houseworx
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November 30, 2017, 09:25:29 PM |
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Hi I am looking for a script that inside normal martingale will monitor for for the numbers and bet if they will show twice in the row? So for example we do have normal 50% strategy with 100% on loose but if there will be 2 in the row below 1% it will bet 10% of balance below 1% and if it is above 99% it will bet 10% of balance above 99%? Is the idea explained correctly?
Doesnt seem that hard to accomplish but just for your interest, waiting for these kind of patterns doesnt change your odds. It's the same as prerolling. You will only bet after your pattern occured which makes you bet less often and will only postpone the possible loss. please don't write your pessimistic stuff all the time. you all people are angry because losed alot of money in dice, and now are saying to all other peoples, that there is no strategy to beat it(because you don't have enought knowledge to figure out it), that is why you all are doing it?! ![Cheesy](https://bitcointalk.org/Smileys/default/cheesy.gif) otherwise i dont understand all you pesimists. Cant remember saying something similar here but ok. I just tried to prevent someone from thinking that these kind of bets change something (I am fine with it as long as it is for fun purposes). I think I am currently in a plus on primedice ![Smiley](https://bitcointalk.org/Smileys/default/smiley.gif) but you cant possibly think that there is a winning strategy which will gain you profit over an inifinte amount of time, are you? on how much bets you are in +? there is difference between words "think" and allmoust "know" ![Wink](https://bitcointalk.org/Smileys/default/wink.gif) how much amount of bets you want like proof of profitable playing?! after some time, if i will not be lazy, i will make a some kind of "forum blog" for all you who thinking in your way.
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Nicoletta
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December 01, 2017, 01:53:15 AM |
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Sorry I was not asking f it is possible to win or not I was asking how to write the script that will bet normal martingale but in the same time will count i there are rolls above 99% or below 1% in the row and if they are 2 will place the bet below or above of 10% o the balance not interrupting the main strategy? It would be nice i fit was counting also how many strikes like that was there already and if there was 5 change minimal row to 3? Please Anyone know how to do that?
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Nicoletta
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December 01, 2017, 05:34:56 PM |
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Any help welcome how to make a script hunting or row of numbers below or above?
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B4RF
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December 01, 2017, 06:11:14 PM |
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Sorry I was not asking f it is possible to win or not I was asking how to write the script that will bet normal martingale but in the same time will count i there are rolls above 99% or below 1% in the row and if they are 2 will place the bet below or above of 10% o the balance not interrupting the main strategy? It would be nice i fit was counting also how many strikes like that was there already and if there was 5 change minimal row to 3? Please Anyone know how to do that?
I did no testing so there might be errors. Use it at your own risk and you might want to adjust the percentages based on your dice site. I think 99% bets are not even allowed on most sites right? basebet=0.00000001 nextbet=basebet chance=49.5
highCount=0 lowCount=0 previousbetBackup=basebet
function dobet() if highCount >= 2 then bethigh = false nextbet = balance * 0.1 chance=99.0 else if lowCount >= 2 then bethigh = true nextbet = balance * 0.1 chance=99.0 else chance=49.5 if win then nextbet = basebet else nextbet = previousbetBackup*2 end previousbetBackup = nextbet end end
if lastBet.Roll > 99 then highCount = highCount+1 else highCount = 0 end if lastBet.Roll < 1 then lowCount = lowCount+1 else lowCount = 0 end end
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HCP
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December 01, 2017, 06:42:50 PM |
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I think 99% bets are not even allowed on most sites right?
I think you got it back to front... and they're wanting to wager 10% if there are 2 rolls in a row under 1 or above 99... then wager on the 1% chance bets... not on the 99% chance bets ![Wink](https://bitcointalk.org/Smileys/default/wink.gif) ie. Roll 1 = 0.74 Roll 2 = 0.87 Roll 3 = wager 10% of balance on chance = 1, bethigh = false (ie. bet low) or Roll 1 = 99.4 Roll 2 = 99.87 Roll 3 = wager 10% of balance on change = 1, bethigh = true (ie. bet high)
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Nicoletta
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December 01, 2017, 07:48:25 PM |
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I think 99% bets are not even allowed on most sites right?
I think you got it back to front... and they're wanting to wager 10% if there are 2 rolls in a row under 1 or above 99... then wager on the 1% chance bets... not on the 99% chance bets ![Wink](https://bitcointalk.org/Smileys/default/wink.gif) ie. Roll 1 = 0.74 Roll 2 = 0.87 Roll 3 = wager 10% of balance on chance = 1, bethigh = false (ie. bet low) or Roll 1 = 99.4 Roll 2 = 99.87 Roll 3 = wager 10% of balance on change = 1, bethigh = true (ie. bet high) No No So regular bet is for example martingale 1sat 49.5 and 100% increase on loose i there will be 2 over 99% in the row i wish to bet 10% of the balance opposite direction on 99%chance as there is low chance of getting the third one. So the script should monitor for >99 and <1 and act if there is 2 in the row. than it should count how many of this hi or low strikes was and let say after 5 it should bet only if there is the row of 3
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Nicoletta
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December 01, 2017, 07:57:50 PM Last edit: December 01, 2017, 10:11:23 PM by Nicoletta |
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well almost basebet=0.00000001 nextbet=basebet chance=49.5
highCount=0 lowCount=0 previousbetBackup=basebet
function dobet() if highCount >= 2 then bethigh = false nextbet = balance * 0.1 chance=99.0 else if lowCount >= 2 then bethigh = true nextbet = balance * 0.1 chance=99.0 else chance=49.5 if win then nextbet = basebet else nextbet = previousbetBackup*2 end previousbetBackup = nextbet end end
if lastBet.Roll > 99 then highCount = highCount+1 else highCount = 0 end if lastBet.Roll < 1 then lowCount = lowCount+1 else lowCount = 0 end end
it looks like it waits one bet before the correct bet i do not know why? anyone knows why after 2 bets i am looking it does 3rd bet on 49.5% and then it does the 99% bet instead o directly after?
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HCP
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December 02, 2017, 05:02:20 AM |
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No No So regular bet is for example martingale 1sat 49.5 and 100% increase on loose i there will be 2 over 99% in the row i wish to bet 10% of the balance opposite direction on 99%chance as there is low chance of getting the third one. So the script should monitor for >99 and <1 and act if there is 2 in the row. than it should count how many of this hi or low strikes was and let say after 5 it should bet only if there is the row of 3
Ahhhh ok, yeah... that makes way more sense! ![Wink](https://bitcointalk.org/Smileys/default/wink.gif) You're looking for clusters of <1 or >99 rolls... and then wager 10% of current balance on the opposite, hoping you don't get 3x "<1" or ">99" rolls in a row. But you're also wanting to count these clusters... so after 5 clusters, change so you only bet 10% if there were 3x "<1" or ">99" rolls.. well almost it looks like it waits one bet before the correct bet i do not know why? anyone knows why after 2 bets i am looking it does 3rd bet on 49.5% and then it does the 99% bet instead o directly after?
It's because the check for highCount >= 2 is effectively being done BEFORE the checking of the previous roll... so, what is happening is that the script is checking if highCount >= 2... then it actually checks the previous roll and increments the count... it should be the other way around and increment first and then check... like this: basebet=0.00000001 nextbet=basebet chance=49.5
highCount=0 lowCount=0 previousbetBackup=basebet
function dobet() if lastBet.Roll > 99 then highCount = highCount+1 else highCount = 0 end if lastBet.Roll < 1 then lowCount = lowCount+1 else lowCount = 0 end
if highCount >= 2 then bethigh = false nextbet = balance * 0.1 chance=99.0 else if lowCount >= 2 then bethigh = true nextbet = balance * 0.1 chance=99.0 else chance=49.5
if win then nextbet = basebet else nextbet = previousbetBackup*2 end previousbetBackup = nextbet end
end
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seuntjie
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December 04, 2017, 12:14:23 PM |
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For those that are not aware (Which I guess is most of you, I haven't posted any documentation about it), a few versions ago I added a site object to the programmer mode that contains details of the site you're currently logged in to in the bot. The "site" object is of type SiteDetails: public class SiteDetails { public string name { get; set; } public decimal edge { get; set; } public decimal maxroll { get; set; } public bool cantip { get; set; } public bool tipusingname { get; set; } public bool canwithdraw { get; set; } public bool canresetseed { get; set; } public bool caninvest { get; set; } public string siteurl { get; set; } } You can use the details to determine whether or not you should try to tip/withdraw, what calculate chance/payout accurately etc. I will at some point implement functions for calculating chance/payout and similar functions to the object as well, but I have no ETA for that. An example of using the object: print('You\'re betting on ' + site.name) payout = (100.0-site.edge)/chance if bethigh then betwin = lastBet.Roll>(site.maxroll-chance) else betwin = lastBet.Roll<(chance) end if site.cantip then if site.tipusingname then tip('seuntjie',1) else tip('91380',1) end else if site.canwithdraw then withdraw('address',1) end
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Mamasmurf19
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December 04, 2017, 01:17:43 PM |
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I have read in a different topic yesterday, that the rule of the average sum applies to random generators. I checked it myself and so far it turns to be correct. The average number from hundreds, thousands, ten thousands rolls is between 49 and 51 with slight exceptions regarding the hundreds. I am not a programmer myself, but is it possible a script to be written, which analyzes the last 50 rolls for example and if the average is displaced from its center ( which we accept that is 50) to start betting on the other side until balance is reached. Not quite sure I am explaining myself clearly... if you have average of 40 you start betting high until you get to 49 for example. Hope you understand what I mean. Not sure is it a possible task either. Anyways it is a fresh idea worth checking it I believe. Cheers.
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houseworx
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December 10, 2017, 04:13:47 PM |
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anyone can tell me what are doing this command lines?
if (randomHighLow) then if (math.random() < .0237) then bethigh = !bethigh end
if script are using only in bethigh mode?! i think nothing, right?
and why there is some 0.0237? any clue?!
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chilly2k (OP)
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December 10, 2017, 04:25:20 PM |
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anyone can tell me what are doing this command lines?
if (randomHighLow) then if (math.random() < .0237) then bethigh = !bethigh end
if script are using only in bethigh mode?! i think nothing, right?
and why there is some 0.0237? any clue?!
randonHighLow must be a true/false variable. If it's true then generate a random number between 0 and 1. So .0237 is 2.37%, so 2.37% of the time switch between betting high and low.
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chilly2k (OP)
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December 15, 2017, 04:27:15 AM |
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I hope someone can help me with my script or my idea. Im totaly new to this :/ I would like to 1. roll the dice with basebet 0.00000001 Chance 49.5% 2. After 4 Wins (not especially in a row) -> nextbet 0.00001000 3. If bet lost = previousbet*2 (repeat 6x times if its still a loosing bet. After 6x losses in a row go back to basebet), if bet won nextbet = basebet (0.00000001) 4. Stop after target = 0.00010000 I tried something like that... but well its not doing what i want it to do ![Cry](https://bitcointalk.org/Smileys/default/cry.gif) startbalance=balance
function dobet()
chance=49.50 basebet=0.00000001
if win then wincounter +=1 end
if wincounter>3 then wincounter=0 nextbet = 0.00001000 <-- #Don´t know why he is not doing this bet Bot jumps to #A or #B if balance > startbalance then nextbet = basebet <-- #A else nextbet=previousbet*2 <-- #B end if currentstreak%6==0 then <-- to avoid loosing strikes but somehow its also not working :/ nextbet=basebet end end also the part with the target is missing... that the bot should stop after he reaches 0.00010000 I hope you can help me ... im totaly new to this .. Thanks You look close... Lua is not the best at telling you whats wrong. I think the whole problem is you didn't define wincounter. Before the function statement add wincounter = 0. Also add nextbet = .00000001 and chance = 49.5 The very first bet is rolled before the function is called, so you need to set that up. You could actually move the lines of code you only need to set once up there.
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HCP
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December 15, 2017, 07:35:31 AM |
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It is because you say: nextbet = 0.00001000 and then IMMEDIATELY give the script two options: if balance > startbalance then nextbet = basetbet else nextbet = previousbet*2 end So regardless of which option is true... nextbet is going to get changed... EVERY time... it will either bet basebet or it will be previousbet*2 Your "if currentstreak%6==0 then" statement is not working to stop losing streaks... because it is INSIDE the "if wincounter > 3" block... so that condition is ONLY checked if wincounter > 3... so it will only trigger when you have a losing streak of 6 AFTER wincounter > 3... but you immediately set wincounter to 0 as soon as getting in, so you'll NEVER have the situation where your losing streak is 6 and wincounter > 3. WARNING: This code is mostly untested... I did a quick check and it *seems* to work as desired... use at your own risk! ![Wink](https://bitcointalk.org/Smileys/default/wink.gif) -- FourWins Strategy for fwalser -- coded by HCP
startbalance = balance target = 0.00010000
chance = 49.50 basebet = 0.00000001 bigbet = 0.00001000 wincounter = 0 fourWins = false
nextbet = basebet
function dobet() if win then wincounter += 1
if fourWins then --win while betting big, reset back to base nextbet = basebet fourWins = false wincounter = 0
else --win while basebetting, check if we have had 4 wins if wincounter > 3 then wincounter = 0 fourWins = true nextbet = bigbet else nextbet = basebet end
end
else -- we lost if fourWins then -- bigbetting, see if our lossstreak is 6 losses if currentstreak == -6 then -- 6x loss streak, cut our losses and reset fourWins = false wincounter = 0 nextbet = basebet else -- loss while big betting, double up! nextbet = previousbet*2 end else -- standard loss nextbet = basebet end
end
--Profit Target check if ((balance - startbalance) > target) then --target profit reached print("Target reached! STOPPING!") nextbet = 0 stop() end
end
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stormbreaker1
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December 18, 2017, 05:25:30 AM |
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tnx HCP i go to try script with doge ![Cheesy](https://bitcointalk.org/Smileys/default/cheesy.gif)
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houseworx
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December 18, 2017, 04:24:16 PM |
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looking for people what are good in mathematical formula making, please pm.
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Nicoletta
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December 20, 2017, 11:50:31 AM |
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Hello my helpful friends. I need a script to bet 1 sat on 49.50 if win bet the same bet i lose bet x2 until it gets a profit 100 sat once profit 100 sat reset and get back to 1 sat bet all this until total profit from start reaches 1000 sat than stop
how to archive that?
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houseworx
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December 20, 2017, 11:57:54 AM |
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Question!what is better to use, for better/easiest bot reading and don't looping: if bla bla then bla bla end
if bla bla then bla bla end
if bla bla then bla bla end OR if bla bla then bla bla elseif bla bla elseif bla bla elseif bla bla end ?!
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HCP
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December 20, 2017, 05:54:37 PM |
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Depending on how you order the if-elseif statements, it *should* be more efficient than multiple individual "if" blocks...
This is because when checking "if-elseif" block, the interpreter will stop checking as soon as it hits the first one that evaluates as true...
However, with individual blocks, the interpreter has to evaluate every single one of them.
Therefore, you should order your if-elseif statements from "most likely" to be true to "least likely" for maximum efficiency.
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