DarkStar_
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May 18, 2016, 12:41:25 AM 

Hello, is this site vanity pool still paying if someone finds the solution?
There is a good chance it is still paying, because if you check the available work page ( https://vanitypool.appspot.com/availableWork) you will see there are a bunch of requests, and if the owner of the pool wasn't paying up, chances are a scam report would be seen already and he would be tagged. I highly doubt the owner would scam though, as he seems like he wants to help people with stuff.








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Timelord2067
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May 18, 2016, 01:37:41 PM 

Hello, is this site vanity pool still paying if someone finds the solution?
There is a good chance it is still paying, because if you check the available work page ( https://vanitypool.appspot.com/availableWork) you will see there are a bunch of requests, and if the owner of the pool wasn't paying up, chances are a scam report would be seen already and he would be tagged. I highly doubt the owner would scam though, as he seems like he wants to help people with stuff. I've noticed over time some of the tougher to solve requests have quietly disappeared  usually the ones with low payment to complexity ratios, so I'd say he's still around. *edit* Last time I asked they were only accepting matching case for solutions.




CjMapope
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May 20, 2016, 06:17:41 AM 

Hey guys, im trying to put up some new work on the site, but having trouble with public key? keeps telling me "public key too short" ;\ not quite sure what it's looking for as i am admittedly pretty noob with ECDSA keypairs ;\ i am using puttygen. Any help appreciated, thx!




Angell


May 21, 2016, 04:32:19 PM 

Hey guys, im trying to put up some new work on the site, but having trouble with public key? keeps telling me "public key too short" ;\ not quite sure what it's looking for as i am admittedly pretty noob with ECDSA keypairs ;\ i am using puttygen. Any help appreciated, thx! Paste it here so we can see what did you copy, probably the wrong thing.




CjMapope
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May 21, 2016, 04:59:34 PM 

Hey guys, im trying to put up some new work on the site, but having trouble with public key? keeps telling me "public key too short" ;\ not quite sure what it's looking for as i am admittedly pretty noob with ECDSA keypairs ;\ i am using puttygen. Any help appreciated, thx! Paste it here so we can see what did you copy, probably the wrong thing. this is the public key i generated sshrsa AAAAB3NzaC1yc2EAAAABJQAAAQEApJ5sklDMvPSn7QOqukjjaDDkUjwUMmRcJexOiYWp3i4LTd9YGvZ PHXdcOS9GdywY3o5mVTrJaghyVevVSZtKxjrB9yXD4Vdowew9bQs1HIzcnAEnXoQ5a8y52PEpF6KL1i YO8FhEAPJZ6Yo6fM7rDtYMtf//10UJ8v6QA9IDtvJtW4bl84C0ai6NRooRpUjihHtVIual4YM98vJgjHwguK1Bl45E/iS8BVpG7Y0BSDiKnyHKp2uo8oSiUApdeeNLCXG749g80/TqAfgNXzIkw3Bn1BZXWP+7QdyB2QowTZbN08zf73SvnVi0U0MpLQIK+8D38HvnGC8kSMyqaK7Y2w== rsakey20160521




Angell


May 21, 2016, 05:12:12 PM 

Hey guys, im trying to put up some new work on the site, but having trouble with public key? keeps telling me "public key too short" ;\ not quite sure what it's looking for as i am admittedly pretty noob with ECDSA keypairs ;\ i am using puttygen. Any help appreciated, thx! Paste it here so we can see what did you copy, probably the wrong thing. this is the public key i generated... You did something wrong, use this site to generate a public key, just move the mouse around to get 100% and then click "Vanity wallet", you'll get a public key, and a first private key, then when somebody solves you problem you'll get from them the second part private key and that is it. https://www.bitaddress.org




CjMapope
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May 21, 2016, 05:38:35 PM 

Hey guys, im trying to put up some new work on the site, but having trouble with public key? keeps telling me "public key too short" ;\ not quite sure what it's looking for as i am admittedly pretty noob with ECDSA keypairs ;\ i am using puttygen. Any help appreciated, thx! Paste it here so we can see what did you copy, probably the wrong thing. this is the public key i generated... You did something wrong, use this site to generate a public key, just move the mouse around to get 100% and then click "Vanity wallet", you'll get a public key, and a first private key, then when somebody solves you problem you'll get from them the second part private key and that is it. https://www.bitaddress.orgawesome. well i see you yourself provide a service so have PM'd you with some work ty!




Angell


May 21, 2016, 10:47:59 PM 

Hey guys, im trying to put up some new work on the site, but having trouble with public key? keeps telling me "public key too short" ;\ not quite sure what it's looking for as i am admittedly pretty noob with ECDSA keypairs ;\ i am using puttygen. Any help appreciated, thx! Paste it here so we can see what did you copy, probably the wrong thing. this is the public key i generated... You did something wrong, use this site to generate a public key, just move the mouse around to get 100% and then click "Vanity wallet", you'll get a public key, and a first private key, then when somebody solves you problem you'll get from them the second part private key and that is it. https://www.bitaddress.orgawesome. well i see you yourself provide a service so have PM'd you with some work ty! I've sent you a PM, I have to check it first.




Timelord2067
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Merit: 184½ (56/28) 36


May 26, 2016, 06:32:13 PM 

Unfortunately OgNasty's Life Boat patch of VanityGen didn't extend to the VanityMiner and after about two weeks of ~42MKeys/sec "mining" I get this: Searching for pattern: "1EXAmoney" Reward: 0.008000 Value: 0.000001 BTC/MkeyHr Difficulty: 50656515217834 [42.28 Mkey/s][total 41252892442624][Prob 55.7%][75% in 7.9d] M atch idx: 1 CPU hash: 900954e1a558005d304c31b07bfa34eab9205fda GPU hash: 944e4590b1334a04131c2a5c3e2ebc1170ebf90c Found delta: 4487231 Start delta: 50331649 [43.30 Mkey/s][total 41475182166016][Prob 55.9%][75% in 7.7d] Oh well...




PieCrafted
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August 27, 2016, 01:46:16 PM 

VanityPool still lists 1Private but refuses to accept solutions (one of my rig found the solution and all of the ones I pointed at VanityPool tried to submit new ones several times).




forumaster


August 28, 2016, 02:51:01 PM 

How to choose what pattern to generate? I don't have a very good GPU and with the autochosen pattern it says 50% in 25 years xD I want to generate the one with the lowest difficult




bitcoiner23
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September 10, 2016, 02:36:17 PM 

If you give a damn a GTX 1080 hashes with 69 Mkey/s. Still not profitable.




Timelord2067
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September 10, 2016, 09:55:11 PM 

If you give a damn a GTX 1080 hashes with 69 Mkey/s. Still not profitable.
Nice. Was thinking of upgrading at least one of my cards  that'd give me a cool 100 MKeys/sec ... HHmmm...




okbaby123
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October 21, 2016, 11:02:23 AM 

An example (available from gobittest website): We have a private key: 18E14A7B6A307F426A94F8114701E7C8E774E7F9A47E2C2035DB29A206321725 which maps to public key: 0450863AD64A87AE8A2FE83C1AF1A8403CB53F53E486D8511DAD8A04887E5B23522CD470243453A 299FA9E77237716103ABC11A1DF38855ED6F2EE187E9C582BA6
and say we want to find a pattern "166". One of the solutions takes a form of a private key B18427B169E86DE681A1A62588E1D02AE4A7E83C1B413849989A76282A7B562F mapping to public key: 049C95E0949E397FACCECF0FE8EAD247E6FD082717E4A4A876049FB34A9ADED110DFEA2EF691CC4 A1410498F4C312F3A94318CD5B6F0E8E92051064876751C8404
If we add the two public keys (like the person looking for the solution would do), we get a public key: 0436970CE32E14DC06AC50217CDCF53E628B32810707080D6848D9C8D4BE9FE461E100E705CCA98 54436A1283210CCEFBB6B16CB9A86B009488922A8F302A27487 which is equivalent to this address: 166ev9JXn2rFqiPSQAwM7qJYpNL1JrNf3h
If we add the two private keys (like the person requesting the address would), we get: CA65722CD418ED28EC369E36CFE3B7F3CC1CD035BFBF6469CE759FCA30AD6D54 which maps to the same public key as the sum of the public keys, and thus  to the same address.
If we add the two public keys (like the person looking for the solution would do), we get a public key: 0436970CE32E14DC06AC50217CDCF53E628B32810707080D6848D9C8D4BE9FE461E100E705CCA98 54436A1283210CCEFBB6B16CB9A86B009488922A8F302A27487 which is equivalent to this address: 166ev9JXn2rFqiPSQAwM7qJYpNL1JrNf3h how?0450863AD64A87AE8A2FE83C1AF1A8403CB53F53E486D8511DAD8A04887E5B23522CD470243453A 299FA9E77237716103ABC11A1DF38855ED6F2EE187E9C582BA 6+ 049C95E0949E397FACCECF0FE8EAD247E6FD082717E4A4A876049FB34A9ADED110DFEA2EF691CC4 A1410498F4C312F3A94318CD5B6F0E8E92051064876751C840 4= 0436970CE32E14DC06AC50217CDCF53E628B32810707080D6848D9C8D4BE9FE461E100E705CCA98 54436A1283210CCEFBB6B16CB9A86B009488922A8F302A2748 7how to calculate it ? the last number 6+4=7? not 6+4=a?




okbaby123
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October 22, 2016, 01:49:16 AM 

An example (available from gobittest website): We have a private key: 18E14A7B6A307F426A94F8114701E7C8E774E7F9A47E2C2035DB29A206321725 which maps to public key: 0450863AD64A87AE8A2FE83C1AF1A8403CB53F53E486D8511DAD8A04887E5B23522CD470243453A 299FA9E77237716103ABC11A1DF38855ED6F2EE187E9C582BA6
and say we want to find a pattern "166". One of the solutions takes a form of a private key B18427B169E86DE681A1A62588E1D02AE4A7E83C1B413849989A76282A7B562F mapping to public key: 049C95E0949E397FACCECF0FE8EAD247E6FD082717E4A4A876049FB34A9ADED110DFEA2EF691CC4 A1410498F4C312F3A94318CD5B6F0E8E92051064876751C8404
If we add the two public keys (like the person looking for the solution would do), we get a public key: 0436970CE32E14DC06AC50217CDCF53E628B32810707080D6848D9C8D4BE9FE461E100E705CCA98 54436A1283210CCEFBB6B16CB9A86B009488922A8F302A27487 which is equivalent to this address: 166ev9JXn2rFqiPSQAwM7qJYpNL1JrNf3h
If we add the two private keys (like the person requesting the address would), we get: CA65722CD418ED28EC369E36CFE3B7F3CC1CD035BFBF6469CE759FCA30AD6D54 which maps to the same public key as the sum of the public keys, and thus  to the same address.
If we add the two public keys (like the person looking for the solution would do), we get a public key: 0436970CE32E14DC06AC50217CDCF53E628B32810707080D6848D9C8D4BE9FE461E100E705CCA98 54436A1283210CCEFBB6B16CB9A86B009488922A8F302A27487 which is equivalent to this address: 166ev9JXn2rFqiPSQAwM7qJYpNL1JrNf3h how?0450863AD64A87AE8A2FE83C1AF1A8403CB53F53E486D8511DAD8A04887E5B23522CD470243453A 299FA9E77237716103ABC11A1DF38855ED6F2EE187E9C582BA 6+ 049C95E0949E397FACCECF0FE8EAD247E6FD082717E4A4A876049FB34A9ADED110DFEA2EF691CC4 A1410498F4C312F3A94318CD5B6F0E8E92051064876751C840 4= 0436970CE32E14DC06AC50217CDCF53E628B32810707080D6848D9C8D4BE9FE461E100E705CCA98 54436A1283210CCEFBB6B16CB9A86B009488922A8F302A2748 7how to calculate it ? the last number 6+4=7? not 6+4=a?No one helping?




Timelord2067
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October 22, 2016, 09:57:08 AM 

how to calculate it ? the last number 6+4=7? not 6+4=a?
No one helping? Might have something to do with the fact we have lives and don't monitor ever thread all day. Did you try multiplying the two values together?




oinkoink
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November 18, 2016, 09:02:37 PM 

An example (available from gobittest website): We have a private key: 18E14A7B6A307F426A94F8114701E7C8E774E7F9A47E2C2035DB29A206321725 which maps to public key: 0450863AD64A87AE8A2FE83C1AF1A8403CB53F53E486D8511DAD8A04887E5B23522CD470243453A 299FA9E77237716103ABC11A1DF38855ED6F2EE187E9C582BA6
and say we want to find a pattern "166". One of the solutions takes a form of a private key B18427B169E86DE681A1A62588E1D02AE4A7E83C1B413849989A76282A7B562F mapping to public key: 049C95E0949E397FACCECF0FE8EAD247E6FD082717E4A4A876049FB34A9ADED110DFEA2EF691CC4 A1410498F4C312F3A94318CD5B6F0E8E92051064876751C8404
If we add the two public keys (like the person looking for the solution would do), we get a public key: 0436970CE32E14DC06AC50217CDCF53E628B32810707080D6848D9C8D4BE9FE461E100E705CCA98 54436A1283210CCEFBB6B16CB9A86B009488922A8F302A27487 which is equivalent to this address: 166ev9JXn2rFqiPSQAwM7qJYpNL1JrNf3h
If we add the two private keys (like the person requesting the address would), we get: CA65722CD418ED28EC369E36CFE3B7F3CC1CD035BFBF6469CE759FCA30AD6D54 which maps to the same public key as the sum of the public keys, and thus  to the same address.
If we add the two public keys (like the person looking for the solution would do), we get a public key: 0436970CE32E14DC06AC50217CDCF53E628B32810707080D6848D9C8D4BE9FE461E100E705CCA98 54436A1283210CCEFBB6B16CB9A86B009488922A8F302A27487 which is equivalent to this address: 166ev9JXn2rFqiPSQAwM7qJYpNL1JrNf3h how?No one helping? interested too

piggybank: 1oinkBob5MDsZukoY8Vmy8TxDH7VovPx



alfaboy23


November 20, 2016, 03:31:52 AM 

Good day!
I've seen this wallet address from the list of my referrals in a faucet, look at the last 3 character: 3GZLKxx7SgYkUXarSRNULxjxRQf4P3DAY3
I thought the addresses only starting in 1 can be generated for vanity address, isn't that a multisig address? If that is possible, how?




oinkoink
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November 20, 2016, 09:01:06 AM 

Good day!
I've seen this wallet address from the list of my referrals in a faucet, look at the last 3 character: 3GZLKxx7SgYkUXarSRNULxjxRQf4P3DAY3
I thought the addresses only starting in 1 can be generated for vanity address, isn't that a multisig address? If that is possible, how? afaik before you base58encode it, instead of 0x00 at the beginning, you start with a 0x05 (prefix/version number) this results in a leading 3 address e.g. 05.payload.checksum > base58encode > 3..... 00.payload.checksum > base58encode > 1.....

piggybank: 1oinkBob5MDsZukoY8Vmy8TxDH7VovPx



alfaboy23


December 02, 2016, 03:40:28 AM 

Good day!
I've seen this wallet address from the list of my referrals in a faucet, look at the last 3 character: 3GZLKxx7SgYkUXarSRNULxjxRQf4P3DAY3
I thought the addresses only starting in 1 can be generated for vanity address, isn't that a multisig address? If that is possible, how? afaik before you base58encode it, instead of 0x00 at the beginning, you start with a 0x05 (prefix/version number) this results in a leading 3 address e.g. 05.payload.checksum > base58encode > 3..... 00.payload.checksum > base58encode > 1..... Thanks for the explanation. But I'm still having trouble understanding codes regarding addresses. Can I just do that using the vanity miner?




