vpncoin (OP)
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June 01, 2015, 10:41:15 AM |
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My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?
1) me - 80d (how far was I from win?) 2) you - 1bf 3) win - a77 (where can I see this number?) 4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"
You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.
Use getblockhash cmd to get target block's HASH: getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461
If you set last N byte's "N" = 3, the right number is "461", If you bet digit value, the right number is 11, why? Bcz that: 4 + 6 + 1 = 11 Thank you. In my last example - the reason why I didn't win was that my bet amount was too low? a77 = 2679 decimal (winning) 80d = 2061 decimal (me) 1bf = 447 decimal (you) I use a single character's digit value, and them add.
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marek3ball-orig
Member
Offline
Activity: 80
Merit: 10
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June 01, 2015, 12:04:25 PM Last edit: June 01, 2015, 02:39:40 PM by marek3ball-orig |
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My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?
1) me - 80d (how far was I from win?) 2) you - 1bf 3) win - a77 (where can I see this number?) 4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"
You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.
Use getblockhash cmd to get target block's HASH: getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461
If you set last N byte's "N" = 3, the right number is "461", If you bet digit value, the right number is 11, why? Bcz that: 4 + 6 + 1 = 11 Thank you. In my last example - the reason why I didn't win was that my bet amount was too low? a77 = 2679 decimal (winning) 80d = 2061 decimal (me) 1bf = 447 decimal (you) I use a single character's digit value, and them add. This is what you mean? (last N byte): a77 = 10+7+7 = 24 (last N byte)'s digit value: a77 = 2679 Are these both examples correct?
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Seccour
Legendary
Offline
Activity: 1619
Merit: 1004
Bitcoiner, Crypto-anarchist and Cypherpunk.
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June 01, 2015, 01:06:42 PM |
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VPNcoin can now be use on the NXT network ! The asset is own by the user yiiy on the nxtforum, proof here. Name: vpn2nxt (vpncoin) Asset ID: 1989622569661755686Issuing Account: NXT-WSHC-U9Z4-BKN6-543CSTotal Assets: 40,000,000 兑换流程: VPN-->NXT:发送vpncoin到以下地址: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4,并附加留言注明接收vpn2nxt资产的NXT钱包地址( 不能使用交易平台地址,必须是自己钱包地址)。收到vpncoin后,会将同等数量的vpn2nxt资产发送到相应的nxt地址。(充值限额:1-500万) NXT-->VPN:购买vpn2nxt资产后,将资产发送到资产的发行账号 NXT-WSHC-U9Z4-BKN6-543CS,并留言注明接收vpncoin的钱包地址。收到资产后,会将同等数量的vpncoin发送到相应的vpncoin地址。 Cash flow: VPN-->NXT. Send vpncoin to the following address: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4, and additional message marked NXT wallet address to receiving vpn2nxt assets( Only wallet address.Trading platform address can't be use.). After receiving vpncoin, I will send an equal number of vpn2nxt assets to the corresponding NXT address. (recharge limit: 1-5,000,000) NXT-->VPN. Buy vpn2nxt assets, then send assets to Issuing Account: NXT-WSHC-U9Z4-BKN6-543CS, and additional message marked receiving Vpncoin wallet address. After receiving assets, I will send the same amount of vpncoin to the corresponding vpncoin address. Vpncoin, www.bitnet.wangvpn2cny, https://yuanbaohui.com/trade/vpn2cny--------vpn2nxt QQqun 319439561------
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vpncoin (OP)
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June 01, 2015, 03:35:41 PM |
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VPNcoin can now be use on the NXT network ! The asset is own by the user yiiy on the nxtforum, proof here. Name: vpn2nxt (vpncoin) Asset ID: 1989622569661755686Issuing Account: NXT-WSHC-U9Z4-BKN6-543CSTotal Assets: 40,000,000 兑换流程: VPN-->NXT:发送vpncoin到以下地址: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4,并附加留言注明接收vpn2nxt资产的NXT钱包地址( 不能使用交易平台地址,必须是自己钱包地址)。收到vpncoin后,会将同等数量的vpn2nxt资产发送到相应的nxt地址。(充值限额:1-500万) NXT-->VPN:购买vpn2nxt资产后,将资产发送到资产的发行账号 NXT-WSHC-U9Z4-BKN6-543CS,并留言注明接收vpncoin的钱包地址。收到资产后,会将同等数量的vpncoin发送到相应的vpncoin地址。 Cash flow: VPN-->NXT. Send vpncoin to the following address: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4, and additional message marked NXT wallet address to receiving vpn2nxt assets( Only wallet address.Trading platform address can't be use.). After receiving vpncoin, I will send an equal number of vpn2nxt assets to the corresponding NXT address. (recharge limit: 1-5,000,000) NXT-->VPN. Buy vpn2nxt assets, then send assets to Issuing Account: NXT-WSHC-U9Z4-BKN6-543CS, and additional message marked receiving Vpncoin wallet address. After receiving assets, I will send the same amount of vpncoin to the corresponding vpncoin address. Vpncoin, www.bitnet.wangvpn2cny, https://yuanbaohui.com/trade/vpn2cny--------vpn2nxt QQqun 319439561------ Nice work, Thank you very much.
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vpncoin (OP)
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June 01, 2015, 03:40:07 PM |
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My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?
1) me - 80d (how far was I from win?) 2) you - 1bf 3) win - a77 (where can I see this number?) 4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"
You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.
Use getblockhash cmd to get target block's HASH: getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461
If you set last N byte's "N" = 3, the right number is "461", If you bet digit value, the right number is 11, why? Bcz that: 4 + 6 + 1 = 11 Thank you. In my last example - the reason why I didn't win was that my bet amount was too low? a77 = 2679 decimal (winning) 80d = 2061 decimal (me) 1bf = 447 decimal (you) I use a single character's digit value, and them add. This is what you mean? (last N byte): a77 = 10+7+7 = 24 (last N byte)'s digit value: a77 = 2679 Are these both examples correct? Our Lottery have 2 guess type. 1, Guess a block's HASH, last N byte.getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461 If we set difficulty = 3, then the right answer is 461. 2, Guess a block's HASH, last N byte's digit value.getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461 If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12
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marek3ball-orig
Member
Offline
Activity: 80
Merit: 10
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June 01, 2015, 05:13:47 PM |
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My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?
1) me - 80d (how far was I from win?) 2) you - 1bf 3) win - a77 (where can I see this number?) 4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"
You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.
Use getblockhash cmd to get target block's HASH: getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461
If you set last N byte's "N" = 3, the right number is "461", If you bet digit value, the right number is 11, why? Bcz that: 4 + 6 + 1 = 11 Thank you. In my last example - the reason why I didn't win was that my bet amount was too low? a77 = 2679 decimal (winning) 80d = 2061 decimal (me) 1bf = 447 decimal (you) I use a single character's digit value, and them add. This is what you mean? (last N byte): a77 = 10+7+7 = 24 (last N byte)'s digit value: a77 = 2679 Are these both examples correct? Our Lottery have 2 guess type. 1, Guess a block's HASH, last N byte.getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461 If we set difficulty = 3, then the right answer is 461. 2, Guess a block's HASH, last N byte's digit value.getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461 If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12 I still don't understand - you explained the last bet here: https://bitcointalk.org/index.php?topic=789961.msg11498167#msg11498167and you told me that I should calculate it as 4 + 6 + 1 = 11 ---> but the bet was not N byte's digit value (guess type 2) Based on your last example I should see it as a HEX number 461. Maybe I'm still missing something important.
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vpncoin (OP)
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June 02, 2015, 04:16:32 AM |
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My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?
1) me - 80d (how far was I from win?) 2) you - 1bf 3) win - a77 (where can I see this number?) 4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"
You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.
Use getblockhash cmd to get target block's HASH: getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461
If you set last N byte's "N" = 3, the right number is "461", If you bet digit value, the right number is 11, why? Bcz that: 4 + 6 + 1 = 11 Thank you. In my last example - the reason why I didn't win was that my bet amount was too low? a77 = 2679 decimal (winning) 80d = 2061 decimal (me) 1bf = 447 decimal (you) I use a single character's digit value, and them add. This is what you mean? (last N byte): a77 = 10+7+7 = 24 (last N byte)'s digit value: a77 = 2679 Are these both examples correct? Our Lottery have 2 guess type. 1, Guess a block's HASH, last N byte.getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461 If we set difficulty = 3, then the right answer is 461. 2, Guess a block's HASH, last N byte's digit value.getblockhash 328399  741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461 If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12 I still don't understand - you explained the last bet here: https://bitcointalk.org/index.php?topic=789961.msg11498167#msg11498167and you told me that I should calculate it as 4 + 6 + 1 = 11 ---> but the bet was not N byte's digit value (guess type 2) Based on your last example I should see it as a HEX number 461. Maybe I'm still missing something important. My English is not good, sorry
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marek3ball-orig
Member
Offline
Activity: 80
Merit: 10
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June 02, 2015, 06:47:15 AM |
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Ok. The last lottery and your bet is calculated this way?
369 = 873 decimal Is this right?
Thank you for your work!
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Hueristic
Legendary
Offline
Activity: 4032
Merit: 5590
Doomed to see the future and unable to prevent it
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June 02, 2015, 01:55:44 PM |
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Ok. The last lottery and your bet is calculated this way?
369 = 873 decimal Is this right?
Thank you for your work!
369=18 I think the way he's doing decimal representation of hex values. It is confusing and the only reason I can think of to do this is to make it a 2 digit guess. FFF=45 000=00 Bet 50 on every value possible. I would but I'm far to lazy.
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“Bad men need nothing more to compass their ends, than that good men should look on and do nothing.”
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vpncoin (OP)
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June 02, 2015, 04:30:24 PM |
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Ok. The last lottery and your bet is calculated this way?
369 = 873 decimal Is this right?
Thank you for your work!
No The last lottery is guess block's HASH's last N byte, it is hex string, not digit value. Hex includes "0 ~ F".
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vpncoin (OP)
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June 02, 2015, 04:47:00 PM |
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Ok. The last lottery and your bet is calculated this way?
369 = 873 decimal Is this right?
Thank you for your work!
369=18 I think the way he's doing decimal representation of hex values. It is confusing and the only reason I can think of to do this is to make it a 2 digit guess. FFF=45 000=00 Bet 50 on every value possible. I would but I'm far to lazy. "369" is Hex string, the last lottery is guess block HASH's last N bytes HEX string, not digit value.
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terman45x
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June 02, 2015, 05:12:49 PM |
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Is there any statistics on actual vpn usage? Like the last month?
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vpncoin (OP)
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June 02, 2015, 05:26:35 PM |
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Mac version coming soon.
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vpncoin (OP)
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June 02, 2015, 05:29:48 PM |
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Is there any statistics on actual vpn usage? Like the last month?
Android dial app is testing...
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Seccour
Legendary
Offline
Activity: 1619
Merit: 1004
Bitcoiner, Crypto-anarchist and Cypherpunk.
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June 02, 2015, 08:16:52 PM |
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Thanks for the news !
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marek3ball-orig
Member
Offline
Activity: 80
Merit: 10
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June 02, 2015, 10:04:34 PM |
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Ok. The last lottery and your bet is calculated this way?
369 = 873 decimal Is this right?
Thank you for your work!
No The last lottery is guess block's HASH's last N byte, it is hex string, not digit value. Hex includes "0 ~ F". Good we are almost there. Now when I know it is not digit value type. How do I calculate result of "369" in this case?
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vpncoin (OP)
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June 02, 2015, 11:47:55 PM |
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Ok. The last lottery and your bet is calculated this way?
369 = 873 decimal Is this right?
Thank you for your work!
No The last lottery is guess block's HASH's last N byte, it is hex string, not digit value. Hex includes "0 ~ F". Good we are almost there. Now when I know it is not digit value type. How do I calculate result of "369" in this case? 369 is my guess, You need bet your text, The answer in the future, is unknown.
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terman45x
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June 03, 2015, 04:25:27 AM |
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Ok. The last lottery and your bet is calculated this way?
369 = 873 decimal Is this right?
Thank you for your work!
No The last lottery is guess block's HASH's last N byte, it is hex string, not digit value. Hex includes "0 ~ F". Good we are almost there. Now when I know it is not digit value type. How do I calculate result of "369" in this case? 369 is my guess, You need bet your text, The answer in the future, is unknown. More like 392. Just watch and see.
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vpncoin (OP)
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June 03, 2015, 07:07:31 AM |
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More like 392. Just watch and see.
+1 It is Hex string, just wait...
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claycoins
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June 03, 2015, 07:11:54 AM |
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Is there any statistics on actual vpn usage? Like the last month?
Android dial app is testing... Nice, always good to see new developments.
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