Bitcoin puzzle transaction ~32 BTC prize to who solves it

[bestie1549]

Why do you use linux time? Satoshi was using windows, either vista or seven, maybe even 8, or xp. 😂 we just need to look for all the keys. Lol
You know what we should do? We should use the same technic to search for rmd160 hash patterns and find collisions. 🙃

I can assume that the Satoshi was using some script (errors = ZERO) with Lagrange interpolation, determining the formula that generates the values may require a different approach, such as symbolic regression or other mathematical techniques together with random numbers and time. I am lost in numbers and hypotheses now. I need green grass..

There is nothing to worry about for now, maybe some could go back in time to see what position Satoshi was taking while throwing the dice or flipping the coins, maybe that way we can know what position we need to also take in order to be able to replicate the same method. How many minutes do you think you need to throw a dice or flip a coin to get puzzle 1 to puzzle 256?
256+254+254+253+252+251+250+249+248+247+246+245+244+243+242+241+240+239+238+237+236+235+234+233+232+231+230+229+228+227+226+225+224+223+222+221+220+219+218+217+216+215+214+213+212+211+210+209+208+207+206+205+204+203+202+201+200+199+198+197+196+195+194+193+192+191+190+189+188+187+186+185+184+183+182+181+180+179+178+177+176+175+174+173+172+171+170+169+168+167+166+165+164+163+162+161+160+159+158+157+156+155+154+153+152+151+150+149+148+147+146+145+144+143+142+141+140+139+138+137+136+135+134+133+132+131+130+129+128+127+126+125+124+123+122+121+120+119+118+117+116+115+114+113+112+111+110+109+108+107+106+105+104+103+102+101+100+99+98+97+96+95+94+93+92+91+90+89+88+87+86+85+84+83+82+81+80+79+78+77+76+75+74+73+72+71+70+69+68+67+66+65+64+63+62+61+60+59+58+57+56+55+54+53+52+51+50+49+48+47+46+45+44+43+42+41+40+39+38+37+36+35+34+33+32+31+30+29+28+27+26+25+24+23+22+21+20+19+18+17+16+15+14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 32895

so you can as well agree with me that the problem here has nothing to do with a pattern or some kind of formula... we have so many ways of getting private keys without making any mistakes. ZERO FREE ERROR VERIFIED METHODS

There is no assumptions here, whenever the person that solved puzzle 120 and 125 is ready he will solve puzzle 130 again. Now for puzzle 66, the highest pool scanned so far is less than 5% so don't expect any results any time soon from these pools. the key range is so vast and the computational resources is so limited We can't complain about wrong bit keys only except there's an evidence that someone successfully scan the full range for any puzzle level and the PK is not found within that range so please let's stop making assumptions and let's focus on better ways to tackle the puzzle. @Digaran mentioned something earlier and said

Why do you use linux time? Satoshi was using windows, either vista or seven, maybe even 8, or xp. 😂 we just need to look for all the keys. Lol
You know what we should do? We should use the same technic to search for rmd160 hash patterns and find collisions. 🙃

let us just assume that this is possible 160 bit is a whole new world and for RMD160 collision you would find so many SHA256 matching so many RMD160 you won't be limited to finding the private keys for puzzle 66 within just the 66 bit range. there would be an enormous range to cover and you would find perfectly matching private keys matching so many RMD160 hashes. but without further ado, I must say we have a great task at hand and we will stop at nothing to find an end to this puzzle

[zahid888]

Important Message to the Creator:

'00008657895489568954e6270000ffffffff000049924a526a523a520a52198c'

Please visualize this key by visiting the following link to read the message: (https://btckeygen.com/)

Kindly fund the key if you have received my message..

[nomachine]

let us just assume that this is possible

Code:

import random, sys, os, time
from datetime import datetime, timedelta
import secp256k1 as ice
from concurrent.futures import ThreadPoolExecutor

os.system("clear")
t = time.ctime()
sys.stdout.write("\033[01;33m")
sys.stdout.write(f"[+] {t}" + "\n")
sys.stdout.flush()

# Define the check_private_key function
def check_private_key(dec, add_set):
    while True:
        dec = random.randint(min_number, max_number)
        HASH160 = ice.privatekey_to_h160(0, True, dec).hex()
        sys.stdout.write("\033[01;33m")
        sys.stdout.write(f"\r[+] {HASH160}" + "\r")
        sys.stdout.flush()
        if HASH160 == add_set:
            dec_to_hex = hex(dec).split('x')[-1]
            HASH160_wif = ice.btc_pvk_to_wif(dec)
            print('\n')
            print(f" Key Found:  |\033[32m {dec_to_hex} \033[0m")
            print(f" WIF         |\033[32m {HASH160_wif} \033[0m")
            print(f" Address     |\033[32m {add_set} \033[0m")
            with open("FOUND_66PUZZLE.txt", "a") as f:
                f.write("HEX:               " + str(dec_to_hex) + '\n' + "Address HASH160:   " + str(add_set) + '\n' + "Private Key:       " + str(HASH160_wif) + '\n')
                f.flush()
                f.close()
            return

# Specify the start and end date and times
start_datetime = datetime(2014, 1, 1, 0, 0, 0)
end_datetime = datetime(2015, 1, 15, 19, 7, 14)

# Calculate the time range in seconds
time_range_seconds = (end_datetime - start_datetime).total_seconds()

# Define the range of numbers and Hash 160
min_number = 36893488147419103232
max_number = 73786976294838206463
add_set = "20d45a6a762535700ce9e0b216e31994335db8a5"

# Initialize a ThreadPoolExecutor
executor = ThreadPoolExecutor(max_workers=10)

current_datetime = start_datetime

while current_datetime <= end_datetime:
    # Format the current datetime to exclude fractional seconds
    timestamp = current_datetime.strftime('%Y-%m-%d %H:%M:%S')

    # Convert the formatted timestamp to a Unix timestamp
    timestamp = int(datetime.strptime(timestamp, '%Y-%m-%d %H:%M:%S').timestamp())

    # Initialize the random number generator with the timestamp
    random.seed(timestamp)

    # Generate a random number within the specified range
    dec = random.randint(min_number, max_number)

    # Submit the check_private_key function as a task to the ThreadPoolExecutor
    future = executor.submit(check_private_key, dec, add_set)

    # Check if the generated private key matches the provided address
    if future.result():
        executor.shutdown()
        break  # Exit the loop if a match is found

    # Increment the current datetime by one second for the next timestamp
    current_datetime += timedelta(seconds=1)

why not ?

[alek76]

why not ?

Without predictable SEED there will be more chances  

[albert0bsd]

Important Message to the Creator:

'00008657895489568954e6270000ffffffff000049924a526a523a520a52198c'

What is this? where it comes from?

I checked it in some hexadecimal editor and there is no a message there:



Can you add some more of context please?

[zahid888]

Important Message to the Creator:

'00008657895489568954e6270000ffffffff000049924a526a523a520a52198c'

What is this? where it comes from?

I checked it in some hexadecimal editor and there is no a message there:



Can you add some more of context please?

[zahid888]

According to this puzzle 66 is reduce 66 times
   

BitCrack.exe -b 128 -t 256 -p 512  -i 256.txt --keyspace f7051f0000000000:f7051fffffffffff --stride 64
[2023-09-08.05:38:07] [Info] Compression : compressed
[2023-09-08.05:38:07] [Info] Seach mode  : ADDRESS
[2023-09-08.05:38:07] [Info] Starting at : F7051F0000000000 (64 bit)
[2023-09-08.05:38:07] [Info] Ending at   : F7051FFFFFFFFFFF (64 bit)
[2023-09-08.05:38:07] [Info] Range       : FFFFFFFFFF (40 bit)
[2023-09-08.05:38:07] [Info] Stride      : 64
[2023-09-08.05:38:07] [Info] Initializing NVIDIA GeForce RTX 3060 Ti
[2023-09-08.05:38:07] [Info] Generating 16,777,216 starting points (640.0MB)
[2023-09-08.05:38:08] [Info] 10.0%  20.0%  30.0%  40.0%  50.0%  60.0%  70.0%  80.0%  90.0%  100.0%
[2023-09-08.05:38:09] [Info] Done
[2023-09-08.05:38:10] [Info] Loading addresses from '256.txt'
[2023-09-08.05:38:10] [Info] 1,340 addresses loaded (0.0MB)
[2023-09-08.05:38:10] [Info] Allocating bloom filter (0.0MB)
[DEV: NVIDIA GeForce R 3613/8191MB] [K: F7051F251C000000 (64 bit), C: 14.495850 %] [I: 64 (7 bit), 1] [T: 1340] [S: 879.60 MK/s] [1,593,835,520 (31 bit)] [00:00:00] [2023-09-08.05:38:11] [Info] Allocating bloom filter (0.0MB)

[2023-09-08.05:38:12] [Info] Found key for address '16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN'. Written to 'Found.txt'
[2023-09-08.05:38:12] [Info] Address     : 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN
                             Private key : F7051F27B09112D4
                             Compressed  : yes
                             Public key  : 03100611C54DFEF604163B8358F7B7FAC13CE478E02CB224AE16D45526B25D9D4D

[DEV: NVIDIA GeForce R 3613/8191MB] [K: F7051FDDE0000000 (64 bit), C: 86.669922 %] [I: 64 (7 bit), 1] [T: 1339] [S: 869.86 MK/s] [9,529,458,688 (34 bit)] [00:00:09]
[2023-09-08.05:38:22] [Info] Reached end of keyspace

BitCrack.exe -b 128 -t 256 -p 512  -i 256.txt --keyspace 1a838b00000000000:1a838bfffffffffff --stride 65
[2023-09-08.05:39:30] [Info] Compression : compressed
[2023-09-08.05:39:30] [Info] Seach mode  : ADDRESS
[2023-09-08.05:39:30] [Info] Starting at : 1A838B00000000000 (65 bit)
[2023-09-08.05:39:30] [Info] Ending at   : 1A838BFFFFFFFFFFF (65 bit)
[2023-09-08.05:39:30] [Info] Range       : FFFFFFFFFFF (44 bit)
[2023-09-08.05:39:30] [Info] Stride      : 65
[2023-09-08.05:39:30] [Info] Initializing NVIDIA GeForce RTX 3060 Ti
[2023-09-08.05:39:30] [Info] Generating 16,777,216 starting points (640.0MB)
[2023-09-08.05:39:32] [Info] 10.0%  20.0%  30.0%  40.0%  50.0%  60.0%  70.0%  80.0%  90.0%  100.0%
[2023-09-08.05:39:33] [Info] Done
[2023-09-08.05:39:33] [Info] Loading addresses from '256.txt'
[2023-09-08.05:39:33] [Info] 1,340 addresses loaded (0.0MB)
[2023-09-08.05:39:33] [Info] Allocating bloom filter (0.0MB)
[DEV: NVIDIA GeForce R 3613/8191MB] [K: 1A838B1297A000000 (65 bit), C: 7.262611 %] [I: 65 (7 bit), 1] [T: 1340] [S: 869.86 MK/s] [12,650,020,864 (34 bit)] [00:00:12] [2023-09-08.05:39:48] [Info] Allocating bloom filter (0.0MB)

[2023-09-08.05:39:48] [Info] Found key for address '18ZMbwUFLMHoZBbfpCjUJQTCMCbktshgpe'. Written to 'Found.txt'
[2023-09-08.05:39:48] [Info] Address     : 18ZMbwUFLMHoZBbfpCjUJQTCMCbktshgpe
                             Private key : 1A838B13505B26867
                             Compressed  : yes
                             Public key  : 0230210C23B1A047BC9BDBB13448E67DEDDC108946DE6DE639BCC75D47C0216B1B

[DEV: NVIDIA GeForce R 3613/8191MB] [K: 1A838B2BE44000000 (65 bit), C: 17.145157 %] [I: 65 (7 bit), 1] [T: 1339] [S: 860.61 MK/s] [29,863,444,480 (35 bit)] [00:00:32]


============================= Puzzle 66 Total keys = (36,893,488,147,419,103,232) ===================================

Lastt Found Address : 23d550f16301af7b0719903616e37378be5d43ab
Puzzl Sarch Address : 20d45a6a762535700ce9e0b216e31994335db8a5
Prfix Match Address : ^ ^ ^         ^ ^  ^ ^  ^^^^      ^^  ^
Charr Match Totalss : 14
Bes58 Match Colorzz : 14GUCBaK3j9JGMGWZVd7curb5Y5uv2EXnJ  31fe6d97c22167688
Bes58 Match Colorzz : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so  312d86d64f36e736f
[2023-09-08.07:17:02] [Info] Compression : compressed
[2023-09-08.07:17:02] [Info] Seach mode  : ADDRESS
[2023-09-08.07:17:02] [Info] Starting at : 31FE6D00000000000 (66 bit)
[2023-09-08.07:17:02] [Info] Ending at   : 31FE6DFFFFFFFFFFF (66 bit)
[2023-09-08.07:17:02] [Info] Range       : FFFFFFFFFFF (44 bit)
[2023-09-08.07:17:02] [Info] Stride      : 66
[2023-09-08.07:17:02] [Info] Initializing NVIDIA GeForce RTX 3060 Ti
[2023-09-08.07:17:02] [Info] Generating 16,777,216 starting points (640.0MB)
[2023-09-08.07:17:04] [Info] 10.0%  20.0%  30.0%  40.0%  50.0%  60.0%  70.0%  80.0%  90.0%  100.0%
[2023-09-08.07:17:05] [Info] Done
[2023-09-08.07:17:05] [Info] Loading addresses from '256.txt'
[2023-09-08.07:17:05] [Info] 1,340 addresses loaded (0.0MB)
[2023-09-08.07:17:05] [Info] Allocating bloom filter (0.0MB)
[DEV: NVIDIA GeForce R 3613/8191MB] [K: 31FE6DFED9C000000 (66 bit), C: 99.551010 %] [I: 66 (7 bit), 1] [T: 1340] [S: 853.55 MK/s] [171,698,028,544 (38 bit)] [00:03:17]
[2023-09-08.07:20:25] [Info] Reached end of keyspace

============================= Puzzle 66 Total keys = (36,893,488,147,419,103,232) ===================================

Lastt Found Address : f0380a677a3ffac008bc403255e3e9e833770b15
Puzzl Sarch Address : 20d45a6a762535700ce9e0b216e31994335db8a5
Prfix Match Address :  ^   ^^ ^      ^^    ^ ^  ^^ ^  ^^     ^
Charr Match Totalss : 14
Bes58 Match Colorzz : 1NuAJp4KKSeiGEcbfTsXk9YTFu9RTu7ytr  2e26fb283392ed368
Bes58 Match Colorzz : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so  312d86d64f36e736f
[2023-09-08.08:08:57] [Info] Compression : compressed
[2023-09-08.08:08:57] [Info] Seach mode  : ADDRESS
[2023-09-08.08:08:57] [Info] Starting at : 2E26FB00000000000 (66 bit)
[2023-09-08.08:08:57] [Info] Ending at   : 2E26FBFFFFFFFFFFF (66 bit)
[2023-09-08.08:08:57] [Info] Range       : FFFFFFFFFFF (44 bit)
[2023-09-08.08:08:57] [Info] Stride      : 66
[2023-09-08.08:08:57] [Info] Initializing NVIDIA GeForce RTX 3060 Ti
[2023-09-08.08:08:57] [Info] Generating 16,777,216 starting points (640.0MB)
[2023-09-08.08:08:59] [Info] 10.0%  20.0%  30.0%  40.0%  50.0%  60.0%  70.0%  80.0%  90.0%  100.0%
[2023-09-08.08:09:00] [Info] Done
[2023-09-08.08:09:00] [Info] Loading addresses from '256.txt'
[2023-09-08.08:09:00] [Info] 1,340 addresses loaded (0.0MB)
[2023-09-08.08:09:00] [Info] Allocating bloom filter (0.0MB)
[DEV: NVIDIA GeForce R 3613/8191MB] [K: 2E26FBFE6D6000000 (66 bit), C: 99.385643 %] [I: 66 (7 bit), 1] [T: 1340] [S: 851.82 MK/s] [171,412,815,872 (38 bit)] [00:03:18]
[2023-09-08.08:12:21] [Info] Reached end of keyspace

============================= Puzzle 66 Total keys = (36,893,488,147,419,103,232) ===================================

Lastt Found Address : 97d9536e5d2505d00ccae94c1fe3f99e6a7fdf8e
Puzzl Sarch Address : 20d45a6a762535700ce9e0b216e31994335db8a5
Prfix Match Address :   ^ ^ ^   ^^ ^ ^^^  ^   ^ ^^ ^^
Charr Match Totalss : 15
Bes58 Match Colorzz : 1EquP32CeUQYtxT9MKDgMCtcAFWHMDnKEg  3804efb4d8c8f7721
Bes58 Match Colorzz : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so  312d86d64f36e736f
[2023-09-08.08:30:44] [Info] Compression : compressed
[2023-09-08.08:30:44] [Info] Seach mode  : ADDRESS
[2023-09-08.08:30:44] [Info] Starting at : 3804EF00000000000 (66 bit)
[2023-09-08.08:30:44] [Info] Ending at   : 3804EFFFFFFFFFFFF (66 bit)
[2023-09-08.08:30:44] [Info] Range       : FFFFFFFFFFF (44 bit)
[2023-09-08.08:30:44] [Info] Stride      : 66
[2023-09-08.08:30:44] [Info] Initializing NVIDIA GeForce RTX 3060 Ti
[2023-09-08.08:30:44] [Info] Generating 16,777,216 starting points (640.0MB)
[2023-09-08.08:30:45] [Info] 10.0%  20.0%  30.0%  40.0%  50.0%  60.0%  70.0%  80.0%  90.0%  100.0%
[2023-09-08.08:30:47] [Info] Done
[2023-09-08.08:30:47] [Info] Loading addresses from '256.txt'
[2023-09-08.08:30:47] [Info] 1,340 addresses loaded (0.0MB)
[2023-09-08.08:30:47] [Info] Allocating bloom filter (0.0MB)
[DEV: NVIDIA GeForce R 3613/8191MB] [K: 3804EFFE274000000 (66 bit), C: 99.278641 %] [I: 66 (7 bit), 1] [T: 1340] [S: 851.82 MK/s] [171,228,266,496 (38 bit)] [00:03:17]
[2023-09-08.08:34:08] [Info] Reached end of keyspace

============================= Puzzle 66 Total keys = (36,893,488,147,419,103,232) ===================================

Lastt Found Address : 24e444da7d2b980206e9e052284298c2935d5722
Puzzl Sarch Address : 20d45a6a762535700ce9e0b216e31994335db8a5
Prfix Match Address : ^  ^   ^^ ^     ^ ^^^^ ^         ^^^
Charr Match Totalss : 14
Bes58 Match Colorzz : 14N4nK3uhTFsTEHi1nrWnf5JpBjjDrSffW  38c6f1f5ff02834b0
Bes58 Match Colorzz : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so  312d86d64f36e736f
[2023-09-08.09:12:16] [Info] Compression : compressed
[2023-09-08.09:12:16] [Info] Seach mode  : ADDRESS
[2023-09-08.09:12:16] [Info] Starting at : 38C6F100000000000 (66 bit)
[2023-09-08.09:12:16] [Info] Ending at   : 38C6F1FFFFFFFFFFF (66 bit)
[2023-09-08.09:12:16] [Info] Range       : FFFFFFFFFFF (44 bit)
[2023-09-08.09:12:16] [Info] Stride      : 66
[2023-09-08.09:12:16] [Info] Initializing NVIDIA GeForce RTX 3060 Ti
[2023-09-08.09:12:16] [Info] Generating 16,777,216 starting points (640.0MB)
[2023-09-08.09:12:18] [Info] 10.0%  20.0%  30.0%  40.0%  50.0%  60.0%  70.0%  80.0%  90.0%  100.0%
[2023-09-08.09:12:19] [Info] Done
[2023-09-08.09:12:19] [Info] Loading addresses from '256.txt'
[2023-09-08.09:12:19] [Info] 1,340 addresses loaded (0.0MB)
[2023-09-08.09:12:19] [Info] Allocating bloom filter (0.0MB)
[DEV: NVIDIA GeForce R 3613/8191MB] [K: 38C6F1FEA06000000 (66 bit), C: 99.463463 %] [I: 66 (7 bit), 1] [T: 1340] [S: 851.82 MK/s] [171,547,033,600 (38 bit)] [00:03:18]
[2023-09-08.09:15:40] [Info] Reached end of keyspace

Another long post 

[digaran]

Important message to the author :  since we are "buddies"
Visualize them in order,
0000380023a22094e68807800000e91c8910e9108f70e0000000000000000000
0000f7808480e79c861c851c800000000820145023880000742627242524252c
104028a0451082080080789c0b946a947b940000e6608440e45a8ddae0120013

When you are done, kindly visualize these on a king size bed.🙈
0000823c4424293c113001280104010000030002e00e82f09a908a90fa900000
You deserve them.😉
@zahid888, what is base58 match colorzz? Which tool has this feature? And finally how much is enough for you to kindly pull out of base58 match finding? Lol.
I love it how you do your things without explaining anything.
I just found a new hobby, using btckeygen.com as a messenger medium.😂

[nomachine]

I just found a new hobby, using btckeygen.com as a messenger medium.😂

I didn't move away much intellectually from this hobby either. In terms of solving the Puzzle 66.
I can print the solved ones and joke here. But that won't help us. 😂

[digaran]

Without a joke, I might have found a definitive solution to solve DLP, I'm not sure how I can implement an algorithm fast and precise to solve a key, but the equation in my head can solve DLP.

@Satoshi/ author/ designer of this challenge, I am willing to work for 1 years exclusively on this particular subject for a salary of $200m, which I would take $20m upfront and if after 1 year we reached the final solution I will take the remaining $180m, and if we couldn't find that solution, I keep the 20m.  

I'm not 100% sure, I only discovered this new equation yesterday, but since all my calculations happen in my head, when I think about it I see the solution, I just need someone who I can trust and a professional programmer.

I will buy an apartment in another city to be alone and undistracted, then I will share the address and my ID.
Obviously I accept no other sponsor/offer. If you are interested send dust to my digaran address with the same address you charged these puzzles, I will then encrypt my dedicated email address with your public key and post it here.

Disclaimer, I do not guarantee any satisfactorily results, this is just my term of business.
Please note, I will continue working on this regardless, and God willing when I manage to solve a puzzle key, I will not share the method.

My dig add is on profile.
Fun to know :
There is a lot of controversy around my reputation, at one point in time, I "suggested" to charge $50 "bucks" from each garbage poster for the cost of their wrong doings. on behalf of forum, not for myself of course, now after 5 years, I'm asking for $200m from the #1 man of Bitcoin. Who could have thought that, right? Lol.

Anyways, I will do my best to keep a decentralized system such as Bitcoin alive and safe, for a better world, even if I'm only 1 man, it still counts.😉

[citb0in]

Without a joke, I might have found a definitive solution to solve DLP, I'm not sure how I can implement an algorithm fast and precise to solve a key, but the equation in my head can solve DLP.

@Satoshi/ author/ designer of this challenge, I am willing to work for 3 years exclusively on this particular subject for a salary of $50m, which I would take $3m upfront and if after 3 years we reached the final solution I will take the remaining $47m, and if we couldn't find that solution, I keep the 3m. 

I'm not 100% sure, I only discovered this new equation yesterday, but since all my calculations happen in my head, when I think about it I see the solution, I just need someone who I can trust and a professional programmer.

I will buy an apartment in another city to be alone and undistracted, then I will share the address and my ID.
Obviously I accept no other sponsor/offer. If you are interested send dust to my digaran address with the same address you charged these puzzles, I will then encrypt my dedicated email address with your public key and post it here.

Disclaimer, I do not guarantee any satisfactorily results, this is just my term of business.
Please note, I will continue working on this regardless, and God willing when I manage to solve a puzzle key, I will not share the method.

My dig add is on profile.
Fun to know :
There is a lot of controversy around my reputation, at one point in time, I "suggested" to charge $50 "bucks" from each garbage poster for the cost of their wrong doings. on behalf of forum, not for myself of course, now after 5 years, I'm asking for $50m from the #1 man of Bitcoin. Who could have thought that, right? Lol.

Anyways, I will do my best to keep a decentralized system such as Bitcoin alive and safe, for a better world, even if I'm only 1 man, it still counts.😉

what a pathetic call, rarely laughed so, just ridiculous - you made my day

[digaran]

what a pathetic call, rarely laughed so, just ridiculous - you made my day

You are right, indeed pathetic, when you can have billions why ask for millions right? Well I like to earn honestly, plus I'm not greedy. But I'm glad you are not whining and laughing, laugh keeps us healthy, keep at it.😉
I need more people like, your comments gives me more incentive.

[nomachine]

the equation in my head can solve.....

It's called imagination. 

[digaran]

the equation in my head can solve.....

It's called imagination. 

Not any more, as I just tested a few tricks, it works. Note that I'm not forcing anyone to believe me, I don't know who to trust that's it, therefore my only option is Satoshi/author of this challenge.

I have been called delusional, scammer, liar etc,  without these name callings I wouldn't be here right now. It's the fuel for my engine.

[alek76]

Creator use master keys or child keys? BIP-32 or BIP-39 format? Who can know?

[bestie1549]

Creator use master keys or child keys? BIP-32 or BIP-39 format? Who can know?

If I can say anything it'd be for the author of this puzzle to bless me beyond my own imagination
I have tried my best but I am still not going to give up either. you can search or do a lookup of my wallet address. I have definitely invested over $30k in the puzzle 66 alone throughout the whole random scan and my wallet address is 1h7EsfXpgCLftpU4vucjkCbX1Wktop8GM, you can do your search from the private key scanner or 66 bits puzzle
I spend so much resources there but no luck
I am running my search lowkey now but I am almost being drained but still not giving up
A blessing is nothing imaginable or unimaginable but nothing is impossible for God to do.
I just pray for the ability to be able to keep  up as it is so much fun

[digaran]

nothing is impossible for God to do.

Only one thing is also impossible for God to do, suicide. Because energy can not be destroyed or created, if he is not the purest kind of energy then what?

Anyhow, your mistake is searching randomly/sequentially, doesn't matter what method you use, 66 bit is very large, you should have at least consult an expert before spending money, or just do a simple calculation like this :

Your speed rate = 5 billion keys per second, how many seconds is 1 year = 31536000 * 5b/2^66 = 467 years to search 66 bit.  If you believe in "luck" and "chance", you should buy lottery tickets to try your luck.

Anyone trying to brute force #66, please stop and first calculate the profit and cost.

[bestie1549]

nothing is impossible for God to do.

Only one thing is also impossible for God to do, suicide. Because energy can not be destroyed or created, if he is not the purest kind of energy then what?

Anyhow, your mistake is searching randomly/sequentially, doesn't matter what method you use, 66 bit is very large, you should have at least consult an expert before spending money, or just do a simple calculation like this :

Your speed rate = 5 billion keys per second, how many seconds is 1 year = 31536000 * 5b/2^66 = 467 years to search 66 bit.  If you believe in "luck" and "chance", you should buy lottery tickets to try your luck.

Anyone trying to brute force #66, please stop and first calculate the profit and cost.

WELL Hope, it is the quintessential human delusion, simultaneously the source of our greatest strength, and our greatest weakness.

[zahid888]

I've been receiving many DMs about this script, and I'm not sure what people find interesting in it. I made this script purely for fun.
I want to emphasize that it should not be used for any malicious purposes or to mislead anyone. Its sole purpose is for education, to show how a single seed can create an entire key. Here's the example script.

Code:

import random
from bit import *
import random

List = ["13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so","1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9",
        "1MVDYgVaSN6iKKEsbzRUAYFrYJadLYZvvZ","19vkiEajfhuZ8bs8Zu2jgmC6oqZbWqhxhG"]
count = 0
found = 0
for i in range (100000000):
    seed = random.getrandbits(128)
    seed_value = int(seed)
    random.seed(seed_value)
    seed = str(seed_value)
    a = random.randrange(2**65,2**66)
    key = Key.from_int(a)
    addr66 = key.address
    hex66 = "%00x" % a
    b = random.randrange(2**66,2**67)
    key = Key.from_int(b)
    addr67 = key.address
    hex67 = "%00x" % b
    c = random.randrange(2**67,2**68)
    key = Key.from_int(c)
    addr68 = key.address
    hex68 = "%00x" % c
    d = random.randrange(2**68,2**69)
    key = Key.from_int(d)
    addr69 = key.address
    hex69 = "%00x" % d
    count+=1
    print('\n\n=============================== Derived From OneSeed =============================\n\nSeeed : {}\nCount : {}\nFound : {}\nAddress 60 : 1Kn5h2qpgw9mWE5jKpk8PP4qvvJ1QVy8su | Private Key : fc07a1825367bbe\nAddress 61 : 1AVJKwzs9AskraJLGHAZPiaZcrpDr1U6AB | Private Key : 13c96a3742f64906\nAddress 62 : 1Me6EfpwZK5kQziBwBfvLiHjaPGxCKLoJi | Private Key : 363d541eb611abee\nAddress 63 : 1NpYjtLira16LfGbGwZJ5JbDPh3ai9bjf4 | Private Key : 7cce5efdaccf6808\nAddress 64 : 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN | Private Key : f7051f27b09112d4\nAddress 65 : 18ZMbwUFLMHoZBbfpCjUJQTCMCbktshgpe | Private Key : 1a838b13505b26867\nAddress 66 : {} | Private Key : {}\nAddress 67 : {} | Private Key : {}\nAddress 68 : {} | Private Key : {}\nAddress 69 : {} | Private Key : {}\nAddress 70 : 19YZECXj3SxEZMoUeJ1yiPsw8xANe7M7QR | Private Key : 349b84b6431a6c4ef1'.format(seed, count, found, '13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so', hex66, '1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9', hex67, '1MVDYgVaSN6iKKEsbzRUAYFrYJadLYZvvZ', hex68, '19vkiEajfhuZ8bs8Zu2jgmC6oqZbWqhxhG', hex69), end='\r')
   
    if addr66 in List or addr67 in List or addr68 in List or addr69 in List:
        print('\n\n================================ Found ================================\n\n')
        g=open(u"Found.txt","a")
        g.write("From one seed:         " +seed+'\n')
        g.write("\n" +addr66)
        g.write("\n" +addr67)
        g.write("\n" +addr68)
        g.write("\n" +addr69)
        g.write("\n"+seed + "\n"+ "\n")
        g.close()
        found += 1
    break

And yes, with great politeness and simplicity... I have allowed the newbie to DM me just to ensure that the creator doesn't drop any hints accidentally  This doesn't mean that everyone should keep messaging, except the creator , He can message me, 24x7

[bestie1549]

I've been receiving many DMs about this script, and I'm not sure what people find interesting in it. I made this script purely for fun.
I want to emphasize that it should not be used for any malicious purposes or to mislead anyone. Its sole purpose is for education, to show how a single seed can create an entire key. Here's the example script.

Code:

import random
from bit import *
import random

List = ["13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so","1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9",
        "1MVDYgVaSN6iKKEsbzRUAYFrYJadLYZvvZ","19vkiEajfhuZ8bs8Zu2jgmC6oqZbWqhxhG"]
count = 0
found = 0
for i in range (100000000):
    seed = random.getrandbits(128)
    seed_value = int(seed)
    random.seed(seed_value)
    seed = str(seed_value)
    a = random.randrange(2**65,2**66)
    key = Key.from_int(a)
    addr66 = key.address
    hex66 = "%00x" % a
    b = random.randrange(2**66,2**67)
    key = Key.from_int(b)
    addr67 = key.address
    hex67 = "%00x" % b
    c = random.randrange(2**67,2**68)
    key = Key.from_int(c)
    addr68 = key.address
    hex68 = "%00x" % c
    d = random.randrange(2**68,2**69)
    key = Key.from_int(d)
    addr69 = key.address
    hex69 = "%00x" % d
    count+=1
    print('\n\n=============================== Derived From OneSeed =============================\n\nSeeed : {}\nCount : {}\nFound : {}\nAddress 60 : 1Kn5h2qpgw9mWE5jKpk8PP4qvvJ1QVy8su | Private Key : fc07a1825367bbe\nAddress 61 : 1AVJKwzs9AskraJLGHAZPiaZcrpDr1U6AB | Private Key : 13c96a3742f64906\nAddress 62 : 1Me6EfpwZK5kQziBwBfvLiHjaPGxCKLoJi | Private Key : 363d541eb611abee\nAddress 63 : 1NpYjtLira16LfGbGwZJ5JbDPh3ai9bjf4 | Private Key : 7cce5efdaccf6808\nAddress 64 : 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN | Private Key : f7051f27b09112d4\nAddress 65 : 18ZMbwUFLMHoZBbfpCjUJQTCMCbktshgpe | Private Key : 1a838b13505b26867\nAddress 66 : {} | Private Key : {}\nAddress 67 : {} | Private Key : {}\nAddress 68 : {} | Private Key : {}\nAddress 69 : {} | Private Key : {}\nAddress 70 : 19YZECXj3SxEZMoUeJ1yiPsw8xANe7M7QR | Private Key : 349b84b6431a6c4ef1'.format(seed, count, found, '13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so', hex66, '1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9', hex67, '1MVDYgVaSN6iKKEsbzRUAYFrYJadLYZvvZ', hex68, '19vkiEajfhuZ8bs8Zu2jgmC6oqZbWqhxhG', hex69), end='\r')
   
    if addr66 in List or addr67 in List or addr68 in List or addr69 in List:
        print('\n\n================================ Found ================================\n\n')
        g=open(u"Found.txt","a")
        g.write("From one seed:         " +seed+'\n')
        g.write("\n" +addr66)
        g.write("\n" +addr67)
        g.write("\n" +addr68)
        g.write("\n" +addr69)
        g.write("\n"+seed + "\n"+ "\n")
        g.close()
        found += 1
    break

And yes, with great politeness and simplicity... I have allowed the newbie to DM me just to ensure that the creator doesn't drop any hints accidentally  This doesn't mean that everyone should keep messaging, except the creator , He can message me, 24x7

i APPRECIATE YOUR NEWBIES, BUT CAN THEY ALSO FUND THIS WALLET "1h7EsfXpgCLftpU4vucjkCbX1Wktop8GM" FOR ABILITY TO CONTINUE HAVING THE SAME FUN EVERYONE ELSE IS HAVING?

NOTHING IS TOO SMALL FROM YOUR NEWBIES. I JUST WANT TO PAY THE ELECTRICAL BILLS ACCRUED AND ALSO BE ABLE TO KEEP THESE MACHINES RUNNING. THANK YOU IN ADVANCE TO YOUR NEWBIES