ARG Puzzle with 3.5 BTC Private Key Prize, Game Over

[dagi]

from OP

the prize awaits you
the final palindrome is key
once small is now tall

so change lowercase to uppercase?
only palindrome i can think of is WOW , is there any others?

0=0 A=10 baby a=36 wow? o

baby hasn't been used and could fit the hint: "once small is now tall"

0=0 A=10 baby a=36 (index)
0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz
?

[1715363585]

1715363585

[Prospero]

from OP

the prize awaits you
the final palindrome is key
once small is now tall

so change lowercase to uppercase?
only palindrome i can think of is WOW , is there any others?

0=0 A=10 baby a=36 wow? o

baby hasn't been used and could fit the hint: "once small is now tall"

baya means just little a?

oh yeah, good point

[hoba]

from OP

the prize awaits you
the final palindrome is key
once small is now tall

so change lowercase to uppercase?
only palindrome i can think of is WOW , is there any others?

palindrome could be also a hint for reversing a string here, but everything I tried doesn't work, so WOW is probably meant by the second line.

get no convincing meaning of the third line till here.

[Timmmaahh]

OP give us some useful hints :'D

[ooxtcoo]

Guys, I believe it's a shift of the original text.
Each character is shifted within the 62 character alphabet described by Crops clue.  
The amount to shift is given by the WOW signal characters.  

This program, for example transforms the "z69JZ..." string into

5KZnsvrXDcP7JFD7GCuZvifrbcBtK4kAe8nHx6ibktgvPJxs4Lp

Notice how the first two characters changed to 5K ? That's what private keys start with.  However, the answer I get doesn't transform into a valid private key since the checksum doesn't match.  I'm posting my program in the hopes someone else has a better variation.  I just want this thing over...

Code:

#include <stdio.h>
#include <string.h>

char* alph = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";

int idxof(char c, char* alphabet) {
    int i;
    for (i=0;i<strlen(alphabet);i++){
        if (alphabet[i] == c) { return i; }
    }
    return -1;
}

main()
{
    char* s = "z69JZqlJn862D1ndx7oLVEMmVOlP1zewEeUCrsI7Roahzpeny7P";
    char* p = "6EQUJ5";

    int i =0;
    int n;
    while (i < strlen(s)) {
        int n = idxof(s[i],alph);
        int v = idxof(p[i%strlen(p)],alph);
        v=(v+n) % 62;
        printf ("%c",alph[v]);
        i++;
    }
    printf ("\n");
}

EDIT: I believe there is either more after the 6EQUJ5 or the algorithm is slightly off.  Remember, if you are trying variations of the 'p' string, you must only use characters from the alphabet.  So no punctuation or spaces.

can you recheck please...

is your result ok?


cause i get a different result:


5KZnsvrXDcP7JFD7GCuZvifrbcBtK4kAe8nHx6ibktgvPJxs4Lp <-your
5KZnsarXDcPgJFD7GfuZvifEbEBtKLkAe8nSx6ibkygvPJxr4Lp <-my


or i have some error in my code, i dont know, cant find it...  



is also seems you used this:

z69JZqlJn862D1ndx7oLVEMmV "O" lP1zewEeUCrsI7Roahzpeny7P

but i think it should be:

z69JZqlJn862D1ndx7oLVEMmV "0" lP1zewEeUCrsI7Roahzpeny7P

a zero!

please correct me if iam wrong!


my c could be better, so i programmed it in delphi...

[arg]

This program, for example transforms the "z69JZ..." string into

5KZnsvrXDcP7JFD7GCuZvifrbcBtK4kAe8nHx6ibktgvPJxs4Lp

can you recheck please...

is your result ok?


cause i get a different result:


5KZnsvrXDcP7JFD7GCuZvifrbcBtK4kAe8nHx6ibktgvPJxs4Lp <-your
5KZnsarXDcPgJFD7GfuZvifEbEBtKLkAe8nSx6ibkygvPJxr4Lp <-my


or i have some error in my code, i dont know, cant find it... 

Yours is wrong somehow. I can confirm that my code returns the same result as alphabetacanary's.

[ooxtcoo]

thanks arg... then i need to search my error...


but is it a zero or a "O" ?

[alphabetacanary]

can you recheck please...

is your result ok?


cause i get a different result:


5KZnsvrXDcP7JFD7GCuZvifrbcBtK4kAe8nHx6ibktgvPJxs4Lp <-your
5KZnsarXDcPgJFD7GfuZvifEbEBtKLkAe8nSx6ibkygvPJxr4Lp <-my


or i have some error in my code, i dont know, cant find it...  



is also seems you used this:

z69JZqlJn862D1ndx7oLVEMmV "O" lP1zewEeUCrsI7Roahzpeny7P

but i think it should be:

z69JZqlJn862D1ndx7oLVEMmV "0" lP1zewEeUCrsI7Roahzpeny7P

a zero!

please correct me if iam wrong!

I think mine is correct.  The 6th char (q) shifts over to 'v' but yours goes to 'a'.  But the 6th char of the WOW sequence is a 5.  So maybe you have an error in your program?

I am using O (capital O) since that's what was posted by the OP.  I actually check both just in case but I think O (capital O) is correct.  Can someone else confirm?

[mirth23]

For the record, yesterday I attempted this same Alphabet cipher shift with the WOW signal as a key as well as the RT ASCEN timecodes, using anything that would cause the string to start out with a 5, backwards and forwards, up and down. I'm getting the same results as you all are, and no dice.

edit: which is 5KZnsvrXDcP7JFD7GCuZvifrbcBtK4kAe8nHx6ibktgvPJxs4Lp in the case of the particular code you're talking about

[ooxtcoo]

but it looks like a zero in the picture...  mhh...

[alphabetacanary]

6EQUJ5WOW as the shifter produces 5KZnsvHhJEKShKs9LduZvifr1mHVFP8FJAsix6ibkt65VvsDSQU but still not correct.

[ooxtcoo]

For the record, yesterday I attempted this same Alphabet cipher shift with the WOW signal as a key as well as the RT ASCEN timecodes, using anything that would cause the string to start out with a 5, backwards and forwards, up and down. I'm getting the same results as you all are, and no dice.

edit: which is 5KZnsvrXDcP7JFD7GCuZvifrbcBtK4kAe8nHx6ibktgvPJxs4Lp in the case of the particular code you're talking about

based on that key you used "O" not zero...

[ooxtcoo]

6EQUJ5WOW as the shifter produces 5KZnsvHhJEKShKs9LduZvifr1mHVFP8FJAsix6ibkt65VvsDSQU but still not correct.

yes i also treyed that all, but with my wrong code 

[alphabetacanary]

but it looks like a zero in the picture...  mhh...

Yes, I agree. It looks more like a zero in the picture.  But I'm pretty sure the OP had posted the 1, 2, 3 clue listing with a capital O.  But it's gone now.

[Gatekeeper]

If the font is the same as the word TWO above it then it's a zero

[arg]

I test both, but O looks to be valid.

https://i.imgur.com/wykAupC.gif

If the font is the same as the word TWO above it then it's a 0

It's a different font.

https://i.imgur.com/qB5JDAG.jpg

https://i.imgur.com/VVlx0vR.jpg


Same as Mirth23, I've tried hundreds of mutations of the strings with no result.

[Gatekeeper]

once small is now tall

is the annoying part, you can't use 6equj5 as the key because the 5th char would become a capital i , which isnt valid
you cant really change all lower case to upper case because i doubt a priv key will have no lower at all

so i guess this part is the key to solving it
we know 6EQUJ5 gives invalid code

 

[shorena]

updated pdf: https://mega.co.nz/#!UhhWHIwB!1nQUPq2gKqCC61xySHS37soRnzaFS0Ov1zSpKpllFZc

thanks to mirth23 it now has a short version.

It has all the hints AFAIK. Enjoy

[arg-sidekick]

In regards to the font, it's Lucida Sans Typewriter with a fuckton of kerning.

I think she was trying to mimic the docs font, but wasn't as anal as arg and myself.

I know, almost certainly, that the first header (RT. ACSEN.) means nothing, but it is one/two pixels higher than OG. I'm really, really plucking ideas out my rectum because I have a possible solution but I'm definitely missing something small.

Also, don't think we're closer than anyone else in this thread, we're really not.

https://i.imgur.com/0WG1oyu.gif

[Timmmaahh]

5UfPnqpcSeUYJFnhqCuj1KamzhQvP5KkeinHxqoDfoeaevcteLp

i get this but not working