BTC_Backdoor
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June 12, 2023, 10:01:06 AM |
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If the target key is not a prime number, you could find a divisor for it, it could either be an even number or an odd number, I guess nobody has ever tried it yet.😉 I'd imagine finding the correct divisor is as difficult as solving the DLP, maybe solving DLP is exactly finding the correct divisor, I wouldn't know, because I never finished high school.🤣 Finally you reached the root problem or in other words security behind secp256k1. Figuring out Odd vs Even is literally the DLP itself. By far, any form of calculation on the curve won't work due to clock math nature of rounding around the resulting points.
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albert0bsd
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June 12, 2023, 11:17:18 AM |
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If the target key is not a prime number, you could find a divisor for it, it could either be an even number or an odd number, I guess nobody has ever tried it yet.😉
i try it two years ago, don't believe that you are the only guy who can think, i guess that some math guy already try all this some 30 or 20 years ago.
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digaran
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June 12, 2023, 01:17:27 PM |
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If the target key is not a prime number, you could find a divisor for it, it could either be an even number or an odd number, I guess nobody has ever tried it yet.😉
i try it two years ago, don't believe that you are the only guy who can think, i guess that some math guy already try all this some 30 or 20 years ago. I wonder if 20, 30 years ago there was any incentive for the math guy to try things harder, but you know even if Newton hadn't discovered gravity we would still be living our lives, just because no one has found the solution doesn't mean the solution doesn't exist.
Finally you reached the root problem or in other words security behind secp256k1. Figuring out Odd vs Even is literally the DLP itself. By far, any form of calculation on the curve won't work due to clock math nature of rounding around the resulting points.
But that going around the curve happens when you try division or + - with very large keys, if you limit your range of operation to a certain bit range, you could eventually find a check point. For simplicity : E.g. subtracting 200 from 1700 = 1500, subtracting 200 from 1500 = 1300, subtracting 1000 from 1300 = 300, subtracting 1700 from 2000 = *300! * see how we reached our checkpoint so fast just with a few normal elementary math operations? What makes it difficult is the size of the actual keys we are looking for, and what we are looking for is not even 0.1% of 2^256 range which most of the people's keys reside in. So far this 0.xxxxxxxx% of the curve order has kicked our asses collectively. 🤣
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albert0bsd
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June 12, 2023, 05:39:42 PM |
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I wonder if 20, 30 years ago there was any incentive for the math guy to try things harder
You should try to read some book of cryptography written 30 years ago, they are more close to something that US Example: A Course in Number Theory and cryptography by Neal Koblitz That have more complex and cool Math exercises to solve, that our rudimentary calculations. But yes they don't have at that moment our incentives, but they still did a really good job.
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GoldTiger69
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June 12, 2023, 07:08:56 PM |
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The thing is: not all people need money incentives (specially real scientists or researchers): Grigori «Grisha» Yákovlevich Perelmán.
Cheers.
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casperas20
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June 13, 2023, 10:16:45 PM |
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hi guys, im new here, does any of u have any doubt that the private keys of 66 and the the remaining keys are not at the showed ranges since the rewards are higher now and noone has reached out to open any private key after the last updated rewards?
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Doktor1975
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June 13, 2023, 10:32:01 PM |
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If the target key is not a prime number, you could find a divisor for it, it could either be an even number or an odd number, I guess nobody has ever tried it yet.😉
i try it two years ago, don't believe that you are the only guy who can think, i guess that some math guy already try all this some 30 or 20 years ago. I wonder if 20, 30 years ago there was any incentive for the math guy to try things harder, but you know even if Newton hadn't discovered gravity we would still be living our lives, just because no one has found the solution doesn't mean the solution doesn't exist.
Finally you reached the root problem or in other words security behind secp256k1. Figuring out Odd vs Even is literally the DLP itself. By far, any form of calculation on the curve won't work due to clock math nature of rounding around the resulting points.
But that going around the curve happens when you try division or + - with very large keys, if you limit your range of operation to a certain bit range, you could eventually find a check point. For simplicity : E.g. subtracting 200 from 1700 = 1500, subtracting 200 from 1500 = 1300, subtracting 1000 from 1300 = 300, subtracting 1700 from 2000 = *300! * see how we reached our checkpoint so fast just with a few normal elementary math operations? What makes it difficult is the size of the actual keys we are looking for, and what we are looking for is not even 0.1% of 2^256 range which most of the people's keys reside in. So far this 0.xxxxxxxx% of the curve order has kicked our asses collectively. 🤣 You're some kind of naive person)) Do you honestly think that Satoshi came up with some kind of magical thing called bitcoin? I'll tell you a secret - elliptic curves were engaged in 2000 BC in Iran))) ECDSA and Secp256k1 - this is not invented by Satoshi!)) This is the encryption standard - the US National Security Agency - it has been used for many many years - to encrypt messages! This is mainly used by the military and special services!
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digaran
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June 14, 2023, 08:09:39 AM |
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You're some kind of naive person)) Do you honestly think that Satoshi came up with some kind of magical thing called bitcoin? I'll tell you a secret - elliptic curves were engaged in 2000 BC in Iran))) ECDSA and Secp256k1 - this is not invented by Satoshi!)) This is the encryption standard - the US National Security Agency - it has been used for many many years - to encrypt messages! This is mainly used by the military and special services!
What is the story of 2000 BC in iran, do you have any sources and names to provide please? Of course militaries use elliptic curves for encryption, but I doubt if they use a publicly available curve for that purpose. And maybe Satoshi didn't invent the ECDSA, secp256k1 curve, but he was smart enough to use it in order to secure bitcoin. Secp256k1 is purely a safe vault, with other characteristics and utilities. Satoshi just chose to lock the door of the bitcoin vault using a locking mechanism we call secp256k1.
Ps, I agree with you, I'm just a simpleton, doing simple stuff, saying simpler things.😉
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BitDominator00
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June 14, 2023, 02:05:58 PM |
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You're some kind of naive person)) Do you honestly think that Satoshi came up with some kind of magical thing called bitcoin? I'll tell you a secret - elliptic curves were engaged in 2000 BC in Iran))) ECDSA and Secp256k1 - this is not invented by Satoshi!)) This is the encryption standard - the US National Security Agency - it has been used for many many years - to encrypt messages! This is mainly used by the military and special services!
What is the story of 2000 BC in iran, do you have any sources and names to provide please? Of course militaries use elliptic curves for encryption, but I doubt if they use a publicly available curve for that purpose. And maybe Satoshi didn't invent the ECDSA, secp256k1 curve, but he was smart enough to use it in order to secure bitcoin. Secp256k1 is purely a safe vault, with other characteristics and utilities. Satoshi just chose to lock the door of the bitcoin vault using a locking mechanism we call secp256k1.
Ps, I agree with you, I'm just a simpleton, doing simple stuff, saying simpler things. Maybe Satoshi created this "puzzle", and once all the private keys are found... maybe a hash of the string composed of all the keys within individual ranges, or maybe something related to them... could lead to the private key that "controls" the addresses that received the first mined bitcoins. Science fiction ? XD
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digaran
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June 14, 2023, 02:46:16 PM |
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Maybe Satoshi created this "puzzle", and once all the private keys are found... maybe a hash of the string composed of all the keys within individual ranges, or maybe something related to them... could lead to the private key that "controls" the addresses that received the first mined bitcoins. Science fiction ? XD
I can't see any science in your theory, it's just a made up scenario in your head, I doubt him to be a liar, he said that he used a deterministic wallet to generate the keys. The only thing I don't understand, are all the keys from one seed and if they are, did he use the first 256 keys and didn't generate more? If he used the first generated 256 keys, which would be impossible to generate 256 keys and all of them have the exact bit range of the intended bit range. So my guess is that he might have used a single seed but had to generate more than 256 keys to find the perfect keys matching the intended bit ranges if masked with leading zeros.
So explain what I mean. Imagine I generate 256 keys and see none of them has 1 in the middle so that I could mask anything behind 1 with zeros and use that key for puzzle #125, for instance. Example 5efad5987dc4a907698547d117b98892 0 5001159481c639e043e52d4f9b832e1 I can't use the key above for puzzle #125 because it has 0 in the middle instead of 1, so I'd either have to manually replace 0 with 1 or generate another key till I see 1 in the middle. In both cases there will be no pattern, no correlation between the keys whatsoever.
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Evillo
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June 14, 2023, 04:01:24 PM |
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Maybe Satoshi created this "puzzle", and once all the private keys are found... maybe a hash of the string composed of all the keys within individual ranges, or maybe something related to them... could lead to the private key that "controls" the addresses that received the first mined bitcoins. Science fiction ? XD
I can't see any science in your theory, it's just a made up scenario in your head, I doubt him to be a liar, he said that he used a deterministic wallet to generate the keys. The only thing I don't understand, are all the keys from one seed and if they are, did he use the first 256 keys and didn't generate more? If he used the first generated 256 keys, which would be impossible to generate 256 keys and all of them have the exact bit range of the intended bit range. So my guess is that he might have used a single seed but had to generate more than 256 keys to find the perfect keys matching the intended bit ranges if masked with leading zeros.
So explain what I mean. Imagine I generate 256 keys and see none of them has 1 in the middle so that I could mask anything behind 1 with zeros and use that key for puzzle #125, for instance. Example 5efad5987dc4a907698547d117b98892 0 5001159481c639e043e52d4f9b832e1 I can't use the key above for puzzle #125 because it has 0 in the middle instead of 1, so I'd either have to manually replace 0 with 1 or generate another key till I see 1 in the middle. In both cases there will be no pattern, no correlation between the keys whatsoever. Yeah .. He, most likely, generated 256 keys and manually updated the first character on the left whenever necessary.
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digaran
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June 14, 2023, 07:55:52 PM |
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Yeah .. He, most likely, generated 256 keys and manually updated the first character on the left whenever necessary.
You really think he just changed 1 digit? Some one who is an expert in cryptography would know better, but maybe he didn't want to make it very difficult and really used randomly generated keys. But if I were him, I'd have changed a few characters to make it really really hard, for example having a few 0s in a key will make it hard to reverse engineer a key manually, and brute force/kangaroo, well they have their limits. One other thing could be placing a key outside a bit range, I'm curious did Satoshi ever confirmed that the keys are truly in the assumed bit ranges or we just hope the amounts of transactions are enough of a proof that the keys are exactly there? But you know what I'd like to see? A large amount in a key with no exactly known bit range, somewhere between 160 and 180 bit not lower and not higher, then solving that key would be a global challenge, though not any amount which someone could spend half of it to use special tools and grab it, something which could only be solved by math and new methods. For example, I haven't seen any tool/ algorithm capable of adding or subtracting 1 to a key and then divide it by 2, kangaroo engages square root calculations, BSGS looks for a match after adding/subtracting calculations, but no tool does + or - 1 then divide!
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Evillo
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June 14, 2023, 08:41:55 PM |
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Yeah .. He, most likely, generated 256 keys and manually updated the first character on the left whenever necessary.
You really think he just changed 1 digit? Some one who is an expert in cryptography would know better, but maybe he didn't want to make it very difficult and re ally used randomly generated keys. But if I were him, I'd have changed a few characters to make it really really hard. Lol .. you have no clue what we're talking about do you! The reason he changes the first character on the left is NOT to make it difficult, it's to make the ranges as per his puzzle requirements.. in fact, even if he changes nothing.. Brutefocring the seed is impossible. A person who knows cryptography would know that humans are terrible in creating secure randomness. Changing numbers or adding zeros doesn't do shit in terms of difficulty, the opposite is true, it can actually increase predictability
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lordfrs
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June 14, 2023, 11:42:50 PM |
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Yeah .. He, most likely, generated 256 keys and manually updated the first character on the left whenever necessary.
You really think he just changed 1 digit? Some one who is an expert in cryptography would know better, but maybe he didn't want to make it very difficult and really used randomly generated keys. But if I were him, I'd have changed a few characters to make it really really hard, for example having a few 0s in a key will make it hard to reverse engineer a key manually, and brute force/kangaroo, well they have their limits. One other thing could be placing a key outside a bit range, I'm curious did Satoshi ever confirmed that the keys are truly in the assumed bit ranges or we just hope the amounts of transactions are enough of a proof that the keys are exactly there? But you know what I'd like to see? A large amount in a key with no exactly known bit range, somewhere between 160 and 180 bit not lower and not higher, then solving that key would be a global challenge, though not any amount which someone could spend half of it to use special tools and grab it, something which could only be solved by math and new methods. For example, I haven't seen any tool/ algorithm capable of adding or subtracting 1 to a key and then divide it by 2, kangaroo engages square root calculations, BSGS looks for a match after adding/subtracting calculations, but no tool does + or - 1 then divide! Now I look at it from a different angle. In binary, the program is more practical, for example, I know the last 8 bits of the private key anyway, because 8 bits equals a maximum of 256 digits. There was a friend who said that if the curve math is 0, multiply, if 1, add, knowing the last bit means solving ecdsa, the last 8 bits are 1 in 256, you can find the rest. If you say the last 16 bits, there is 1 possibility in 65536, these numbers can be tried, you will reduce 125 bits -16 bits =109bits. This is the code from sympy import mod_inverse import secp256k1 as ice
k=mod_inverse(2,N) neg1=ice.point_negation(ice.scalar_multiplication(1))
def ters(Qx,Scalar): ScalarBin = str(bin(Scalar))[2:] le=len(ScalarBin) for i in range (0,le): if ScalarBin[le-i] == "0": Qx=ice.point_multiplication(k,Qx) else: Qx=ice.point_addition(Qx,neg1) Qx=ice.point_multiplication(k,Qx) return ice.point_to_cpub(Qx)
for x in range(65536): print(ters(pub,x))
If the last bit is 1, it moves the point forward when divided by (2). 7fffffffffffffffffffffffffffffff5d576e7357a4501ddfe92f46681b20a1 + if the last bit is 0 then normal divides
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If you want to buy me a coffee
Btc = 3246y1G9YjnQQNRUrVMnaeCFrymZRgJAP7
Doge = DGNd8UTi8jVTVZ2twhKydyqicynbsERMjs
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Milly1
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June 15, 2023, 03:34:36 PM |
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Good evening everyone! I've been following this forum on and off for several years. I want to wish you all good luck for the 32 BTC puzzle. Well, it has increased now. Please note that this message is translated into English because I don't speak English well enough. Last night, I stumbled upon one of your pages by chance, about fifteen pages back! One of you had a brilliant idea. I don't remember the person's username, but they didn't explain much. However, as I reread the creator's message, it made sense. I did some research, and indeed, it matched. I have never coded in my life, but I followed some tutorials last night and achieved the same results (since the person shared their results). I dreamt about it all night! : ) And this morning, Eureka! I found a continuation of their work, an idea! I've been thinking about it all day, doing calculations and probabilities in my head, but unfortunately, I've been busy with work. I'm about to head home and try all this mess! I will keep you updated whether I find the answer or get closer to it! I will share the results and the method used. Please bear with me, as it takes me a lot of time to code something since I'm not an expert like most of you! I just wanted to say to those who are trying to find a mathematical solution that there isn't a single formula, but many small calculations and probabilities at times! Focus on the creator's message and on the ranges where each key is located, even those that have already been found! The goal is not a complicated mathematical formula but rather asking the right questions!! I hope this will inspire you!
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GR Sasa
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June 15, 2023, 06:12:30 PM |
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Last night, I stumbled upon one of your pages by chance, about fifteen pages back! One of you had a brilliant idea. I don't remember the person's username, but they didn't explain much.
DO YOU mean Professor of wilds ? He's ideas sorry are shit. They don't work because keys are generated on fly. We already discussed this.
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unclevito
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June 15, 2023, 09:19:33 PM |
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sssergy2705
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June 16, 2023, 04:44:56 AM |
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