sree6020
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June 08, 2019, 02:42:58 PM |
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Hello Can anyone say if luckygames.io is supported on Seuntjie dicebot.If yes please write a code for luckygames which performs the following function : Place a basebet of 0.0003 with 3X payout and bethigh=true/false(doesn't matter). Increase on loss is set at 25% and increase on win set to -50%.The bet is started with these conditions. Now if at any stage the bet amount falls below 0.000003 then the nextbet=basebet.
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Victorycoin
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June 09, 2019, 10:09:47 AM |
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Hello Can anyone say if luckygames.io is supported on Seuntjie dicebot.If yes please write a code for luckygames which performs the following function : Place a basebet of 0.0003 with 3X payout and bethigh=true/false(doesn't matter). Increase on loss is set at 25% and increase on win set to -50%.The bet is started with these conditions. Now if at any stage the bet amount falls below 0.000003 then the nextbet=basebet.
I think @seuntjie will write about it as soon as possible if it is supported on the site luckygames also you should get a response either it support the code or not, you should wait for the update.
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HCP
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June 09, 2019, 09:33:41 PM |
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Hello Can anyone say if luckygames.io is supported on Seuntjie dicebot.
All supported sites are listed right on the front page of bot.seuntjie.com: https://bot.seuntjie.com/
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sree6020
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June 10, 2019, 05:53:49 AM |
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Hello Can anyone say if luckygames.io is supported on Seuntjie dicebot.
All supported sites are listed right on the front page of bot.seuntjie.com: https://bot.seuntjie.com/Yah I see luckygames.io is not supported. @HCP Thanks for the info. But can you help me with the same code for bitsler instead.
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Victorycoin
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June 14, 2019, 06:07:09 PM |
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Hello Can anyone say if luckygames.io is supported on Seuntjie dicebot.
All supported sites are listed right on the front page of bot.seuntjie.com: https://bot.seuntjie.com/Yah I see luckygames.io is not supported. @HCP Thanks for the info. But can you help me with the same code for bitsler instead. You should ask to @seuntjie for that either they would be able to help you or not by creating the same type of code for bitsler, you may send them a message to to get fast response.
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sree6020
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June 15, 2019, 03:32:33 AM |
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Hello Can anyone say if luckygames.io is supported on Seuntjie dicebot.
All supported sites are listed right on the front page of bot.seuntjie.com: https://bot.seuntjie.com/Yah I see luckygames.io is not supported. @HCP Thanks for the info. But can you help me with the same code for bitsler instead. You should ask to @seuntjie for that either they would be able to help you or not by creating the same type of code for bitsler, you may send them a message to to get fast response. Thanks @Victory coin for the info
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velesIII
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June 18, 2019, 02:19:50 PM |
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Hello! Strategy for Dice bot There is a great strategy that anyone can help write code. The main bet is always 0.00000001 Satoshi randomized to less than 50. We are waiting for the numbers <50 to drop out three times. For example 75, 55, 51. After that, increase the rate based on the balance Balance / 2/2/2/2/2/2/2/2/2/2 ten times divided by two. The resulting bet is played at <50, that is, we check the availability of the series. As soon as the loss occurs, it drops out> 50. Increase bid by * 2 ____________________________________________________________ We bet on by less, if we win then continue with the bet to check the series to bet on> 50 before losing, and then we return to the main bet 0.00000001. If we lose, we increase the bet by * 2 and again put on less. If we win, we continue with the Balance / 2/2/2/2/2/2/2/2/2/2 bet divided by 2 again to check the series to be> 50 before losing, and then we return to the main bet 0.00000001. Twice our bet did not win with an increase. ______________________________________________________________ Then, according to anology, we continue to increase the stakes and set it already at <50, too, if we lose 2 times. We have 6 bids left until the deposit is drained. They can be divided as you like. 3 bets> 50, 3 bets <50. Or 1,2> 50. In manual mode, the strategy shows excellent results. But painful tiring. Who can help?
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HCP
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June 19, 2019, 10:32:18 PM |
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I'm sorry... but I don't really understand the strategy as you have explained it. The main bet is always 0.00000001 Satoshi randomized to less than 50. We are waiting for the numbers <50 to drop out three times. For example 75, 55, 51. After that, increase the rate based on the balance Balance / 2/2/2/2/2/2/2/2/2/2 ten times divided by two. The resulting bet is played at <50, that is, we check the availability of the series.
As I understand it, you're min-betting with 50% chance (low) until you get 3 losses in a row? Then you divide your balance in half 10 times... effectively (balance / 2^10) => (balance / 1024)... and make that your bet amount... while still betting "low" (< 50)? But then I get very lost here: As soon as the loss occurs, it drops out> 50.
What do you mean "it drops out> 50"? ![Huh](https://bitcointalk.org/Smileys/default/huh.gif) Increase bid by * 2 ____________________________________________________________ We bet on by less, if we win then continue with the bet to check the series to bet on> 50 before losing, and then we return to the main bet 0.00000001. If we lose, we increase the bet by * 2 and again put on less. If we win, we continue with the Balance / 2/2/2/2/2/2/2/2/2/2 bet divided by 2 again to check the series to be> 50 before losing, and then we return to the main bet 0.00000001. Twice our bet did not win with an increase.
As far as I can understand here... you're saying we bet "low" until we win (increasing by *2)... If win then continue to bet at the higher amount? then reset to 0.00000001 once we lose?... then wait for another 3 losses in a row... then repeat the entire process? ![Huh](https://bitcointalk.org/Smileys/default/huh.gif) Unfortunately, this is very confusing and I really don't understand how the strategy works at this point. ______________________________________________________________ Then, according to anology, we continue to increase the stakes and set it already at <50, too, if we lose 2 times. We have 6 bids left until the deposit is drained. They can be divided as you like. 3 bets> 50, 3 bets <50. Or 1,2> 50.
And here you're just randomly betting hi/low? ![Huh](https://bitcointalk.org/Smileys/default/huh.gif) I know it is difficult to try to put into words how the strategy works... but perhaps you could list a series of bets (amount + hi/low) and results to demonstrate how it works in the various examples.
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velesIII
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June 20, 2019, 05:55:22 AM |
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Hi! 1 Satoshi is the initial bet, until 3 bets fall out less for freebitcoin 5000, for example (4004,3888,1009) or more than 5000 for example (5420,8865,5215) any combinations. After that, we begin to increase the stack balance / 2 * 10
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velesIII
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June 20, 2019, 06:01:40 AM |
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Further, as soon as the rate was increased, we believe that a series of rates went from our example (4004,3888,1009), then logically it would be 4185,3545,1475, etc. before the first loss bet, for example 8565, Similarly (5420,8865,5215), we believe that 7852,9995 will fall further before losing, for example, 1565
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velesIII
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June 20, 2019, 07:39:21 AM |
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If we get a loss by the fourth bet, then we begin to double it * 2 We have 10 moves to the exit from the loss. We alternate them 3 more than 5000, 2 less than 5000 and 3 more than 5000, 2 less than 5000. This is the worst scenario. When all the moves will be used. And so the example went to the series (4004,3888,1009) these stacks of 1 satoshi no matter they won or lost or 4004, won 3888 lost, 1009 won. It is important for us that they are all less than 5000. This is a condition for raising stacks. Similar with rates higher than 5000.
Example (4004,3888,1009) new balance rate / 2 * 10 we believe that there will be a long series. If you received a winnings for example 1245, then again we bet on the continuation of the series. Until the first loss 7585. If the number of winnings is more than 4 to 40, then we immediately return the stack by 1 satoshi to the beginning. If the loss hit the intended win 1-3. After we start this bet increase * 2 and In our example, a loss of 7585 (balance / 2 * 10) * 2 is set to more than 5000. ________________________________________________________________ If they won the example 5478. Then we make the next bet. (balance / 2 * 10) / 2 Half from originally increased. And again we check a series of rates higher than 5000. (this is for increasing profitability). If a series has gone then we click well before the first loss. If you immediately lose, then return to 1 satoshi To the top of the script. __________________________________________________________________ If the loss is for example 1005, then the new rate (balance / 2 * 10) * 3 and again we put on more than 5000. ___________________________________________________________________ If you won for example 8999 then repeat: Then we make the next bet. (balance / 2 * 10) / 2 namely this. (not this rate (balance / 2 * 10) * 3) Half from originally increased. And again we check a series of rates higher than 5000. (this is for increasing profitability). If a series has gone then we click well before the first loss. If you immediately lose, then return to 1 satoshi To the top of the script. _________________________________________________________________ If the loss is for example 2582, then the new rate (balance / 2 * 10) * 4 and now we put on less than 5000. Twice put on more than 5000 now we change less than 5000. Similar with the following rates up to level 10. Betting combinations for betting with an increase * 2 2 less 3 more 3 less 2 more You need to make it possible to change the sequence: For example: 1 less, 1 more, 3 more, 2 less 3 more. The most important
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seuntjie
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June 20, 2019, 07:46:44 AM |
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Make a set of examples with bet amounts, chance, win/loss result etc.
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sree6020
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June 20, 2019, 08:46:54 AM |
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Hi, can someone help me with this strategy :The basebet is 0.00000001 placed at 1.8711X payout and bethigh=true.This bet is placed continuously until two consecutive win happens. when two consecutive win happens the nextbet becomes 0.00000100 placed at 1.8711X and bethigh=false.If this bet is a win then the conditions get back to initial that is 0.00000001 and bethigh=true.And if the bet was a loss, then also the conditions get back to initial and search for two consecutive wins and when two wins occur, the nextbet becomes 0.00000200.And again continues to initial conditions.
For example: basebet=0.00000001 1.8711X bethigh=true 1st bet-loss 2nd bet-loss 3rd bet-loss 4th bet-win 5th bet-win Now above two consecutive win occurs. So condition for next bet is 0.00000100 1.8711X bethigh=false. 6th bet-win/loss Here for the 6th bet either the result is a win or a loss the condition for 7thbet is the initial conditions i.e., 0.00000001 1.8711X and bethigh=true and continues until again two consecutive win occurs. 7thbet-loss 8th bet - loss 9th bet -win 10th bet -win Now if the 6th bet was a loss then the 11th bet will be 0.00000200 1.8711X and bethigh=false.And if the 6th bet was a win, then 11th bet will be 0.00000100 1.8711X and bethigh=false.Now again for 12 th bet conditions get back to initial and continues until two consecutive win occurs. When the two win happens the nextbet will be chosen with respect to the result of 11th bet i.e., it will be double the bet at 11 th bet if it was a loss or 0.00000100 if a win.
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Victorycoin
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June 23, 2019, 10:36:15 AM |
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Make a set of examples with bet amounts, chance, win/loss result etc.
Would you like to write code base on the example of bet amounts, chance, win/loss result etc to make it more helpful for us or something else, thanks in advance if you write the code.
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janggernaut
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JUPITER : Decentralized Exchange Aggregator on Sol
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June 23, 2019, 03:06:22 PM |
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Would you like to write code base on the example of bet amounts, chance, win/loss result etc to make it more helpful for us or something else, thanks in advance if you write the code.
I don't get your question. Seunjti will be only write the code for dicebot after you tell him what's your strategy with base bet, winning chance, % after lose or %after win, how many rolls, etc. How can he write the code if there is no such information?
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seuntjie
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June 24, 2019, 06:13:14 AM |
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Seunjti will be only write the code
No I won't. I generally don't help with programmer mode scripts. I might give a hint or a nudge in the correct direction or show you where something went wrong IF you tried it yourself, but I most definitely do not write scripts for people from scratch. There are other members of the community that does help though, like HCP and chilly2k. You can also post on forum.seuntjie.com, there are some people over there that help as well.
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velesIII
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June 24, 2019, 09:12:17 AM |
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Hello! The above strategy is written which I use myself. If you turn it into a bot, then there will be a fairy tale. In this form, as described above, I have been testing for more than six months. The results are excellent. Anyone help with writing the code.
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1982dre
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June 24, 2019, 07:03:58 PM |
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Hello! The above strategy is written which I use myself. If you turn it into a bot, then there will be a fairy tale. In this form, as described above, I have been testing for more than six months. The results are excellent. Anyone help with writing the code.
Just remember all strategies works in the beginning till you hit it worse red streak ;-) but it can be a fairytale is you stop on time
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velesIII
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June 26, 2019, 05:08:30 AM |
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basebet=0.00000001 nextbet=basebet Chance=47 function dobet()
if!win then nextbet=basebet*1 else nextbet=basebet end
bethigh=true print(curentprofit)
count=count+3 if lastBet.Roll >50.00 and lastBet.Roll <99.99 then count=0 end
if win then nextbet=basebet*3 end if currentstreak==-1 then nextbet=basebet end bethigh=false print(curentprofit) if currentstreak==-1 then nextbet=previousbet*2 end if win then nextbet=previousbet*2/2 end if win then nextbet=previousbet*2/2 end if win then nextbet=previousbet*2/2 end if win then nextbet=previousbet*2/2 end
if currentstreak==-1 then nextbet=basebet
bethlow=false print(curentprofit)
count=count+3 if lastBet.Roll >0.01 and lastBet.Roll <49.99 then count=0 end
if win then nextbet=basebet*2 end if currentstreak==-1 then nextbet=basebet end end
bethigh=true print(curentprofit) if currentstreak==-1 then nextbet=previousbet*2 end if win then nextbet=previousbet*2/2 end if win then nextbet=previousbet*2/2 end if win then nextbet=previousbet*2/2 end if win then nextbet=previousbet*2/2 end if currentstreak==-1 then nextbet=basebet end end
Hello! That's what I got according to the logic of statistics. But some functions do not work correctly. Cannot catch 3 consecutive bets <50 or> 50. See what is wrong.
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HCP
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July 18, 2019, 09:29:06 PM |
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@Agent009 This script should do what you've asked... As always, it hasn't been extensively tested (I simply used the simulation and exported the results to check it), so use at your own risk!You will need to modify the "edge" variable to match the "House Edge" of the site you want to play on... 1% HouseEdge = 1... 0.8% HE = 0.8 etc. Then set the basePayout and baseBet to suit your requirements. They are defaulted to 10x payout and 0.00000010 BTC ------------------------------------------------------------------------------- -- -- Payout Martingalge Script for Agent009 by HCP -- -- BTC Donations to: 33gzi64cvCr4i9ECGPwvZktzS2qknRUFhC -- -------------------------------------------------------------------------------
edge = 1 -- set to the house edge of your site basePayout = 10 -- set to the base payout that you want payout = basePayout
chance = (100 - edge) / payout -- calculate chance based on house edge baseChance = chance
baseBet = 0.00000010 -- 1 "unit" nextbet = baseBet -- set our initialBet
bethigh = false
function dobet()
if win then -- reset to base bet/chance/payout nextbet = baseBet chance = baseChance payout = basePayout else -- increase payout payout = payout + 1 -- recalculate chance chance = (100 - edge) / payout -- increase bet by 1 unit nextbet = previousbet + baseBet end
end
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