Otoh
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March 16, 2012, 10:15:03 PM |
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I will shoot myself if astana, dareq or some other scammer ends up winning this.
What will happen if that is the case?
We would then have their shipping address and other personal information, and it would be winrar. But what about the BFL Single? Will they receive that as well or one of these? painted balck of course with just the red nose LED-ed
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I HATE TABLES I HATE TABLES I HA(╯°□°)╯︵ ┻━┻ TABLES I HATE TABLES I HATE TABLES
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wogaut
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March 16, 2012, 10:21:00 PM |
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Me thinks entree in line #11936 in the salted hash table won, no?
Checking... (it's just my phone and me...)
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Matthew N. Wright (OP)
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March 16, 2012, 10:21:36 PM |
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I will shoot myself if astana, dareq or some other scammer ends up winning this.
What will happen if that is the case?
Uhh, obviously I'd send it to the winner regardless.
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deepceleron
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March 16, 2012, 10:22:17 PM Last edit: March 16, 2012, 10:36:54 PM by deepceleron |
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The first 4936 tickets have 27,303,493 chances to win. The rest of the tickets have 27,303,492. Very small but a slight bias towards the earlier tickets. To be even the max valid random number is 40270 * 27303492 - 1 = 1099511622839. Just exclude numbers larger than that.
All I have to say to this..0xFFFFFFFFFF you... (thought someone could make a math joke in the thread that wasn't also a math fail...) The official block to determine the winning ticket number will be 171,450.
blockexplorer.com: Block 171450 Short link: http://blockexplorer.com/b/171450Hash?: 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 blockchain.infohttp://blockchain.info/block-index/194593/000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3Hash 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 funkymunky ABE siteShort Link: http://blockexplorer.funkymonkey.org/b/EGfzyHgKQHash: 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 Still needs to be confirmed some more to avoid the chance of a blockchain reorg, but I think we have our winner.
First ticket 0; Last ticket 40619; total number of tickets 40620; for those with the same spreadsheet as me. last-10 of hash: b7514187e3 http://we.lovebitco.in/lottery.html: Winning ticket number 11131 Calculator Method from page 3: Verify the block hash from two independent sources (ideally one being your local blockchain), Open Windows Calculator. Select View->Programmer. Select "Hex" radio button, Paste last 10 digits of hash into calculator ( b7514187e3), Press "Dec" radio button to convert to decimal ( 787342264291) Press "Mod", Enter number of tickets ( 40620) Press = See winner ( 11131) The winner is on spreadsheet line 36: 11045-11244: c267a549d21a37b371b8d4fa5b944d55bd5624dfcc735f4045031fd53a640bff
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danieldaniel
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March 16, 2012, 10:23:35 PM |
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The first 4936 tickets have 27,303,493 chances to win. The rest of the tickets have 27,303,492. Very small but a slight bias towards the earlier tickets. To be even the max valid random number is 40270 * 27303492 - 1 = 1099511622839. Just exclude numbers larger than that.
All I have to say to this..0xFFFFFFFFFF you... (thought someone could make a math joke in the thread that wasn't also a math fail...) The official block to determine the winning ticket number will be 171,450.
blockexplorer.com: Block 171450 Short link: http://blockexplorer.com/b/171450Hash?: 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 blockchain.infohttp://blockchain.info/block-index/194593/000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3Hash 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 funkymunky ABE siteShort Link: http://blockexplorer.funkymonkey.org/b/EGfzyHgKQHash: 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 Still needs to be confirmed some more to avoid the chance of a blockchain reorg, but I think we have our winner. Who is that? lol
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Matthew N. Wright (OP)
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March 16, 2012, 10:24:41 PM |
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The first 4936 tickets have 27,303,493 chances to win. The rest of the tickets have 27,303,492. Very small but a slight bias towards the earlier tickets. To be even the max valid random number is 40270 * 27303492 - 1 = 1099511622839. Just exclude numbers larger than that.
All I have to say to this..0xFFFFFFFFFF you... (thought someone could make a math joke in the thread that wasn't also a math fail...) The official block to determine the winning ticket number will be 171,450.
blockexplorer.com: Block 171450 Short link: http://blockexplorer.com/b/171450Hash?: 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 blockchain.infohttp://blockchain.info/block-index/194593/000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3Hash 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 funkymunky ABE siteShort Link: http://blockexplorer.funkymonkey.org/b/EGfzyHgKQHash: 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3 Still needs to be confirmed some more to avoid the chance of a blockchain reorg, but I think we have our winner. Yeeaaah gonna need some elaboration on that one.
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wogaut
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March 16, 2012, 10:27:08 PM |
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mod(hex2dec('0b7514187e3'),40620)=11131
Note: added a leading 0 to avoid my calculator creating a negative number.
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bitfoo
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March 16, 2012, 10:27:20 PM |
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Hash 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3
Last 10 hex digits: b7514187e3 In decimal: 787342264291 787342264291 % 40270 = 16881 Now who has that ticket number?!
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Blazr
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March 16, 2012, 10:27:43 PM |
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Yeeaaah gonna need some elaboration on that one.
Wait, you don't even understand how this process works? Ohh God, we're all screwed. This is the perfect way to fake a raffle (I'm not hinting in anyway at all this is the case) "We'll just use the blockchain to do it, don't worry about it, its completely random, its too complicated to explain, involves md5 collisions and such"
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Blazr
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March 16, 2012, 10:28:33 PM |
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mod(hex2dec('0b7514187e3'),40620)=11131
787342264291 % 40270 = 16881
Now who has that ticket number?!
Oh shit!
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wogaut
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March 16, 2012, 10:29:01 PM |
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Hash 000000000000099e18b84b47fba8ee569f117c8545fa375f33381bb7514187e3
Last 10 hex digits: b7514187e3 In decimal: 787342264291 787342264291 % 40270 = 16881 Now who has that ticket number?! Not 40270 that has changed see the latest table
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Matthew N. Wright (OP)
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March 16, 2012, 10:29:19 PM |
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Yeeaaah gonna need some elaboration on that one.
Wait, you don't even understand how this process works? Ohh God, we're all screwed. This is the perfect way to fake a raffle (I'm not hinting in anyway at all this is the case) "We'll just use the blockchain to do it, don't worry about it, its completely random, its too complicated to explain, involves md5 collisions and such" I understand it in theory, I just need to see it done and explained.
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bitfoo
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March 16, 2012, 10:30:23 PM |
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Not 40270 that has changed see the latest table
So where is the table, and who has the ticket numbers?
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wogaut
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March 16, 2012, 10:31:04 PM |
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Not 40270 that has changed see the latest table
So where is the table, and who has the ticket numbers? Check the lastest ver of the Google doc
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wogaut
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March 16, 2012, 10:33:04 PM |
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So who has ticket 11131?
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bitfoo
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March 16, 2012, 10:33:22 PM |
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So who has ticket 11131?
c267a549d21a37b371b8d4fa5b944d55bd5624dfcc735f4045031fd53a640bff
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notme
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March 16, 2012, 10:33:41 PM |
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Not 40270 that has changed see the latest table
So where is the table, and who has the ticket numbers? Check the lastest ver of the Google doc Looks like row 36.
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wogaut
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March 16, 2012, 10:34:04 PM |
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So who has ticket 11131?
c267a549d21a37b371b8d4fa5b944d55bd5624dfcc735f4045031fd53a640bff Yeah, but that's salted!
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Matthew N. Wright (OP)
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March 16, 2012, 10:34:41 PM |
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So who has ticket 11131?
c267a549d21a37b371b8d4fa5b944d55bd5624dfcc735f4045031fd53a640bff Yeah, but that's salted! It's not salted. It's just the e-mail address. As for that being the true winner, I'll wait until DeepCeleron, DeathandTaxes and Theymos all sign off on it (since they seem to be the most knowledgeable about this method of confirming).
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