Petr1fied
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June 06, 2013, 05:32:02 PM |
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rpcport?
P2P Port = 9998 RCP Port = 9999
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Lhunephel (OP)
Member
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Activity: 90
Merit: 10
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June 06, 2013, 06:09:20 PM |
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I hope that somebody will set up a pool soon. I'm not familiar with pushpool and don't wanted to set up a not working or instable pool. I dropped BigVern a line, but now response until now The difficulty should lower with a rising network hash rate. A higher network hash rate results in a lower target timespan. At the moment solo mining should still be possible. Until now I found three blocks and I only have a small mining rig with two GPUs. But I'm really glad that the second start of this block chain was a lot of better than the first one
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Lhunephel (OP)
Member
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Activity: 90
Merit: 10
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June 06, 2013, 06:11:49 PM |
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Btw. you can see the current difficulty at the bottom of http://quantumcoin.org/. I'll try to set up a block explorer in the next week.
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CJM1682
Member
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Activity: 86
Merit: 10
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June 06, 2013, 06:20:37 PM |
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still no finds lol 1700kh from launch.
QQA3RdsMrAfb5DryHUFLXASpmS9RRF8KKK
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LTC: LcN9tjjcNyjgE7HnZHSC686fWuhUUCiWsn BTC: 163MGvqd2mr7iHumVYSpEM9jpS7dfEEqkv CHN: CY2tsr2JKmQa7tUgZW9SkRJyUNwHzvveT2 FTC: 6uH8iaXt23WPVcJHy8eGLtm5cst5kYQnhN
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dellstreakone
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June 06, 2013, 06:29:46 PM |
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i cant sync the wallet , just show 1000 blocks ~ and out of sync
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joee
Member
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Activity: 69
Merit: 10
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June 06, 2013, 06:35:13 PM |
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i cant sync the wallet , just show 1000 blocks ~ and out of sync
Did you download the new wallet from OP?
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sumantso
Legendary
Offline
Activity: 1050
Merit: 1000
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June 06, 2013, 06:36:07 PM |
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Waiting for a pool. In the meantime anybody donate to get me off 0? Thanks
QNMb5ABxqthA3omfANZc5GfbY5D9Jc8Ymm
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Sondey10mg
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June 06, 2013, 06:37:26 PM |
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Didn't get lucky yet, but this seems a very smooth release!
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Sondey10mg
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June 06, 2013, 06:43:21 PM |
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How many coins are already mined? I'm at 91 blocks, but I want to be sure I'm on the right chain..
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dellstreakone
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June 06, 2013, 06:45:20 PM |
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i think about 10 QTC
 { "blocks" : 94, "currentblocksize" : 1000, "currentblocktx" : 0, "difficulty" : 0.75771766, "errors" : "", "generate" : false, "genproclimit" : -1, "hashespersec" : 0, "networkhashps" : 6795002, "pooledtx" : 0, "testnet" : false }
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Sondey10mg
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June 06, 2013, 06:47:29 PM |
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i think about 10 QTC
 { "blocks" : 94, "currentblocksize" : 1000, "currentblocktx" : 0, "difficulty" : 0.75771766, "errors" : "", "generate" : false, "genproclimit" : -1, "hashespersec" : 0, "networkhashps" : 6795002, "pooledtx" : 0, "testnet" : false }
Thank you!
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cryptohunter
Legendary
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Activity: 2100
Merit: 1167
MY RED TRUST LEFT BY SCUMBAGS - READ MY SIG
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June 06, 2013, 06:49:25 PM |
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this seems quite an interesting coin.
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gudmunsn
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June 06, 2013, 06:56:55 PM |
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been solo mining 5mhash for about 20 mins and found only 1 block.
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tyrion70
Legendary
Offline
Activity: 934
Merit: 1000
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June 06, 2013, 06:57:59 PM |
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Hi all, I created a p2pool and blockexplorer. Due to the exotic retargeting some stats might be off, but for p2pool mining this should not be an issue as payouts are calculated on real blockvalue. Address of the pool http://qtc.p2pool.nl:9500The stats are at http://qtc.p2pool.nl/stats/The blockexplorer can be found at http://qtc.p2pool.nlLet me know if u encounter any issues. Haven't found a block yet because diff is pretty high for my miners.. Cheers! EDIT: It's a P2Pool so use your wallet address as username. On the stats page you can find a description on how to mine.
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Lhunephel (OP)
Member
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Activity: 90
Merit: 10
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June 06, 2013, 07:08:43 PM |
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@tyrion70: Cool Thanks for providing an explorer and p2pool. That's great. The value of one block increases with the difficulty. This is a list of the block values until difficulty 20. The formula is rather simple: nSubsidy = ((0.2 * exp(nDifficulty / 250) / pow(nDifficulty, -0.25)) * 50), but working. The minimum block value is 10, the maximum block value is 50 (will be reached with appr. difficulty 110). 0.000000 = 0.000000 1.000000 = 10.040080 2.000000 = 11.987589 3.000000 = 13.319620 4.000000 = 14.370230 5.000000 = 15.255568 6.000000 = 16.031010 7.000000 = 16.727643 8.000000 = 17.364805 9.000000 = 17.955406 10.000000 = 18.508524 11.000000 = 19.030804 12.000000 = 19.527266 13.000000 = 20.001803 14.000000 = 20.457497 15.000000 = 20.896834 16.000000 = 21.321848 17.000000 = 21.734230 18.000000 = 22.135398 19.000000 = 22.526555 20.000000 = 22.908732
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Lhunephel (OP)
Member
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Activity: 90
Merit: 10
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June 06, 2013, 07:09:54 PM |
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@Sondey10mg: We're at block 99 at the moment. The first 50 blocks got a block value of 0. The last 49 blocks got a block value of 10. So there should be 490 QTCs available.
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tyrion70
Legendary
Offline
Activity: 934
Merit: 1000
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June 06, 2013, 07:15:45 PM |
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@tyrion70: Cool Thanks for providing an explorer and p2pool. That's great. The value of one block increases with the difficulty. This is a list of the block values until difficulty 20. The formula is rather simple: nSubsidy = ((0.2 * exp(nDifficulty / 250) / pow(nDifficulty, -0.25)) * 50), but working. The minimum block value is 10, the maximum block value is 50 (will be reached with appr. difficulty 110). Yeah I found the code in the code ;-) Thing is, p2pool is written in python so you can't just copy it. It's also in a oneliner. For example: lambda height: 1*500000000 >> (height + 1)//840000 So far I never took the time to figure out how to calculate more exotic nSubidies.. I'll have a look into it though.. If you have any ideas let me know.. Cheers
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Sondey10mg
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June 06, 2013, 07:16:24 PM |
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I'm on the right blockchain Even found a block with my 300kh/s. Now mining on the pool though. Great job!
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tyrion70
Legendary
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Activity: 934
Merit: 1000
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June 06, 2013, 07:27:45 PM |
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Found the way it's done with bitbar: def get_subsidy(nCap, nMaxSubsidy, bnTarget): bnLowerBound = 0.01 bnUpperBound = bnSubsidyLimit = nMaxSubsidy bnTargetLimit = 0x00000fffff000000000000000000000000000000000000000000000000000000
while bnLowerBound + 0.01 <= bnUpperBound: bnMidValue = (bnLowerBound + bnUpperBound) / 2 if pow(bnMidValue, nCap) * bnTargetLimit > pow(bnSubsidyLimit, nCap) * bnTarget: bnUpperBound = bnMidValue else: bnLowerBound = bnMidValue
nSubsidy = round(bnUpperBound, 6)
if nSubsidy > bnUpperBound: nSubsidy = nSubsidy - 0.000001
return int(nSubsidy * 1000000)
At least python knows the exp function ;-) Now to change it to Quantumcoin... I think it should be something like this: def get_subsidy(bnTarget):
return int(((0.2 * exp(bnTarget/ 250) / pow(bnTarget, -0.25)) * 50) * 1000000)
Or straight in the dict: SUBSIDY_FUNC=lambda target: int(((0.2 * exp(bnTarget/ 250) / pow(bnTarget, -0.25)) * 50) * 1000000),
I'll experiment a bit Cheers
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gudmunsn
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June 06, 2013, 07:35:48 PM |
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This coin actually seems to work...I have found 5 blocks, 3 rejects, and ZERO orphans when I started mining......that's a first.
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