LoyceV


May 26, 2016, 01:42:34 PM 

It is But the other way around: 10050=50%, and that takes half the time of 1002575%. = zero!Archived for future reference http://archive.is/MXUonLol, why would you archive my typo? I fixed it now, I just hit the wrong button. A few (!) pages back I mentioned the discrepancies with the time estimation for 50% 75% etc This is from my system right now: Searching for pattern: "1EXAmoney" Reward: 0.008000 Value: 0.000001 BTC/MkeyHr Difficulty: 50656515217834 [38.97 Mkey/s][total 33002830692352][Prob 47.9%][50% in 15.0h] using OclVanityMiner64.exe  to my way of thinking, half of 50 should be 25... Similarly, this is where I'm at now... Searching for pattern: "1EXAmoney" Reward: 0.008000 Value: 0.000001 BTC/MkeyHr Difficulty: 50656515217834 [42.58 Mkey/s][total 40233450078208][Prob 54.8%][75% in 8.2d] (again, I would have imagined at 40/50 I'd be 80% done  No?) The percentage is not based on a linear algorithm. The key's that you are processing are generated based on randomness. So the progress indicator is following some statistical algorithms that involve normal distribution, 'bellcurves', probability etc. In short; this indicator shows the chance that you would have found a hit by now. Exactly. The "percentage left" is cut in half every x minutes, where x is the time it shows you for 50% when you start it.







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Timelord2067


May 26, 2016, 02:09:26 PM 

I've spent the last three hours being badgered by somebody because KeyBase.Io won't read my message to them... (not to mention the previous 24 hours) ... and it's nearly midnight... Exactly. The "percentage left" is cut in half every x minutes, where x is the time it shows you for 50% when you start it.
This isn't making sence. Are you saying IF a job were to take Five hundred hours to reach 50% it would take a further  Five Hundred hours to reach 75%
 Two Hundred and Fifty hours to reach 75%
 D  Three Apples
If the answer is a further Five Hundred hours to reach 75%, (and half of 25 = 12.5% therefore 75% + 12.5% = 87.5%), would it be about (I said about people) a further two hundred hours to reach the next bench mark 80%? (not withstanding the 87.5% half of half of half of 100%)?




LoyceV


May 26, 2016, 02:38:25 PM 

Exactly. The "percentage left" is cut in half every x minutes, where x is the time it shows you for 50% when you start it.
This isn't making sence. Are you saying IF a job were to take Five hundred hours to reach 50% it would take a further  Five Hundred hours to reach 75%
 Two Hundred and Fifty hours to reach 75%
 D  Three Apples
If the answer is a further Five Hundred hours to reach 75%, (and half of 25 = 12.5% therefore 75% + 12.5% = 87.5%), would it be about (I said about people) a further two hundred hours to reach the next bench mark 80%? (not withstanding the 87.5% half of half of half of 100%)? 500 hours for 50% chance 500 more hours for 75% chance (1000 hours total) 500 more hours for 87.5% chance (1500 hours total) etc.




TheBossMan
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May 26, 2016, 05:50:49 PM 

I have been quite lucky, I found x8 that I searched for did take like 3 days to get them all but persistence pay's off!




Timelord2067


May 26, 2016, 06:44:27 PM 

Exactly. The "percentage left" is cut in half every x minutes, where x is the time it shows you for 50% when you start it.
This isn't making sence. Are you saying IF a job were to take Five hundred hours to reach 50% it would take a further  Five Hundred hours to reach 75%
 Two Hundred and Fifty hours to reach 75%
 D  Three Apples
If the answer is a further Five Hundred hours to reach 75%, (and half of 25 = 12.5% therefore 75% + 12.5% = 87.5%), would it be about (I said about people) a further two hundred hours to reach the next bench mark 80%? (not withstanding the 87.5% half of half of half of 100%)? 500 hours for 50% chance 500 more hours for 75% chance (1000 hours total) 500 more hours for 87.5% chance (1500 hours total) etc. As Missy says to me all the time... Bonkers!I suppose there's no point asking why it doesn't just make it a little more linear instead of exponential?




LoyceV


May 26, 2016, 07:41:07 PM 

I suppose there's no point asking why it doesn't just make it a little more linear instead of exponential?
A chance to find something simply isn't lineair, as it will never reach 100% chance. The chance always stays the same: if it's 500 hours for 50% chance, it's exactly the same chance after you've run it after a week. That's why you can just as well restart the the search at any moment.




Velkro
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Activity: 1260
<3 Vanity Addresses :)


May 28, 2016, 05:39:53 AM 

A chance to find something simply isn't lineair, as it will never reach 100% chance.
Agree, i love vanity addresses so i studied on my own a lot. Because of that, i know you can restart your generation process how many times u want, and still have same chance to find address.




LoyceV


May 28, 2016, 06:00:36 AM 

A chance to find something simply isn't lineair, as it will never reach 100% chance.
Agree, i love vanity addresses so i studied on my own a lot. Because of that, i know you can restart your generation process how many times u want, and still have same chance to find address. WARNING! DO NOT use the site advertised by the Red Trust user above!Too bad red trust doesn't show up on this topic, so scammers can happily advertise their scam in this topic. bitcoin stolen from the address generated by bitcionvanitygen.com





Avirunes
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May 29, 2016, 08:32:16 AM 

Just have a question. I don't have any graphic card installed and i want to do mining work on bounty pool but it gives me error OpenCl.dll missing which I guess is because I don't have any graphic card. So is there any way to do this work without having a graphic card??




LoyceV


May 29, 2016, 08:38:51 AM 

Just have a question. I don't have any graphic card installed and i want to do mining work on bounty pool but it gives me error OpenCl.dll missing which I guess is because I don't have any graphic card. So is there any way to do this work without having a graphic card??
You must have an onboard graphics card, right? My laptop has an onboard GeForce, so it can even be quite acceptable for vanity searching. It's too slow though to be profitable for the mining pool, and if you're running CPU only, I doubt it will be worth your time and electricity.




Velkro
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<3 Vanity Addresses :)


June 05, 2016, 12:41:05 PM 

So is there any way to do this work without having a graphic card??
Well maybe there is, but it would be so slow that its not worth it. Currently there are many cheap graphic cards that could do the job for you. If you will not "mine vanity addresses", you could switch later to mining with graphic card some alt coins. So depends on you how you want aproach it.




bitba.org


June 11, 2016, 02:47:47 PM 

I want to run vanitygen and if address balance is not zero vanity tell me what may i do ?




defcon23
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June 11, 2016, 02:50:00 PM 

I want to run vanitygen and if address balance is not zero vanity tell me what may i do ?
when you run vanitygen it will create a new pair of keys ... so this kind of problem should'nt never happend




xhomerx10
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June 11, 2016, 04:24:14 PM 

I want to run vanitygen and if address balance is not zero vanity tell me what may i do ?
Not that you will ever have the opportunity but in the extremely unlikely case that this happens, only your conscience can tell you what to do.




LoyceV


June 11, 2016, 07:28:42 PM 

I want to run vanitygen and if address balance is not zero vanity tell me what may i do ?
Not that you will ever have the opportunity but in the extremely unlikely case that this happens, only your conscience can tell you what to do. It's much more likely to just guess Bill Gates' creditcard number, that's only 16 digits, and only numbers. Strangely nobody worries about that, but when it comes to bitcoin, all of a sudden guessing 70 characters seems like a possibility.




Jude Austin
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The Real Jude Austin


June 11, 2016, 07:42:53 PM 

Yeah, I've been searching for a collision for like 3 years now, not a single one.




hexafraction


June 11, 2016, 11:35:10 PM 

Yeah, I've been searching for a collision for like 3 years now, not a single one. I would think that Electrum would be far less efficient than a purposemade application that simply has a set datastructure designed for fast contains() operations containing all addresses with nondust amounts (by searching the chain) attached to an iterated key generator would increase your efficiency (still extremely futile and not likely at all to find any collisions). Remember that people actually use the Electrum servers for real transactions they need to send and receive.




Jude Austin
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The Real Jude Austin


June 12, 2016, 01:57:59 AM 

Yeah, I've been searching for a collision for like 3 years now, not a single one. I would think that Electrum would be far less efficient than a purposemade application that simply has a set datastructure designed for fast contains() operations containing all addresses with nondust amounts (by searching the chain) attached to an iterated key generator would increase your efficiency (still extremely futile and not likely at all to find any collisions). Remember that people actually use the Electrum servers for real transactions they need to send and receive. I am running a special made script through Electrum Python console that generates random Bitcoin addresses and then checks the balance on my local Insight server. If an address has a totalReceived balance then it adds the address to the wallet using importprivkey(), will also send a pushbullet notification to my phone/laptop. I still haven't implemented what I will do if I find a balance but I want to sign a message telling people where to contact me if this was their address. If they sign back then I will refund the balance to an address of their choice as I don't intend on stealing from people. It's well known that the odds of finding a collision are not favorable but I like challenges so I am destined to find one. I should actually be counting how many addresses I have search so if I do happen to find one I will have a ratio to share. I've been thinking about using machine learning to see if I can find a pattern in the key generation but I need to read more and I don't think there is enough storage to get even close to the amount of data I need to find a pattern.




defcon23
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June 12, 2016, 08:55:12 AM 

Yeah, I've been searching for a collision for like 3 years now, not a single one. yeah , i had already seen a runing script scanning the entire blockchain database to looking for nondust amount .. and this script never got any collision too.. anyway that's always interesting, as a challenge, to try running these kind of scripts ,or better : to try coding them ( in an ethical way, indeed ) and, as mentioned above, only your conscience could tell you what to do in case of an "hypotetic" collision ..




