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Author Topic: [ANN] Restart of Quantumcoin (SUCCESSFULLY RELEASED)  (Read 11469 times)
Petr1fied
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June 06, 2013, 05:32:02 PM
 #41

rpcport?

P2P Port = 9998
RCP Port = 9999
Lhunephel (OP)
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June 06, 2013, 06:09:20 PM
 #42

I hope that somebody will set up a pool soon. I'm not familiar with pushpool and don't wanted to set up a not working or instable pool. I dropped BigVern a line, but now response until now Sad The difficulty should lower with a rising network hash rate. A higher network hash rate results in a lower target timespan. At the moment solo mining should still be possible. Until now I found three blocks and I only have a small mining rig with two GPUs.

But I'm really glad that the second start of this block chain was a lot of better than the first one Smiley
Lhunephel (OP)
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June 06, 2013, 06:11:49 PM
 #43

Btw. you can see the current difficulty at the bottom of http://quantumcoin.org/. I'll try to set up a block explorer in the next week.
CJM1682
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June 06, 2013, 06:20:37 PM
 #44

still no finds lol 1700kh from launch.

QQA3RdsMrAfb5DryHUFLXASpmS9RRF8KKK

LTC: LcN9tjjcNyjgE7HnZHSC686fWuhUUCiWsn      BTC: 163MGvqd2mr7iHumVYSpEM9jpS7dfEEqkv
CHN: CY2tsr2JKmQa7tUgZW9SkRJyUNwHzvveT2   FTC: 6uH8iaXt23WPVcJHy8eGLtm5cst5kYQnhN
dellstreakone
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June 06, 2013, 06:29:46 PM
 #45

i cant sync the wallet , just show 1000  blocks ~  and out of sync
joee
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June 06, 2013, 06:35:13 PM
 #46

i cant sync the wallet , just show 1000  blocks ~  and out of sync

Did you download the new wallet from OP?
sumantso
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June 06, 2013, 06:36:07 PM
 #47

Waiting for a pool. In the meantime anybody donate to get me off 0? Thanks

QNMb5ABxqthA3omfANZc5GfbY5D9Jc8Ymm

Sondey10mg
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June 06, 2013, 06:37:26 PM
 #48

Didn't get lucky yet, but this seems a very smooth release!

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Sondey10mg
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June 06, 2013, 06:43:21 PM
 #49

How many coins are already mined? I'm at 91 blocks, but I want to be sure I'm on the right chain..

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dellstreakone
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June 06, 2013, 06:45:20 PM
 #50

i think about 10 QTC



{
"blocks" : 94,
"currentblocksize" : 1000,
"currentblocktx" : 0,
"difficulty" : 0.75771766,
"errors" : "",
"generate" : false,
"genproclimit" : -1,
"hashespersec" : 0,
"networkhashps" : 6795002,
"pooledtx" : 0,
"testnet" : false
}
Sondey10mg
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June 06, 2013, 06:47:29 PM
 #51

i think about 10 QTC



{
"blocks" : 94,
"currentblocksize" : 1000,
"currentblocktx" : 0,
"difficulty" : 0.75771766,
"errors" : "",
"generate" : false,
"genproclimit" : -1,
"hashespersec" : 0,
"networkhashps" : 6795002,
"pooledtx" : 0,
"testnet" : false
}


Thank you!

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cryptohunter
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June 06, 2013, 06:49:25 PM
 #52

this seems quite an interesting coin.

gudmunsn
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June 06, 2013, 06:56:55 PM
 #53

been solo mining 5mhash for about 20 mins and found only 1 block.

tyrion70
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June 06, 2013, 06:57:59 PM
 #54

Hi all,

I created a p2pool and blockexplorer.

Due to the exotic retargeting some stats might be off, but for p2pool mining this should not be an issue as payouts are calculated on real blockvalue.

Address of the pool
http://qtc.p2pool.nl:9500

The stats are at
http://qtc.p2pool.nl/stats/

The blockexplorer can be found at
http://qtc.p2pool.nl

Let me know if u encounter any issues. Haven't found a block yet because diff is pretty high for my miners..

Cheers!

EDIT: It's a P2Pool so use your wallet address as username. On the stats page you can find a description on how to mine.

Lhunephel (OP)
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June 06, 2013, 07:08:43 PM
 #55

@tyrion70: Cool Smiley Thanks for providing an explorer and p2pool. That's great.

The value of one block increases with the difficulty. This is a list of the block values until difficulty 20. The formula is rather simple: nSubsidy = ((0.2 * exp(nDifficulty / 250) / pow(nDifficulty, -0.25)) * 50), but working. The minimum block value is 10, the maximum block value is 50 (will be reached with appr. difficulty 110).

Code:
0.000000 = 0.000000
1.000000 = 10.040080
2.000000 = 11.987589
3.000000 = 13.319620
4.000000 = 14.370230
5.000000 = 15.255568
6.000000 = 16.031010
7.000000 = 16.727643
8.000000 = 17.364805
9.000000 = 17.955406
10.000000 = 18.508524
11.000000 = 19.030804
12.000000 = 19.527266
13.000000 = 20.001803
14.000000 = 20.457497
15.000000 = 20.896834
16.000000 = 21.321848
17.000000 = 21.734230
18.000000 = 22.135398
19.000000 = 22.526555
20.000000 = 22.908732
Lhunephel (OP)
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June 06, 2013, 07:09:54 PM
 #56

@Sondey10mg: We're at block 99 at the moment. The first 50 blocks got a block value of 0. The last 49 blocks got a block value of 10. So there should be 490 QTCs available.
tyrion70
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June 06, 2013, 07:15:45 PM
 #57

@tyrion70: Cool Smiley Thanks for providing an explorer and p2pool. That's great.

The value of one block increases with the difficulty. This is a list of the block values until difficulty 20. The formula is rather simple: nSubsidy = ((0.2 * exp(nDifficulty / 250) / pow(nDifficulty, -0.25)) * 50), but working. The minimum block value is 10, the maximum block value is 50 (will be reached with appr. difficulty 110).

Yeah I found the code in the code ;-) Thing is, p2pool is written in python so you can't just copy it. It's also in a oneliner. For example:

Code:
lambda height: 1*500000000 >> (height + 1)//840000

So far I never took the time to figure out how to calculate more exotic nSubidies.. I'll have a look into it though.. Smiley If you have any ideas let me know..

Cheers

Sondey10mg
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June 06, 2013, 07:16:24 PM
 #58

I'm on the right blockchain  Smiley Even found a block with my 300kh/s. Now mining on the pool though. Great job!

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tyrion70
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June 06, 2013, 07:27:45 PM
 #59

Found the way it's done with bitbar:

Code:
def get_subsidy(nCap, nMaxSubsidy, bnTarget):
    bnLowerBound = 0.01
    bnUpperBound = bnSubsidyLimit = nMaxSubsidy
    bnTargetLimit = 0x00000fffff000000000000000000000000000000000000000000000000000000


    while bnLowerBound + 0.01 <= bnUpperBound:
        bnMidValue = (bnLowerBound + bnUpperBound) / 2
        if pow(bnMidValue, nCap) * bnTargetLimit > pow(bnSubsidyLimit, nCap) * bnTarget:
            bnUpperBound = bnMidValue
        else:
            bnLowerBound = bnMidValue


    nSubsidy = round(bnUpperBound, 6)


    if nSubsidy > bnUpperBound:
        nSubsidy = nSubsidy - 0.000001


    return int(nSubsidy * 1000000)

At least python knows the exp function ;-) Now to change it to Quantumcoin... I think it should be something like this:

Code:
def get_subsidy(bnTarget):

    return int(((0.2 * exp(bnTarget/ 250) / pow(bnTarget, -0.25)) * 50) * 1000000)

Or straight in the dict:

Code:
        SUBSIDY_FUNC=lambda target: int(((0.2 * exp(bnTarget/ 250) / pow(bnTarget, -0.25)) * 50) * 1000000),

I'll experiment a bit Smiley

Cheers

gudmunsn
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June 06, 2013, 07:35:48 PM
 #60

This coin actually seems to work...I have found 5 blocks, 3 rejects, and ZERO orphans when I started mining......that's a first.

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