FreeBitco.in-$200 FreeBTC🏎Win Lambo🔥0.2BTC DailyJackpot🏆$32,500 Wager Contest

[boumalo]

Great Site - Saved my record

http://screencast.com/t/h3p73pTh

Best site for new users to get into owning some Bitcoin.

Pays on time every time.

Congrats, keep playing

I'd like someone to post a 400k 4M or 40M win

[snarlpill]

I asked wetsuit before on here, months ago, if anybody had ever hit 10,000 in Free Roll or 8888 in the multiplier. I don't think he ever responded, but I would still be interested to know. I like low-chance wins, like when you see somebody on just-dice hitting under 5 at 5% chance and winning big.

[wetsuit]

I asked wetsuit before on here, months ago, if anybody had ever hit 10,000 in Free Roll or 8888 in the multiplier. I don't think he ever responded, but I would still be interested to know. I like low-chance wins, like when you see somebody on just-dice hitting under 5 at 5% chance and winning big.

Honestly, I do not know how many have hit the big number because I do not keep a record of rolls to keep the database load low. At 500 million rolls, keeping  record of each would increase overhead by a lot.

[boumalo]

I asked wetsuit before on here, months ago, if anybody had ever hit 10,000 in Free Roll or 8888 in the multiplier. I don't think he ever responded, but I would still be interested to know. I like low-chance wins, like when you see somebody on just-dice hitting under 5 at 5% chance and winning big.

Honestly, I do not know how many have hit the big number because I do not keep a record of rolls to keep the database load low. At 500 million rolls, keeping  record of each would increase overhead by a lot.

@snarlpill : you can check the biggest jackpot@overall winners on http://freebitco.in/?op=stats

[energa]

Hello

how it works?

its like gambling? or some HYIP offer?

[deisik]

Hello

how it works?

its like gambling? or some HYIP offer?

You can gamble (like in an online casino), but you can also earn free bitcoins once an hour (free faucet). Surely not HYIP or anything related...

[boumalo]

Hello

how it works?

its like gambling? or some HYIP offer?

You can gamble (like in an online casino), but you can also earn free bitcoins once an hour (free faucet). Surely not HYIP or anything related...

You cannot deposit to gamble though, you can only gamble what you won from the faucets or referrals

[deisik]

Hello

how it works?

its like gambling? or some HYIP offer?

You can gamble (like in an online casino), but you can also earn free bitcoins once an hour (free faucet). Surely not HYIP or anything related...

You cannot deposit to gamble though, you can only gamble what you won from the faucets or referrals

Yeah, people would lose a lot more!

[Mayuyu48]

anyone knows how much freebitco pay us for 1 roll in $?
it seems they pay us in USD instead BTC, since their payment always change when bitcoin prices change

[deisik]

anyone knows how much freebitco pay us for 1 roll in $?
it seems they pay us in USD instead BTC, since their payment always change when bitcoin prices change

Why does it interest you? Evidently, wetsuit buys bitcoins for dollars, that's why the payment keeps constantly changing...

[natri]

Hey guys. I love this faucet however I think it is deceiving in terms of payoff and it's probability of high winnings.
Rolling a number between 1-10000 would imply a 1/10000 probability of hitting 10000, however, I think it is much lower.

Anyways, I've actually tested the randomness of rolls and the result was that rolls ARE NOT RANDOM, p=0,004 (sample 500, chi-squared).
This low p means it's almost impossible that I made error of type I, so rolls actually aren't random at all...
More info regarding my testing procedure here: http://www.reddit.com/r/Bitcoin/comments/28dtaa/wondering_freebitcoin_provably_unfair/

So, I would love if the rolls were truly random, even if it meant a lower top prices. Right now, it just seems deceiving to the point of scamming...
(btw, I've never rolled more than 9993 on any of my multiplier or regular rolls on neither faucet, probability of which should be over 75%...)

Raising false hopes, huh?

[Luror]

Hey guys. I love this faucet however I think it is deceiving in terms of payoff and it's probability of high winnings.
Rolling a number between 1-10000 would imply a 1/10000 probability of hitting 10000, however, I think it is much lower.

The probability is actually 1/20000, take a look at my earlier post:

With 2889 referrals, I find it odd that I've never gotten a 50% commission from a 0.22500000 BTC payout (10000 lucky number).

I'm in doubts the probability of rolling "10000" is 0.0001 with current algorithm, it would be interesting if someone would do an independent test (run an implementation of current algorithm 1,000,000 times, look at the amount of 10000's).

upd Ok, I looked at algorithm closer, and if everything is properly randomized, we can calculate the probability theoretically:

"3. The first 8 characters of the hex string are taken and converted to a decimal.
4. This decimal is then divided by 429496.7295 and rounded up to the nearest whole number.
5. This whole number is used as your roll, with the maximum possible value being 10,000."

We have hex strings from "00000000" to "ffffffff" (0 to 4294967295), 4294967296 in total. "ffffffff" converts to 4294967295/429496.7295 = 10000.

The biggest number which will be rounded to 10000 is 9999.5, back converting it (*429496.7295), we'll get 4294752546.63525.

So the numbers from the interval [4294752547, 4294967295] will be converted to "10000", the quantity of them = 4294967295-4294752547+1 = 214749.

The probability of getting "10000" = 214749/4294967296 = 0.00005000014789402484893798828125 (~ 1/20000)

P.S. After 40,000 rolls one should get 86% probability of rolling "10000" at least once (proof: https://www.wolframalpha.com/input/?i=1-%281-0.00005000014789402484893798828125%29^40000)

[wetsuit]

I shall set up a javascript based roll verifier within a couple of days to hopefully stop all the "your game is not fair" accusations.

[Luror]

Anyways, I've actually tested the randomness of rolls and the result was that rolls ARE NOT RANDOM, p=0,004 (sample 500, chi-squared).
This low p means it's almost impossible that I made error of type I, so rolls actually aren't random at all...
More info regarding my testing procedure here: http://www.reddit.com/r/Bitcoin/comments/28dtaa/wondering_freebitcoin_provably_unfair/

This is interesting, it is possible after all that pseudo-random numbers (for seeds) are not quite random. Why didn't you share full test results? It would be nice for someone to repeat it (though it's quite time consuming: 500 hours).

(btw, I've never rolled more than 9993 on any of my multiplier or regular rolls on neither faucet, probability of which should be over 75%...)

But you said you made only 500 rolls? Or did you mean some bigger test? You need more rolls to get 3rd and 4th prizes (at least 1250-5000).

[0 - 9885]: ~ 1/20000 + 9885/10000 = 0.98855
[9886 - 9985] ~ (9985-9886+1)/10000 = 0.01 (~ once per 100 rolls)
[9986 - 9993] ~ (9993-9986+1)/10000 = 0.0008 (~ once per 1250 rolls)
[9994 - 9997] ~ (9997-9994+1)/10000 = 0.0004 (~ once per 2500 rolls)
[9998 - 9999] ~ (9999-9998+1)/10000 = 0.0002 (~ once per 5000 rolls)
[10000] ~ 1/20000 = 0.00005 (~ once per 20 000 rolls)

sanity check: 0.98855+0.01+0.0008+0.0004+0.0002+0.00005 = 1

[wetsuit]

Anyways, I've actually tested the randomness of rolls and the result was that rolls ARE NOT RANDOM, p=0,004 (sample 500, chi-squared).
This low p means it's almost impossible that I made error of type I, so rolls actually aren't random at all...
More info regarding my testing procedure here: http://www.reddit.com/r/Bitcoin/comments/28dtaa/wondering_freebitcoin_provably_unfair/

This is interesting, it is possible after all that pseudo-random numbers (for seeds) are not quite random. Why didn't you share full test results? It would be nice for someone to repeat it (though it's quite time consuming: 500 hours).

(btw, I've never rolled more than 9993 on any of my multiplier or regular rolls on neither faucet, probability of which should be over 75%...)

But you said you made only 500 rolls? Or did you mean some bigger test? You need more rolls to get 3rd and 4th prizes (at least 1250-5000).

[0 - 9885]: ~ 1/20000 + 9885/10000 = 0.98855
[9886 - 9985] ~ (9985-9886+1)/10000 = 0.01 (~ once per 100 rolls)
[9986 - 9993] ~ (9993-9986+1)/10000 = 0.0008 (~ once per 1250 rolls)
[9994 - 9997] ~ (9997-9994+1)/10000 = 0.0004 (~ once per 2500 rolls)
[9998 - 9999] ~ (9999-9998+1)/10000 = 0.0002 (~ once per 5000 rolls)
[10000] ~ 1/20000 = 0.00005 (~ once per 20 000 rolls)

sanity check: 0.98855+0.01+0.0008+0.0004+0.0002+0.00005 = 1

The client seeds are actually generated using javascript entirely on the client side. This is the part of the Javascript code that generates the client seed (can be found in the JS file http://static4.freebitco.in/min/main1403284658.js now but the name of the file changes when I make updates) :

Code:

charSet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
var randomString = '';
for (var i = 0; i < 16; i++) 
{
  var randomPoz = Math.floor(Math.random() * charSet.length);
  randomString += charSet.substring(randomPoz,randomPoz+1);
}
$('#next_client_seed').val(randomString);

[natri]

But you said you made only 500 rolls? Or did you mean some bigger test? You need more rolls to get 3rd and 4th prizes (at least 1250-5000).

That last statement ("I've never rolled more than 9993 on any of my multiplier or regular rolls on neither faucet") I referred to all of my plays on either freebitco.in and freedoge.co.in which total way over 2000 rolls so by calculating 1-(9993/10000)^2000+ the probability should be 75%+.

Ok, lets assume prob for rolling 10k is 1/20000. But by simply checking the freebitco.in WEBSITE STATS, there was currently 538,271,966 played and 394.52490422 BTC earned, if we consider that you can ONLY win top roll price (huge undervaluation) and probability is 1/20000 to earn ONLY 0.1 BTC (undervalued) -> the expected earned value of BTC should be 2700 BTC (way more than 394).

And if we say that all ppl were extremely unlucky we can check;
variance=npq=538271996*1/20000*19999/20000
sqrt(var)=164

99.7% rule (3 std deviations): Still users should earn at LEAST: 2700-3*164= 2200 BTC, and this is with only top win of 0.1 btc.

[Luror]

Anyways, I've actually tested the randomness of rolls and the result was that rolls ARE NOT RANDOM, p=0,004 (sample 500, chi-squared).
This low p means it's almost impossible that I made error of type I, so rolls actually aren't random at all...
More info regarding my testing procedure here: http://www.reddit.com/r/Bitcoin/comments/28dtaa/wondering_freebitcoin_provably_unfair/

This is interesting, it is possible after all that pseudo-random numbers (for seeds) are not quite random. Why didn't you share full test results? It would be nice for someone to repeat it (though it's quite time consuming: 500 hours).

(btw, I've never rolled more than 9993 on any of my multiplier or regular rolls on neither faucet, probability of which should be over 75%...)

But you said you made only 500 rolls? Or did you mean some bigger test? You need more rolls to get 3rd and 4th prizes (at least 1250-5000).

[0 - 9885]: ~ 1/20000 + 9885/10000 = 0.98855
[9886 - 9985] ~ (9985-9886+1)/10000 = 0.01 (~ once per 100 rolls)
[9986 - 9993] ~ (9993-9986+1)/10000 = 0.0008 (~ once per 1250 rolls)
[9994 - 9997] ~ (9997-9994+1)/10000 = 0.0004 (~ once per 2500 rolls)
[9998 - 9999] ~ (9999-9998+1)/10000 = 0.0002 (~ once per 5000 rolls)
[10000] ~ 1/20000 = 0.00005 (~ once per 20 000 rolls)

sanity check: 0.98855+0.01+0.0008+0.0004+0.0002+0.00005 = 1

The client seeds are actually generated using javascript entirely on the client side. This is the part of the Javascript code that generates the client seed (can be found in the JS file http://static4.freebitco.in/min/main1403284658.js now but the name of the file changes when I make updates) :

Code:

charSet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
var randomString = '';
for (var i = 0; i < 16; i++) 
{
  var randomPoz = Math.floor(Math.random() * charSet.length);
  randomString += charSet.substring(randomPoz,randomPoz+1);
}
$('#next_client_seed').val(randomString);

Ok, I don't know much about Javascript programming, but I googled a little, and it seems Math.random() is not so good for some things, still it is unclear whether it can give effects like natri got:

https://stackoverflow.com/questions/5651789/is-math-random-cryptographically-secure
https://stackoverflow.com/questions/578700/how-trustworthy-is-javascripts-random-implementation-in-various-browsers
https://security.stackexchange.com/questions/20029/generate-cryptographically-strong-pseudorandom-numbers-in-javascript

The best answer seems to be this: http://stackoverflow.com/a/18507748

"Recent browsers expose window.crypto.getRandomValues() which is cryptographically strong" <--- can you use this?

[wetsuit]

But you said you made only 500 rolls? Or did you mean some bigger test? You need more rolls to get 3rd and 4th prizes (at least 1250-5000).

That last statement ("I've never rolled more than 9993 on any of my multiplier or regular rolls on neither faucet") I referred to all of my plays on either freebitco.in and freedoge.co.in which total way over 2000 rolls so by calculating 1-(9993/10000)^2000+ the probability should be 75%+.

Ok, lets assume prob for rolling 10k is 1/20000. But by simply checking the freebitco.in WEBSITE STATS, there was currently 538,271,966 played and 394.52490422 BTC earned, if we consider that you can ONLY win top roll price (huge undervaluation) and probability is 1/20000 to earn ONLY 0.1 BTC (undervalued) -> the expected earned value of BTC should be 2700 BTC (way more than 394).

And if we say that all ppl were extremely unlucky we can check;
variance=npq=538271996*1/20000*19999/20000
sqrt(var)=164

99.7% rule (3 std deviations): Still users should earn at LEAST: 2700-3*164= 2200 BTC, and this is with only top win of 0.1 btc.

Those rolls include both free and multiply rolls, and multiply rolls are way more in number.

[wetsuit]

Anyways, I've actually tested the randomness of rolls and the result was that rolls ARE NOT RANDOM, p=0,004 (sample 500, chi-squared).
This low p means it's almost impossible that I made error of type I, so rolls actually aren't random at all...
More info regarding my testing procedure here: http://www.reddit.com/r/Bitcoin/comments/28dtaa/wondering_freebitcoin_provably_unfair/

This is interesting, it is possible after all that pseudo-random numbers (for seeds) are not quite random. Why didn't you share full test results? It would be nice for someone to repeat it (though it's quite time consuming: 500 hours).

(btw, I've never rolled more than 9993 on any of my multiplier or regular rolls on neither faucet, probability of which should be over 75%...)

But you said you made only 500 rolls? Or did you mean some bigger test? You need more rolls to get 3rd and 4th prizes (at least 1250-5000).

[0 - 9885]: ~ 1/20000 + 9885/10000 = 0.98855
[9886 - 9985] ~ (9985-9886+1)/10000 = 0.01 (~ once per 100 rolls)
[9986 - 9993] ~ (9993-9986+1)/10000 = 0.0008 (~ once per 1250 rolls)
[9994 - 9997] ~ (9997-9994+1)/10000 = 0.0004 (~ once per 2500 rolls)
[9998 - 9999] ~ (9999-9998+1)/10000 = 0.0002 (~ once per 5000 rolls)
[10000] ~ 1/20000 = 0.00005 (~ once per 20 000 rolls)

sanity check: 0.98855+0.01+0.0008+0.0004+0.0002+0.00005 = 1

The client seeds are actually generated using javascript entirely on the client side. This is the part of the Javascript code that generates the client seed (can be found in the JS file http://static4.freebitco.in/min/main1403284658.js now but the name of the file changes when I make updates) :

Code:

charSet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
var randomString = '';
for (var i = 0; i < 16; i++) 
{
  var randomPoz = Math.floor(Math.random() * charSet.length);
  randomString += charSet.substring(randomPoz,randomPoz+1);
}
$('#next_client_seed').val(randomString);

Ok, I don't know much about Javascript programming, but I googled a little, and it seems Math.random() is not so good for some things, still it is unclear whether it can give effects like natri got:

https://stackoverflow.com/questions/5651789/is-math-random-cryptographically-secure
https://stackoverflow.com/questions/578700/how-trustworthy-is-javascripts-random-implementation-in-various-browsers
https://security.stackexchange.com/questions/20029/generate-cryptographically-strong-pseudorandom-numbers-in-javascript

The best answer seems to be this: http://stackoverflow.com/a/18507748

"Recent browsers expose window.crypto.getRandomValues() which is cryptographically strong" <--- can you use this?

EDIT : Looked into that and seems like it is experimental so users might run into compatibility issues. I shall try to replace the current random string generator with a stronger one.

[natri]

But you said you made only 500 rolls? Or did you mean some bigger test? You need more rolls to get 3rd and 4th prizes (at least 1250-5000).

That last statement ("I've never rolled more than 9993 on any of my multiplier or regular rolls on neither faucet") I referred to all of my plays on either freebitco.in and freedoge.co.in which total way over 2000 rolls so by calculating 1-(9993/10000)^2000+ the probability should be 75%+.

Ok, lets assume prob for rolling 10k is 1/20000. But by simply checking the freebitco.in WEBSITE STATS, there was currently 538,271,966 played and 394.52490422 BTC earned, if we consider that you can ONLY win top roll price (huge undervaluation) and probability is 1/20000 to earn ONLY 0.1 BTC (undervalued) -> the expected earned value of BTC should be 2700 BTC (way more than 394).

And if we say that all ppl were extremely unlucky we can check;
variance=npq=538271996*1/20000*19999/20000
sqrt(var)=164

99.7% rule (3 std deviations): Still users should earn at LEAST: 2700-3*164= 2200 BTC, and this is with only top win of 0.1 btc.

Those rolls include both free and multiply rolls, and multiply rolls are way more in number.

Alright, that explains it sufficiently enough then

But why is there such a huge discrepancy when generating a roll. Notice the frequency of occurrences inside the 5001-6000 bracket. I am not trying to accuse or anything but the randomness procedure might well be flawed.

Posting results:

Number   Expected   Observed   (O-E)^2/E
1-1000       50     45     0,5
1001-2000   50   42   1,28
2001-3000   50   50   0
3001-4000   50   39   2,42
4001-5000   50   52   0,08
5001-6000   50   77   14,58
6001-7000   50   51   0,02
7001-8000   50   41   1,62
8001-9000   50   42   1,28
9001-10000   50   61   2,42

EDIT: No proof or whatsoever, but I somehow also got a gut feeling that some individual numbers appear with way higher frequency than the others...