to get target block's HASH:

Code:

getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If you set last N byte's "N" = 3, the right number is "461",
If you bet digit value, the right number is 11, why?
Bcz that: 4 + 6 + 1 = 11

Thank you. In my last example - the reason why I didn't win was that my bet amount was too low?

a77 = 2679 decimal (winning)
80d = 2061 decimal (me)
1bf = 447 decimal (you)

I use a single character's digit value, and them add.

This is what you mean?

(last N byte):
 a77 = 10+7+7 = 24

(last N byte)'s digit value:
 a77 = 2679

Are these both examples correct?

Our Lottery have 2 guess type.
1, Guess a block's HASH, last N byte.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 3, then the right answer is 461.

2, Guess a block's HASH, last N byte's digit value.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12

I still don't understand - you explained the last bet here: https://bitcointalk.org/index.php?topic=789961.msg11498167#msg11498167
and you told me that I should calculate it as 4 + 6 + 1 = 11 ---> but the bet was not N byte's digit value (guess type 2)

Based on your last example I should see it as a HEX number 461.

Maybe I'm still missing something important.

[vpncoin]

My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?

1) me - 80d (how far was I from win?)
2) you - 1bf
3) win - a77 (where can I see this number?)
4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"

You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.

Use getblockhash cmd to get target block's HASH:

Code:

getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If you set last N byte's "N" = 3, the right number is "461",
If you bet digit value, the right number is 11, why?
Bcz that: 4 + 6 + 1 = 11

Thank you. In my last example - the reason why I didn't win was that my bet amount was too low?

a77 = 2679 decimal (winning)
80d = 2061 decimal (me)
1bf = 447 decimal (you)

I use a single character's digit value, and them add.

This is what you mean?

(last N byte):
 a77 = 10+7+7 = 24

(last N byte)'s digit value:
 a77 = 2679

Are these both examples correct?

Our Lottery have 2 guess type.
1, Guess a block's HASH, last N byte.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 3, then the right answer is 461.

2, Guess a block's HASH, last N byte's digit value.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12

I still don't understand - you explained the last bet here: https://bitcointalk.org/index.php?topic=789961.msg11498167#msg11498167
and you told me that I should calculate it as 4 + 6 + 1 = 11 ---> but the bet was not N byte's digit value (guess type 2)

Based on your last example I should see it as a HEX number 461.

Maybe I'm still missing something important.

My English is not good, sorry

[marek3ball-orig]

Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

[Hueristic]

Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal  
Is this right?

Thank you for your work!

369=18 I think the way he's doing decimal representation of hex values. It is confusing and the only reason I can think of to do this is to make it a 2 digit guess. FFF=45 000=00

Bet 50 on every value possible. I would but I'm far to lazy.

[vpncoin]

Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

No

The last lottery is guess block's HASH's last N byte, it is hex string, not digit value.
Hex includes "0 ~ F".

[vpncoin]

Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal  
Is this right?

Thank you for your work!

369=18 I think the way he's doing decimal representation of hex values. It is confusing and the only reason I can think of to do this is to make it a 2 digit guess. FFF=45 000=00

Bet 50 on every value possible. I would but I'm far to lazy.

"369" is Hex string, the last lottery is guess block HASH's last N bytes HEX string, not digit value.

[terman45x]

Is there any statistics on actual vpn usage? Like the last month?

[vpncoin]

Mac version coming soon.

[vpncoin]

Is there any statistics on actual vpn usage? Like the last month?

Android dial app is testing...

[Seccour]

Thanks for the news !

[marek3ball-orig]

Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

No

The last lottery is guess block's HASH's last N byte, it is hex string, not digit value.
Hex includes "0 ~ F".

Good we are almost there.

Now when I know it is not digit value type. How do I calculate result of "369" in this case?

[vpncoin]

Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

No

The last lottery is guess block's HASH's last N byte, it is hex string, not digit value.
Hex includes "0 ~ F".

Good we are almost there.

Now when I know it is not digit value type. How do I calculate result of "369" in this case?

369 is my guess,
You need bet your text,
The answer in the future, is unknown.

[terman45x]

Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

No

The last lottery is guess block's HASH's last N byte, it is hex string, not digit value.
Hex includes "0 ~ F".

Good we are almost there.

Now when I know it is not digit value type. How do I calculate result of "369" in this case?

369 is my guess,
You need bet your text,
The answer in the future, is unknown.

More like 392. Just watch and see.

[vpncoin]

More like 392. Just watch and see.

+1

It is Hex string, just wait...

[claycoins]

Is there any statistics on actual vpn usage? Like the last month?

Android dial app is testing...

Nice, always good to see new developments.