Bitcoin puzzle transaction ~32 BTC prize to who solves it

[GR Sasa]

What is going on..... Today i saw 4 beggars including me here on the forum. wtf

[s.john]

this is not the right place to ask for money, this thread is meant for storming and sharing ideas about solving the challenge.

[WanderingPhilospher]

The easy math to calculate expected group ops using kangaroo is to take your bit range, divide by 2, add 1.05. (bit range / 2) + 1.05 so for #125 = 125/2 + 1.05 = 63.55.

So you are saying solving 125 is almost the same as solving 64? While 125 is 32 times bigger than 120, are you saying if we use kangaroo we could reduce the range to equivalent of brute forcing 63.55? Your math is confusing, unless kangaroo operations is different than brute force ops.

Again, #125 is not 32 times larger, searching, using kangaroo, than #120...

YES, Kangaroo is way different that brute force. That is why 120, 115, 110, etc was solved before 66, 67, 68, etc.

But to keep it simple, yes, kangaroo would reduce the #125 search to an equivalence of brute forcing 2^63.55 keys...

[ProjectSe7en]

Alberto igual podrías escribirme de favor! hay funciones y experiencia que tú tienes que nos pueden beneficiar.

 

Hi, there is no need to write in Spanish i can read English without need to translate it, so if you want to speak in Spanish you can do it in PM or telegram.

Regards

I can’t send DM to you, cause my rank.

[WanderingPhilospher]

Anyways, @WanderingPhilosopher is there any news about the new program? Did you get it to move up in bit size?

Negative...I have not solved the stride function on GPU yet. I am going a different direction until that is solved.

In the meantime, everyone needs to think/guess/fortune cookie/etc, what they think the second character is for #125, b/c it starts with a 1, we know that much. So what are the first 2 characters, 1F, 1E, 1D, 17, 15, etc?
I have a plan to attack this and let people help in the range (1F, 1E, etc.) they feel is the contains the private key...more to follow.

[Evillo]

Anyways, @WanderingPhilosopher is there any news about the new program? Did you get it to move up in bit size?

Negative...I have not solved the stride function on GPU yet. I am going a different direction until that is solved.

In the meantime, everyone needs to think/guess/fortune cookie/etc, what they think the second character is for #125, b/c it starts with a 1, we know that much. So what are the first 2 characters, 1F, 1E, 1D, 17, 15, etc?
I have a plan to attack this and let people help in the range (1F, 1E, etc.) they feel is the contains the private key...more to follow.

Why? How many bits would be the key space if we got the first  two characters right?

No wait don't answer that lemme try..
61.55 bits

[WanderingPhilospher]

Anyways, @WanderingPhilosopher is there any news about the new program? Did you get it to move up in bit size?

Negative...I have not solved the stride function on GPU yet. I am going a different direction until that is solved.

In the meantime, everyone needs to think/guess/fortune cookie/etc, what they think the second character is for #125, b/c it starts with a 1, we know that much. So what are the first 2 characters, 1F, 1E, 1D, 17, 15, etc?
I have a plan to attack this and let people help in the range (1F, 1E, etc.) they feel is the contains the private key...more to follow.

Why? How many bits would be the key space if we got the first  two characters right?

No wait don't answer that lemme try..
61.55 bits

Close...2^61.05

I've gotta do some prep work/leg work to get this right...

[Evillo]

Anyways, @WanderingPhilosopher is there any news about the new program? Did you get it to move up in bit size?

Negative...I have not solved the stride function on GPU yet. I am going a different direction until that is solved.

In the meantime, everyone needs to think/guess/fortune cookie/etc, what they think the second character is for #125, b/c it starts with a 1, we know that much. So what are the first 2 characters, 1F, 1E, 1D, 17, 15, etc?
I have a plan to attack this and let people help in the range (1F, 1E, etc.) they feel is the contains the private key...more to follow.

Why? How many bits would be the key space if we got the first  two characters right?

No wait don't answer that lemme try..
61.55 bits

Close...2^61.05

I've gotta do some prep work/leg work to get this right...

We could start in that range from the middle, then near the end, and eventually near the beginning.

Like 18'ish then 1F'ish then 11'ish

Then turns out to be 13 and screws us up. Tough task.

[GR Sasa]

And how can you calculate or guess which letter comes next? There is no way. Hash is only one way and only one piece. I can't say that puzzle 66 randomly starts at 3C that easy

[WanderingPhilospher]

And how can you calculate or guess which letter comes next? There is no way. Hash is only one way and only one piece. I can't say that puzzle 66 randomly starts at 3C that easy

I’m not guessing. All ranges will be accounted for, but if someone thinks the key lies in 1, 2, 3, etc ranges. They can focus their firepower in that range. But at least half of work in every range will be good and help towards the private key. And all of the work in the range where the key does lie, will be good.

[Evillo]

And how can you calculate or guess which letter comes next? There is no way. Hash is only one way and only one piece. I can't say that puzzle 66 randomly starts at 3C that easy

I’m not guessing. All ranges will be accounted for, but if someone thinks the key lies in 1, 2, 3, etc ranges. They can focus their firepower in that range. But at least half of work in every range will be good and help towards the private key. And all of the work in the range where the key does lie, will be good.

What about random kangaroos? Is it worth the thought?

[Kamoheapohea]

The 0.09 btc to 1BgGZ9tcN4rm9KBzDn7KprQz87SZ26SAMH maybe start of a countdown? What happens at 0? End of puzzle?

[WanderingPhilospher]

And how can you calculate or guess which letter comes next? There is no way. Hash is only one way and only one piece. I can't say that puzzle 66 randomly starts at 3C that easy

I’m not guessing. All ranges will be accounted for, but if someone thinks the key lies in 1, 2, 3, etc ranges. They can focus their firepower in that range. But at least half of work in every range will be good and help towards the private key. And all of the work in the range where the key does lie, will be good.

What about random kangaroos? Is it worth the thought?

Kangaroos are random in nature. Random starting point then they follow a jump path or you can reset them to another random starting point after they find a DP (distinguished point).

I (and whoever else joins in my race) will be using kangaroo however, I am using some other tools to shorten the range. Every little bit helps lol

[WanderingPhilospher]

The 0.09 btc to 1BgGZ9tcN4rm9KBzDn7KprQz87SZ26SAMH maybe start of a countdown? What happens at 0? End of puzzle?

IMO it was a signal so peeps would know to look at the challenge wallets; since that wallet is the most watched, recognizable address. Could be wrong though 🤷‍♂️

[Evillo]

The 0.09 btc to 1BgGZ9tcN4rm9KBzDn7KprQz87SZ26SAMH maybe start of a countdown? What happens at 0? End of puzzle?

IMO it was a signal so peeps would know to look at the challenge wallets; since that wallet is the most watched, recognizable address. Could be wrong though 🤷‍♂️

Not wrong, it was the only address with a solved pvt key that got funded almost 10x its original prize. That's a light switch.

[algorithm32]

So I was thinking, puzzle keys are not sequentially generated and masked with 0s, what if for example, for a range which is supposed to start with 1like 0x10000:0xfffff , the key generated randomly had 0x2 or 0x3 at 5th character from the right? Then Satoshi would have needed to use another key.

Example:
ae65342fff1ec7f98cade1a14fe45d0ec1778a5102b9d56cbbaa8c67f6466fda

Note, the 6 in bold, since I need my key to start with 1, I can't mask this key with leading zeros, so I would discard it and would use another one.
So don't waste your time by looking for deterministic wallet patterns, or comparing the solved keys with unsolved keys as I said and Satoshi himself said it, there is no pattern, not because we don't want people to solve them, but because we don't want them to waste their time.

What we all should focus on is the puzzles with known public keys, I'd suggest everyone to dive into the vast ocean of public keys, while we all will drown and die eventually, it will be a hell of a swim! Lol.

After seeing ten folding of the pot, I have lost my focus, I can't think throughly because now the competition has more incentive!🤣

This is what the creator did:

1- he generated an hd wallet.

Code:

0= 2f53a1484d4a3dc07d1871e4fe03c93c4397bd249a2517a80648d04e6d336e04
1= afba199519780579bc25d2f48bf48990f101bdae3db690f3f89b466c8f184525
2= 3e326376b83c52cbe6e402ab005e22de1719547e0d77a91590c4847f7a388f0c
3= 52183491eec653d4b5be15ed20a64159065583229b86fd72ca3752e88cf4e981
4= aad8c9ecb72a3f8daf8b733882ee17407b73f542b42b61eed0e902427d0e726d
5= 1d226b88d3a7b2a3bc9d4cc00fcccfe3b82b90a82e642380151796d9e524a16c
6= a4f72e154cd69588c173318f65c232587cc3f2dd975001337910d7f6b144dfbd
7= d6a1e18f4335f048837c70ea246f8673b41e5a74e3584b7824d2fa5d4c477bf5
8= 9b3a9db7778a60cf0d2c3d474ba17ef418c2397ac519ac9c1b60f60e995d949c
9= a8c032f71cb33e85cc02b91f3e4f97e3632050686bb31e1b4009c24f7e0eb079
10= 7f5de9390396eb2e7ab6cca50fdbff4d211f35537fb079c07e940a80fb16fc55
11= 818a91b6a5d7e199275059176113bc9f6eb8a13e03a40da1b072ad9081c783f8
12= 839400cd04c58069eb0f63600270f08f98bb67601f51e5cd80568ecc96389dd6
13= 2730ce4279a4307c935607f170ef8386461f19a9315b8d2470456023b1ca364e
14= 12845cff465e8f7310833dc9f16094b6e0c8f77f8f170da586a19e3255bafd3a
15= ad96e57180828f1b511afad8b85e6b9357c3eed67b7083fed0372c8570c8d696
16= f06a094e06d27a89265334855788bcaf097c4cf1688b027e994ed4b6c9a342e2
17= dcc3bb56f688fb57c5401543c8cb23a3e06342b4be57bd2dd332dec25d9f730a
18= 8564dd006f263b70701fd54fd92e065aaf1914ce50b0cee4b9ed979c3cb23be4
19= b6ec38849f2fb8949cebdafb286a68893e209a6770b2c6d0dc27088e41a46ad6
20= 6a307f21a5629851fb64092bae0c012e9d03c55432fec93a32b73f9ae6f203dc
21= 62dbc93cf77926189a6a18b5172ec2db5987489182a534644cb9e6a7fcde1c43
22= 682ad1bf7559abea4c67eb83c42608138a509380907b0c8c253ea3550d7dbc14
23= 025ef6ff4e77742a3adb2b0353468d429abcca6d367aae2a4adb54cb738f17fa
24= 60d8575ecad17a74b55e96b1c4b731fea77d093a77e402d4bf3de9e41a1d81a5
25= 1c942ce6983800902c8efdb12959b818b1eb6df4b08f6df7da043c0803d24d6b
26= 025880ce462fb1089555b8b8fa447c7bdd45e459e51858d7a770f781849bc27d
27= 7b2ddac45ee1ecbbeaf8a9e74acd270f25df3ec6d2f5d6fab259b0339e449615
28= 214288f193c1b86f1e7838ea2e78c237eb3989d96101dae703b2d83073e844d6
29= 8ce8c9851249dc1cc7d813f17cc899b616d63b1793cc09f43b54b233f037f5c7
30= dc8f88c2d35dee4b190d6112c9150a347ce5a686c4bcee59161f4f877ec62cf4
31= 9d4daa53dae6f802e4148c61dc288838789dbe58df0597468ed11d62c2919026
32= adbfe7e8babaf6068276f2f3993acb17c46eae7979c5d34327f0551ae8ac6a81
33= c92c74133aa74b61b7ac35b93d5a3cd84be1420b89794127668e9da71aeb5d8b
34= d3a035b42d3248380cdeedc9da66dd4a5478632e3c653b3cabfc0a93778789b6
35= 311d915d62b0d40965ed0ff425a249ef04d64e17cedcf054250551bce877743c
36= 14c00a6056d772aed6582e5472141920d7ff71ef31a2517985ce0d686bc3075a
37= 466828636f57391f91dd84eba5767dc5cdbf3c54ed141f36926d545861e6f1c0
38= ae702618e871ee4f25e44786dd561838a557a8e709cf4272978210a9cc8ceab3
39= 8c579bde189d28071d95571aae84dcc17f78991a20906d09a1aeb0f731ec9ce3
40= 783bba3425d542100634ff072da26881911e7e39dfab422215b9b9ebe3b7c675
41= aac45347e0e97bfbefaef651195d5b00bb12a42157ea359825a99279e4d4a8aa
42= 79060ef79cbf0760d82f96f2b5fc3c7059141fcb08a06f1216ba675648fe6c61
43= c29785c4037cd3059f3c2fe92314f5253d7f795161192dc210366272fcd3a3ec
44= fb3773697d44a0bc983f82c7c4c3c7ed22a95fff778d142cc91d091a52b04759
45= 9f0add40391cbbc53b306c1420d936f90bb81cdb6093c0cac5debe962052ae1b
46= 61b8f807f069da2f02f3d8e12ef817d3d250078541b07e2ec28f3b9ad47dfb07
47= d2f2a42eb5d53df3382b97a7bd775f81ad734663b185b836ecfd35abeee67bd6
48= 53c41511a826b979f1be86082bca1f9486998347ead14094ff32735d79a21566
49= a0d32e74b6448368bbb316b70788170fda211f4c74da3fcb5c97f495aba5b451
50= 734497e7ce5ad8c9337055b51ec0b1927a640f168fd854413fbeb56f5c4ec91f
51= 651f7b6fc524c094737da922ecea2834953859693792fa8ab3e2f1034fa09446
52= 4ffa8651a257960331e62dcd6726e318f0a85e3949aa32f9bac56b77d2c2b690
53= 8f4daf49bda283df8f998be94d47d398745fecf105cce37c0bf82728e9d1767c
54= aeafcddee6be30adb052b84a9490cc69b9bc54b9d3687c745a536deeed8b0354
55= 8f464529a75cd124818f1a104e26d39bb16ffcb5f4f9af1fe7a65edabb9583f1
56= 76086159c8f5344be3da2a34f0d74044d5dc4f9fb7e40b69fd3447e4f9c01e5b
57= 9745431abca05ddac2e1db2302461eb21bc84779149f9f1ce9290b746e72fb9f
58= 50a77f01e9433207688888c1ca2d0b6b2313e8018d71ef0e673372f13cea52a8
59= 12f452607470f347d275b9711430e5f903b7c6fd16cf3e873bebac0b913fd63d
60= 906f93f999754795e141258f3444ed3a9929491688806c6ba6d08d00814b2795
61= b2f4a62bfa642479f243e4769e054fcb0cb7bb41f3e5c4f9b82d28cb257e5cc5
62= 252ca9fad4804e2619a7b867668a970f3d301e53c9ba270ceced0897d91e6a49
63= 818a8d0f84fb5bbf7aba3b528d075bb97f22db984e1f8039b3f188d185f467c1
64= b0c43d2b10b1c1cb0300f54cb60457e815f92335023f5d92c954fc4205d2361c
65= a3528ddb893c6746f7454745d2fea367c31b307941c420ccde8cf6c96c5c9e13
66= d5506924dea980caa6cd69180543c653ff8f48b6f2297e1084bb94cc020761ea
67= 4567962f746f1f490653e11aac5905964036b38ccc2dc1d01ad436f0c595a06d
68= f0246fdad279b26dcf83a248cbe1e4006e7d2908da0151751fd1a1b0ff555527
69= 6e6a31d9624855fdf129ebb7b8619caa48ddf212932ec230ef346bda83fe7828

2-the first 8 address the creator write them manually.
3- The following keys were used only in their last digits in hex and the rest were changed to 0.
4- change the first hex of each key using a PATTERN to be below range.
5- put money in the result.

Code:

N-------------------- custom hd wallet pk----------------------------  ---------decimal--------   -----puzzle decimal--------------------

1=  0000000000000000000000000000000000000000000000000000000000000001   1                                1
2=  0000000000000000000000000000000000000000000000000000000000000003   3                                3
3=  0000000000000000000000000000000000000000000000000000000000000007   7                                7
4=  0000000000000000000000000000000000000000000000000000000000000008   8                                8
5=  0000000000000000000000000000000000000000000000000000000000000015   21                               21
6=  0000000000000000000000000000000000000000000000000000000000000031   49                               49
7=  000000000000000000000000000000000000000000000000000000000000004c   76                               76
8=  00000000000000000000000000000000000000000000000000000000000000e0   224                              224

9=  000000000000000000000000000000000000000000000000000000000000019c   412                              467
10= 0000000000000000000000000000000000000000000000000000000000000279   633                              514
11= 0000000000000000000000000000000000000000000000000000000000000455   1109                             1155
12= 0000000000000000000000000000000000000000000000000000000000000af8   2808                             2683
13= 0000000000000000000000000000000000000000000000000000000000001dd6   7638                             5216
14= 000000000000000000000000000000000000000000000000000000000000264e   9806                             10544
15= 0000000000000000000000000000000000000000000000000000000000006d3a   27962                            26867
16= 000000000000000000000000000000000000000000000000000000000000c696   50838                            51510
17= 00000000000000000000000000000000000000000000000000000000000142e2   82658                            95823
18= 000000000000000000000000000000000000000000000000000000000003730a   226058                           198669
19= 0000000000000000000000000000000000000000000000000000000000053be4   343012                           357535
20= 00000000000000000000000000000000000000000000000000000000000d6ad6   879318                           863317
21= 00000000000000000000000000000000000000000000000000000000001203dc   1180636                          1811764
22= 00000000000000000000000000000000000000000000000000000000002e1c43   3021891                          3007503
23= 00000000000000000000000000000000000000000000000000000000005dbc14   6142996                          5598802
24= 0000000000000000000000000000000000000000000000000000000000df17fa   14620666                         14428676
25= 00000000000000000000000000000000000000000000000000000000011d81a5   18710949                         33185509
26= 0000000000000000000000000000000000000000000000000000000003d24d6b   64114027                         54538862
27= 00000000000000000000000000000000000000000000000000000000069bc27d   110871165                        111949941
28= 000000000000000000000000000000000000000000000000000000000d449615   222598677                        227634408
29= 0000000000000000000000000000000000000000000000000000000013e844d6   333989078                        400708894
30= 000000000000000000000000000000000000000000000000000000003037f5c7   808973767                        1033162084
31= 000000000000000000000000000000000000000000000000000000007ec62cf4   2126916852                       2102388551
32= 00000000000000000000000000000000000000000000000000000000b2919026   2995884070                       3093472814
33= 00000000000000000000000000000000000000000000000000000001e8ac6a81   8198580865                       7137437912
34= 000000000000000000000000000000000000000000000000000000031aeb5d8b   13336534411                      14133072157
35= 00000000000000000000000000000000000000000000000000000004778789b6   19185240502                      20112871792
36= 00000000000000000000000000000000000000000000000000000009e877743c   42554848316                      42387769980
37= 000000000000000000000000000000000000000000000000000000186bc3075a   104887158618                     100251560595
38= 0000000000000000000000000000000000000000000000000000002861e6f1c0   173441216960                     146971536592
39= 00000000000000000000000000000000000000000000000000000049cc8ceab3   316964399795                     323724968937
40= 000000000000000000000000000000000000000000000000000000e731ec9ce3   992975035619                     1003651412950
41= 000000000000000000000000000000000000000000000000000001ebe3b7c675   2112649414261                    1458252205147
42= 00000000000000000000000000000000000000000000000000000279e4d4a8aa   2722553440426                    2895374552463
43= 0000000000000000000000000000000000000000000000000000065648fe6c61   6967661587553                    7409811047825
44= 00000000000000000000000000000000000000000000000000000e72fcd3a3ec   15887030789100                   15404761757071
45= 0000000000000000000000000000000000000000000000000000191a52b04759   27600847128409                   19996463086597
46= 00000000000000000000000000000000000000000000000000002e962052ae1b   51222322261531                   51408670348612
47= 00000000000000000000000000000000000000000000000000006b9ad47dfb07   118312734161671                  119666659114170
48= 0000000000000000000000000000000000000000000000000000a5abeee67bd6   182157866073046                  191206974700443
49= 0000000000000000000000000000000000000000000000000001735d79a21566   408320286528870                  409118905032525
50= 0000000000000000000000000000000000000000000000000002f495aba5b451   831873620489297                  611140496167764
51= 0000000000000000000000000000000000000000000000000007b56f5c4ec91f   2169814731639071                 2058769515153876
52= 000000000000000000000000000000000000000000000000000ef1034fa09446   4205646197068870                 4216495639600700
53= 00000000000000000000000000000000000000000000000000156b77d2c2b690   6029136892180112                 6763683971478124
54= 00000000000000000000000000000000000000000000000000282728e9d1767c   11302055743420028                9974455244496707
55= 00000000000000000000000000000000000000000000000000636deeed8b0354   27986895649309524                30045390491869460
56= 00000000000000000000000000000000000000000000000000965edabb9583f1   42325540049617905                44218742292676575
57= 000000000000000000000000000000000000000000000000013447e4f9c01e5b   86773341595115099                138245758910846492
58= 00000000000000000000000000000000000000000000000002290b746e72fb9f   155668256818133919               199976667976342049
59= 000000000000000000000000000000000000000000000000073372f13cea52a8   518884762512413352               525070384258266191
60= 0000000000000000000000000000000000000000000000000febac0b913fd63d   1147199695777420861              1135041350219496382
61= 00000000000000000000000000000000000000000000000016d08d00814b2795   1643968897298933653              1425787542618654982
62= 000000000000000000000000000000000000000000000000382d28cb257e5cc5   4047936493048454341              3908372542507822062
63= 0000000000000000000000000000000000000000000000007ced0897d91e6a49   9001860678459222601              8993229949524469768
64= 000000000000000000000000000000000000000000000000f3f188d185f467c1   17577981254080686017             17799667357578236628
65= 000000000000000000000000000000000000000000000001c954fc4205d2361c   32954241733872465436             30568377312064202855

66= 000000000000000000000000000000000000000000000003de8cf6c96c5c9e13   71376695939255016979
67= 00000000000000000000000000000000000000000000000784bb94cc020761ea   138691610353546519018
68= 00000000000000000000000000000000000000000000000f1ad436f0c595a06d   278634391653427028077
69= 0000000000000000000000000000000000000000000000151fd1a1b0ff555527   389674417014778975527

70= 000000000000000000000000000000000000000000000030ef346bda83fe7828   902680235798173743144             970436974005023690481

1- the creator used a pattern to start the keys.
2-the creator used a deterministic portfolio (it is another pattern but more complex).

Do you still believe that there is no pattern?
the creator maybe thought the same as you at the time and thought it was 100% random i guess.
Soon I will share more details, how to reduce the range.



my BTC bc1qxxt0zfle4q5uf4p0jkxk47s8sghp83mmej8rq4

[Andzhig]

2-the creator used a deterministic portfolio (it is another pattern but more complex).

He could use programming languages, python, c++... (2015 year, what were the random generators and what hardware did he use) or, if possible, hardware wallets Leger etc... in this case, if possible, you need to work in this direction with the processor of the Leger itself or emulate its processor (and through seed selection). Moreover, we do not know where these funds (+10x) come from, they can be stolen from the exchange, etc., but the author did not appear.

[ApePunk]

Creator or someone has private key of 161-256 bit range (disable)?
I will check the key in correct range. All has pubkey but you never found key with tools is big range.

[digaran]

I (and whoever else joins in my race) will be using kangaroo however, I am using some other tools to shorten the range. Every little bit helps lol

If you have a keyhunt cuda that could be used for 125+ ranges and on windows, I could join, but I don't think you have that, so while you are doing your work, I'm using  mouse and keyboard instead of software! Lol twice.

[Evillo]

I (and whoever else joins in my race) will be using kangaroo however, I am using some other tools to shorten the range. Every little bit helps lol

If you have a keyhunt cuda that could be used for 125+ ranges and on windows, I could join, but I don't think you have that, so while you are doing your work, I'm using  mouse and keyboard instead of software! Lol twice.

#125 needs Kangaroo. Nothing else. Normal brute force is gonna take entire universe time.