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Author Topic: bustabit.com -- The Social Gambling Game  (Read 293939 times)
klutzbelgian
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November 29, 2015, 09:00:39 PM
 #2221

This is just a heads up. I've been waiting for more then 2.5 hours for a withdraw to confirm. I'm posting the txid to see if anybody can see why its taking so long.

txid: e5a361b7da376bcf7f9575e1a16414faac6261f850740dabf9d9f6c0f1b445ed

Medium Priority...

so many input for low fee
jdh015232
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November 29, 2015, 09:02:07 PM
 #2222

so is this website ok and legit still?? what happened to the original moneypot?
RHavar
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November 29, 2015, 09:03:36 PM
 #2223

This is just a heads up. I've been waiting for more then 2.5 hours for a withdraw to confirm. I'm posting the txid to see if anybody can see why its taking so long.

txid: e5a361b7da376bcf7f9575e1a16414faac6261f850740dabf9d9f6c0f1b445ed

I think I've explained it already a couple times why on support, but it's because after that transaction was sent a flux of new transactions have come in with higher priority, and backlogged it. I promise you'll get your money, and I even created a conflicting transaction for you with an *extremely* high fees:
https://live.blockcypher.com/btc/tx/c0c364ec8bfee5059f6cb4a3fe1578643ce5bce43b2f5510d25822364732ff59/

There's nothing else I can do, and you just need to be patient, and I promise you'll get your money.

Incidentally, once 0.12 bitcoin comes out, this will be supported much better and won't be a problem.

Check out gamblingsitefinder.com for a decent list/rankings of crypto casinos. Note: I have no affiliation or interest in it, and don't even agree with all the rankings ... but it's the only uncorrupted review site I'm aware of.
Ghris
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November 29, 2015, 09:06:18 PM
 #2224

so is this website ok and legit still?? what happened to the original moneypot?

Yea this is still okay and legit. Same owner. Moneypot domain was used for another project of the same owner (check it out).

So basically it is all the same but just moved to another domain.
Muttley
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November 29, 2015, 09:07:37 PM
 #2225

so is this website ok and legit still?? what happened to the original moneypot?

Yes, it is legit (until now). No serious issues.

ranlo
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November 30, 2015, 03:14:37 AM
 #2226

This is just a heads up. I've been waiting for more then 2.5 hours for a withdraw to confirm. I'm posting the txid to see if anybody can see why its taking so long.

txid: e5a361b7da376bcf7f9575e1a16414faac6261f850740dabf9d9f6c0f1b445ed

I think I've explained it already a couple times why on support, but it's because after that transaction was sent a flux of new transactions have come in with higher priority, and backlogged it. I promise you'll get your money, and I even created a conflicting transaction for you with an *extremely* high fees:
https://live.blockcypher.com/btc/tx/c0c364ec8bfee5059f6cb4a3fe1578643ce5bce43b2f5510d25822364732ff59/

There's nothing else I can do, and you just need to be patient, and I promise you'll get your money.

Incidentally, once 0.12 bitcoin comes out, this will be supported much better and won't be a problem.

I just want to say... this is ridiculous (not you, the backlog). 0.002+ BTC fee on a somewhat small (byte-wise) transaction and after 7 hours it still has ZERO confirmations? Wow...

https://nanogames.io/i-bctalk-n/
Message for info on how to get kickbacks on sites like Nano (above) and CryptoPlay!
oryeger
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November 30, 2015, 08:30:51 AM
 #2227

This is just a heads up. I've been waiting for more then 2.5 hours for a withdraw to confirm. I'm posting the txid to see if anybody can see why its taking so long.

txid: e5a361b7da376bcf7f9575e1a16414faac6261f850740dabf9d9f6c0f1b445ed

I think I've explained it already a couple times why on support, but it's because after that transaction was sent a flux of new transactions have come in with higher priority, and backlogged it. I promise you'll get your money, and I even created a conflicting transaction for you with an *extremely* high fees:
https://live.blockcypher.com/btc/tx/c0c364ec8bfee5059f6cb4a3fe1578643ce5bce43b2f5510d25822364732ff59/

There's nothing else I can do, and you just need to be patient, and I promise you'll get your money.

Incidentally, once 0.12 bitcoin comes out, this will be supported much better and won't be a problem.

I just want to say... this is ridiculous (not you, the backlog). 0.002+ BTC fee on a somewhat small (byte-wise) transaction and after 7 hours it still has ZERO confirmations? Wow...

few weeks back I had to wait 14 hours for my transaction to show !
FX_Trader
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November 30, 2015, 08:36:26 AM
 #2228

I love playing this game, today won some bits, earlier lost, but the main thing is I love it !!
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December 04, 2015, 11:29:14 AM
Last edit: December 04, 2015, 02:49:20 PM by oryeger
 #2229

Hi Ryan, I have been trying to figure out the engine behind that makes this game provably fair.
I have read the FAQ and the thread about  "Fair Seeding Event".

I understood that you have generated 10 million hashes (with a private key and the hash from an arbitrary block set in the future).
And I understand that you play the game backwards from the 10th million hash to the 1st.
The thing I fail to understand is how the bust odd is derived from the hash that is played at the moment.

here is a quote from dooglus:
Quote
Moneypot will play through that chain of hashes, in reverse order, and use the hashes to determine the crash point in a provably fair manner.
here is a quote from the FAQ:
Quote
Third, it works out what the multiplier would be if there was no house edge.

I know i`m missing a component/level to understand it and I hope you or anyone else can explain it to me in ELI5 form.
blockage
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December 05, 2015, 12:03:39 AM
 #2230

The thing I fail to understand is how the bust odd is derived from the hash that is played at the moment.

I know i`m missing a component/level to understand it and I hope you or anyone else can explain it to me in ELI5 form.

The exact algorithm was describe in the 'provably fair seeding event'. Here it is without additional noise:

The method to convert a game hash, mix it with the picked client seed to a money pot multiplier:

Code:
function crashPointFromHash(serverSeed, clientSeed) {
  function divisible(hash, mod) {
    // We will read in 4 hex at a time, but the first chunk might be a bit smaller
    // So ABCDEFGHIJ should be chunked like  AB CDEF GHIJ
    var val = 0;
    
    var o = hash.length % 4;
    for (var i = o > 0 ? o - 4 : 0; i < hash.length; i += 4) {
      val = ((val << 16) + parseInt(hash.substring(i, i+4), 16)) % mod;
    }

    return val === 0;
  }

  var hash = crypto.createHmac('sha256', serverSeed).update(clientSeed).digest('hex');

  /* In 1 of 101 games the game crashes instantly. */
  if (divisible(hash, 101))
     return 0;

  /* Use the most significant 52-bit from the hash
     to calculate the crash point */
  var h = parseInt(hash.slice(0,52/4),16);
  var e = Math.pow(2,52);

  return Math.floor((100 * e - h) / (e - h));
}

Unfortunately, this isn't exactly ELI5. Here is also the original code that gives more details to the last line. You can also take a look at how the winning probability and the house edge are derived from the above function. The details are in the code of the onsite calculator. If you're really don't feel comfortable reading code, I can try again..

michael555
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December 05, 2015, 01:44:24 AM
 #2231

Does anybody have the script https://www.bustabit.com/user/crminer
uses?
dooglus
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December 05, 2015, 03:48:07 AM
Last edit: December 05, 2015, 04:00:50 AM by dooglus
 #2232

Code:
function crashPointFromHash(serverSeed, clientSeed) {
  function divisible(hash, mod) {
    // We will read in 4 hex at a time, but the first chunk might be a bit smaller
    // So ABCDEFGHIJ should be chunked like  AB CDEF GHIJ
    var val = 0;
    
    var o = hash.length % 4;
    for (var i = o > 0 ? o - 4 : 0; i < hash.length; i += 4) {
      val = ((val << 16) + parseInt(hash.substring(i, i+4), 16)) % mod;
    }

    return val === 0;
  }

  var hash = crypto.createHmac('sha256', serverSeed).update(clientSeed).digest('hex');

  /* In 1 of 101 games the game crashes instantly. */
  if (divisible(hash, 101))
     return 0;

  /* Use the most significant 52-bit from the hash
     to calculate the crash point */
  var h = parseInt(hash.slice(0,52/4),16);
  var e = Math.pow(2,52);

  return Math.floor((100 * e - h) / (e - h));
}

Or, in English:

To get from the sha256 hash to the crashpoint:

1) if the hash is exactly divisible by 101, crashpoint is 0x
2) otherwise crashpoint is (1 + 99e/(e-h)) / 100 to 2 decimal places, where e is 2^52 and h is the first 13 characters of the hash

Intuitively:

h ranges from 0 to 2^52-1.

If h is very small, e-h is very big, 99e/(e-h) is very close to 99, and the crashpoint is 1.00x.

If h is very big, e-h is small, 99e/(e-h) is very big, and the crashpoint is huge.

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cancerbola
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December 05, 2015, 04:58:20 AM
 #2233

Does anybody have the script https://www.bustabit.com/user/crminer
uses?

It's just a 1000x martingaling script (or as many people call it, a "nyan chaser").
But it's quite risky because sometimes a 1000x only comes after 10k rounds, so you end up "martinfailing" (go bankrupt)
However, the BaB gods have been relatively nice in November, so there weren't any severe "nyan droughts" recently.

I would suggest that you start chasing nyan only after it hasn't come for ~4k rounds or so.
dooglus
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December 05, 2015, 05:17:51 AM
 #2234

I would suggest that you start chasing nyan only after it hasn't come for ~4k rounds or so.

Waiting for a 4k nyan-gap won't improve your odds at all. You know that, right?

All it will do is mean that you are playing less games, and so your money will last longer just because of that fact.

Just-Dice                 ██             
          ██████████         
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    ██████████████████████   
        ██████████████       
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   Play or Invest                 ██             
          ██████████         
      ██████████████████     
  ██████████████████████████ 
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    ██████████████████████   
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December 05, 2015, 11:31:06 AM
Last edit: December 05, 2015, 11:45:14 AM by oryeger
 #2235

Code:
function crashPointFromHash(serverSeed, clientSeed) {
  function divisible(hash, mod) {
    // We will read in 4 hex at a time, but the first chunk might be a bit smaller
    // So ABCDEFGHIJ should be chunked like  AB CDEF GHIJ
    var val = 0;
    
    var o = hash.length % 4;
    for (var i = o > 0 ? o - 4 : 0; i < hash.length; i += 4) {
      val = ((val << 16) + parseInt(hash.substring(i, i+4), 16)) % mod;
    }

    return val === 0;
  }

  var hash = crypto.createHmac('sha256', serverSeed).update(clientSeed).digest('hex');

  /* In 1 of 101 games the game crashes instantly. */
  if (divisible(hash, 101))
     return 0;

  /* Use the most significant 52-bit from the hash
     to calculate the crash point */
  var h = parseInt(hash.slice(0,52/4),16);
  var e = Math.pow(2,52);

  return Math.floor((100 * e - h) / (e - h));
}

Or, in English:

To get from the sha256 hash to the crashpoint:

1) if the hash is exactly divisible by 101, crashpoint is 0x
2) otherwise crashpoint is (1 + 99e/(e-h)) / 100 to 2 decimal places, where e is 2^52 and h is the first 13 characters of the hash

Intuitively:

h ranges from 0 to 2^52-1.

If h is very small, e-h is very big, 99e/(e-h) is very close to 99, and the crashpoint is 1.00x.

If h is very big, e-h is small, 99e/(e-h) is very big, and the crashpoint is huge.

1) How can I divide a hash string by a number or use in in a math forumla? doest hashes have numerical value ?
2) the value of e is generated randomly or its derived out of something ?

if you can show me an exmaple of this calculation it would be great.

2) Also how are the odds of X multiplier to appear are calculated ?


RHavar: thank you for the explanation that part I understood but you made it even clearer.
I dont really know about how dice works at the backend but there is a method used by jackpot sites in the cs:go community where they used a secret string + a random generated number into a hash. they publish the hash and the secret before the game ends, once the game concludes you can take the winning number and the secret string and hash to check if it matches the hash that was published.
I can understand that this method is weak because you need to trust the site owners to generate true random numbers and strings.
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December 07, 2015, 04:22:13 AM
Last edit: December 07, 2015, 07:24:15 AM by dooglus
 #2236

1) How can I divide a hash string by a number or use in in a math forumla? doest hashes have numerical value ?

Good question. Hashes are really just very big numbers. They are usually written in hexadecimal (base 16) which uses digits 0-9 and a-f. 'a' means 10, 'b' means 11, ..., 'f' means 15.

Rather than the decimal (base 10) system, where "246" means 2 hundreds (ten squared), 4 tens and 6 ones, in hexadecimal "246" would mean 2 (16 squareds), 4 sixteens and 6 ones.

So even though the hash string has letters a through f in it, it is still just a number, and can be divided by other numbers.

2) the value of e is generated randomly or its derived out of something ?

e is just 2 to the power of 52. It is one greater than the maximum value that can be represented by a 13 digit hexadecimal number.

if you can show me an exmaple of this calculation it would be great.

I can try. I just went to bustabit and screenshotted the most recent crashes:



I copied the full hash of the top row. It is 0f81acc25a875c843f3ee3f9563bfa875be311d7585306e743120a4e68f51f0f

Then I checked that each of the next hashes forms a chain:

Code:
$ echo -n 0f81acc25a875c843f3ee3f9563bfa875be311d7585306e743120a4e68f51f0f | sha256sum
1da773ad50c9f5ce2098713e90bfe667c467fb1e1b14d3623113336899cfff4c  -

$ echo -n 1da773ad50c9f5ce2098713e90bfe667c467fb1e1b14d3623113336899cfff4c | sha256sum
c0799484b3dda03da0ab75f21ea6c34ee636dcfa40be81bc44ade2bcd6760754  -

$ echo -n c0799484b3dda03da0ab75f21ea6c34ee636dcfa40be81bc44ade2bcd6760754 | sha256sum
ba5faf9f3b9c84ac1d7ddc957a2376e9cb3638ac6f54ad4274febdf5beec2632  -

$ echo -n ba5faf9f3b9c84ac1d7ddc957a2376e9cb3638ac6f54ad4274febdf5beec2632 | sha256sum
5d3ebb05c6b2b5ab6a7397a820ae8d710712f7cf2376630dd2ed3fa747ec325c  -

That shows that the sha256 hashes are chained as described. Each game's hash is the sha256 hash of the next game's hash.

To do the calculations, I'm going to use 'nodejs', a standalone Javascript interpreter:

Code:
$ nodejs
> crypto = require('crypto');
> e = Math.pow(2,52); // e is just 2^52
4503599627370496
> clientSeed = '000000000000000007a9a31ff7f07463d91af6b5454241d5faf282e5e0fe1b3a'; // hash of block 339300
'000000000000000007a9a31ff7f07463d91af6b5454241d5faf282e5e0fe1b3a'

> serverSeed = '0f81acc25a875c843f3ee3f9563bfa875be311d7585306e743120a4e68f51f0f'; // this is the server seed shown when the game is over
'0f81acc25a875c843f3ee3f9563bfa875be311d7585306e743120a4e68f51f0f'
> hash = crypto.createHmac('sha256', serverSeed).update(clientSeed).digest('hex'); // combine the server seed with the client seed
'1cda7a31c271dd9e8b95798aedb9d6adfd83de975f5edd8315de7675b1cdc9ea'
> first13 = hash.slice(0,13); // take the first 13 digits of the hash
'1cda7a31c271d'
> h = parseInt(first13, 16); // convert it from hexadecimal to decimal
507594856474397
> Math.floor((100 * e - h) / (e - h)) / 100 // apply the formula to get the crash point
1.12

> serverSeed = '1da773ad50c9f5ce2098713e90bfe667c467fb1e1b14d3623113336899cfff4c';
'1da773ad50c9f5ce2098713e90bfe667c467fb1e1b14d3623113336899cfff4c'
> hash = crypto.createHmac('sha256', serverSeed).update(clientSeed).digest('hex');
'e2b986d935a2696722fe80a862ea044a12682341175fda4b6419524f2b38e75b'
> first13 = hash.slice(0,13);
'e2b986d935a26'
> h = parseInt(first13, 16);
3988583347345958
> Math.floor((100 * e - h) / (e - h)) / 100
8.66

> serverSeed = 'c0799484b3dda03da0ab75f21ea6c34ee636dcfa40be81bc44ade2bcd6760754';
'c0799484b3dda03da0ab75f21ea6c34ee636dcfa40be81bc44ade2bcd6760754'
> hash = crypto.createHmac('sha256', serverSeed).update(clientSeed).digest('hex');
'6798fcb15192969301ce58db9010a8d3ad4c53d834a63fd090d41851f5b07900'
> first13 = hash.slice(0,13);
'6798fcb151929'
> h = parseInt(first13, 16);
1822508354705705
> Math.floor((100 * e - h) / (e - h)) / 100
1.67

> serverSeed = 'ba5faf9f3b9c84ac1d7ddc957a2376e9cb3638ac6f54ad4274febdf5beec2632';
'ba5faf9f3b9c84ac1d7ddc957a2376e9cb3638ac6f54ad4274febdf5beec2632'
> hash = crypto.createHmac('sha256', serverSeed).update(clientSeed).digest('hex');
'bed205075a7b1ce33616840b9681a5b84522bf34b26ff3e758c3eb788b1e49af'
> first13 = hash.slice(0,13);
'bed205075a7b1'
> h = parseInt(first13, 16);
3356947788441521
> Math.floor((100 * e - h) / (e - h)) / 100
3.89

> serverSeed = '5d3ebb05c6b2b5ab6a7397a820ae8d710712f7cf2376630dd2ed3fa747ec325c';
'5d3ebb05c6b2b5ab6a7397a820ae8d710712f7cf2376630dd2ed3fa747ec325c'
> hash = crypto.createHmac('sha256', serverSeed).update(clientSeed).digest('hex');
'd7f97ec4c79f14c1e731101c7422facd5e0662eeb5481eaba9a7a681588f5697'
> first13 = hash.slice(0,13);
'd7f97ec4c79f1'
> h = parseInt(first13, 16);
3799465178462705
> Math.floor((100 * e - h) / (e - h)) / 100
6.34

I had to tell it the client seed, which is the hash of block 339300 - a block height that was picked before the block was solved, in the seeding event post, and each of the server seeds. From that information it was able to calculate the 5 crash points from the image. I didn't check whether the hashes were divisible by 101 (because I don't know how to using node), so let's do it in Python:

Code:
$ python
Python 2.7.9 (default, Mar  1 2015, 12:57:24)
[GCC 4.9.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> 0x0f81acc25a875c843f3ee3f9563bfa875be311d7585306e743120a4e68f51f0f % 101
20L
>>> 0x1da773ad50c9f5ce2098713e90bfe667c467fb1e1b14d3623113336899cfff4c % 101
43L
>>> 0xc0799484b3dda03da0ab75f21ea6c34ee636dcfa40be81bc44ade2bcd6760754 % 101
41L
>>> 0xba5faf9f3b9c84ac1d7ddc957a2376e9cb3638ac6f54ad4274febdf5beec2632 % 101
4L
>>> 0x5d3ebb05c6b2b5ab6a7397a820ae8d710712f7cf2376630dd2ed3fa747ec325c % 101
22L

That's showing the remainder after dividing each hash by 101. It's not zero for any of them, so the crash point is never 0x.

2) Also how are the odds of X multiplier to appear are calculated ?

I don't remember the details of that. I did work through it once, and found an error, so Eric (I think) ended up fixing the code.

I can understand that this method is weak because you need to trust the site owners to generate true random numbers and strings.

Yes - it's one thing for the owners to prove that they picked the outcome before you played (by publishing its hash), but that's not enough. They should also be able to prove that they had no control of the outcome. If you're playing roulette, and picking red or black, it's not enough for me to prove that I committed to rolling green "zero" before you made your bet. I should also be able to prove that I'm not picking zero more often than I should be.

That is the point of the "seeding event" I linked to above.

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December 07, 2015, 07:26:21 AM
 #2237

Code:
   var hash = sha265(i);

Pretty edgy of you to use sha256's unpopular twin brother sha265! Smiley

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    ██████████████████████   
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   Play or Invest                 ██             
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December 08, 2015, 09:36:55 PM
 #2238

For some people who were having trouble connecting, I've issued a new ssl certificate that should hopefully fix that. Also thanks to a patch by kungfuant, the game client is significantly faster.

And in other news, we set a record of having 173 people online at once! (Although the vast majority are idlers)

Check out gamblingsitefinder.com for a decent list/rankings of crypto casinos. Note: I have no affiliation or interest in it, and don't even agree with all the rankings ... but it's the only uncorrupted review site I'm aware of.
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December 09, 2015, 01:21:45 AM
 #2239

Code:
   var hash = sha265(i);

Pretty edgy of you to use sha256's unpopular twin brother sha265! Smiley
We got a badass over here Tongue Wink
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December 09, 2015, 03:33:43 PM
 #2240

I knew I had some holes in my knowledge that seems obvious to you guys by looking at the code and the FAQ couldn't satisfy me.
dooglus, your ELI5 explanation was great, thank you I understood everything perfectly.

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