Wall Observer BTC/USD - Bitcoin price movement tracking & discussion

[ChartBuddy]

Coin
Explanation

[Chef Ramsay]

Anyone tried 1broker yet? https://1broker.com/m/r.php?i=1353

I've seen this at least 3-4 times by now so you're spamming at the moment, partner. Can you offer any interest to those that will check out the site? You should pay for advertising.

[Tuck Fheman]

https://youtu.be/EZFnQEwxkeM

 

[ChartBuddy]

Coin
Explanation

[ChartBuddy]

Coin
Explanation

[12345mm]

hmmm .. wait ... what ? ... stroked out there for a second ... pancakes ?

[YourMother]

So sad to see this. They were acting so bullish after those "Nasdaq Technology" release news.

People were supposed to give a shit about this 

[ChartBuddy]

Coin
Explanation

[macsga]

Nice gravure you got there btw. You have a nice hand. You drew it on 11.2013? I *think* I'm getting the point, (I may not, you don't think that I'm actually smart do you?) and I assume you tried to figure it out no?

Thanks. But that cartoon was not related to bitcoin, it was for lecture notes of a course on math for CS.  Posted it here just because of the "Greeks and logic" topic.

I figured out it wasn't bitcoin related, that's why I posted the (2) answers...
Seriously; messing around with random data and trying to find the logic in between was something that always excited me. The rarest "human" ability nowadays (and the centuries before) is/was the combinational knowledge (ie: how do you make sense from -phenomenally- random data). I believe this should be a mandatory test in every HR department of EVERY ''high tech'' company (computer/medical/pharmaceutical etc).

You see, it's not enough to possess the information (ie: studies), you must also be able to solve the puzzle! Now I'm typing this, I remembered that the "social myth" says, there is a test that every employee should pass in order to get hired in certain companies in Japan.

Here it goes:  

Code:

A farmer returns from the market, where he bought a she-goat, a cabbage and a wolf (what a crazy market :-). 
On the way home he must cross a river. His boat is small and won't fit more than one of his purchases. 
He cannot leave the she-goat alone with the cabbage (because the she-goat would eat it), nor he can 
leave the she-goat alone with the wolf (because the she-goat would be eaten).
How can the farmer get everything on the other side in this river crossing puzzle? 

[12345mm]

begin on start side of the river with wolf, goat , and cabbage - go across the river with the goat , leaving the cabbage and wolf behind (wolf won't eat the cabbage) , leave the goat on the target side , go back to the beginning side of the river (leaving the goat on the target side) , bring the wolf back with you and leave it on the target side , bring the goat back with you to the beginning side (leaving the wolf on the target side) , then , leave the goat behind on the beginning side of the river and bring the cabbage with you to the target side of the river , come back with empty boat , leaving cabbage and wolf on the target side of the river , return to the beginning side of the river to retrieve the goat , and then return to the target side of the river with goat, cabbage , and wolf , all intact ... easy

[POM]

Im optimistic about the NASDAQ news, i hope the rally to $300 is upon us soon

[macsga]

begin on start side of the river with wolf, goat , and cabbage - go across the river with the goat , leaving the cabbage and wolf behind (wolf won't eat the cabbage) , leave the goat on the target side , go back to the beginning side of the river (leaving the goat on the target side) , bring the wolf back with you and leave it on the target side , bring the goat back with you to the beginning side (leaving the wolf on the target side) , then , leave the goat behind on the beginning side of the river and bring the cabbage with you to the target side of the river , come back with empty boat , leaving cabbage and wolf on the target side of the river , return to the beginning side of the river to retrieve the goat , and then return to the target side of the river with goat, cabbage , and wolf , all intact ... easy

Correct, but there's a shorter solution. Click here: http://brainden.com/crossing-river.htm there is a lot more where the riddle came from. Beautiful puzzles and - BTW: you're hired!

[12345mm]

begin on start side of the river with wolf, goat , and cabbage - go across the river with the goat , leaving the cabbage and wolf behind (wolf won't eat the cabbage) , leave the goat on the target side , go back to the beginning side of the river (leaving the goat on the target side) , bring the wolf back with you and leave it on the target side , bring the goat back with you to the beginning side (leaving the wolf on the target side) , then , leave the goat behind on the beginning side of the river and bring the cabbage with you to the target side of the river , come back with empty boat , leaving cabbage and wolf on the target side of the river , return to the beginning side of the river to retrieve the goat , and then return to the target side of the river with goat, cabbage , and wolf , all intact ... easy

Correct, but there's a shorter solution. Click here: http://brainden.com/crossing-river.htm there is a lot more where the riddle came from. Beautiful puzzles and - BTW: you're hired!

yeah just sortof banged that out without thinking (6 beers in) - i'm sure there's a step or two in the middle where you could double-up and increase efficiency - *i'm an expert level chess player (semi-professional) with a genius mind geared towards pattern recognition / math - puzzles = simple , though occasionally i take the long way around

[macsga]

begin on start side of the river with wolf, goat , and cabbage - go across the river with the goat , leaving the cabbage and wolf behind (wolf won't eat the cabbage) , leave the goat on the target side , go back to the beginning side of the river (leaving the goat on the target side) , bring the wolf back with you and leave it on the target side , bring the goat back with you to the beginning side (leaving the wolf on the target side) , then , leave the goat behind on the beginning side of the river and bring the cabbage with you to the target side of the river , come back with empty boat , leaving cabbage and wolf on the target side of the river , return to the beginning side of the river to retrieve the goat , and then return to the target side of the river with goat, cabbage , and wolf , all intact ... easy

Correct, but there's a shorter solution. Click here: http://brainden.com/crossing-river.htm there is a lot more where the riddle came from. Beautiful puzzles and - BTW: you're hired!

yeah just sortof banged that out without thinking (6 beers in) - i'm sure there's a step or two in the middle where you could double-up and increase efficiency - *i'm an expert level chess player (semi-professional) with a genius mind geared towards pattern recognition / math - puzzles = simple , though occasionally i take the long way around

I'm impressed! I'm nowhere near your level... BTW: It doesn't matter if you take the long road; since the destination is reached. It was a nice call from you (especially after 6 beers). I couldn't even read after a 6-pack!!

[12345mm]

haha yeah ... bonus points for being the first person to answer a logic problem whilst blotto ! ... if only being a genius would get me a job and not sitting in my pj's trading bitcoin all day ! ... though i guess in a way i've achieved total independence and self employment , i'm still underutilized as far as making a meaningful contribution to society given ability ... and making less than i'd like

[ChartBuddy]

Coin
Explanation

[12345mm]

oh and here's a fun one back for you all - was on brooklyn 99 last week or two - you've got 12 people on an island , 11 of which are the same weight , and only a balance beam to tell them apart , and you can only use the balance beam 3 times total to tell them apart - which one of the 12 people is the heavy or light one ?

[KryptoFoo]

Took profits on yesterday's long trade off the nasdaq news. Waiting mode activated.

[macsga]

oooo sorry incorrect - cannot split into 6 and 6 - one of the people is lighter *OR* heavier , splitting 6 and 6 cannot reveal whether the heavy/light person is on either side ... Wink ... (the heavy side of 6 could reveal that those 3 vs 3 of them are equal on the 2nd weighing , and leave you with an inability to determine who's the odd duck out of the 6 who weren't on the heavy side of the 1st weighing) ... it's a tricky one ... 6v6 was my first inclination as well , but the key is 1 of 12 is lighter OR heavier ...

In this case you will have to split the odds:

Heavier person case:
1. You split them in half (six persons per side)
2. Take the heaviest side and split them once more (3 persons per side)
3. Take the heaviest side and you end up with 3 persons.
4. Choose randomly the 2 of them and weight them.

If they're equal, you found the one outside. Otherwise the heavier one will be revealed by the balance.

Thinner person case:
Then you have to repeat the process for the case the person is thinner than the others.

1. You split them in half (six persons per side)
2. Take the lightest side and split them once more (3 persons per side)
3. Take the lightest side and you end up with 3 persons.
4. Choose randomly the 2 of them and weight them.

If they're equal, you found the one outside. Otherwise the thinner one will be revealed by the balance.

There is another way by dividing the weight of the persons you weighted and find if they're of the same weight every time, (ie: first time total weight/6, second time total weight/3 etc), but... I prefer simpler solutions

PS: It seems I missed the job then

[12345mm]

oooo sorry incorrect - cannot split into 6 and 6 - one of the people is lighter *OR* heavier , splitting 6 and 6 cannot reveal whether the heavy/light person is on either side ... ... (the heavy side of 6 could reveal that those 3 vs 3 of them are equal on the 2nd weighing , and leave you with an inability to determine who's the odd duck out of the 6 who weren't on the heavy side of the 1st weighing) ... it's a tricky one ... 6v6 was my first inclination as well , but the key is 1 of 12 is lighter OR heavier ...

*haha i'd hire ya anyway you seem clever enough

*the answer involves first doing 4vs4 , then eliminating either 8 or 4 from the 1st weighing , next you switch up the teams a little bit , assuming the 8 are NOT eliminated , in order to eliminate a few more , eventually you get to 3 or 2 that can be weighed , of course if 8 are eliminated , then figuring out who's the odd duck out of 4 with 2 weighings isn't terrible difficult at all