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Author Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it  (Read 193691 times)
JonJonBon
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Today at 12:22:56 PM
 #5301

Hello everyone, can you tell me if there has been a message here for a long time? where it says "if it would be possible to divide a point on the curve by 2, then find the private key, etc.." I've seen this message here before and it was answered by someone. I can't seem to find this page.
Division by 2 just means to multiply by 1/2 mod N.
1/2 just means 2's inverse so that 2*x = 1 mod N.
Inverse of x mod N just means xN-2 mod N (Fermat Little Theorem).

Let's take F = { y(x) = 2x mod 11, 0 < x < 11 }

and some known y = 5: 2x = 5 mod 11

"Divide" public key by 2: 2x/2 = 5/2 mod 11

2x-1 = 2-1 * 5 mod 11
2-1 = 211-2 mod 11 = 6

So: 2x-1 = 5*6 mod 11 = 8

Great, now you have to find x - 1. Repeat? Sounds like nothing really changed.

Let's take F = { (x, y) = [k]G, 0 < k < N }

and some known (x, y) = Q: [k]G = Q

"Divide" public key by 2: [k/2]G = [1/2]Q

[k/2]G = [2-1]Q
2-1 = 2N-2 mod N

So: [k/2 mod N]G = [2N-2 mod N]Q

Great, now you have to find k / 2. Repeat? Sounds like nothing really changed.

If you fall into the trap that k is somehow half the size now, remember this:
1. Division of a field element means multiplying the element with the divisor's field inverse.
    k is not an integer in an infinite field, but a finite field. You can't just half it's value, that only makes sense in an
    infinite field, and only if such an inverse really exists.
2. Groups do not have multiplication operation, only addition. There's no such thing as multiplying or division of elliptic points, they form a group, not a field. "Point multiplication by k" just means adding the point to itself k times. "Division by k" means adding the same point to itself kN-2 mod N times. You need to respect the definitions of what something can be called a "group" or "field", "finite" vs "infinite", not invent or borrow properties from different structures. It can't work.


Yes, I read about it here on the forum! thanks for the answer! But there was a message on this branch with a division by 2. and there was an answer to it, but I don't remember which one and on which page these messages are also I don't remember. But the question is, if it were possible to divide public keys by 2? would it make it easier to find the private key? what I remember seems to be the answer to that message was "if we could divide the public key by 2, then finding the private key would be easy, and it seems to have given the formula", if I was wrong, please correct me!
GR Sasa
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Today at 02:28:34 PM
 #5302


Yes, I read about it here on the forum! thanks for the answer! But there was a message on this branch with a division by 2. and there was an answer to it, but I don't remember which one and on which page these messages are also I don't remember. But the question is, if it were possible to divide public keys by 2? would it make it easier to find the private key? what I remember seems to be the answer to that message was "if we could divide the public key by 2, then finding the private key would be easy, and it seems to have given the formula", if I was wrong, please correct me!

I suspect and breath a bad digaran breath here...

He told you and explained indirectly that it doesn't help find the original private key. You'll just be in a infinite loop with unknown keys that cannot be found. So you'll endup having trying to find some random private keys the same way as finding the orginal key if you decide to divide or even multiple.


Yes you can divide any key by 2, 3 or even 9999999999999999999999 but it doesn't make any sense, because the key won't really be divideded according to our needs because of floats

EDIT: I might have understood your point. YES you could divide the key by 2 since you have 50 % 50 % that its even or odd and if you're lucky enough if the original private key ends with 2, 4, 8 or 10 (even numbers) yes you could divide and cut a little bit of its length and size but then what? What's next? The new key is still big as hell to be found and searched. And if you try to keep dividing the divided keys by 2 you will definitely f*ck up with a key and divide a key that ends with a odd number ( 1 , 3 , 5 , 7 , 9 ) and then good morning u will end with a random key on the curve that is totally unknown.

It doesn't help.
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