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Author Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it  (Read 192026 times)
Jolly Jocker
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March 12, 2022, 04:41:06 PM
Last edit: March 13, 2022, 05:56:15 PM by Jolly Jocker
 #1781

Test Code for the 64 bit range... ca. 310000000 keys/hr...

Code:
import random
from threading import Thread
import secp256k1 as ice
from time import sleep
print('\n ========= ================= ==ADDRESS HUNTER== ================= ==========\n\n')
y=1000000
count=-2000000
def process1(number):
    line_count=0
    num = random.randrange(0x8000000000000000,0xffffffffffffffff)
    for i in range(number):
        num+=i
        addr = ice.privatekey_to_address(0, True, num)
        lineA = (addr, hex(num))
        line_count+=1
                    
        if '16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN' in lineA:
            file=open(u"BTH.Target.Info.txt","a")
            file.write('\n ' + str(lineA))
            file.close()
            wait = input("Press Enter to Exit.")
            exit()
                        
        if line_count == y:
            print(' current line: ', str(lineA))
            line_count=0
                    
while True:
    count+=(2*y)
    number = y
    threads = []
    print('\n Total Scanned Lines: ' + str(count) + '\n')
    for n in range(0,2):
        t = Thread(target=process1, args=(number,))
        threads.append(t)
        t.start()
        
    for t in threads:
        t.join()

donate BTC:  1DonateZNR9BUaCqJTgXCoyyCpRSosFujR
I tested your code, but the wrong ddd code doesn't collide even with 2 hex, which is a big problem



this is what your code should look like which works at 100% delete tqdm slowing code 10%
import random
from tqdm import tqdm
import secp256k1 as ice
for x in tqdm(range(100000000)):
 num = random.randrange(0xd2c00,0xd2cff)
 add = ice.privatekey_to_address(0,True,num)
 if "1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum" in (add):
  f=open("von.txt","a")
  f.write(str(num)+"-"+(add)+"\n")
  f.close()

I see you didn't understand the principle of my code...

This code (slightly modified) for the search for that Pubkey of 16jY7.... with 4 Threads make more as 380000000 Keys in 30 minutes...
I'll keep working on it... I'm sure there's more to come^^

Code:
import time
import random
import secp256k1 as ice
from time import sleep
from threading import Thread
from multiprocessing import Value
t = time.ctime()
print('',t)
print('\n |========== ========== ==========! PUBKEY HUNTER !========== ========== ==========||============\n\n')
print(' [*] create privkeys....', end='\r')

list=[]
a=2
y=1048576
counter = Value('L')
def process1(counter,number,n):
    ran = random.randrange(0x8000000000000001,0xffffffffffffffff)
    for i in range(number):
        ran+=1
        pub = ice.privatekey_to_h160(0, True, ran).hex()
        lineA = pub, hex(ran)
        list.append(lineA)
        if len(list)==y:
            for line in list:
                line!='\n'
                with counter.get_lock():
                    counter.value += 1
           
                if '3ee4133d991f52fdf6a25c9834e0745ac74248a4' in line:
                    threads.clear()
                    a=0
                    f=open("16jY7.txt","a")
                    f.write(str(line) +"\n")
                    f.close()
                    print('\n\n Target found!! \n' + str(line))
                    exit()
               
                if (counter.value)%y == 0:
                    print(' [ Recent-Line:', str(line),'] Total:', str(counter.value))#, end='\r')
                    list.clear()
                       
while len(list)<=y:
    number = y
    threads = []
    for n in range(a):
        t = Thread(target=process1, args=(counter,number,n))
        threads.append(t)
        t.start()

    for t in threads:
        t.join()

ok i take it back, I won't go into that anymore there are only 2 options 64 address has total epic fail hex or in this range is not at all happy hunting

The range doesn't matter in principle, we're just unlucky that we came too late and the lower areas have already been solved... every higher range reduces the chance of finding the desired address. Of course, luck plays a big part...
The "fun" factor and further learning how to use Python inspire the whole thing...

so don't fret Smiley Happy hunting!! despite everything ...
COBRAS
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March 14, 2022, 01:24:56 AM
Last edit: March 14, 2022, 09:41:48 AM by mprep
 #1782


Code:
import sys
import time
import random
#from tqdm import tqdm
from time import sleep
import secp256k1 as ice

print('\n      B I N A R Y   S E E D   S C A N   Q U A D R O   \n')
print(' 11_________________0____________________________________________\n')
x=16000
y=131071
list=[]
x0=0b100000000000000000000000000000000000000000000
for n in range(y):
    x1 = (x0+n)
    a1 = bin(random.randrange(131072,262143))#[2:].zfill(18)
    a1 = (a1)[2:]
    for i in range(x):
        a0 = str("1")           
        a2 = str("0")
        a3 = bin(random.randrange(x1,0b111111111111111111111111111111111111111111111))
        a3 = (a3)[3:]#.zfill(44)
        a4 = bin(random.randrange(x1,0b111111111111111111111111111111111111111111111))
        a4 = (a4)[3:]#.zfill(44)
        a5 = bin(random.randrange(x1,0b111111111111111111111111111111111111111111111))
        a5 = (a5)[3:]#.zfill(44)
        a6 = bin(random.randrange(x1,0b111111111111111111111111111111111111111111111))
        a6 = (a6)[3:]#.zfill(44)
        binb = "".join(a0+a1+a2+a3)
        binc = "".join(a0+a1+a2+a4)
        bind = "".join(a0+a1+a2+a5)
        bine = "".join(a0+a1+a2+a6)
        list.append(binb)
        list.append(binc)
        list.append(bind)
        list.append(bine)
        if len(list)==x:
            line_count=0
            for bina in (list):
                bina!='\n'
                addr = ice.privatekey_to_address(0, True, int(bina,2))
                line_count+=1
                                 
                if addr.startswith('16jY7'): # 16jY7
                    ran = int(bina,2)
                    print('',bina, '\n')
                    sys.stdout.write('\r ' + hex(ran))
                    sys.stdout.write(' ' + '| ' + addr + ' ' + str(n))
                    sleep(1)
                    sys.stdout.write('\n\n continue...\n\n')
                    sleep(1)

                if addr == "16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN":
                    ran = int(bina,2)
                    print('\n\n Target found!!' + hex(ran) + ' \n ' + addr,'\n')
                    file=open(u"16j.Target.Info.txt","a")
                    file.write('\n ' + hex(ran) + ' | ' + addr)
                    file.close()
                    sleep(2)
                    wait = input("Press Enter to Exit.")
                    sleep(1)
                    exit()
                   
                if line_count==x:
                    list.clear()
                   
        if len(list)==0:
            print(' scan... ', str(n), end='\r')                       

Ca 42000 keys/s from c000000000000000 to ffffffffffffffff... The sector between  11_________________0 comprise a range of 131071 and will be processed.
The rest of this line are random numbers from 4 different generators..
The counter reflects the number of loops...

      B I N A R Y   S E E D   S C A N   Q U A D R O

 11_________________0____________________________________________

 1110010110110011011010011110001111111110100110111011100101000111

 0xe5b369e3fe9bb947 | 16jY7mM6wrpuAy53vKkh7QXm1JNdWK9Myu 19

 continue...

 1110010011000111001010001111000110100111001000001001110001000100

 0xe4c728f1a7209c44 | 16jY7Ezk5et98CVBWYEigGRwWovzhEtaQ3 121

 continue...

 scan...  192

Hi. I think your idea interesting. In this article another method how to recover privkey with add pubkeys what you think about this ?
https://toadstyle.org/cryptopals/66.txt

K is prrivkey, b is a picies of privkey:

For example, with n = 6, trace(58) gives me:

  # k = 111010
  # i = 2, b = 1
  add(1Q, 1Q)
  add(2Q, 1Q)
  # i = 3, b = 1
  add(3Q, 3Q)
  add(6Q, 1Q)
  # i = 4, b = 0
  add(7Q, 7Q)
  # i = 5, b = 1
  add(14Q, 14Q)
  add(28Q, 1Q)
  # i = 6, b = 0
  add(29Q, 29Q)

And here's trace(62):

  # k = 111110
  # i = 2, b = 1
  add(1Q, 1Q)
  add(2Q, 1Q)
  # i = 3, b = 1
  add(3Q, 3Q)
  add(6Q, 1Q)
  # i = 4, b = 1
  add(7Q, 7Q)
  add(14Q, 1Q)
  # i = 5, b = 1
  add(15Q, 15Q)
  add(30Q, 1Q)
  # i = 6, b = 0
  add(31Q, 31Q)





asic miner
github.com/achow1o1

update: Kiss
1J8wBriLsHvE52Jah75bKU1VSxj9btzLeq
1EhRDeGsoQVkAsiCtbDUbNnRW8a977bduS

Update2
2021.03.02
1CAsB6DdK6ezYzefzRe3SuQ1bZztsgaiQS
12JQGbJUHohtfoPbbZKbF8Z8hW5wYde1KN
1DKsKYzpqaTAg3Q4KrCBJ7AS4R1YyQrisE
1GymA7nkPZVBz3crj2NuFfGZsngTTX51Sb

How you crack them bro ? Thx



Enother interesting code - https://github.com/jairopaiva/BitcoinExprCracker

Search metadata for finding privkey... Needs modification for work

[moderator's note: consecutive posts merged]

[
PrivatePerson
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March 14, 2022, 07:48:58 AM
 #1783

Enother interesting code - https://github.com/jairopaiva/BitcoinExprCracker

Search metadata for finding privkey... Needs modification for work
uses 1 processor core, does not work on 0279be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798
sungurvid
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March 14, 2022, 10:22:04 AM
Last edit: March 16, 2022, 11:38:45 AM by sungurvid
 #1784

is there any new method for trying to find private keys? vidmate app download insta save
 
COBRAS
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March 14, 2022, 03:22:31 PM
 #1785

Enother interesting code - https://github.com/jairopaiva/BitcoinExprCracker

Search metadata for finding privkey... Needs modification for work
uses 1 processor core, does not work on 0279be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798

Did you try this bro ?

:
K is prrivkey, b is a picies of privkey:

For example, with n = 6, trace(58) gives me:

  # k = 111010
  # i = 2, b = 1
  add(1Q, 1Q)
  add(2Q, 1Q)
  # i = 3, b = 1
  add(3Q, 3Q)
  add(6Q, 1Q)
  # i = 4, b = 0
  add(7Q, 7Q)
  # i = 5, b = 1
  add(14Q, 14Q)
  add(28Q, 1Q)
  # i = 6, b = 0
  add(29Q, 29Q)


Huh

[
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March 14, 2022, 06:36:24 PM
 #1786


Did you try this bro ?

no, I don't understand what it is.
COBRAS
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March 14, 2022, 07:52:12 PM
 #1787


Did you try this bro ?

no, I don't understand what it is.

Read this https://toadstyle.org/cryptopals/66.txt

??

[
Jolly Jocker
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March 16, 2022, 05:54:37 AM
Last edit: March 17, 2022, 07:31:26 AM by mprep
 #1788


Code:
import sys
import time
import random
#from tqdm import tqdm
from time import sleep
import secp256k1 as ice

print('\n      B I N A R Y   S E E D   S C A N   Q U A D R O   \n')
print(' 11_________________0____________________________________________\n')
x=16000
y=131071
list=[]
x0=0b100000000000000000000000000000000000000000000
for n in range(y):
    x1 = (x0+n)
    a1 = bin(random.randrange(131072,262143))#[2:].zfill(18)
    a1 = (a1)[2:]
    for i in range(x):
        a0 = str("1")           
        a2 = str("0")
        a3 = bin(random.randrange(x1,0b111111111111111111111111111111111111111111111))
        a3 = (a3)[3:]#.zfill(44)
        a4 = bin(random.randrange(x1,0b111111111111111111111111111111111111111111111))
        a4 = (a4)[3:]#.zfill(44)
        a5 = bin(random.randrange(x1,0b111111111111111111111111111111111111111111111))
        a5 = (a5)[3:]#.zfill(44)
        a6 = bin(random.randrange(x1,0b111111111111111111111111111111111111111111111))
        a6 = (a6)[3:]#.zfill(44)
        binb = "".join(a0+a1+a2+a3)
        binc = "".join(a0+a1+a2+a4)
        bind = "".join(a0+a1+a2+a5)
        bine = "".join(a0+a1+a2+a6)
        list.append(binb)
        list.append(binc)
        list.append(bind)
        list.append(bine)
        if len(list)==x:
            line_count=0
            for bina in (list):
                bina!='\n'
                addr = ice.privatekey_to_address(0, True, int(bina,2))
                line_count+=1
                                 
                if addr.startswith('16jY7'): # 16jY7
                    ran = int(bina,2)
                    print('',bina, '\n')
                    sys.stdout.write('\r ' + hex(ran))
                    sys.stdout.write(' ' + '| ' + addr + ' ' + str(n))
                    sleep(1)
                    sys.stdout.write('\n\n continue...\n\n')
                    sleep(1)

                if addr == "16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN":
                    ran = int(bina,2)
                    print('\n\n Target found!!' + hex(ran) + ' \n ' + addr,'\n')
                    file=open(u"16j.Target.Info.txt","a")
                    file.write('\n ' + hex(ran) + ' | ' + addr)
                    file.close()
                    sleep(2)
                    wait = input("Press Enter to Exit.")
                    sleep(1)
                    exit()
                   
                if line_count==x:
                    list.clear()
                   
        if len(list)==0:
            print(' scan... ', str(n), end='\r')                       

Ca 42000 keys/s from c000000000000000 to ffffffffffffffff... The sector between  11_________________0 comprise a range of 131071 and will be processed.
The rest of this line are random numbers from 4 different generators..
The counter reflects the number of loops...

      B I N A R Y   S E E D   S C A N   Q U A D R O

 11_________________0____________________________________________

 1110010110110011011010011110001111111110100110111011100101000111

 0xe5b369e3fe9bb947 | 16jY7mM6wrpuAy53vKkh7QXm1JNdWK9Myu 19

 continue...

 1110010011000111001010001111000110100111001000001001110001000100

 0xe4c728f1a7209c44 | 16jY7Ezk5et98CVBWYEigGRwWovzhEtaQ3 121

 continue...

 scan...  192

Hi. I think your idea interesting. In this article another method how to recover privkey with add pubkeys what you think about this ?
https://toadstyle.org/cryptopals/66.txt

K is prrivkey, b is a picies of privkey:

For example, with n = 6, trace(58) gives me:

  # k = 111010
  # i = 2, b = 1
  add(1Q, 1Q)
  add(2Q, 1Q)
  # i = 3, b = 1
  add(3Q, 3Q)
  add(6Q, 1Q)
  # i = 4, b = 0
  add(7Q, 7Q)
  # i = 5, b = 1
  add(14Q, 14Q)
  add(28Q, 1Q)
  # i = 6, b = 0
  add(29Q, 29Q)

And here's trace(62):

  # k = 111110
  # i = 2, b = 1
  add(1Q, 1Q)
  add(2Q, 1Q)
  # i = 3, b = 1
  add(3Q, 3Q)
  add(6Q, 1Q)
  # i = 4, b = 1
  add(7Q, 7Q)
  add(14Q, 1Q)
  # i = 5, b = 1
  add(15Q, 15Q)
  add(30Q, 1Q)
  # i = 6, b = 0
  add(31Q, 31Q)





asic miner
github.com/achow1o1

update: Kiss
1J8wBriLsHvE52Jah75bKU1VSxj9btzLeq
1EhRDeGsoQVkAsiCtbDUbNnRW8a977bduS

Update2
2021.03.02
1CAsB6DdK6ezYzefzRe3SuQ1bZztsgaiQS
12JQGbJUHohtfoPbbZKbF8Z8hW5wYde1KN
1DKsKYzpqaTAg3Q4KrCBJ7AS4R1YyQrisE
1GymA7nkPZVBz3crj2NuFfGZsngTTX51Sb

How you crack them bro ? Thx



Enother interesting code - https://github.com/jairopaiva/BitcoinExprCracker

Search metadata for finding privkey... Needs modification for work


Thanks a lot Bro!

But, I have to fight my way through this first... and it's not so easy, especially since English is not my mother tongue... so it needs a while ^^

you know, g00gle translater .... lol XD



A little toy... 4 cores in working.. Happy Hunting!!

Code:
import time
import random
import secp256k1 as ice
from time import sleep
from multiprocessing import Process, Value

a = 4
y = 2097152
counter = Value('L')
def process1(number,counter,):
    while True:
        a = random.randint(2**63, 2**64)
        for x in range(number):
            x = x
            bina = bin(a)[2:]
            zeros = bina.count("0")
            if zeros >= 16:
                if zeros <= 43:
                    addr = ice.privatekey_to_address(0, True, a)
                    with counter.get_lock():
                            counter.value += 1
                   
                    if addr.startswith('16jY7q'):
                        print('\n Pattern found: '+hex(a)+' | '+ addr)
                        sleep(1)
                        print("\n continue...\n")
                       
                    if addr == "16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN":
                        file=open(u"16jY.Info.txt","a")
                        file.write('\n '+hex(a)+' | '+ addr)
                        file.close()
                        wait = input("Press Enter to Exit.")
                        sleep(1)
                        exit()
                       
                    if x == 0:
                        print ('', hex(a), bina, zeros, '', str(counter.value))
               
               
            a = a +1
        pass

if __name__ == '__main__':
    t = time.ctime()
    print('',t)
    number = y
    workers = []
    print('\n\n BINARY MULTI PY \n #64: 8000000000000000...ffffffffffffffff\n\n')
    print('                                                                                    zeros')
    print(' == PRIVKEY HEX == |____________________________ BINARY ____________________________|  | CNT == \n')
    for r in range(a):
        p = Process(target=process1, args=(number,counter,))
        workers.append(p)
        p.start()

    for worker in workers:
        worker.join()           

Quote

  Wed Mar 16 22:50:29 2022


 BINARY MULTI PY
 #64: 8000000000000000...ffffffffffffffff


                                                                                                                                                zeros
 == PRIVKEY HEX == |____________________________ BINARY ____________________________|  | CNT ==

 0x8fb6f979c971deb7 1000111110110110111110010111100111001001011100011101111010110111 23  1
 0xd71cef3d4d5dbb35 1101011100011100111011110011110101001101010111011011101100110101 24  2
 0xbf232d596f8c506f 1011111100100011001011010101100101101111100011000101000001101111 29  79
 0xb303436dcb92d933 1011001100000011010000110110110111001011100100101101100100110011 32  293

 Pattern found: 0xd71cef3d4d64dbb4 | 16jY7h2kCHJmhW42oUFyCeyucfrsRSNM9t

 continue...


 Pattern found: 0xb303436dcba91968 | 16jY7qGbzuSoT18AEyfZ1tyEsv8uzN5Bmp

 continue...

 0xe85e879a14758f47 1110100001011110100001111001101000010100011101011000111101000111 31  8239375
 0xa9b982acb6cf7e30 1010100110111001100000101010110010110110110011110111111000110000 30  8330122
 0xed25182830ace349 1110110100100101000110000010100000110000101011001110001101001001 37  8381965
 0xc162d7c463b14442 1100000101100010110101111100010001100011101100010100010001000010 37  8607642



[moderator's note: consecutive posts merged]
COBRAS
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March 17, 2022, 03:43:47 AM
 #1789

A little toy... 4 cores in working.. Happy Hunting!!

Code:
import time
import random
import secp256k1 as ice
from time import sleep
from multiprocessing import Process, Value

a = 4
y = 2097152
counter = Value('L')
def process1(number,counter,):
    while True:
        a = random.randint(2**63, 2**64)
        for x in range(number):
            x = x
            bina = bin(a)[2:]
            zeros = bina.count("0")
            if zeros >= 16:
                if zeros <= 43:
                    addr = ice.privatekey_to_address(0, True, a)
                    with counter.get_lock():
                            counter.value += 1
                    
                    if addr.startswith('16jY7q'):
                        print('\n Pattern found: '+hex(a)+' | '+ addr)
                        sleep(1)
                        print("\n continue...\n")
                        
                    if addr == "16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN":
                        file=open(u"16jY.Info.txt","a")
                        file.write('\n '+hex(a)+' | '+ addr)
                        file.close()
                        wait = input("Press Enter to Exit.")
                        sleep(1)
                        exit()
                        
                    if x == 0:
                        print ('', hex(a), bina, zeros, '', str(counter.value))
                
                
            a = a +1
        pass

if __name__ == '__main__':
    t = time.ctime()
    print('',t)
    number = y
    workers = []
    print('\n\n BINARY MULTI PY \n #64: 8000000000000000...ffffffffffffffff\n\n')
    print('                                                                                    zeros')
    print(' == PRIVKEY HEX == |____________________________ BINARY ____________________________|  | CNT == \n')
    for r in range(a):
        p = Process(target=process1, args=(number,counter,))
        workers.append(p)
        p.start()

    for worker in workers:
        worker.join()          

Quote

  Wed Mar 16 22:50:29 2022


 BINARY MULTI PY
 #64: 8000000000000000...ffffffffffffffff


                                                                                                                                                zeros
 == PRIVKEY HEX == |____________________________ BINARY ____________________________|  | CNT ==

 0x8fb6f979c971deb7 1000111110110110111110010111100111001001011100011101111010110111 23  1
 0xd71cef3d4d5dbb35 1101011100011100111011110011110101001101010111011011101100110101 24  2
 0xbf232d596f8c506f 1011111100100011001011010101100101101111100011000101000001101111 29  79
 0xb303436dcb92d933 1011001100000011010000110110110111001011100100101101100100110011 32  293

 Pattern found: 0xd71cef3d4d64dbb4 | 16jY7h2kCHJmhW42oUFyCeyucfrsRSNM9t

 continue...


 Pattern found: 0xb303436dcba91968 | 16jY7qGbzuSoT18AEyfZ1tyEsv8uzN5Bmp

 continue...

 0xe85e879a14758f47 1110100001011110100001111001101000010100011101011000111101000111 31  8239375
 0xa9b982acb6cf7e30 1010100110111001100000101010110010110110110011110111111000110000 30  8330122
 0xed25182830ace349 1110110100100101000110000010100000110000101011001110001101001001 37  8381965
 0xc162d7c463b14442 1100000101100010110101111100010001100011101100010100010001000010 37  8607642



Hi. How to change cores from 4 to 64 and more ?

Bro, can you put code to file and upload file to file share hosting ? I work from phone very hard put past without damage a code.

Regards Bro

[
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March 17, 2022, 11:50:05 AM
Last edit: March 17, 2022, 01:08:51 PM by Jolly Jocker
 #1790

you can select the number of cores via ' a = ' in the top of the scrypt ..
I have to deal with the upload first... I haven't done it yet..

i just see that " a " wasn't a good choice for the cores, since a is already used in scrypt.. change from "a = 4" to "c =4" and in the part "for r in range(a): " to " for r in range(c): " important!!

Although it works with "a" , it could lead to errors!


The corrected code !

Code:
import time
import random
import secp256k1 as ice
from time import sleep
from multiprocessing import Process, Value

c = 4
y = 2097152
counter = Value('L')
def process1(number,counter,):
    while True:
        a = random.randint(2**63, 2**64)
        for x in range(number):
            x = x
            bina = bin(a)[2:]
            zeros = bina.count("0")
            if zeros >= 16:
                if zeros <= 43:
                    addr = ice.privatekey_to_address(0, True, a)
                    with counter.get_lock():
                            counter.value += 1
                    
                    if addr.startswith('16jY7q'):
                        print('\n Pattern found: '+hex(a)+' | '+ addr)
                        sleep(1)
                        print("\n continue...\n")
                        
                    if addr == "16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN":
                        file=open(u"16jY.Info.txt","a")
                        file.write('\n '+hex(a)+' | '+ addr)
                        file.close()
                        wait = input("Press Enter to Exit.")
                        sleep(1)
                        exit()
                        
                    if x == 0:
                        print ('', hex(a), bina, zeros, '', str(counter.value))
                
                
            a = a +1
        pass

if __name__ == '__main__':
    t = time.ctime()
    print('',t)
    number = y
    workers = []
    print('\n\n BINARY MULTI PY \n #64: 8000000000000000...ffffffffffffffff\n\n')
    print('                                                                                    zeros')
    print(' == PRIVKEY HEX == |____________________________ BINARY ____________________________|  | CNT == \n')
    for r in range(c):
        p = Process(target=process1, args=(number,counter,))
        workers.append(p)
        p.start()

    for worker in workers:
        worker.join()          

 


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March 19, 2022, 07:18:36 PM
 #1791

Here's another 64 bit pool for puzzle #64

http://bitcoinchallenge.site/64-bit-user-stats/

https://github.com/WanderingPhilosopher/64-Bit-Random-Pool-2

https://discord.gg/Kv2sSFUX
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March 19, 2022, 10:01:32 PM
 #1792

you can select the number of cores via ' a = ' in the top of the scrypt ..
I have to deal with the upload first... I haven't done it yet..

i just see that " a " wasn't a good choice for the cores, since a is already used in scrypt.. change from "a = 4" to "c =4" and in the part "for r in range(a): " to " for r in range(c): " important!!

Although it works with "a" , it could lead to errors!


The corrected code !

Code:
import time
import random
import secp256k1 as ice
from time import sleep
from multiprocessing import Process, Value

c = 4
y = 2097152
counter = Value('L')
def process1(number,counter,):
    while True:
        a = random.randint(2**63, 2**64)
        for x in range(number):
            x = x
            bina = bin(a)[2:]
            zeros = bina.count("0")
            if zeros >= 16:
                if zeros <= 43:
                    addr = ice.privatekey_to_address(0, True, a)
                    with counter.get_lock():
                            counter.value += 1
                    
                    if addr.startswith('16jY7q'):
                        print('\n Pattern found: '+hex(a)+' | '+ addr)
                        sleep(1)
                        print("\n continue...\n")
                        
                    if addr == "16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN":
                        file=open(u"16jY.Info.txt","a")
                        file.write('\n '+hex(a)+' | '+ addr)
                        file.close()
                        wait = input("Press Enter to Exit.")
                        sleep(1)
                        exit()
                        
                    if x == 0:
                        print ('', hex(a), bina, zeros, '', str(counter.value))
                
                
            a = a +1
        pass

if __name__ == '__main__':
    t = time.ctime()
    print('',t)
    number = y
    workers = []
    print('\n\n BINARY MULTI PY \n #64: 8000000000000000...ffffffffffffffff\n\n')
    print('                                                                                    zeros')
    print(' == PRIVKEY HEX == |____________________________ BINARY ____________________________|  | CNT == \n')
    for r in range(c):
        p = Process(target=process1, args=(number,counter,))
        workers.append(p)
        p.start()

    for worker in workers:
        worker.join()          

 


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Traceback (most recent call last):
  File "main.py", line 3, in <module>
    import secp256k1 as ice
ModuleNotFoundError: No module named 'secp256k1'
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March 19, 2022, 10:23:54 PM
 #1793

you can select the number of cores via ' a = ' in the top of the scrypt ..
I have to deal with the upload first... I haven't done it yet..

i just see that " a " wasn't a good choice for the cores, since a is already used in scrypt.. change from "a = 4" to "c =4" and in the part "for r in range(a): " to " for r in range(c): " important!!

Although it works with "a" , it could lead to errors!


The corrected code !

Code:
import time
import random
import secp256k1 as ice
from time import sleep
from multiprocessing import Process, Value

c = 4
y = 2097152
counter = Value('L')
def process1(number,counter,):
    while True:
        a = random.randint(2**63, 2**64)
        for x in range(number):
            x = x
            bina = bin(a)[2:]
            zeros = bina.count("0")
            if zeros >= 16:
                if zeros <= 43:
                    addr = ice.privatekey_to_address(0, True, a)
                    with counter.get_lock():
                            counter.value += 1
                    
                    if addr.startswith('16jY7q'):
                        print('\n Pattern found: '+hex(a)+' | '+ addr)
                        sleep(1)
                        print("\n continue...\n")
                        
                    if addr == "16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN":
                        file=open(u"16jY.Info.txt","a")
                        file.write('\n '+hex(a)+' | '+ addr)
                        file.close()
                        wait = input("Press Enter to Exit.")
                        sleep(1)
                        exit()
                        
                    if x == 0:
                        print ('', hex(a), bina, zeros, '', str(counter.value))
                
                
            a = a +1
        pass

if __name__ == '__main__':
    t = time.ctime()
    print('',t)
    number = y
    workers = []
    print('\n\n BINARY MULTI PY \n #64: 8000000000000000...ffffffffffffffff\n\n')
    print('                                                                                    zeros')
    print(' == PRIVKEY HEX == |____________________________ BINARY ____________________________|  | CNT == \n')
    for r in range(c):
        p = Process(target=process1, args=(number,counter,))
        workers.append(p)
        p.start()

    for worker in workers:
        worker.join()          

 


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Traceback (most recent call last):
  File "main.py", line 3, in <module>
    import secp256k1 as ice
ModuleNotFoundError: No module named 'secp256k1'
https://github.com/iceland2k14/secp256k1
first download these files, you must run the python code in the folder where those files are stored
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March 19, 2022, 10:27:39 PM
 #1794

Traceback (most recent call last):
  File "main.py", line 3, in <module>
    import secp256k1 as ice
ModuleNotFoundError: No module named 'secp256k1'




This module appears frequently on the last few pages, and there is also a download link... so again for everyone ^^

"[faster "bit" there is a library from "ice" https://github.com/iceland2k14/secp256k1 there it is necessary to throw its libraries into the folder with the script.]"
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March 20, 2022, 06:01:50 PM
Last edit: March 20, 2022, 06:15:21 PM by Jolly Jocker
 #1795

I took the time to program a small tool to create this list..     Pattern: "16jY7qLJn"

maybe someone can do something with it, because the assignment of the pubkeys to the respective addresses is meaningful.
The list is sorted by pubkey. ( somewhat shortened due to lack of space )

Code:
('0200a89f5508695dd9c0900621681ff9b961d67772c323642a5e1f042d4cff3529', 'CCC4140031FEDA91', '16jY7qLJnMcUAdSQqtQzqcBMcrSRedgSk2')
('0200d8fb32f510c9c0cf659de7ef3ec5df5357d52ff8b356fca3aaa56e3b1e34d0', 'C845851F3595B29D', '16jY7qLJnrEmEdeY1ESqhcV2eejTYYihUz')
('02038120202a3157ab9e1b75bd185aee2d3fc3c09c4df356b0609562011a9d26e7', 'CCECAF00D74EFDAA', '16jY7qLJnJsNNyArhGgdcZBEKhR4DAXDvE')
('020404a74780b2c8f7a9a5f28e8b40a9eebe284097e05251f2037b4fa8fc97ab5d', 'C7445D5B38507F83', '16jY7qLJnepq968DgsxCqcfdeoqC3oX4yZ')
('020637952f64dfdd3c907857ed1f9b0f2b8b696136271384be96b458b2f5be38f0', 'CCEE88000BF3C9D3', '16jY7qLJnXHDFpJFrbEKPGVgS8h6XDjuLE')
('020799d410b4ca32b06dcb175268f437c0722885ad37e4fdbbc24145d1713417d1', 'A8C1DEBFC21902CC', '16jY7qLJna6grEq9tQz9FketLK6zDFLYNa')
('02091ed71dcd26e3b004409aa9211d8886663604eff9bac5ee9c14e9e6b0a89d89', '89F84ED1040B8782', '16jY7qLJnbwfCSSRXivZnCFG6phBAYvT1b')
('02094ddabdee0217b83b5abf285c60b7339ca71113762e227b4e6724983b9d8f89', '986EBB933EEE0962', '16jY7qLJnFpswGCQLBKoStQCoevvQb53G1')
('020953dd312efece156fade157f92ce57bccab87e85f272d5c0739b6cf6548520d', 'E2E1399B7F7EAE88', '16jY7qLJnMNGbuKo8w4ZunxcXtXjJHsf5j')
('020afa3ba6cc87ed60c56d2f4913a3804eda634bcf676bfe3e81786fed3c2b8470', 'B2885F30E6063B77', '16jY7qLJnQVihCA2Fcf6dDF9sYpA3TraHM')
('020b837269fbd708d433a694c32654bedd66175c2e397f273140b61a5ee916b021', 'E4B45971ECA7F5D2', '16jY7qLJnqQhrBCNFF5RJBsEjf6h7s2Pwq')
('020c183a237ba57a19c56b6ba9ed21d837307fad0ce369223ec02dc76df7e4f717', 'E687819A73B0D830', '16jY7qLJnjzpYWN9cqNXPsrvXKJhyNRbfd')
('020cbd5f57fbf0034809b3f112f1d33a2b5a8f580d110608532caeb95d30d5c98f', 'E570CE674AB8433D', '16jY7qLJn68WC24oCCbiApv1mmQPzsSWUv')
('020d33c9b1acb4e0a931b080c0f25d751f7bc9caa899d1907e8a79825ea40efbf6', 'BC6BBAAB1BEE0BE7', '16jY7qLJnZ44prYqrey4e99w61VZGZg65z')
('020d6089beec67cab0865f45690034b0ebeb2d7c5c40a4a2ed0aa822b7196ed895', 'C4DC9C0049D95DAB', '16jY7qLJnFLhrdYWZPdXmcg1ZE9pM7FisM')
('020ddbf6d854f92c21f6caf38ddac4ac0d7b547e38b1ff4d0e25e2a813f02924ca', 'CA6DF3000D542EEA', '16jY7qLJnZ4dcqeD8unXdpUczZTyza1y6F')
('0210988a7c2be0a7142eefe71b1dcdd358e61d15e47b293d58c24a8eb7c892d52d', 'A81975005CC66F98', '16jY7qLJnqiSjVcdAXdLpQSRVEVuDSpJM8')
('02116b732961730fa1bec1e1745c6de77787275400f73a3ed49032740afb6e323d', 'AFB0B40000B4CA6E', '16jY7qLJn1jqi1X7zf6f8iVBaJcpDoXWzk')
('0212608d7d304ffdb516ae21e3ce9b1a4b9aa1fd87bf722c0614acd3154352b6fb', 'A37E37006AFDBCA1', '16jY7qLJnMd3T5pEsjaMm9ErDZBCndfVBe')
('02139edcd79ec4ffdf7f4fe59d5d49ebcf30c66284a99ecfc88d21a9e6f3e487dc', 'EEB9AB334DF2770D', '16jY7qLJnxHBp3dqwV2kzYq1LucfZzgxsH')
('0216e507ed22039c2ec79f442bec4d3d696e0ea59d7826036ac50824582ec2a6b7', 'A9896478F913D4BA', '16jY7qLJnwbnmdMMYMyEfeXVC46UKNwGR2')
('0219b71b25ba5a74de65e76e79e9aa0ac53cb44381ffd9010e9f676a10b79c3d69', 'CC6C0C00A521FD62', '16jY7qLJnrqR3sy8SoMPrjyX53rJ6NC7Bw')
('021a336b45c301ef15486f4b00f6341ab619f2b632a697962da84d9f89de07e9be', 'E560CCCD46FD0290', '16jY7qLJnDjCcPohFResu1FTxwp7stW4PE')
('021b8742dc73ba324e92b463a828b685adcd04181271bf9384a27a4353f938cd68', 'EB78E99A80E1D123', '16jY7qLJnVvUHqZ96upirrHCHS7ETULczt')
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('03968a036c0b94c19eb549f343e8d60b029d2fc00423e094d0872c228e4a93cf30', 'E86DA3355B41DE08', '16jY7qLJnjsgatEfX8c8be7ndALNxixkhi')
('039695d868848ecfbc4b0a9972c87ea3570d65b9b039ba28e7eb081d55cde11c5e', 'EDF15333EF0A5CC5', '16jY7qLJnyLMtk2RbJzhc67QawKwAisLPq')
('0397ac1b9c51f198cb87522869f8e518b320489ec68ed8c9d22afa38171c04e581', 'C15A1200F75AD8EB', '16jY7qLJnFUUwD5t2x3RdBKTbC1eGcyF1k')
('039a0d9ba74d79d792a3ef79b8b79942309afbe8eef313ab9325faca42a2d12bf9', 'CB3C60009EF6B004', '16jY7qLJn9ayfuiHA2JXtTBLT9ae4XtWuj')
('039b812c5d783d8e3d5f6af5db24a712464e789348c3f09fcaecf7bd2d3ad1c31a', 'E861B001882ECB30', '16jY7qLJnMFy13W24kBN5SS282UQwvMqN9')
('039bf0aadc20ee747a6487d6787ec2dea2fc5bf150ae8ef1c06eb540713b4c942a', 'E71DA6678287DC74', '16jY7qLJnjkMyWbQgMWg8CKg8yZ1Bd58UB')
('039c051a373969d3e00c31b88a09158dfcefb007449f7c2e07148065e0c024e3a0', 'AFC92C00B979883C', '16jY7qLJn8QddVvvJEGTbAVKh6JkuiCuKj')
('039db71719be7c92844b10a1858767049425bc5b60fb19aeae35ba805912bdff72', 'AF123B00B9D1F09C', '16jY7qLJnvvue8v8zBFWKXpf9Cig1WQRXU')
('039e82593d2abf17d25840da59f3f265ed5a45470dcbb0b92d639c952b56d9a366', 'EEE8D199C2D84A9B', '16jY7qLJnSA9iEvCNksL6JUv5m7CTaLgft')
('039edf5687b4c32116aa04b5dfdd79a6e4aa694ec85238f16f5da6d046bd28db2c', '9357254130F9270A', '16jY7qLJnxht5HL2NBywuoC8jK34rz8NJv')
('039f7308acbae1b53a11506184ad17d3562758d36aa32ccf1ee150c3770517cb5a', 'C512EA0050D8D9B0', '16jY7qLJnvpd11939Kq5ckrZ78ManLtUtS')
('03a042ec45628ef1f10d2a5f6df034bbce845cdfbe8860138481c3971c0275087e', 'C49662E8F7D2D6BB', '16jY7qLJnqBp3rdh88Y6ETzhAxqh4hHs6q')
('03a493dfb869aa8c770f1b0111b6bcc2887e2255883d126123d7ac18c7d03e8bc0', 'AEBA51003F18DE8E', '16jY7qLJnv4SAurcF5dEi2DG7K8JkJh9km')
('03a6221131839500c30f0f22410d86e7b8c4b1a37fa566bb418427336a791d2116', 'EBE2EB35503B43E4', '16jY7qLJnx4f4yqNvmp7LtnaatiUuwgUwW')
('03a6738b07f64654dd6e3a89f053938882356513b8f75fa9afd1c21ee0d6fbc083', 'EA7BBCCDB0F7B2A3', '16jY7qLJnmvACiGwX3Zm8iNEPdexKfas4f')
('03a86880bc0249c031f6bf191b720ea4f99337cbac9f6a821b93b20fdb8e1a22ae', 'E070F666E2573DE8', '16jY7qLJn843XsGiFY3oazx3BpJTg7gRiT')
('03acee934468277bf0b2e33c868d2def711f964ee5575af646499de669236284c9', 'AB7482000EFE85BD', '16jY7qLJnUg7YTekvW6Wka3q7fdNtqdC6j')
('03ad75fa7d1c3097af86735afcd950bc7c876de6de86c36742120ac8b169f1defe', 'C3778300BB3B69B6', '16jY7qLJnT45i8pbFn2nLLwTJnZaV9fgtm')
('03b2611a764b33427f7e59894a0153de291cdb6441e41460d3aa1eb7b1208ed06d', 'E9E2019AF1C052C6', '16jY7qLJnDToFrGzPttm8Cmi3sTjQTfsLi')
('03b444995b2ec17c71d8f0db2d85f9bd621f49f5eee38d9b724d452974653dfdb7', 'CF9E650097205A8B', '16jY7qLJnZFTJnRsjBLLGcq27bUcfuxPTF')
('03b5593a1fe240a9b395363e445a8659022d30d8548127bae8d704a4da65afca5c', 'E89D8334E970664A', '16jY7qLJntnaTGCiVF4FpyZsBuPPfJPVBv')
('03b97503e696e81dd3e33f898ee9211d1ce9db432fa418e490cf89f1a91a36ac36', 'E808784C4A608B3A', '16jY7qLJnkshPqcGuHRFtJGrSoxxMCsCEx')
('03baa2db85594cbb37031d739894e56c2e4f7e232943d4073e7234eb34e2f6c687', 'EDEC26E9C9E3F377', '16jY7qLJnSwho77XBFFwY4rpN891YYWh3b')
('03bec0816ceb287dc21f28220682adbc02915bbc4d38f9a4bac9d6656528b94ed4', 'AE75D700B608AD77', '16jY7qLJniV67EwigXdiDRjBak4Bqevbks')
('03beefe370755b87b4330de8b470cfea3a290e3d57fe1516f750cc2de44557d7ec', 'E3732B34EEBA8944', '16jY7qLJnGNP2sRrRDTrjbhs1jPuPKPfzo')
('03bfe277a9f27af701fac3dde4795116b8435b0977c3c57968388d19193cc30d37', 'BAB305558D193E4E', '16jY7qLJneSZrBqpiLzymUsw3HUoQcVeJs')
('03c3f67bf7c4da1e088b6c6df83b91d6eef5e06265d1dac0147f6deb12ad21c2d7', 'ABCAF600C50869BF', '16jY7qLJnf9qg7cmWogBCs9KQ6zNWBadgv')
('03c410f1429b71237f9bb5222768e25ca736d2dc59495600764d50e149ea09169e', 'E8A2699BFE9682EA', '16jY7qLJnp2pbdT67BVN6MjtzNE6oPkTMZ')
('03c4d849881f66cd41d0e28a6d033d98f857476a0ce0cec02871c70bf73f85bef8', 'AC015500AA512D6E', '16jY7qLJnvd6DouYVwCe335qWHUCYm7ZVf')
('03c4fa496173b6200cd65e92a16e4ff040476cc55d24591df32516699301eed01f', 'C2C2B30046D14249', '16jY7qLJnUtNieWEk1sqrWYp9wy1ne7KVZ')
('03c78eda87989dd5d5855bb0d3f5a0ef8e2279c0cef30a4d401154433298bff85a', 'CF8AA8000A8004E5', '16jY7qLJnyXhjQPKtFKUW2LqLnfxW6MPmb')
('03c871804e20ea790540bb000d81309d8b2470b29baf9700af74e5d419b5123343', '9B54D134631E5B19', '16jY7qLJnnkjdFXZcPGy2tMjUPQQApEmDc')
('03c90117a2934f133463815525c5a15700c01440c21aa5b92fa972b3a29fba46ee', 'C44B91E42375905B', '16jY7qLJn19vvyctGxbtBuJrrpRCt5er9H')
('03cb31e3b52202a54603d898ab47464dd15f2cc10ae2448c9c174159ca506504e2', 'E99F14CEAA0EE0E2', '16jY7qLJnmjsaoWLBsv3kXZF6S62unTTaP')
('03cddee9404d43b8537f4039fbb468ce69ccf1c732edf99a64777703c5e3c887ae', 'E2ACBB355EE92B67', '16jY7qLJntgdNidHSJuPTa4fH3LAMBASky')
('03d0ec25b5ec833cb8214bf6f09a922e9afd83308289a9e42c19b1d863d09754a3', 'CAD38600F1D10FCE', '16jY7qLJnwDZNc4yoiAPLbuvd8d7U9UFQA')
('03d5b48c4540c69a606a28b566d79f29a1e3122f2a3d4b627d62e4b73670fe6392', 'A38E680009272537', '16jY7qLJnghn59BuTVLjcwxPsDzvUmcgnL')
('03d629b1a2b8fb4af913ee3c233901c13cf7d33737c7d1606c0f429b2008b539db', 'C0F6D830D35D978B', '16jY7qLJnwGgTij1RDtLj1LzMY9L6wk6qQ')
('03d6388b901fb7cf6047b80a801f373541903d2664d96e50a916c03bc8b961e0fe', 'CFFF5F008D61E444', '16jY7qLJnwDDqnjh4tUGnuZ7qHQ7xE1Bu8')
('03d6c54a3a476e0faf565ff559abf6e6eb5476ecb57ca48643e26e03a545ef73b9', 'C7D0CE0081F66AA0', '16jY7qLJnBqTzD24NmJU2wFthonhZ5fwQo')
('03d71030f07efb84a13933cf7b9fa9c6d9b280751ad53915148370fa7ed658dc93', 'A421F000B7DF8061', '16jY7qLJnC1GquZnnjQLnmgfqz7YEzwiL8')
('03d7bc53ae23a51d4859dda96b87ed06cd2a29ce738f54e9f5c2fcf63087ca1761', 'EE072B6004228577', '16jY7qLJnttAUrwnWVMu6DHHiE7Z17aQEr')
('03d95ebc4c2aceebbb2785f08a0e3f5c815747db4b97579f03231ac398795a161d', 'FF696CFF78DD33C2', '16jY7qLJn6vYeDSgzKpdocFLhudWPsCLCV')
('03db196219c448ef4d0848fa29de5b16e08f5f69c8caf213d66a2add3a0679d047', 'A3AD1500AC0E306F', '16jY7qLJnstTgBAyGJEANvYUnCqS5SmyEK')
('03dc0100ddda788c36a68ebad00786638a2ccddcf45ea7f42af83df09a436bd44b', 'AF80F3004EE502E5', '16jY7qLJn2fXcGg2ntYSFShDm8tsyTorZC')
('03ddac12e9d7820b00062d76968f62568dff9a5a17fcd6c252c826fee1395abe1f', 'EBA374CCE415A459', '16jY7qLJnzdqiXpt7f484D39QQLmWufxiM')
('03de8d0611e7226fbab8f5efc202d65b2040c614232de7bddd2eeaddbad4da6552', 'E982E8021A7C3DFE', '16jY7qLJnAGNUChgoingyzkPi3GuBAGCNN')
('03dfaeac7f9269beaa6ee3c0bb9bf6d2c646fdbcc8acab52791f2e4432e25b00ad', 'EE045BA02E5672B9', '16jY7qLJnsZu4vZz2ceQcatusBAnXXRTBh')
('03e17a13f46bcda242bfcff9f1ac40630ebbc54c75e877316088ed9486f87c52e3', '92464E0001412E8E', '16jY7qLJnHGW8iFkv4eGPKBeDQkAf2wk6N')
('03e238a449441839afdd1671eb69ccaeed152eaee78ad315b093f5fb3b0a6e7e65', '8A500564D1A344A2', '16jY7qLJnikKMRWYNo4U5AMLCSZpb99jTJ')
('03e27209fe924799801f1b0fba8a019cd9bee576ff7c5de78a325803397f70c3b2', 'C212630092232A6E', '16jY7qLJn7n2krf1zG38CN41ezuS3cSPX9')
('03e2e78935a2ac1aac187e05e31c53a93e3b9b8b2fc44c4d073b974a5c3c9426d3', '94D053333B23EB36', '16jY7qLJnhhupS32EEJhwv4KLHc4eZaCsL')
('03e50b44f5a613b4fac4b9ec386834c7953289c081e97b13f012eade770f1efb56', 'E0164B341EB51BA3', '16jY7qLJniyBP4SWLBR7Ys8WJRim2KXre5')
('03e5b694f5f8feb050335714013672de830eeb93ea1de4dc248cc5096a4a23d03e', 'C6140E007C5AE796', '16jY7qLJnCqaer4xgyukzgpkHF2NJsVjMn')
('03e6e3306e85bcd08bfc6266437f8211763813879ad1ee08e2d88339d640cc4615', 'CF4F71009D684449', '16jY7qLJnFd6CHEe8GzghvvwuytZ5EnxAi')
('03e7d9e46c0c9b48f94519c355369abc7f58548887e33870a8b5717497ad047204', '83A5912DABC2C017', '16jY7qLJn1XopLkqGvNp8gRRpKpfHLgML6')
('03e8480b4cb784584444690aab69aff14ce4ac88a89b032a275e83c8e60b264560', '80001A1A0B33FFFA', '16jY7qLJng79ZYaMRTnDxziUU9Pg2x4HAF')
('03e8c11d2f37e7e8dc651f47559733511d75d302b362a2706ee742347803f5cf73', '8443474BC9D2D542', '16jY7qLJnKSFLsRqHEGLX3iYwSvU6ySxZu')
('03e9f9079a3ea9a9151a418ad32e32cf90f533676f01fbda310751cb0c24c5a5f7', 'A929C6007A2A0B52', '16jY7qLJn4JfUt1o1XXXReJY7ba6ygFeRJ')
('03eb06f1794c77b99920cd7493d4fe98f2ac1e26d566dbadb84c61c636ed10ab64', 'AF644700AE15543A', '16jY7qLJny98qX7QiXX687hRw5wqGxXeS5')
('03eb07da0adc887d23a28ee384ff6374b12f947d4e3d15adb823a607570cdf6fc0', '84EE474DFBF8DE96', '16jY7qLJnME5xgbEhkdJsSHnhokjbBbu88')
('03eb8cae4a22cfc4028876a73f0cc2344a834ba9b2105a8c01381abd77c529acd2', 'A671AD0077C97FBB', '16jY7qLJnmcCa9Kc1G7PyM7gPkDGBe2BdC')
('03ec98713705b1f7a402441d53b506be08aa6b7247f559fbd66dee2a21a5d1c148', 'D71500004B498429', '16jY7qLJnKj8W1fCUcproVfnSYgMkqEyfV')
('03ee7353538debb1f526c91e49e2e4dcbba60e93a069eb1df6f09ece7d4408c0ad', 'C2DD3300C7A64DA4', '16jY7qLJnWCmSR4EECMMhtJYsA1FtWs8Px')
('03eea22459763640f05442cfb7d9eb96d785ff6a1e8fb13842cb5426d8d9bd8f33', 'B3CD2CB402F842BD', '16jY7qLJnANLkXBhTPCe5LhJ1BStnqfRw1')
('03efc1aa9ad6328a608271e0369994aff786555fed8e32ff2cdc501baf897b542c', 'E2E2300230502DAE', '16jY7qLJnC5BmpZdqGCT9iemdoKz1bi4Fa')
('03efdb001334f5dbfb6f28f879f09cb0a36f59ecbb920909a759921105d9d51c33', 'FE2865C6DBFEC383', '16jY7qLJnX2cZXJ78wV1ef42e7cLAZJ1Vn')
('03f27b25ef64dbd8a8ceaa40f872dd79c9d01fbcf059a671c8df57c708659d8ffe', 'E74C9334679B0B5E', '16jY7qLJn4SGRHYKER5NsnA9gcJngv5nog')
('03f3c0cc6752df6121e16e994ff44749b18b43ca6382de39a9a93a0bc2e8522c99', 'D83FEF5406698788', '16jY7qLJnkwTUBkJrbHyBPzUMSrXzSiQqt')
('03f4011b0c34b36bcea652457842ab87c1c5568b1b698da2b806c5ea596cd97629', 'CA2208005484586C', '16jY7qLJnvH3EisXyTXRN3QkxkCRwyaENc')
('03f6c1bb33160f1896e331b2989503cf4f715cd526ca37d483b2641a66474210f3', 'A3689B001C2D3919', '16jY7qLJns29hFr2KbW928ugg21Cx7P6Xi')
('03f6f9396a2649088d891308fff7cf066e78f86af0e0e336ed8e77bbbfd5c22b04', 'B817117EA76EA2D2', '16jY7qLJnncxUo9uzrBVntYQHEperUMoNm')
('03f7f23749aa519e182292b3f6ab0ffbe1a64a2f62c3e75e3f5fe72fc5f8e86f65', 'E927533456EB2F68', '16jY7qLJnBsaZBMfzSd5ZscK5PsNkonGMV')
('03f90682ae07302539e32a9b5b130690cd1ddc032c7dd3f24eddbc803bc57b8855', 'D45921D9B206053C', '16jY7qLJnT2uyE4umB8yLrv4ECoV54tfMN')
('03fb23c63144cd091f85c09b4c3b72905f6ea0a021e19f28553c378947532985ab', 'A89340004F2840CB', '16jY7qLJn2sqNyUckPHAxJx7wfHELLzLe7')
('03fb287e8c1afb1bad7e1841ac151a2cf3d15070010c354fba3eb12b6259b764fe', 'B51BDD55F149F10E', '16jY7qLJnEWbiTdYWuKHW6XSpduxEMEjes')
('03fc3acee9bc1a9b2e974e33e54926e7ad51001acf0751d6f08f0bbe76ad71e0d7', 'EA609001BF75F25F', '16jY7qLJnkjtRwseFG71YEMDyFxefE6uYR')
('03fcc448d808160a18acac6910fdb0863b9d07056788d164e0cc03d4c4e035f0ab', '8BB203974D48B13C', '16jY7qLJnHPYTL5daotAZJudvupQ3Wk2kw')
('03fce08b5215b860815fe5d9bf1a146d1d20a20e141926311f510890699d56134e', 'CA6DC9004F3E9E2F', '16jY7qLJn3nvJzFhdPwJP3GmckRkix3UvT')
('03fdb31a34ade12f59ac78d45faa1d683540b5b744e8009e6b79220e42fd6dff76', 'A10F2600708A8835', '16jY7qLJn6PmBE25TN1Fbe1yT1deVNBq7k')
('03ff4d34549c0b0feb2f350dc5c6d43fc5ea63ecb29a74afa6e9b1c9704e3c4ae4', 'E9421801FD3D5661', '16jY7qLJnjXrniqYWxF1oKSYRDTbda2nAU')
('03ff52c764bd785e1ff60bf6e5145765b5f633f81c27de0aa0dc87d89619d00060', '8DD4ECD2E4EB2CDD', '16jY7qLJnXfwnsfDQsDs72vJJu5XTmPDqJ')
('03ff94c3c4030faf55a10bda211e1d4d0891e3c68089e1ace2e62ce2f2f2eeb405', '8A6153AA9FBFE29C', '16jY7qLJnsEheSTVBw7q7KBfhmF8aT96yu')
donate BTC: 1DonateZNR9BUaCqJTgXCoyyCpRSosFujR
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March 20, 2022, 06:45:10 PM
 #1796

Why generate a template: "16jY7qLJn"?
There are still a lot of such addresses, this will not help in any way to find the private key from 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN
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March 20, 2022, 07:12:30 PM
Last edit: March 20, 2022, 10:33:39 PM by Jolly Jocker
 #1797

Why generate a template: "16jY7qLJn"?
There are still a lot of such addresses, this will not help in any way to find the private key from 16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN
"16jY7qLJn........................................",  3ee4133d991............................................
"16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN", 3ee4133d991f52fdf6a25c9834e0745ac74248a4

and now I look at the pubkeys...

you understand?

These are a large part of the patterns, who was found in the range 2**63 to 2**64... ( a total of 662 were found ).. that's really meaningful ... who can tell you that the address you're looking for is really in this range!? ... we're all looking for ways to find this address... why shouldn't patterns help? you have to exhaust all possibilities... maybe someone with all the pubkeys can calculate a narrowing down of the range... if you find the pubkey for the said address, you will also find the privkey..."many ways lead to Rome"
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March 21, 2022, 01:33:47 PM
 #1798

Between the first
16jY7qLJnMcUAdSQqtQzqcBMcrSRedgSk2 (KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZ2jqSaxonym9TTx57nT)
and last
16jY7qLJnsEheSTVBw7q7KBfhmF8aT96yu (KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYwD8Wy8p94y3aGy9Dw6)
address in your list, the difference in private keys is 19 characters, if it is 11 then it can be easily brute. But 8 characters is a huge abyss...
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March 24, 2022, 03:13:34 AM
Last edit: March 24, 2022, 04:35:59 AM by BorisTheHorist
 #1799

Jolly Jocker,

From your info I have this:
[16jY7qLJnxtt8FSYMze4DRVMWQF47auU8M,8ec5edb376aeb55a]
[16jY7qLJnxht5HL2NBywuoC8jK34rz8NJv     ,9357254130f9270a]
[16jY7qLJnx4enVJC2Ao3wRv3tRusseu5Yb     ,af6f7a0015695aa4]
[16jY7qLJnxcZQ1ff7Y6ascX2FwkVfMEqcn     ,b0d6bbb249f4d96f]
[16jY7qLJnxoBx9Zhsa1tN62rfZXX1bgKNp    ,c4230300dfe089af]
[16jY7qLJnxPwmtRgVS3HBg2RtAoHe1koZF  ,d461baace35db135]
[16jY7qLJnx4f4yqNvmp7LtnaatiUuwgUwW   ,ebe2eb35503b43e4]
[16jY7qLJnx2ixrxCnTLSraerkgyB3YYAiT        ,edf9cd60356dcc19]
[16jY7qLJnxHBp3dqwV2kzYq1LucfZzgxsH    ,eeb9ab334df2770d]

my bet based on your data is that #64 is between edf9cd60356dcc19:eeb9ab334df2770d
but that is probably not true.

Edit: b is after H in the Base58 Alphabet do with that what you will
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March 24, 2022, 03:38:57 AM
 #1800

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